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Finding the Number of Permutations….. with Repeat ow many arrangements are there of four letters from the word PREACHING? 9 P 4 w many distinct arrangements of BRAINS are there eeping the vowels together? 5! x 2! = 240 re are 6 different flags available for signaling. A nsists of at least 4 flags tied one above the other ny different signals can be made? 6 P 4 + 6 P 5 + 6 P 6 = 1800 Math 30-1 1 = 3024 9! 9 4! 9! 5!

11.1C Finding the Number of Permutations….. with Repeats

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Finding the Number of Permutations 4. In how many ways can the letters of the word MATHPOWER be arranged if: a) there are no restrictions? 9! = 362 880 b) the first letter must be a P and the last letter an A? 1 x 7! x 1 = 5040 c) the letters MATH must be together? 6! x 4! = 17 280 d) the letters MATH must be together and in that order? 1 x 6! = 720 Math 30-1

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Page 1: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 1

11.1C Finding the Number of Permutations….. with Repeats

1. How many arrangements are there of four letters from the word PREACHING?

9P4

2. How many distinct arrangements of BRAINS are there keeping the vowels together?

5! x 2! = 240

3. There are 6 different flags available for signaling. A signal consists of at least 4 flags tied one above the other. How many different signals can be made?

6P4 + 6P5 + 6P6 = 1800

= 3024 9!

9 4 !

9!5!

Page 2: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 2

Finding the Number of Permutations4. In how many ways can the letters of the word MATHPOWER be arranged if:

a) there are no restrictions?

b) the first letter must be a P and the last letter an A?

d) the letters MATH must be together and in that order?

c) the letters MATH must be together?

9! = 362 880

1 x 7! x 1 = 5040

1 x 6! = 720

6! x 4! = 17 280

Page 3: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 3

Permutations with RepetitionHow many four-letter arrangements can be made using the letters of PEER?

4P4 = 4! = 24 WAYS

PEERPEERPREEPREEPEREPERE

RPEERPEEREPEREPEREEPREEP

EPEREPEREEPREEPREERPEERP

EREPEREPERPEERPEEPREEPRE

There are 24 arrangements however there are only 12 differentarrangements. - 12 matching pairs of 2 four-letter arrangements.

24 /2 or 12 Arrangements

Page 4: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 4

How many six-letter distinguishable arrangements can be made using the letters of CHEESE?

6P6 = 6! But the three E’s can be rearranged 3! = 6 different ways within any one particular arrangement of letters. These six arrangements would be seen as the same if the E’s were no longer distinct:

We must divide by 3!

6 6

3!P 6 5 4 3!

3!

6 5 4 120

Page 5: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 5

The number of permutations of n objects taken n at a time, ifthere are a alike of one kind, and b alike of another kind, c alikeof a third kind, and so on, is:

n!a!b!c!...

Permutations with Repetition

The number of permutations of n objects taken r at a time, ifthere are a alike of one kind, and b alike of another kind, c alikeof a third kind, and so on, is:

! ! !...n rP

a b c

Page 6: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 6

Permutations with Repetition1. In how many ways can the letters of the word POPPIES be arranged?

a) without restrictions b) if each arrangement begins with a P

c) if the first two letters are P

d) if all three P’s are together

e) If the first letter is a P and the second is not a P

= 840= 360

= 120= 120

= 240

7P7

3!

7!3! 36!

3!

32 5!3!

5!3!3!

34 5!3!

Page 7: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 7

2. In how many ways can the letters of the word ENGINEERING be arranged?

11!number of arrangements=3!3!2!2!

= 277 200

3. Naval signals are made by arranging coloured flags in a vertical line. How many signals using six flags can be made if you have: a) 3 green, 1 red, and 2 blue flags? b) 2 red, 2 green, and 2 blue flags?

a) 6!

3!2! = 60

Permutations with Restrictions

b) 6!

2!2!2! = 90

11 11

3!3!2!2!P

6 6

3!2!P 6 6

2!2!2!P

Page 8: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 8

Permutations with Restrictions

5. How many arrangements are there, using all the letters of the word REACH, if the consonants must be in alphabetical order?

If the order of letters cannot be changed, then treat theseletters as if they were identical.

5!number of arrangements =3! = 20

4. Find the number of arrangements of the letters of UTILITIES:a) if each begins with one I and the second letter not an I.

arrangements 3 6 7!

3!2!

= 7560

b) if each begins with exactly two I’s.

arrangements 3 2 6 6!

3!2!

= 21607 73 6

3!2!P 6 63 2 6

3!2!P

5 5=3!11P

Page 9: 11.1C Finding the Number of Permutations….. with Repeats

Tom lives four blocks north and seven blocks west of Alice. Each time Tom visits Alice, he travels only eastward or southward. How many different routes can Tom travel to visit Alice?

Tom must travel a combination of EEEEEEE and SSSS, to arrive at Alice’s house.

The number of ways in which he could do this would be

Possible route for Tom isESESESESEEE.

Another possible route isEEEEESSSEES.

= 330.

Pathways using Permutations with Repeats

11!7!4!

11 11

7!4!P

Page 10: 11.1C Finding the Number of Permutations….. with Repeats

Calculate the number of different paths from A to B.

= 15 120

Compound Pathways

9 9

5!4!P 4 4

2!2!P 6 6

3!3!P

Page 11: 11.1C Finding the Number of Permutations….. with Repeats

Calculate the number of different paths from A to B.

Would the number of pathways change if the path went from B to A?

4 2 8

Page 12: 11.1C Finding the Number of Permutations….. with Repeats

Math 30-1 12

Page 5245, 8, 11, 15, 17, 24, C1