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MIX DESIGN ALKALI ATIVATED COMPOSITES { GG %Na2O = 6.5% = 0.065 %Sio2 = 6.5% = 0.065 Sio2/Na2O= 1 Assuming quantity of blended material = 1000 gm , quantity of Na2O required 6.5% of flyash 65 gm quantity of sio2 require 6.5% of flyash 65 gm Given, 1000 gm Na2Sio3 contains= 265 gm of Sio2 & 80 gm of Na2O & 655 gm of H2O So, to ge 65 gms of Na2O,Quantity of Na2SiO3 = 245.283 gm of Na2sio3 1000 gm of Na2sio3 contain 80 gm of Na2O 245.283 gm of Na2sio3 contain 19.62264 gm of Na2O 1000 gm of Na2sio3 contain 655 gm of H2O 245.283 gm of Na2sio3 contain 160.6604 gm of H2O Remaining Na2o= 45.37736 gm was obtained from NaOH soln. 1000 gm of NaOH in pellets form contain= 775 gm & 225 gm 775 gm of Na2O is present in = 1000 gm 45.37736 gm of Na2O is present in = 58.55143 gm Calculation of Water [H2O] content : 1000 gm Na2Sio3 contains= 655 gm of H2O 245.283 gm 160.6604 gm of H2O 1000 gm of NaOH in pellets form contain= 225 gm 58.55143 gm of NaOH in pellets form contain= 13.17407 gm 173.8344 gm SAMPLE CALCULATION 0.29 Total quantity of binder required= 1000 + 65 of Sio2 obtained from Na2SiO3 Na2Sio3 contains= Total water content from chemicals Na2Sio3+NaOH pellet Fixing up Water /Binding material ratio=

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Sheet1MIX DESIGN ALKALI ATIVATED COMPOSITES { GGBFS + FLYASH}%Na2O=6.5%=0.065%Sio2=6.5%=0.065Sio2/Na2O=1Assuming quantity of blended material =1000gmSo, quantity of Na2O required =6.5%of flyash65gmquantity of sio2 required =6.5%of flyash65gmGiven,1000gmNa2Sio3 contains=265gmof Sio2&80gmof Na2O&655gmof H2OSo, to get 60 gm of Na2O , quantity of Na2sio3 required =65gms of Na2O,Quantity of Na2SiO3 =245.2830188679gm of Na2sio31000gmof Na2sio3 contain=80gmof Na2O245.2830188679gmof Na2sio3 contain=19.6226415094gmof Na2O1000gmof Na2sio3 contain=655gmof H2O245.2830188679gmof Na2sio3 contain=160.6603773585gmof H2ORemaining Na2o=45.3773584906gmwas obtained from NaOH soln.1000gmof NaOH in pellets form contain=775gmof Na2O&225gmof H2O775gmof Na2O is present in =1000gmof NaOH pellets45.3773584906gmof Na2O is present in =58.5514303104gmof NaOH pelletsCalculation of Water [H2O] content :1000gmNa2Sio3 contains=655gmof H2O245.2830188679gmNa2Sio3 contains=160.6603773585gmof H2O1000gmof NaOH in pellets form contain=225gmof H2O58.5514303104gmof NaOH in pellets form contain=13.1740718198gmof H2oTotal water content from chemicals Na2Sio3+NaOH pellets =173.8344491783gmof H2OSAMPLE CALCULATIONFixing up Water /Binding material ratio=0.29Total quantity of binder required= 1000 +65of Sio2obtained from Na2SiO319.6226415094OF Na2O obtained from Na2SiO345.3773584906OF Na2O obtained from NaOHWater required=327.7EXTRA Water to be added mechanically=153.8655508217Considering NaOH pellets to be 97% pure=97%100gmof NaOH pellets=103gm58.5514303104gmof NaOH pellets=60.3079732197gmof NaOH pelletsTherefore QUANTITY OF NA2SIO3=245.2830188679QUANTITY OF NAOH=60.3079732197CHEMICAL WATER TOTAL=173.8344491783Aggregate Proportions:All - in - aggregate =70%0.7of total Binding Material700gmcoarse Aggregate=60%0.6of All - in - aggregate420gmFine aggregate =40%0.4of All - in - aggregate280gmBinder/sand=1Sand=1000gm

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