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3-Bipolar Junction TransistorsTransistor ConstructionThe transistor is a three-layer semiconductor device consisting of either two n- and one p-typelayers of material(npn transistor) or two p- and one n-type layers of material(pnp transistor).The outer layers of the transistor widths much greater than those of the sandwiched p- or n-type material
The doping of the sandwiched layer is also considerably less than that of the outer layers, thislower doping level decreases the conductivity (increases the resistance) of this material bylimiting the number of free carriers
Fig (3-1) (a)pnp (b) npn.
The terminals have been indicated by E for emitter , C for collector , and B for base.The abbreviation BJT , from bipolar junction transistor , is often applied to this three-terminaldevice.The term bipolar reflects the fact that holes and electrons participate in the injection process into the oppositely polarized material. If only one carrier is employed (electron or
hole), it is considered a unipolar device.
Transistor OperationIn Fig (3-2) the pnp transistor has been redrawn without the base-to-collector bias.The depletion region has been reduced in width due to the applied bias, resulting a heavy flowof majority carriers from the p- to the n-type material.Let us now remove the base-to-emitter bias of the pnp transistor. The flow of majority carriersis zero, resulting in only a minority-carrier flow.i.e. one p-n junction of a transistor is reverse biased, while the other is forward biased .
Fig (3-2) Forward-biased of a pnp CB tr Fig (3-3) Reverse-biased of a pnp CB tr
In Fig (3-4) both biasing potentials have been applied to a pnp transistor, with the resultingmajority- and minority-carrier flow indicated. A large number of majority carriers will diffuseacross the forward-biased p-n junction into the n-type material.
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Fig (3-4) Majority and minority carrier flow of a pnp transistor
Since the sandwiched n-type material is very thin and has a low conductivity, a very smallnumber of these carriers will take this path of high resistance obtaining the base current I B in μA, the magnitude of the emitter I E and collector I C currents in mA
Applying KCL to the transistor of Fig (3-4) as if it were a single node, we obtain
[3-1] The I C has two components-the majority and minority carriers. The minority-current componentis called the leakage current I CO ( CO = C urrent with emitter terminal O pen). Therefore:
[3-2] I C in mA
I CO in μA or nA , is temperature sensitive
Common-Base Configuration (CB)
Fig (3-5) Notation and symbols used with the CB (a) pnp transistor (b) npn transistor.
For fixed values of V CB in the CB configuration the ratio of a small change in I C to a smallchange in I E is commonly called the common-base short-circuit amplification factor and
is given by the symbol
(alpha).
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[3-3]
The term short circuit indicates that the load is short-circuited when is determined.
Typical values of vary from 0.90 to 0.998 .For most practical applications can be obtained using the following equation:
[3-4] Therefore Eqs [3-2] be:
[3-5]
The current amplification I C / I E is always less than 1 for the CB configuration. This latter
characteristic should be obvious since I C =
I E and
is always less than 1.
Two sets of characteristics are necessary to represent the behavior of the pnp CB transistor1--the driving point (or input)2--the output set.
The output or collector characteristics of Fig (3-6a) relate the collector (output) current to thecollector-to-base (output) voltage and (input) emitter current . The collector characteristicshave three basic regions of interest:1--the active regionIn the active region the collector junction is reverse-biased , while the emitter junction is
forward-biased, it is the only region employed for the amplification of signals with minimumdistortion.-When the emitter current I E =0 the collector current I C = I CO ( emitter input circuit is open)-When the emitter current increases above Zero, I C =I E (in active region)
[3-6]
Fig (3-6) pnp CB transister (a) O/P Collector characteristics (b) I/P Emitter characteristics
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Fig (3-7) Reverse saturation current
2--the cutoff regionIn cut off region the collector and emitter junction are both reverse biased, resulting innegligible collector current.
3--and saturation regionIn saturation region the collector & emitter junction are forward biased , resulting in theexponential change in the collector current with small change in collector to base potential.
For fixed values of collector voltage V CB in the input characteristics fig(3-6b) as V EB increases,the I E will increased , Increasing levels of V CB result in a reduced level of V EB to establishthe same current.
[3-7] Example 1:Using the characteristic of fig (3-6):
Solution:
The proper biasing of the CB determined using the approximation I C ≈I E and assuming forthe moment that I B ≈ 0µA.
Fig (3-8) the configuration for the pnp CB transistor.
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Common-Emitter Configuration (CE)
Fig (3-9) Notation and symbols used with CE configuration (a)npn transistor(b)pnp transistor
Two sets of characteristics are again necessary to describe the behavior of CE configuration:-One for the input or base circuit.-One for the output or collector circuit. Both are shown in Fig (3-10)
Fig (3-10) npn CE transistor (a) O/P Collector characteristics (b) I/P Base characteristic
-In the active region the collector junction is reverse biased, while the emitter junction isforward-biased, this region employed for voltage, current, or power amplification.
-in cutoff region for the CE, I C = l CEO determined the cutoff for the CE configuration
For C.E I C ≠ 0 when I B = 0For C.B I C = I CO when I E = 0The reason for this is,
Eqs[3-5]
But Eqs[3-1]
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[3-8]
If we consider the case where I B=0 , and substitute this value in Eqs.[3-8],then
[3-9]
AndThe collector current defined by Eqs[3-9] will be assigned the notation indicated by Eqs[3-10].
[3-10] In Fig (3-11) the conditions surrounding this newly defined current are demonstrated.
Fig (3-11) Circuit related to I CEO condition
The CE forward-current amplification factor is
[3-11]
The value obtained for beta ( β ) from Eqs[3-11] is called ac or dynamic value.
[3-12]
The value obtai ned for β from Eqs[ 3-12] is called the dc beta, since I C and I B in Eqs[3-12] aredc values, β vary from 20 to 600.Eqs[3-12]
Eqs[3-4]
Eqs[3-1]
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Substituting:
And dividing by I C
We obtain:
[3-13] or
[3-14]
Then
[3-15] Example 2:
Using the characteristics of fig (3-10)
Solution:
Example 3:
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Solution:
The input char for CE & CB configuration is, the increase in input current is due to anincrease in majority carriers crossing the B-to-E junction with increasing forward-bias potential.
Common-Collector Configuration (CC)The CC configuration is used primarily for impedance matching purposes since it has a highinput impedance and low output impedance, opposite to that which is true of the CB & CE configurations.
Fig (3-12) Notation and symbols used with CC configuration(a)pnp transistor(b)npn transistor
The output characteristics of the CC configuration are the same as for the CE configuration.
Transistor Maximum RatingsThe standard transistor data sheet will include at least three maximum ratings:-Collector dissipation (power), collector voltage, And collector current The power or dissipation rating is the product of the collector voltage and current.For the CE configuration
[3-16] -For the CB configuration the collector dissipation is determined by the following equation.
[3-17]
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Summary
Biasing the two PN junction in an NPN transistor
The NPN transistor with both bias sources connected
Equivalent NPN transistor diagrams
Equivalent PNP transistor diagrams
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I CBO is the collector current that flows when the emitter is open
Input and output voltage in NPN and PNP common-base transistors
Common-emitter bias arrangements
Input and output voltages and currents for NPN and PNP transistor in the CE configuration
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V CE ~ V CB + 0.7 for Si , when V CE is reduced to about 0.7, then V CB ~ 0 and the collector-base junction is no longer reverse biased.
CC bias configuration
Input and output voltage and current in the CC configuration
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4-DC Biasing (BJTS)To use these devices for amplification of voltage or current, or as control (on or off) elements, itis necessary first to bias the device. The usual reason for this biasing is to turn the device onand to place it in operation in the region of its characteristic where the device operates mostlinearly.Operating point:
Since the aim of biasing is to achieve a certain condition of current and voltage called theoperating point (quiescent point or Q-point).Operating region is the area of current or voltage within the maximum limits for the particulardevice. These maximum ratings are indicated on the characteristic of Fig (4-1) by a horizontalline for the maximum current, I max and a vertical line for the maximum voltage V max
Fig (4-1) various operating points
Operating in the linear regions, cutoff region, and saturation region of the BJT characteristicare provided as follows:1. Linear-region operation:Base-emitter forward biased, Base-collector reverse biased, I C = βI B , is true only in this region2. Cutoff-region operation:Base-emitter reverse biased 3. Saturation-region operation:Base-emitter forward biased, Base-collector forward biased
Fixed-Bias Circuit The fixed-bias circuit shown in Fig (4-2) provides a relatively straightforward and simple
starting point in the dc bias considerations.It is possible to consider the biasing of a BJT by separately analyzing the base-emitter andthe base-collector dc bias loops.
Fig (4-2) Fixed-bias circuit
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Forward Bias of Base-Emitter Consider the base-emitter circuit loop shown, writing the KVL equation for the loop, we get:
Fig (4-3) Base-emitter loopWe can solve the foregoing equation for the base current I B
[4-1] Since the supply voltage V CC and V BE are fixed values, as a good approximation we may even
neglect the few tenths of a volt drop ( V BE ) obtaining the simplified form for the base current I B
[4-2] Reverse Bias of Base-Collector The collector-emitter section (Fig4-4) consists of the supply battery, the collector resistor, andthe transistor collector-emitter junction. The currents through the collector and emitter areabout the same since I B is small in comparison to either
Fig (4-4) Collector-Emitter loopFor linear amplifier operation the I C is related to the I B by the transistor current gain, β
[4-3] Calculating voltage drops in the collector-emitter loop, we get
[4-4] Example 1: Compute the dc bias voltages and currents for the circuit of Fig (4-5).
Fig (4-5) dc fixed-bias for Ex 1:
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Solution:
Example 2: Compute the collector voltage and current for the circuit of fig (4-6).
Fig (4-6) Circuit for Example 2 :Solution:
DC Bias Circuit with emitter resistor The dc bias circuit of Fig (4-7) contains R E to provide better bias stability than the fixed-biascircuit
Fig (4-7) emitter-stabilization resistor Base-Emitter Loop A partial circuit diagram of the base-emitter loop is shown in Fig (4-8).
Fig (4-8) Base-emitter loop with emitter resistor.
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Writing KVL equation for the loop, we get
[4-5] Collector-Emitter LoopThe collector emitter loop is shown in fig (4-9).writing KVL for this loop we get
Fig (4-9) Collector-Emitter loop with emitter resistor.The collector current I C is calculated using the relation
[4-6] [4-7]
[4-8] The voltage at which the transistor is based is measured from collector to emitter V CE
Example 3: Calculate the dc bias voltage V CE and current I C in the circuit of Fig (4-10)
Fig (4-10) E-stabilized bias cct for Ex 3: & Ex 4:Solution:
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Example 4: Calculate the value of collector resistor R C needed V C = 10 v , using Fig (4-10)Solution:
Note: that I B and I C are still the same values as calculated in Ex 3: using Eq[4-11]
Improved Bias Stability The addition of the emitter resistor to the dc bias of the BJT improved stability ( the dc biascurrents and voltages remain closer to where they were set by the circuit even when outside
conditions supply voltage, temperature, and transistor beta change)
Example 5: Prepare a table comparing the bias voltage and currents of the circuit of Fig (4-5) for the given value of β = 50 and for a new value of β = 100 .Solution:Using the results calculated in Ex1: then repeating for a value of β = 100 yields the following:
I C is seen to change by 100% due to the 100% change in β (and no change in I B ).Using the results calculated in Ex3: then repeating for a value of β = 50 , we have the following:
DC Bias Circuit Independent of β (Approximate Analysis )In the previous dc bias circuits the values of I B and voltage of the collector depend on β, but βis temperature sensitive for this reasons needs to provide a dc bias circuit that isindependent of the transistor beta β
Fig (4-11) Beta-independent dc bias circuit
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a) base-emitter Loop. If the resistance seen looking into the base ( Fig4-12) is much larger than that of resistor R B2 ,then the base voltage is set by the voltage divider of R B1 and R B2 , then the current throughR Bl goes almost completely into R B2 and the two resistors in series.
Fig (4-12) bias circuit for approximate V BCalculating V B to the voltage-divider network of resistors R B1 and R B2 , we get
[4-9] Where V B is the voltage measured from base to ground. We then calculate the V E
[4-10] The current in the emitter may then be calculated from
[4-11]
[4-12]
[4-13] b) Collector-emitter Loop
[4-14] V B is set by R B1 & R B2 and the supply voltage V CC , V E is the same V B, R E determines I E & I C ,
R C determines the V C and, V CE voltage.
Example 6: Calculate the dc bias voltage V CE and current I C for the circuit of Fig (4-13)
Fig (4-13) Beta-stabilized circuit for Ex 6:
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Solution:
Exact Analysis A more exact analysis can be obtained by using the Thevenin equivalent of the voltage divideras described by the following analysis:
[4-15]
[4-16]
The dc circuit to be analyzed can be redrawn as in fig (4-14) then calculate I B.
Fig (4-14) Dc circuit to analyze using Thevenin Eq
[4-17]
The value of V CE can be obtained using Eq[4-6]
Example 7: Calculate the dc bias voltage V CE and current I C for the circuit of Fig (4-13).Solution:
Example 8: Using an exact bias analysis of the circuit of Fig (4-13), compare the I C & V CE forthe given β of 140 and for a new β of 70 Solution:Using the results calculated in Ex 7 : and repeating for a value of β = 70, we have
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The circuit maintains the I C and V CE even with a change in β of 100%, the bias values only
changed by less than 3% in this circuit.The approximate analysis would be satisfactory as long as
DC Bias with Voltage Feedback The use of emitter resistor to provide improved bias stability, voltage feedback also providesimproved dc bias stability.
Fig (4-15) Dc bias cct with voltage feedback
Base Emitter loopWriting the KVL equation around the base-emitter loop of the voltage feedback circuit gives
Fig (4-16) Partial circuit showing base-emitter loop
[4-18] Collector-Emitter LoopThe partial circuit diagram of the collector-emitter section show in fig (4-17) the KVL equation is
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[4-19]
Fig (4-17) Partial circuit showing collector-emitter loop
Example 9: Calculate the dc I E & V CE for the circuit of fig (4-18) using voltage feedback
Solution:
Fig (4-18) V-F circuit for Ex 9:
Example 10: Calculate the dc I C current & V C for the bias circuit of Fig (4-19).Solution:
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Fig (4-19) Dc bias with R E & V-F
Example 11: Analysis of various DC bias circuits
Calculate the collector current Ic and voltage V CE for the circuit of Fig (4-20)
Fig (4-20) Bias circuit for Example 11:Solution:
Example 12: Calculate the bias voltage V E and current I C for the circuit of Fig (4-21)
Fig (4-21) Bias circuit for Example 12 :
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Solution: Writing the base-emitter loop equation
Example 13: Calculate the collector voltage V C for the circuit of fig (4-22)
Fig (4-22) Bias circuit for Example 13:Solution:
Example 14: Determine the collector voltage V C and current I C for the circuit of fig (4-23).
Fig (4-23) Bias circuit for Example 14:Solution:
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Example 15: Calculate the emitter current I E and collector voltage V C for circuit in fig (4-24)
Fig (4-24) Circuit for example 15:Solution:
Graphical DC bias analysis A graphical technique is another method for finding the operating point of a transistor circuit.The typical CE collector characteristic shown in Fig4-25, the circuit constraints must also betaken into account in obtaining the actual operating point ( quiescent point or Q -point)
Fig (4-25) Transistor collector characteristic As typical of most circuits previously covered
We can rewrite that equation to solve for the collector current as follows:
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[4-20] Eq[4-20] shows the circuit equation as that of a straight line with slope
And y-intercept1. For I C = 0, V CE = V CC 2. For V CE = 0, I C = V CC / (R C + R E )
Fig (4-26) Dc load lineThe straight line connecting these points called the dc load line as in Fig (4-26)
Fig (4-27) Effect of varying ( R C +R E ) or V CC on dc load line: a- effect of resistor on dc load line,
b- effect of supply voltage on dc load line. plotting transistor characteristic and dc load line on one graph for determination Q-point .
Fig (4-28) obtaining Q point
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Example 16: Determine the quiescent operating point ( Q ) for the circuit of fig (4-29) using thetransistor collector characteristic of fig (4-25).
Fig (4-29) Bias circuit for Example 16 :Solution: A dc load should be plotted on the collector characteristic of fig (4-25) this dc load line is plotted by drawing a straight line from the point
Fig(4-30) shows the circuit dc load line and the transistor collector characteristic with the Q- point marked at the intersection of the dc load line and base current of I B = 30.4 µA. Thetransistor is seen to be biased at
Fig (4-30) Graphical analysis for Ex 16 :
Design of DC bias circuitsIt is important to be able to design a circuit to operate at a desired or specified bias point. Oftenthe manufacturer's specification sheets provide information stating a suitable operating point
for a particular transistor and other circuit factors dictate some conditions of current swing ,voltage swing , and value of common supply voltage, which can be used in determining theQ-point in a design.
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Design of Bias Circuit with Emitter Feedback Resistor The supply voltage and operating point will be selected from the manufacturer's information onthe transistor used in the amplifier.
Fig (4-31) Emitter-stabilization bias circuit
There are two unknown quantities: 1-the values of R C 2- the value of R E V E is typically around one-fifth (1/5) to one-tenth (1/10) of the supply voltage V CC . Selecting theemitter voltage in this way will permit calculating the R E and R C we get
Example 17: Calculate the resistor values R E , R C , and R B for a transistor amplifier circuithaving emitter-resistor stabilization (Fig4-31). The current gain of a transistor is 90 at a I C of 5mA Use a supply voltage V CC of 20V Solution:The operating point selected from the information of tran I CQ =5 mA & V CEQ =10 V .
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Design of Current Gain Stabilized (Beta Independent) Circuit Circuit in Fig (4-32) provides stabilization both for I CO & current gain changes, the emittervoltage selected to be one-tenth (1/10) of the supply voltage ( V CC ).
Fig (4-32) current gain stabilization design
Example 18: Design a dc bias circuit for an amplifier circuit as in Fig (4-32). The transistor hasa current gain of 150, at a collector current of 1 mA, and the supply voltage for the presentcircuit is 16 V. Provide design for V CQ = V CC /2 .Solution;
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Bias StabilizationIn any amplifier circuit the collector current I C will vary with change in temperaturebecause of the three following main factors:1. Reverse I C current leakage current I CO which doubles for every 10° increase in temperature2. Base-emitter voltage V BE which decreases by 2.5 mV per °C3. Transistor current gain β which increases with temperature.
Table-1
Notice that the significant increase of leakage current I CO not only causes the curves to rise
but also that an increase in beta occurs as shown in fig by the larger spacing between thecurves at the higher temperature.Since the fixed-bias circuit provides an I B whose value depends on the V CC and R B, neither ofwhich is affected by temperature or the change in I CO or β, the same I B will exist at hightemperatures as indicated on the fig
Fig (4-33) Shift in dc bias point ( Q-point ) due to change in temperature (a) 25 ˚C (b) 100 ̊C
Stability Factor, S A stability factor S , is the ratio of a change in collector current I C to the change in the parameter value that caused it due to change in temperature Thus a stability factor is ameasure of how sensitive collector bias current is to change in a parameter value
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Fig4-34a shows a basic transistor circuit and the effect of I CO Fig4-34b the result of analyzing the stability based on change in I CO only ( β & V BE constant)Stability factor varies from the ideal case of S = 1 up to a maximum value of S = β + 1 whichoccurs for the fixed-bias circuit ( R B / R E > β + 1 )S is smallest for larger values of R E ( R E improves S, makes S smaller )
Fig (4-34) Effect of I CO
[4-21]
Example 19: In a circuit using a transistor typified by the parameters in Table-1 calculate thechange in I C from 25°C to 100°C for(a) Fixed bias ( R B /R E → ∞ )
(b) R B /R E = 11,(c) R B /R E = 0.01.Solution:
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Analysis of the stability factor due to change in V BE will result in
Since smaller values of S indicate better stability, the larger the value of R E the better thecircuit stability due to changes in V BE with temperature.
Example 20: Determine the change in I C for a transistor having parameters listed in Table-1over a temperature range from 25 to 100°C for a circuit having R E = 1 k Ω (and β+1 >> R B /R E ).Solution:
Analysis of the effect of β changing with temperature on the circuit bias stability results in
[4-22]
Example 21: Calculate the change in collector current for the transistor having parameters asgiven in Table-1 from room temperature to 100°C. Assume that R B /R E = 20 for the circuit usedand that I C at room temperature is 2 mA.Solution:
The collector current changing from 2 mA at room temperature to 2.315 mA at 100°C
represents a change of about 16%.The three parameters affecting S the change due to β variation is probably greatest The design of a good bias stabilized circuit most on stabilizing the effect of changesin transistor beta.
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So the total change in collector current over a certain temperature range is:
[4-23]
, & are the total change in the respective parameter values over the
temperature range. The expression is an approximation because all three parameters arechanging simultaneously with temperature
BJT switching circuitsTransistors are widely used in digital logic circuits and switching applications called an inverter. Alternate between a Low 0V and a high voltage + 5V
When the input is high +5V, V BE is forward biased and current flows through R B , the valuesof R B and R C are chosen so that the amount of base current flowing is enough to saturate thetransistor (to drive it into the saturation region of its output characteristics).
Fig4-36 an npn transistor inverter, or switch
V CE corresponding to this point is V CE(sat) is very nearly 0V, the current at the saturation point iscalled I C(sat) is very nearly to V CC / R C When the transistor is saturated, it is said to be ON "a High input to the inverter + 5V results ina Low output 0V "
When the input to the transistor is Low 0V, the base-emitter junction has No forward biasapplied to it, so NO I B and hence NO I C flows therefore NO voltage drop across R C so that V CE must be the same as V CC = + 5V, By substituting I C = 0 in the equation for V CE
V CE = V CC -I C R C = V CC - (0)(R C ) = V CC
In this situation, the transistor is in the cutoff region of its output characteristics and is said tobe OFF . In designing and analyzing transistor inverters. It is usually assumed thatI C(sat) = V CC /R C and that V E(sat) = 0 V
Fig4-37 When the input to the inverter is high +5V the transistor is saturated and its output islow ~0V, When the input to the inverter is low, the transistor is cut off its output is high.
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We can easily derive the voltage-current relations in a transistor inverter, since the transistor iscut off when the input is Low, the equations we will study are that apply when the input is high
V HI is the high level of the input voltage. Usually the same as V CC
Example 22: Verify that the circuit in fig8-38 behaves like an inverter when the input switchesbetween 0V and +5V. Assume that the transistor is Silicon and that β=100.
Fig4-38 Example 22 :Solution:It is necessary to verify that the transistor is saturated when V in = +5V.
Example 23:
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Example 24: Determine R B & R C for the transistor inverter of I Csat = 10mA
Solution: At saturation:
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SUMMARY (BJT)1-A bipolar junction transistor (BJT) consists of three regions: emitter, base, and collector.2- The three regions of a BJT are separated by two pn junctions.3- The two types of bipolar transistor are the npn and the pnp.4- The term bipolar refers to two types of current: electron current and hole current.5- One p-n junction of a transistor is forward-biased while the other is reverse-biased .
6- The dc emitter current is always the largest current of a transistor whereas the basecurrent is always the smallest. The emitter current is always the sum of the other two.7- The collector current is made up of two components: the majority component and theminority current (also called the leakage current).8- The arrow in the transistor symbol defines the direction of conventional current flow for theemitter current and thereby defines the direction for the other currents of the device9- A three-terminal device needs two sets of characteristics to completely define itscharacteristics.10- In the active region of a transistor, the base-emitter junction is forward-biased while thecollector-base junction is reverse-biased.11- In the cutoff region the base-emitter and collector-base junctions of a transistor are both
reverse-biased.12- In the saturation region the base-emitter and collector-base junctions are forward biased.13- On an average basis, as a first approximation, the base-to-emitter voltage of an operatingtransistor can be assumed to be 0.7 V 14- The quantity alpha (α) relates the collector and emitter currents and is always close to one.15- The impedance between terminals of a forward-biased junction is always relatively smallwhile the impedance between terminals of a reverse-biased junction is usually quite large.16- The arrow in the symbol of an npn transistor points out of the device (not pointing in),while the arrow points in to the center of the symbol for a pnp transistor, pointing in17- For the linear amplification purposes, cutoff for the common-emitter configuration will bedefined by I C =I CEO 18- The quantity beta ( β ) provides an important relationship between the base and thecollector currents; the dc beta is defined by a simple ratio of dc currents at an operating point 19- To ensure that a transistor is operating within its maximum power level rating, simply findthe product of the collector-to-emitter voltage and collector current, and compare it to the ratedvalue.20- No matter what type of configuration a transistor is used in, the basic relation shipsbetween the currents are always the same, and the base-to-emitter voltage is the thresholdvalue if the transistor is in the on state.21- The operating point defines where the transistor will operate on its character curves underdc conditions. For linear amplification, dc operating point should avoid the regions of saturationand cutoff.22- For most configurations the dc analysis begins with a determination of the base current .23- For the dc analysis of a transistor network, all capacitors are replaced by an open circuit equivalent.24- The fixed-bias configuration is the simplest of transistor biasing arrangement but it is alsoquite unstable due its sensitivity to beta at the operating point 25- Determining the saturation (maximum) collector current for any configuration can usuallybe done quite easily if an imaginary short circuit is superimpose between the collector andemitter terminals of the transistor. The resulting current through the short is then the saturationcurrent.26- The equation for the load line of a transistor network can be found by applying KVL to the
output or collector network. The Q-point is determined by finding the intersection between thebase current and the load drawn on the device characteristics.27- The emitter-stabilized biasing arrangement is less sensitive to changes in beta providingmore stability for the network. However, that any resistance in the emitter leg is "seen" at the
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base of the transistor as a much larger resistor ( βR E ≥ 10R 2 ), a fact that will reduce the basecurrent of the configuration.28- The voltage-divider bias configuration is probably the most common of all configurations.Its popularity is due primarily to its Low sensitivity to change beta from one transistor toanother of the same lot. The exact analysis can be applied to any configuration, but theapproximate can be applied only if the reflected emitter resistance as seen at the base is
much larger ( βR E ≥ 10R 2 ) than the lower resistor of the voltage-divider bias arrangementconnected to the base of the transistor.29- When analyzing the dc bias with a voltage feedback configuration, be sure to rememberthat both the emitter resistor and the collector resistor are reflected back to the base circuit bybeta. The least sensitivity to beta is obtained when the reflected resistance is much larger thanthe feedback resistor between the base and collector.30- For the common-base configuration the emitter current is normally determined first due tothe presence of the base-to-emitter junction in the same loop. Then the fact that the emitterand collector current are essentially of the same magnitude is employed.31- A clear understanding of the procedure employed to analyze a dc transistor network willusually permit a design of the same configuration with a minimum of difficulty and confusion.
Simply start with those relationships that minimize the number of unknowns, and then proceedto make some decisions about the unknown elements of the network.32- In a switching configuration, a transistor quickly moves between saturation and cutoff, orvice versa. Essentially, the impedance between collector and emitter can be approximated asa short circuit for saturation and an open circuit for cutoff.33- When checking the operation of a dc transistor network, first check that the base-to-emittervoltage is very close to 0.7 V and that the collector-to-emitter voltage is between 25% and 75%of the applied voltage V CC 34-The analysis of pnp configurations is exactly the same as that applied to npn transistorswith the exception that current directions will reverse and voltages will have the opposite polarities.
35- Beta is very sensitive to temperature, and V BE decreases about 7.5 mV (0.0075 V) for each10° increase in temperature on a Celsius scale. The reverse saturation current typicallydoubles for every 10° increase in Celsius temperature.36- Keep in mind that networks that are the most stable and least sensitive to temperaturechanges have the smallest stability factors.
CB npn CB pnp
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Reveres saturation current
CE npn CE pnp
Circuit conditions related to I CEO
CC pnp CC npn
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Determining the proper biasing arrangement for a CE npn transistor
Equation
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