Upload
others
View
4
Download
0
Embed Size (px)
Citation preview
Biochemistry of carbohydrates/
pentose phosphate pathway الفريق الطبي األكاديمي
لكــية الطب البرشي
البلقاء التطبيقية / املركز
6102/6166أ حياها و من
Done By: - Khansaa’ Mahmoud
- Renad Aburumman
Page 1
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
**This topic starts from the minute (07:30) of the record, what was
previously said, is a revision of the previous lectures.
The pentose phosphate pathway is called sometimes as PPP, or hexose
monophosphate shunt.
It is not considered a metabolic pathway because it has no start nor end;
it is an intersection of a set of metabolic reactions, it is a multistep
reactions interacting with each other, so you are not going to memorise
this intersection pathway but you have to understand the segnifience and
physiologic importance of this pathway.
Here you see about 10 structures, all of them will participate in this
pathway. (You are not supposed to memorize their structures, except
those who are familiar to you, glucose for example).
Some of these sugars are hexoses, pentoses, ketoses and aldoses; they are
intermediates pf the PPP.
Page 2
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
The number in the figure are the indicators of enzymes, you are not
supposed to memorize them too.
PPP use glucose-6-phosphate that comes from -glycogen.
-the phosphorylation of glucose.
-Originate from fructose or
galactose.
This compound (glucose-6-phosphate) is oxidized with a catalyst enzyme,
called glucose-6-phosphate dehydrogenase. (This enzyme must be
memorized, because some chemical problems may occur when it is
deficient in cells, they are called glucose-6-phosphate deficiency
diseases).
Page 3
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
In this step, the glucose-6-phosphste is oxidized by the enzyme glucose-6-
phosphate dehydrogenase, and it uses -as coenzyme- NADP+. You usually
deal with NAD as a coenzyme, but this enzyme (G-6-P dehydrogenase)
uses NADP.
*As a summary: NADP coenzyme that is used by
G6Pdehydrogenase to oxidize glucose-6-phsphate to 6-
phosphogluconic acid(6PG).
**The important thing here is the production of NADPH, which is very
important molecule for the biosynthesis reactions, so the source of
NADPH is the PPP (the conversion of G-6-P to 6-phosphgluconic acid by
the enzyme G-6-P dehydrogenase ), NADPH is very important for the
fatty acids biosynthesis.
Fatty acids synthase and other enzymes use NADPH as a coenzyme.
Page 4
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
As a summary: Oxidation of glucose-6-phosphate to 6-phosphocluconic
acid then to and production of NADPH, how many NADPH in the oxidation
stage are produced? Two NADPH molecules because there are two
oxidation reactions(one from G6P6-PG/the other one from 6-PGRu-5-
P).
Page 5
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
Page 6
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
The second feature what you have to understand and memorize is the
isomerization.
From the first stage riboluse-5 phosphate(Ru-5-P) is produced and this
could be isomerized to Xu5 phosphate or ribose 5 phosphate (R-5-P).
Ru-5-P(ketone) R-5-P(aldehyde) is an important step because it's
produce R-5-P &the importance of producing ribose 5 phosphate that it is
used in the synthesis of DNA and RNA(nucleotide metabolism) because
they contain a pentose sugar that is ribose 5 phosphate.
So where do we get the ribose sugar to synthesis of nucleotides from?
We get it from the pentose phosphate pathway, the isomerization of
ribulose-5-phosphate to ribose-5-phosphate.
What are the components of nucleotides?
*Nitrogenous base
*phosphate group
*Ribose sugar, what is it? Pentose sugar, what is it is source?
Isomerization of ribulose. Where does it come from? From the
dehydrogenation of glucose-6-phosphate.
Page 7
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
Page 8
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
The third feature of the PPP is the carbon rearrangement (minute 21:00)
Here you see ribose 5 phosphate, Xu-5-phosphate, glyceraldehyde-3-
phosphate, S-7-P, fructose-6-phosphate, E-4-P. All of these are sugars you
are not supposed to memorize their names and structures, but you have
to understand them.)
These sugars - you see- some of them are composed of 7 carbon atoms
some are composed of six carbon atoms, Some have three carbon atoms
some with four carbon atoms.
so in this stage there is a rearrangement between the sugar in which they
give different types of sugars, by enzymes that will arrange or do some
reactions to produce different types of sugars.
The importance of this for the E-4-P(compose of 4 C atoms) sugar it is
essential precursor synthesis of aromatic amino acids like phenylalanine,
tryptophan and tyrosine,In order to synthesis these important amino acids
in our bodies E-4-P is required.
From where do we get this sugar?
From the rearrangement of carbons.
(To see that clearly in details check slides 7 + 9)
This is one imp. thing about carbon rearrangement , another important
one fructose-6-phosphate and glyceraldehyde-3-phosphate, where did
you see those molecules (sugars) took places as intermediates? In
glycolysis.
So supposedly, you have shortage in these intermediates pentose
phosphate pathway provides these intermediates for the glycolysis to be
continued, and this another physiological importance of PPP in carbon
rearrangement is providing intermediates for the glycolysis and
gluconeogenesis.
As a summary:
The importance of the pathway is:
1. production of NADPH, in the oxidation stage, important for biosynthetic
reactions such as fatty acids synthesis.
2. Provides ribose-5-phosphate, for nucleotide synthesis, in the
Page 9
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
isomerization stage.
3. Carbon rearrangement. *to provide intermediates for glycolysis and
gluconeogenesis and *precursors for aromatic amino acid synthesis
tryptophan, tyrosine and phenylalanine. The sugar that is the precursor is
E-4-P.
Why this pathway is called pentose not Hexose, as long as the sugars are
Hexoses not pentoses? Because the pentoses are the most important
sugars among the others, to produce nucleotides for nucleic acids. This
pathway also has other names as mentioned before.
So this pathway is multifunctional not directional like conventional
pathways such as *glycolysis (from glucose to pyruvate) and
gluconeogenesis (from pyruvate to glucose), or *oxidation of fatty acids
(from fatty acid to acetyl co a). So it is a multifunctional pathway
producing different molecules according to * the need of the cell and
*the availability of substrates.
(32:54) quick summary:
The importance of oxidation stage is production of NADPH; it produces
two molecules of NADPH through two reactions. The first is the
Page 10
Biochemistry of carbohydrates/ pentose
phosphate pathway
و من أحياها
6102/6166
conversion of glucose-6-phosphate to 6-phosphoglugonic acid, and the
second one is the conversion of 6-phosphoglugonic acid to riboluse-5-
phosphate. The importance of producing NADPH is that it contributes
biosynthesis fatty acids.
The importance is isomerization is producing ribose-5-phosphate, the
importance of ribose-5- phosphate is the synthesis of nucleotides which
contributes nucleic acids synthesis.
The importance of carbon rearrangement is producing different sugars,
(fructose-6-phosphate and glyceraldehyde-3-phosphate which are used in
glycolysis and gluconeogenesis) and (E-4-P which is used an automatic
amino acids synthesis such as tyrosine, phenylalanine and tryptophan).
(Slides 8 + 9)
R-5-P and Xu-5-P both have five carbon atoms and 5+ 5=10, which equals
3 + 7, which are S-7-P and GLAYAL-3-phsphate.
Two Sugars, which one is five carbon atoms ,converted to Sugars one of
them 7 and 3 carbon atoms.
This is the carbon rearrangement.
How does that happen? By the enzyme transketonase (memorize its
name), the portion of CH2OOH from the Xu-5-P is taken to produce
heptolose. It took two carbon atoms adding them to the 5 atoms of R-5-P
to give S-7-P, the left three carbon atoms are converted to
glyceraldehyde-3- phosphate, and which is important in glycolysis. Then
those products would be rearranged to give 4 and 6 carbon atoms sugars
which are fructose-6-phosphate (used in glycolysis) and E-4-P (used as a
precursor for automatic amino acid synthesis).
Heptolose + triose will be converted to hexose + pentose. The enzyme
used is called Transaldolase because it transfers an aldehyde group.
(Memorize the enzymes name).
Thank you