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12- 2 Chords and Arcs. Dawned Pea Hugger Limb Ann. Don't be a girly man. More Circle Properties. R. Chord – A segment whose endpts are on a circle. Ex: PQ. C. P. Central s – in a circle, whose vertex is at the center of the circle. Rays of central s are radii of the circle . - PowerPoint PPT Presentation
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12- 2 Chords and Arcs
Dawned Pea Hugger Limb Ann
Don't be a girly man
More Circle Properties
C
Q
P
R Chord – A segment whose endpts are on a circle.
•Ex: PQ
Central s – in a circle, whose vertex is at the center of the circle.
•Rays of central s are radii of the circle .
•Sum of central s (w/ no common interior pts) are 360°
Thm12-4 Central s have chords. Chords have Arcs. Arcs have Central s.
More Circle Properties
A
B
C
O
What can you say about arc AB and arc AC?
Thm 12-51)Chords equidistant from the center are .
- If TP RP, then AB CD
2) chords are equidistant from the center.
- If CD AB, then TP RP
Thm 12-5 If 1 & 2 are true, then TP bisects AB & RP bisects CD.
- If AT BT, then CR DR
A TB
P
RD
C
llll
llll
12. 2 Chords and Arcs
Ex.2: Solve for the missing Variables
• mB = 32
A
BP
D
l
l
l
l
9cm
12.5cm
1616
AB =
mP =
m1 =
m2 =
BP =
25cm
148
74
74
15.4cm
a2 + b2 = c2
92 + 12.52 = BP2
81 + 156.25 = BP2
BP = 15.4cm
12. 2 Chords and Arcs
<1
<2
Thmn 12-6•In a circle, a diameter that is to a chord bisects the chord & its arc.
Thm 12-7•In a circle, a diameterthat bisects a chord (that is not a diameter) is to the chord.
Thm 12-8•In a circle, the bisector of a chord contains the center of the circle.
12. 2 Chords and Arcs
Ex.4: Solve for the missing sides.
A
B
D C
7m
3m
BC =
AB =
AD =
7m
14m
7.6m
aa22 + b + b22 = c = c22
3322 + 7 + 722 = AD = AD22
9 + 49 = AD9 + 49 = AD22
AD = 7.6mAD = 7.6m
12. 2 Chords and Arcs
12-2 HW pg.673 #1,2,3-5,10,11,13,14,18,30,32 pg. 580# 7-9
12. 2 Chords and Arcs
Ease Ace Life Ox
He's a sly fox