Soal :3 2

X + 4 X - 10 = 0

Selang 1,2

Jawab :

Xb = 2Xa = 1

X1 = Xb+Xa/2X1 = 1.500

f (x) = f(1.5) = 2.37500

X2 = X1+Xa/2X2 = 1.250

f (x) = f(1.25) = -1.79688

X3 = X2+X1/2X3 = 1.375

f (x) = f(1.375) = 0.16211

X4 = X3+X2/2X4 = 1.313

f (x) = f(1.312) = -0.84839

X5 = X4+X3/2X5 = 1.344

f (x) = f(1.344) = -0.35098

X6 = X5+X4/2X6 = 1.328

f (x) = f(1.328) = -0.60163

X7 = X6+X5/2X7 = 1.336

f (x) = f(1.336) = -0.47680

X8 = X7+X6/2X8 = 1.332

f (x) = f(1.332) = -0.53934

X9 = X8+X7/2X9 = 1.334

f (x) = f(1.334) = -0.50810

X10 = X9+X8/2X10 = 1.333

f (x) = f(1.333) = -0.52373

Kesalahan RelatifNo. (Xa+Xb)/2 f (X)1 1.500 2.375002 1.250 -1.796883 1.375 0.162114 1.313 -0.848395 1.344 -0.350986 1.328 -0.601637 1.336 -0.476808 1.332 -0.539349 1.334 -0.50810

10 1.333 -0.52373