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This presentation gives you an idea about how the normalization process is being done in JEE by using board percentile as the basis.
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Presented byAnchit Das 13810010
Ashish Pandey 13810020Gaurav kumar Gupta 13810030
Kartik Khamesra 13810040Mohit Chaudhary 13810050
Pawan Arora 13810060Shashi Kiran Lugun 13810070
Vaibhav Agarwal 13810080
NORMALISATION
Adjusting values measured on different scales to notionally common scales.
In Indian JEE context:
Process for ensuring students are neither advantaged nor disadvantaged by the difficulty of their respective board exams
NORMALISATION
Percentile Score:
No. of candidates in the group with aggregate marks less than the candidatesTotal number of Candidate in that group
For example, the 20th Percentile is the value (or score) below which 20 Percent of the observations may be found.
ANALYTICS OF NORMALISATION
100 *
i) Note down the aggregate marks (A0) obtained by each student in JEE- Main.ii) Compute the percentile (P) of each student on the basis of aggregate marks in his/her own board (B0) computed from the list of five subjects specified (each marked out of 100). The percentile is to be computed among all students of the board whose subject combinations meet the eligibility criteria of JEE-Main.iii) Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level. Regard this as B1.iv) Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the set of aggregate scores obtained in the JEE- Main by the students of that board. Regard this as B2.The normalized board score of the candidate will be computed as:
Bfinal = 0.5 * (B1 + B2)
Procedure for Normalization
Step 1: Calculate Percentile (Pi) of the Candidate with reference to the group of Candidates of Board ABCD who also satisfy the eligibility criteria of JEE (Main).
Normalisation of Board Marks for JEE (Main)
Step 2. Arrange JEE (Main) score of all 11.5 lakhs Candidates in ascending order and find out Percentile for each score.
Normalisation of Board Marks for JEE (Main)
Step 3. Arrange JEE (Main) score of Candidates from Board ABCD only, in ascending order and find out the Percentile for each score.
Normalisation of Board Marks for JEE (Main)
Step 4. 4.i Use Percentile (Pi), 50.07, calculated from step 1 and find out the same Percentile in the Percentile calculated in step 2.
Normalisation of Board Marks for JEE (Main)
4.ii Now, to find B1, find out JEE (Main) score, corresponding to the matched Percentile in 4.i above. This is B1. Here, B1 = 48.
Normalisation of Board Marks for JEE (Main)
Step 5. 5.i Use Percentile (Pi), 50.07, calculated from step 1 (Table 2) and find out the same Percentile in the Percentile calculated in step 3 (Table 4).
Normalisation of Board Marks for JEE (Main)
5. ii Now, to find B2, find out JEE (Main) score, corresponding to the matched Percentile in 5.i. above. This is B2.
Here B2 = 80. Board Percentage (B0)
Normalisation of Board Marks for JEE (Main)
Step 6.Normalised Board mark of the Candidate from Board ABCD who has scored 60% will be
Bfinal = 0.5 * (B1 + B2) => Bfinal = 0.5 * (48+80) => Bfinal = 0.5 * (128) => Bfinal = 64
Normalisation of Board Marks for JEE (Main)
For the purpose of admission to CFTIs where it has been decided to use the JEE Mains performance and the Normalized Board performance in the 60:40 ratio, the composite score for drawing the merit list will be computed as:
C = 0.6 * AO + 0.4 * Bfinal
Normalisation of Board Marks for JEE (Main)
How boards played important role in determining JEE score
Example to support the argument that boards are playing the role of deciding factors whereas the JEE (main) has become almost redundant:
Student Name: KarthikBoard: CBSEMarks in JEE (main): 99Board Percentage: 94.6AIR: 34000 (approximately.) Student Name: AshishBoard: CBSEMarks in JEE (main): 135Board Percentage: 90AIR: 60000 (approximately.)
Example to support the argument that different boards differ radically in terms of their competition levels.
Student Name= GauravBoard= CBSEBoard Percentage= 90.2%Marks in JEE (main) = 267Rank= Beyond 5000 Student Name= AnchitBoard= Rajasthan BoardBoard Percentage= 90%Marks in JEE (main) = 195Rank= 4400
Example to explain how major the role played by the boards was
Student Name: VaibhavBoard: CBSEMarks in JEE (main): 201Board Percentage: 88AIR: 23000 (approximately.) Student Name: MohitBoard: CBSEMarks in JEE (main): 201Board Percentage: 94AIR: 9000 (approximately.)
THANK YOU