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Algebra 1B Algebra 1B Chapter 9 Chapter 9 Solving Quadratic Equations The Quadratic Formula

Algebra 1B Chapter 9

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Algebra 1B Chapter 9. Solving Quadratic Equations The Quadratic Formula. Warm Up Evaluate for x = –2, y = 3, and z = –1. 1. x 2. 4. 2. xyz. 6. 3. x 2 – yz. 4. y – xz. 7. 1. 5. – x. 6. z 2 – xy. 7. 2. - PowerPoint PPT Presentation

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Page 1: Algebra 1B Chapter 9

Algebra 1BAlgebra 1BChapter 9Chapter 9

Solving Quadratic EquationsThe Quadratic Formula

Page 2: Algebra 1B Chapter 9

Warm Up

Evaluate for x = –2, y = 3, and z = –1.

6 1. x2 2. xyz

3. x2 – yz 4. y – xz

4

5. –x 6. z2 – xy

7 1

7 2

Page 3: Algebra 1B Chapter 9

In the previous lesson, you completed the square to solve quadratic equations. If you complete the square of ax2 + bx + c = 0, you can derive the Quadratic Formula.

Page 4: Algebra 1B Chapter 9
Page 5: Algebra 1B Chapter 9

To add fractions, you need a common denominator.

Remember!

Page 6: Algebra 1B Chapter 9

Additional Example 1A: Using the Quadratic Formula

Solve using the Quadratic Formula.

6x2 + 5x – 4 = 0

6x2 + 5x + (–4) = 0 Identify a, b, and c.

Use the Quadratic Formula.

Simplify.

Substitute 6 for a, 5 for b, and –4 for c.

Page 7: Algebra 1B Chapter 9

Additional Example 1A Continued

Solve using the Quadratic Formula.

6x2 + 5x – 4 = 0

Simplify.

Write as two equations.

Solve each equation.

Page 8: Algebra 1B Chapter 9

Additional Example 1B: Using the Quadratic Formula

Solve using the Quadratic Formula.

x2 = x + 20

1x2 + (–1x) + (–20) = 0 Write in standard form. Identify a, b, and c.

Use the Quadratic Formula.

Simplify.

Substitute 1 for a, –1 for b, and –20 for c.

Page 9: Algebra 1B Chapter 9

Additional Example 1B Continued

Solve using the Quadratic Formula.

x = 5 or x = –4

Simplify.

Write as two equations.

Solve each equation.

x2 = x + 20

Page 10: Algebra 1B Chapter 9

In Your Notes! Example 1a Solve using the Quadratic Formula. Check your answer.

–3x2 + 5x + 2 = 0

Identify a, b, and c.

Use the Quadratic Formula.

Substitute –3 for a, 5 for b, and 2 for c.

Simplify.

–3x2 + 5x + 2 = 0

Page 11: Algebra 1B Chapter 9

In Your Notes! Example 1a Continued

Solve using the Quadratic Formula. Check your answer.

Simplify.

Write as two equations.

Solve each equation.x = – or x = 2

–3x2 + 5x + 2 = 0

Page 12: Algebra 1B Chapter 9

In Your Notes! Example 1b

Solve using the Quadratic Formula. Check your answer.

2 – 5x2 = –9x

Write in standard form. Identify a, b, and c.

(–5)x2 + 9x + (2) = 0

Use the Quadratic Formula.

Substitute –5 for a, 9 for b, and 2 for c.

Simplify

Page 13: Algebra 1B Chapter 9

In Your Notes! Example 1b Continued

Solve using the Quadratic Formula. Check your answer.

Simplify.

Write as two equations.

Solve each equation.

2 – 5x2 = –9x

x = – or x = 2

Page 14: Algebra 1B Chapter 9

In Your Notes! Example 1b Continued

Solve using the Quadratic Formula. Check your answer.

–5(2)2 + 9(2) + 2 0

–20 + 18 + 2 0

0 0

Check –5x2 + 9x + 2 = 0–5x2 + 9x + 2 = 0

–5 + 9 + 2 0

0 0

+ 2 0

Page 15: Algebra 1B Chapter 9

Because the Quadratic Formula contains a square root, the solutions may be irrational. You can give the exact solution by leaving the square root in your answer, or you can approximate the solutions.

Page 16: Algebra 1B Chapter 9

Additional Example 2: Using the Quadratic Formula to Estimate Solutions

Solve x2 + 3x – 7 = 0 using the Quadratic Formula.

Check reasonableness

Estimate : x ≈ 1.54 or x ≈ –4.54.

Page 17: Algebra 1B Chapter 9

In Your Notes! Example 2

Solve 2x2 – 8x + 1 = 0 using the Quadratic Formula.

Check reasonableness

Estimate : x ≈ 3.87 or x ≈ 0.13.

Page 18: Algebra 1B Chapter 9

There is no one correct way to solve a quadratic equation. Many quadratic equations can be solved using several different methods: •Graphing •Factoring •Completing the square •Square roots and using •the Quadratic Formula

Page 19: Algebra 1B Chapter 9

Additional Example 3: Solving Using Different Methods

Solve x2 – 9x + 20 = 0. Show your work. Use at least two different methods. Check your answer.

Method 1 Solve by graphing.

y = x2 – 9x + 20Write the related quadratic

function and graph it.

The solutions are the x-intercepts, 4 and 5.

Page 20: Algebra 1B Chapter 9

Additional Example 3 Continued

Solve x2 – 9x + 20 = 0. Show your work. Use at least two different methods. Check your answer.

Method 2 Solve by factoring.

x2 – 9x + 20 = 0

(x – 4)(x – 5) = 0

x – 4 = 0 or x – 5 = 0

x = 4 or x = 5

Factor.

Use the Zero Product Property.

Solve each equation.

Page 21: Algebra 1B Chapter 9

Additional Example 3 Continued

Solve x2 – 9x + 20 = 0. Show your work. Use at least two different methods. Check your answer.

Check: 4 and 5

Check x2 – 9x + 20 = 0x2 – 9x + 20 = 0

(4)2 – 9(4) + 20 0 16 – 36 + 20 0

0 0

(5)2 – 9(5) + 20 0

25 – 45 + 20 0

0 0

Page 22: Algebra 1B Chapter 9

In Your Notes! Example 3a

Solve. Show your work and check your answer.

x2 + 7x + 10 = 0

Method 3 Solve by completing the square.

x2 + 7x + 10 = 0

x2 + 7x = –10

x2 +7x = –10 Add to both sides.

Factor and simplify.

Take the square root of both sides.

Page 23: Algebra 1B Chapter 9

In Your Notes! Example 3a Continued

Solve. Show your work and check your answer.

x2 + 7x + 10 = 0

Solve each equation.or

x = –2 or x = –5

(–2)2 + 7(–2) + 10 0

4 – 14 + 10 00 0

(–5)2 + 7(–5) + 10 0

25 – 35 + 10 0

0 0

Check x2 + 7x + 10 = 0 x2 + 7x + 10 = 0

Page 24: Algebra 1B Chapter 9

In Your Notes! Example 3b

Solve. Show your work and check your answer.

–14 + x2 – 5x = 0

Method 4 Solve using the Quadratic Formula.

x2 – 5x – 14 = 0

1x2 – 5x – 14 = 0 Identify a, b, and c.

Substitute 1 for a, –5 for b, and –14 for c.

Simplify.

Page 25: Algebra 1B Chapter 9

In Your Notes! Example 3b Continued

Solve. Show your work and check your answer.

–14 + x2 – 5x = 0

x = 7 or x = –2

or Write as two equations.

Solve each equation.

Page 26: Algebra 1B Chapter 9

In Your Notes! Example 3b Continued

Solve. Show your work and check your answer.

–14 + x2 – 5x = 0

x2 – 5x – 14 = 0

72 – 5(7) – 14 0

49 – 35 – 14 0

14 – 14 0

0 0

Check x2 – 5x – 14 = 0

–22 – 5(–2) – 14 0

4 + 10 – 14 0

14 – 14 0

0 0

Page 27: Algebra 1B Chapter 9

In Your Notes! Example 3c Solve. Show your work and check your answer.

2x2 + 4x – 21 = 0

Method 1 Solve by graphing.

2x2 + 4x – 21 = y Write the related quadratic function.

Divide each term by 2 and graph.

The solutions are the x-intercepts and appear to be ≈ 2.4 and ≈ –4.4.

Page 28: Algebra 1B Chapter 9

Sometimes one method is better for solving certain types of equations. The table below gives some advantages and disadvantages of the different methods.

Page 29: Algebra 1B Chapter 9