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A Compound Microscope This is an example for image formation in a compound microscope, similar to the one done in the lecture. The following gives a step-by-step description how to analyze the image formation process. Each of the 14 solution steps is illustrated by a drawing (figure), shown in a separate pdf- and ppt-file. You should download this figure file before starting on the problem and solution below. Look through the sequence of figures in this file to get an overview of the solution, when working through the 14 solution steps below. You must always begin the solution to problems like this by making a large, clean drawing. Start with the information given in the problem statement. Then fill in more details, as you work your way, step by step, through the solution. The (pdf/ppt) figure file accompanying this solution outline illustrates how such a drawing should be made, as you proceed with each step of your calculation. Problem Statement: A compound microscope is built with an objective lens (=Lens 1) of focal length f1=0.65cm, and an eyepiece lens (=Lens 2) of focal length f2=2.50cm with Lens 2 to the right of Lens 1. A small object (Obj1) of size 0.032cm is placed 0.70cm to the left of Lens 1. The distance between the two lenses is adjusted so that the final image (Img2), as seen by the eye, looking through the eyepiece, is located at the eye’s near point distance, 20cm to the left of Lens 2. State or calculate all image parameters: d1, d1, d2, d2, h1, h1, h2, h2’. Calculate the lens-to-lens distance L. Calculate the angle Q e subtended at the Eye by the final image, Img2, when viewed through the eyepiece Lens 2. Calculate the angle Q ref subtended at the Eye by the original object, placed at the near point, 20cm in front of the eye and viewed without microscope. From Q e and Q ref, calculate the angular magnification MQ = Q e / Q ref. Solution Steps: 1. Draw lenses, original source object (Obj1) and receiver of final image (Eye) on optical axis, with Obj1 drawn as an arrow pointing upward. 2. Trace the general ray direction through lenses: from the source (Obj1) to the receiver (Eye).

A Compound Microscope download this figure file · 2020-01-24 · A Compound Microscope This is an example for image formation in a compound microscope, similar to the one done in

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Page 1: A Compound Microscope download this figure file · 2020-01-24 · A Compound Microscope This is an example for image formation in a compound microscope, similar to the one done in

ACompoundMicroscopeThisisanexampleforimageformationinacompoundmicroscope,similartotheonedoneinthelecture.Thefollowinggivesastep-by-stepdescriptionhowtoanalyzetheimage formationprocess.Eachof the14solutionsteps is illustratedbyadrawing(figure),showninaseparatepdf-andppt-file.Youshoulddownloadthisfigurefilebefore startingon theproblemand solutionbelow.Look through the sequenceoffiguresinthisfiletogetanoverviewofthesolution,whenworkingthroughthe14solutionstepsbelow.Youmustalwaysbeginthesolutiontoproblemslikethisbymakingalarge,cleandrawing.Startwiththeinformationgivenintheproblemstatement.Thenfillinmoredetails,asyouworkyourway,stepbystep,throughthesolution.The(pdf/ppt)figurefile accompanying this solution outline illustrates how such a drawing should bemade,asyouproceedwitheachstepofyourcalculation.ProblemStatement:Acompoundmicroscope isbuiltwithanobjective lens (=Lens1) of focal lengthf1=0.65cm,andaneyepiecelens(=Lens2)offocallengthf2=2.50cmwithLens2totherightofLens1.Asmallobject(Obj1)ofsize0.032cmisplaced0.70cmtotheleftofLens1.Thedistancebetweenthetwolensesisadjustedsothatthefinalimage(Img2),asseen by the eye, looking through the eyepiece, is located at the eye’s near pointdistance,20cmtotheleftofLens2.Stateorcalculateallimageparameters:d1,d1’,d2,d2’,h1,h1’,h2,h2’.Calculatethelens-to-lensdistanceL.CalculatetheangleQesubtendedattheEyebythefinalimage,Img2,whenviewedthroughtheeyepieceLens2.CalculatetheangleQrefsubtendedattheEyebytheoriginalobject,placedatthenearpoint,20cminfrontoftheeyeandviewedwithoutmicroscope.FromQeandQref,calculatetheangularmagnificationMQ=Qe/Qref.SolutionSteps:

1. Drawlenses,originalsourceobject(Obj1)andreceiveroffinalimage(Eye)onopticalaxis,withObj1drawnasanarrowpointingupward.

2. Tracethegeneralraydirectionthroughlenses:fromthesource(Obj1)tothereceiver(Eye).

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3. Mark“in”,“out”,“notin”and“notout”foreachlens,usingraytracedthroughbothlensestofigureoutwhichsideofeachlensis“in”,whichsideis“out”.

4. MarkfocalpointF1forLens1onopticalaxis,relativetoObj1andLens1.Sincef1>0,F1mustbeonthe“in”sideofLens1.So,F1istotheleftofLens1.Also:|d1|>|f1|,soObj1isfurtherawaythanF1fromLens1.

5. Drawandmarkobjectdistanced1asanarrowfromLens1toObj1.SinceObj1is, by definition, on the “in” side of Lens1, Obj1 is a real object andd1>0: d1=+0.70cm

6. Calculateimagedistanced1’ofImg1fromLens1: d1’=(1/f1-1/d1)-1=(1/0.65–1/0.70)-1cm=+9.10cm>0CalculatethelateralmagnificationofLens1: m1=-d1’/d1=-(9.10/0.70)=-13.0<0,sincebothd1>0,d1’>0.Sinced1’>0,Img1isreal,i.e.,onthe“out”sideofLens1.Sincem1’<0,Img1isinverted relative to Obj1. Draw Img1 on the optical axis accordingly: as adownwardarrowtotherightofLens1.Drawandmarkimagedistanced1’asandarrowfromLens1toImg1.Note:atthispoint,youmaynotknowyetwhetherImg1isplacedtotheleftortotherightofLens2!?Pickoneofthetwochoices!Ifitlaterturnsouttobewrongyoucancorrectthedrawingthen.Thepdf-FigureforStep6showsImg1to the left, i.e., on the “in” sideofLens2,which turnsout tobe thecorrectchoiceofplacement(seeStep8).

7. DrawImg2,theimageofLens2.SinceImg2isthefinalimage,tobeseenbytheEye,itmustbeplacedinfrontoftheEye,i.e.,atleastanear-pointdistanceaway,totheleftoftheEyeandLens2.SincethisplacesImg2onthe“notout”sideofLens2,Img2isavirtualimageanditsimagedistanced2’mustbenegative: d2’=-|d2’|=-dnear=-20.0cm<0Drawandmarkimagedistanced2’asanarrowfromLens2toImg2.Note: at this point, youmay not know yet whether Img2 has the same oropposite(invertedorerect?)orientationasObj2ºImg1!?Pickoneofthetwochoices!Ifitlaterturnsouttobewrongyoucancorrectthedrawingthen.Thepdf-Figure for Step 7 shows Img2 pointing down, i.e., having the sameorientation as Obj2ºImg1, which turns out to be the correct choice oforientation(seeStep8).

8. Calculateobjectdistanced2ofObj2ºImg1fromLens1:

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d2=(1/f2-1/d2)-1=(1/2.50–1/(-20.0))-1cm=+2.22cm>0CalculatethelateralmagnificationofLens2: m2=-d2’/d2=-((-20)/2.22)=+9.00>0,sinced2>0,d2’<0.Sinced2>0,Obj2isreal,i.e.,locatedonthe“in”sideofLens2.SoObj2istotheleftofLens2.IfyoudidplaceImg1ºObj2incorrectlyrelativetoLens2(totherightofLens2),inStep6,correctitnow:Img1ºObj2andLens2mustbedrawnsuchthatObj2istotheleftofLens2.Drawandmarkobjectdistanced2asanarrowfromLens2toImg2.

Sincem2’>0,Img2isnotinvertedrelativetoObj2:Img2musthavethesameorientationasObj2ºImg1.So,ifyoudiddrawImg2incorrectly(asanupward-pointingarrow),inStep7,correctitnow:Img2mustbedrawnasanarrowpointingdownward.

9. CalculatetheLens1-Lens2distanceL: L=d1’+d2=+9.10cm+2.22cm=11.32cmDrawLbetweenLens1andLens2.

10. Statetheoriginalobjectheighth1forObj1andcalculateimageheighth1’forImg1: h1=0.032cm h1’=m1h1=(-d1’/d1)h1=-(9.10/0.70)(0.032cm)=-0.416cmMarkh1andh1’inthedrawing.

11. Statetheobjectheighth2forObj2.SinceImg1fromLens1servesastheobjectforLens2,Obj2,seedrawing: h2=h1’=-0.416cmThencalculateimageheighth2’forImg2: h2’=m2h2=(-d2’/d2)h2=-((-20.)/(+2.22)(-0.416cm)=-3.74cmMarkh2andh2’inthedrawing.

12. CalculatetheangleQe subtendedat theEyebythe final image, Img2,when

viewedthroughtheeyepieceLens2.Theheight,he,andapproximatedistancefromEye(piece),de,forthatfinalimagearegiven he=|h2’|=3.74cm and de=|d2’|=20.0cmThus: Qe»tan(Qe)=he/de=|h2’|/|d2’|=3.74/20=0.187radMark he, de,Qe in the microscope drawing. Draw he, de,Qe in a separatedrawing,ifneededforyourownclarification.

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13. CalculatetheangleQrefsubtendedattheEyebytheoriginalobject,placedattheeye’snearpoint,infrontoftheeyeandviewedwithoutmicroscope.Theheight,href,anddistancefromEye(piece),dref,fortheoriginalobjectaregiven href=h1=0.032cmand dref=dnear=20.0cmThus: Qref»tan(Qref)=href/dref=h1/dnear=0.032/20=0.0016radMakeaseparatedrawing,toshowonlyhref=h1,dref=dnearandQref

14. Calculatetheangularmagnification:

MQ=Qe/Qref=0.187/0.0016=117.Exercises:

1. Repeattheforegoingcalculationusingthesameinputparameters,exceptthatthefinalimage,Img2,isnowplacedveryfarawayfromtheEye(piece),atadistance de=|d2‘|=¥ sothat 1/d2‘=0.

2. Repeat the foregoingcalculations,both forde=|d2‘|=20cm andde=|d2‘|=¥,usingthesameinputparameters,exceptthatLens2isreplacedbyadivergentlenswithnegativefocallength:f2=-2.50cm.Whathappenstod2andm2now?DoyouneedtomodifytheplacementofObj2relativetoLens2inyourdrawing?IsObj2ºImg1totherightortotheleftofLens2now?Note:Obj2maybeavirtualobjectnow,eventhoughImg1isstillarealimage.Do you need to modify the orientation of the final image, Img2, in yourdrawing?IsImg2anupwardoradownwardarrownow?HowdoesMQchangewhencomparedtothecasef2=+2.50cm?

3. Use the approximate angular magnification formula given in the textbookwhich,inournotationandignoringthesign,readsasfollows:

MQ=dneard1‘/|f1f2|[ThetranslationOurNotationßàTextbookNotationisasfollows:OurNotation: dnear d1‘ f1 f2TextbookNotation: N di fobjective feyepiece.]

Howdotheresultsfromthetextbookformulacomparetotheexactresults,calculatedfromMQ=Qe/Qref?

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Eye

Compound Microscope: Step1

Object 1

Lens 1 Lens 2

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Eye

Compound Microscope: Step2

General Direction of Light RaysPassing thru LensesObject 1

Lens 1 Lens 2

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

Eye

Compound Microscope: Step3

General Direction of Light RaysPassing thru Lenses

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

F1Eye

Compound Microscope: Step4

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

F1

d1

Eye

Compound Microscope: Step5

Page 10: A Compound Microscope download this figure file · 2020-01-24 · A Compound Microscope This is an example for image formation in a compound microscope, similar to the one done in

1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

F1

d1 d1’

Eye

Compound Microscope: Step6

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

F1

d2’

d1 d1’

Eye

Compound Microscope: Step7

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

F2

F1

d2

d2’

d1 d1’

Eye

Compound Microscope: Step8

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

F2

F1

d2

d2’

d1 d1’

L

Eye

Compound Microscope: Step9

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

h1’

h1 F2

F1

d2

d2’

d1 d1’

L

Eye

Compound Microscope: Step10

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

h2’

h1’=h2

h1 F2

F1

d2

d2’

d1 d1’

L

Eye

Compound Microscope: Step11

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θe

|h2’|=he

|d2’|=de

Eye

Compound Microscope: Step12

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θrefhref = h1

Eye

Compound Microscope: Step13

dref = dnear

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Compound Microscope: Step14

θe

|h2’|=he

|d2’|=de

θrefhref=h1

MΘ = θe / θref

dref = dnear

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1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

θe

h2’

h1’=h2

h1 F2

F1

d2

d2’

d1 d1’

L

Eye

Compound Microscope

Page 20: A Compound Microscope download this figure file · 2020-01-24 · A Compound Microscope This is an example for image formation in a compound microscope, similar to the one done in

1: in 1: not out

1: not in 1: out

2: in 2: not out

2: not in 2: out

θe

|h2’|=he

h1’=h2

h1 F2

F1

d2

|d2’|=de

d1 d1’

L

Eye

Compound Microscope