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Workshopig a I I Ltp x2y3 It By od j di doc I tdyy T di Lt B oily doc By 3 25 Along x 5g doc 5dg ii dI CLtMC5yYg3G dy t P y 5g 2dg 125 Lt B y dy t 25 Bys dy 25 52 6 B y dy y o I Si di fo 25652 6 B y dy 25 FL t B org

dy - edge.edx.org

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I Ltp x2y3 It Byod j di docI tdyy T di Lt B oilydoc By
3 25
Along x 5g doc 5dg ii dI CLtMC5yYg3Gdy t Py 5g2dg
125 Lt B y dy t 25Bysdy 25 52 6B y dy
y o I
Si di fo 25652 6B y dy 25 FL t B
I it
5 25 sino cos05 sindOT
5z Sindsi cos018 Its cosofE
J di C 25sins lots 2 cosd sold f I D Z O S R
Si di R fo 2sin'dold L Dx i o 5 I Co ily Co 4g I
5 I J Liye 5 costs sin 08 sind5 toosold
4s sin I
SC th ut da If for 4 s sind dsdd
O z
D J _350501 3555435 cosittsint ftp.T do fo5fYf23s2 sdsddd2
5x2iTx o 3sBds
Convert it to cylindrical E cos45 sin ofof
of sings cos Of E I
J s3 cos ft sin4015 t s osdsindfcosbtsinH.JO
Three sides to cylinder8
2 Bottom dei sdsdf I J dot O
3 side do sold dies ii dei s cos40 tsin 40 ddd2
Si di fo fo s cos I tsin 4 dddZ
Note 5 2 fo dz 5
Si dei 16 5 f cos oldolt sin oldd
80 77 47 112074
it r3indrthr2coscetr2tandFl7
rsitnaFee since4 rEosa
rateof Catan a
sinYet coshe since
Coste 4 r
G The icecream cone
doe R'sina.dd.de ri
R Czaffaz sina.IQ ob
dersinddrdddu dw 4sinclcosdrsdrdd
dot Bzer
t 2rt3fsT
vertices at
Como Ca a b Ca a b Ea a b Gaia b
Calculate for this surface
p egb die dedge
E fpdoi faaf.aegbd.edu I
The force on a tilted surface can be
found by considering the equation of the surface surface in diagram
Z hat x O
The normal to this surface is just the gradient of the scalar function
2 Z C
Normalising we have of at bat tab
ota dydlri dyd.IAEbx.az dyftabd.caEbxraztbz
E Heda aL f
I f gbzxtadgd.cat boil
easab C z.cyd.cat boil
es f IcaE bail
2egba g CAI BI
component will be the same as
but the se or y component will
be different
Summing the forces on all five
surfaces we have
Is a begI
In general