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subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………… computed PP date …… 9/10/2009 checked ………………………….. page 1 REF CALCULATION DESIGN OF FORM WORK FOR SLAB BOTTOM project : pottuvil 1.0 slab thickness 175 mm loading DL sw :- 4.20 IL 1.50 ser. load :- 5.70 ult. load :- 8.28 2.0 Timber design (ply wood) use 15 mm tk plywood SF 1.25 spacing 0.38 m udl -w 2.17 kN/m sw- kN/m 0.12 density 783 design w 2.28 kN/m E 6300 width-b 1000 mm I 96000 depth-d 15 mm 1020 mm 15.3 mm M 0.03 kNm 2.43 45.00 section is satisfactory Deflection deflec- permissible 2.11 mm deflec- actual 0.54 mm section is satisfactory 3.0 Design of secondary members use 25x50 mm timber section design loa 2.28 kN/m span 0.300 m BM = 0.03 kNm SF = 0.34 kN length - m 0.300 sc8 spacing- m 0.380 m 17.5 sw- kN/m 0.01 sf 2 w - kN/m 2.28 bearing 3.9 design w 2.30 density 1080 b - mm 50 E 10700 d - mm 25 51 25.5 M - kNm 0.03 SF - kN 0.34 kN/m 2 kN/m 2 kN/m 2 kN/m 2 kg/m 3 N/mm 2 mm 4 b1 d1 bending stress- pbm N/mm 2 bending strength- N/mm 2 b1- mm d1 - mm

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Page 1: Form Work Design New

subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….

computed PP date …… 9/10/2009

checked ………………………….. page 1 ofpages

REF CALCULATION OUTPUT

DESIGN OF FORM WORK FOR SLAB BOTTOM project : pottuvil

1.0 slab thickness 175 mm

loading

DL sw :- 4.20

IL 1.50

ser. load :- 5.70

ult. load :- 8.28

2.0 Timber design (ply wood)

use 15 mm tk plywood

SF 1.25

spacing 0.38 m

udl -w 2.17 kN/m

sw- kN/m 0.12 density 783

design w 2.28 kN/m E 6300

width-b 1000 mm I 96000

depth-d 15 mm

1020 mm

15.3 mm

M 0.03 kNm

2.43

45.00 section is satisfactory

Deflection

deflec- permissible 2.11 mm

deflec- actual 0.54 mm section is satisfactory

3.0 Design of secondary members

use 25x50 mm timber section

design load 2.28 kN/m

span 0.300 m

BM = 0.03 kNm

SF = 0.34 kN

length - m 0.300 sc8

spacing- m 0.380 m 17.5

sw- kN/m 0.01 sf 2

w - kN/m 2.28 bearing 3.9

design w 2.30 density 1080

b - mm 50 E 10700

d - mm 25

51

25.5

M - kNm 0.03

SF - kN 0.34

kN/m2

kN/m2

kN/m2

kN/m2

kg/m3

N/mm2

mm4

b1

d1

bending stress- pbm N/mm2

bending strength- pbm N/mm2

b1- mm

d1 - mm

Page 2: Form Work Design New

subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….

computed PP date …… 9/10/2009

checked ………………………….. page 2 ofpages

REF CALCULATION OUTPUT

4.65 bending is satisfactory 19.635

0.40 shear is satisfactory 2.525

k - factors

m sf bearing

stresses 17.5 2 3.9

k2 0.8 0.9 0.6

k3 1.25 1.25 1.25

k4 1.0 1.0 1.0

k5 1.0 1.0 1.0

k6 1.0 1.0 1.0

k7 1.02 1.02 1.02

k8 1.1 1.1 1.1

19.635 2.525 3.282

deflec- per 0.83 deflection is satisfactory

E 10700

deflec- actu 0.61

Hence the section is 25x50 mm timber section

with 0.380 m spacing.

4.0 Design of primary members

Ref : BS5950 : Part : 1990

use 16 mm dia R/F bars

design load 2.29 kN/m steel p 75.5

span 0.380 m bar wt 0.0152 kN/m

BM = 0.04 kNm

SF = 0.43 kN

shear capacity

275

out side dia. D = 16.00 mm

29.87 kN

SF = 0.43 kN

Section is satisfactory

0.11 kNm

BM = 0.04 kNm

Section is satisfactory

pbm - N/mm2

psf - N/mm2

kN/m3

Check for shear cl: 4.2.3

design strength Py = N/mm2

Pv =

Moment capacity cl:4.2.5

MC =

Page 3: Form Work Design New

subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….

computed PP date …… 9/10/2009

checked ………………………….. page 3 ofpages

REF CALCULATION OUTPUT

per. def. = 1.1 mm

actual def. = 0.67 mm section is satisfactory

Hence the section is 16 mm dia R/F bars

with 0.300 m spacing.

5.0 Design of secondary members Ref : BS5950 : Part : 1990

use 50 mm dia medium duty GI pipes

design load 2.90 kN/m

span 1.020 m

BM = 0.38 kNm

SF = 1.48 kN

shear capacity

275

out side dia. D = 59.80 mm

thickness t = 2.2 mm

in side dia. d = 55.40 mm

39.43 kN

SF = 1.48 kN

Section is satisfactory

D/t = 27.18

40 57.0 80

plastic

1.52 kNm

BM = 0.38 kNm

Section is satisfactory

per. def. = 2.8 mm

actual def. = 0.86 mm section is satisfactory

Hence the section is 50 mm dia medium duty GI pipes

with 0.380 m spacing.

Deflection cl:2.5.1

Check for shear cl: 4.2.3

design strength Py = N/mm2

Pv =

Section classification cl: 3.5.2

Moment capacity cl:4.2.5

MC =

Deflection cl:2.5.1

Page 4: Form Work Design New

subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….

computed PP date …… 9/10/2009

checked ………………………….. page 4 ofpages

REF CALCULATION OUTPUT

6.0 Design of primary members

FOR JACK SUPPORTS

use 100x100 mm timber section

design load 6.22 kN/m

span 1.600 m

BM = 1.99 kNm

SF = 4.97 kN

length - m 1.600 sc8

spacing- m 1.020 m 17.5

sw- kN/m 0.16 sf 2

w - kN/m 6.22 bearing 3.9

design w 6.38 density 1080

b - mm 100 E 10700

d - mm 150

102

153

M - kNm 1.99

SF - kN 4.97

5.00 bending is satisfactory 19.635

0.48 shear is satisfactory 2.525

k - factors

m sf bearing

stresses 17.5 2 3.9

k2 0.8 0.9 0.6

k3 1.25 1.25 1.25

k4 1.0 1.0 1.0

k5 1.0 1.0 1.0

k6 1.0 1.0 1.0

k7 1.02 1.02 1.02

k8 1.1 1.1 1.1

19.635 2.525 3.282

deflec- per 4.44 deflection is satisfactory

E 10700

deflec- actu 3.5

Hence the section is 100x100 mm timber section

with 1.020 m spacing.

5.0 Jacks should be provided at 1.020 m spacing.

Load on Jack :- 9.9 kN

b1- mm

d1 - mm

pbm - N/mm2

psf - N/mm2

Page 5: Form Work Design New

subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….

computed PP date …… 9/10/2009

checked ………………………….. page 5 ofpages

REF CALCULATION OUTPUT

Page 6: Form Work Design New

1 Loading

Density of Plywood: 7.83 kN/m3Plywood Thickness: 15 mmLoad Plywood: 0.1 kN/m2Tile: 0.6 kN/m2Services: 0.5 kN/m2

DL: 1.2 kN/m2IL: 4 kN/m2Ser Lo: 5.2 kN/m2Ul.Load: 8.1 kN/m2

2 Timber (Plywood) Design

Density: 783 kg/m3

Page 7: Form Work Design New

Sanken Construction (Pvt) Ltd. Record No:SL/DD/CLS/11

Design Office Revision No.00

Design of the formwork System

Subject Formwork for Platform Job GreenpathJob no 001

ComputedUmesh Date 4/20/2023Checked Peiris Page

Reference Calculation

1.0 Information

Slab weight mm

Concrete Density

Concrete Grade

Plywood Density 7.83Plywood Thickness 15 mm

2.0 LoadingsPlywood Sweight 0.12

Vinyl Tile Dead 0.60

Dead Load 0

Imposed Load 2

3.0 Combinations

Servisibility Limit State 2

Ultimate Limit State 3.2

4.0 Timber design for Plywood Sections

Plywood thickness 12 mm

Support Spacing 0.2 m2.00 kN/m

Density 783

Elastic Modulous 6300

I 152813.952

Self weight 0.92Safety factors4.1 Safety factor for Loading 1.25

Effective SpanClear Span+ 50mm for solid rectangular SectionsBredth 1000 mm

CALCULATION SHEET

kN/m3

N/mm2

kN/m3

kN/m2

kN/m2

kN/m2

kN/m2

kN/m2

kN/m2

Uniformly Distributed Load -w (1 m )

kg/m3

N/mm2

mm4

kN/m2

Page 8: Form Work Design New

Depth 12 mm

Consider wet exposure conditions

1.02

Effective Bredth 1020 mm

Effective Depth 12.24 mm

BendingBS 5268 : Part 2-1996

Table 1.3 0.80

Table 1.4 1.75

Cl. 2.10.5. 1.00

Cl. 2.10.6. 1.17

Cl. 2.9. 1.00

0.70

Design Load 3.65 kN/m

Admissible Moment 0.02 kNm

Admissible Bending Stress = M x y

I

0.91

Allowable Bending Strength 5.16

Section is Satisfied for bending.

ShearAdmissible Shear Stress = 1.5F Cut Half

A

0.45

Safety Factors

Table 1.3 0.80

Table 1.4 1.75

Cl. 2.10.4. 1.00

Cl. 2.9. 1.00

Built up Secti 0.80

Allowable Shear Stress 4.96

Section is Satisfied for Shear.

DeflectionAdmissible deflection = 0.003 x span

0.60 mmActual deflection = Bending deflection + Shear Deflection

K1

K2

K3

K6

K7

K8

Built up Section K36

N/mm2

N/mm2

N/mm2

K2

K3

K5

K8

K36

N/mm2

Page 9: Form Work Design New

Bending Deflection =384EI

0.08 mm

Shear Deflection = 8AG

Shear Modulus 450000.0000 mm

Shear deflection can be neglected.

Actual deflection 0.08 mm

Section is Satisfied for deflection.

Therefore plywood section is OK for the floor.

5.0 Design for GI pipes (Secondary Members)BS 5950-1 : 2000

Use 50mm diameter GI pipesWeight of pipe 6.17 kg/m

Self Weight = 0.06 kN/mService Load = 0.58 kN/mDesign Load = 0.81 kN/m

Span = 450 mm

Bending Moment = 0.02 kNmShear Force = 0.18 kN

Shear

Steel Grade S275

275.00

Outer Diameter 60.80 mmInner Diameter 51.80 mmThickness 4.50 mm

Cl. 4.2.3. Shear Capacity =78.80 kN

Shear Force = 0.18 kN

Section is Satisfied for Shear.

Section ClassificationD/t 13.51Limiting Values

5wL4

Kwl2

N/mm2

Design Strength (Py) N/mm2

.6 x Py x Av

Page 10: Form Work Design New

€ 1.00

40.00

50.00

140.00

Table 12 Section is Class 1 Plastic

Moment

Low Shear

Cl.4.2.5

S=6

14293.98

3930844.50 Nmm3.93 kNm

Bending Moment = 0.02 kNm

Section is Satisfied for Bending.

Deflection

Table 8 Allowable Deflection = 1.25 mmActual Deflection = 0.01 mm

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the floor.

6.0 Design for I sections (Primary Members)BS 5950-1 : 2000

Use 150 x 100 x 21.1 kg/m section

Design Load 1.81 kN/mSpan 1.60 m

40 €2

50 €2

140 €2

Moment Capacity (Mc )= Py x S

d13-d2

3

mm3

Mc =

Page 11: Form Work Design New

Section 150 x 100 x 21.1Weight = 21.10 kg/m

275D = 148 mmB = 100.0 mmT = 9 mmt = 6 mmr = 11 mm

1020

61.7 mm

23.7 mm

138

Loading

Imposed DL= 1.45 kN/mSelf wt. = 0.21 kN/m

span = 1.60 m

Ult. load = 1.81 kN/mService load = 1.66 kN/mBM = 0.58 kNmSF = 1.45 kN

Shear

Steel Grade S275

275.00

Cl. 4.2.3. Shear Capacity =219.78 kN

Shear Force = 1.45 kN

Section is Satisfied for Shear.

MomentSection Classificationb/T 5.56

Limiting Values

€ 1.00

9 € 9.0010 € 10.0015 € 15.00

Table 12 Section is Class 1 Plastic

Py = N/mm2

IX = cm4

RX =

RY =

ZX = cm3

Design Strength (Py) N/mm2

.6 x Py x Av

Page 12: Form Work Design New

Section Classificationd/t 21.67

Limiting Values

€ 1.00

80 € 80.00100 € 100.00120 € 120.00

Table 12 Section is Class 1 Plastic

Moment

Low Shear

Cl.4.2.5

S=

54465.87

14978115.49 Nmm14.98 kNm

Bending Moment = 0.58 kNm

Section is Satisfied for Bending.

Lateral Torsional Buckling

Actual value =

1.00

0.58 kNm

Table 13 Effective Length Multiple Factor = 0.70

Cl. 4.3.6.7. Slenderness ratios (λ) =

18.15

47.26Critical Slenderness ratio = 47.26

Cl. 4.3.6.7.

Moment Capacity (Mc )= Py x S

btf ( d - tf ) + 0.25tw ( d - 2t

mm3

Mc =

mLT x M

mLT =

Both Flanges fully restrained against rotaion on plan.

LE

rx

LE

ry

λLT = uνλ√βW

Page 13: Form Work Design New

Cl. 4.3.6.8. u = 0.90Cl. 4.3.6.8. x = 16.44Cl. 4.3.6.7. ν = 1

0.92

λ = 47.26

Cl. 4.3.6.9. 1.00

39.01

275.00

Table 16 270.82

54465.87

14750557.07 Nmm14.75 kNm

Section is Satisfied for Lateral torsional buckling.

DeflectionBeams carrying plaster or other brittle finish 4.44 mmOther Beams 8.00 mm

Actual Deflection = 0.07 mm

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the floorUse 150 x 100 x 21.1 kg/m section

7.0 Props

Slab thickness = 0.45 m

Concrete density = 24.00

Wt. per unit meter = 10.80

[1 + 0.05 (λ/x)2]0.25

βW =

λLT =

Py = N/mm2

Pb = N/mm2

Sx = mm3

Mb = Pb x Sx

Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.

kN/m3

kN/m2

Page 14: Form Work Design New

Safe working load of a steel prop = 1900.00 kg18.64 kN

Then load transfer from Slab = 10.80 kN

Therefore spacing of props = 1.73 m

Provide a space of 1.6m everywhere except for special locations.

Punching Shear check

Width of the Support = 200.00 mmUltimate design load = 18.64 kNDepth of the Slab = 85.00 mm

Shear Stress (v) = F4 x ( 3d + c) x d

0.48

Considering nominal steel is used,

0.45

8.0 Scafolding System (Opition 02)

Slab thickness = 1.05 m

Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.

Consider a 1 m2

Previous calculations

for slabs

N/mm2

vc = N/mm2

Therefore need additional timber sections having a width of 200mm to distribute the load through-out the slab.

Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.

Page 15: Form Work Design New

Concrete density = 24.00

Wt. per unit meter = 25.20

Allowable working load of a scafolding leg = 1500.00 kgSafe working load of a leg = 750.00 kg

7.36 kN

Then load transfer from Slab = 10.21 kNTributorySlab

for a

Therefore spacing of props = 0.72 m

Provide a space of .9m everywhere except for special locations.This is considering scafoldingarrangements.

Punching Shear check

Width of the Support = 200.00 mmUltimate design load = 7.36 kNDepth of the Slab = 85.00 mm

Shear Stress (v) = F4 x ( 3d + c) x d

0.19

Considering nominal steel is used,

0.45

kN/m3

kN/m2

Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.

Consider a 0.45 x 0.90 m2 area

Previous calculations

for slabs

N/mm2

vc = N/mm2

Therefore no need additional timber sections at the bottom expept 200 mm *200 mm support.

Page 16: Form Work Design New

Load transfer to 8th floor = (10.8-2.5)

8.3

Then load transfer from Slab = 6.72 kNTributorySlab

for a

Therefore spacing of props = 1.09 m

Load transfer to 7th floor = (8.3-2.5)

5.8

Then load transfer from Slab = 4.70 kNTributorySlab

for a

Therefore spacing of props = 1.57 m

Load transfer to 6th floor = (5.8-2.5)

3.3

Then load transfer from Slab = 2.67 kNTributorySlab

for a

kN/m2

kN/m2

Consider a 0.45 x 1.80 m2 area

Provide a space of 0.9m everywhere except for special locations. Since the load from 0.45*1.8 m2 cannot taken by the arrangement

kN/m2

kN/m2

Consider a 0.45 x 1.80 m2 area

Provide a space of 0.9m everywhere except for special locations. Since the load from 0.45*1.8 m2 cannot taken by the arrangement

kN/m2

kN/m2

Consider a 0.45 x 1.80 m2 area

Page 17: Form Work Design New

Therefore spacing of props = 2.75 m

Provide a space of 1.8m everywhere except for special locations.

Load transfer to 6th floor = (3.3-2.5)

0.8

Then load transfer from Slab = 0.65 kNTributorySlab

for a

Therefore spacing of props = 11.35 m

Provide a space of 1.8m everywhere except for special locations.

DESIGNED BY :-

Chinthana BandaraBSc. Eng. (Hons.), AMIE(SL)Designs DepartmantSanken Construction (Pvt) Ltd.

CHECKED BY :-

P Prasantha PeirisBSc. Eng. (Hons.), CEng., MIE(SL),MSSE(SL)PG Dip in Struct. Eng. Design.Designs Departmant

Sanken Construction (Pvt) Ltd.

17/08/2012

Since 6th floor was designed to a imposed load of 10 kN/m2 minimum no need to support the structure beyond Panel 1,2,3 and 4.

kN/m2

kN/m2

Consider a 0.45 x 1.80 m2 area

Page 18: Form Work Design New
Page 19: Form Work Design New

Record No:SL/DD/CLS/11

Revision No.00

Output

2 kN/m2

3.2 kN/m2

Page 20: Form Work Design New

Section is Satisfied for bending.

Section is Satisfied for Shear.

Page 21: Form Work Design New

Section is Satisfied for deflection.

Therefore plywood section is OK for the

floor.

Section is Satisfied for Shear.

Page 22: Form Work Design New

Section is Class 1 Plastic

Section is Satisfied for Bending.

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the

floor.

Page 23: Form Work Design New

Section is Satisfied for Shear.

Section is Class 1 Plastic

Page 24: Form Work Design New

Section is Class 1 Plastic

) + 0.25tw ( d - 2tf )2

Section is Satisfied for Bending.

Both Flanges fully restrained against rotaion on plan.

Effective Length Multiple Factor =

0.70

Page 25: Form Work Design New

Section is Satisfied for Lateral torsional

buckling.

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the

floor

Since beams are taking the load from the slab above, only the weight of 450 mm thick

Page 26: Form Work Design New

DESIGNED BY :-

Chinthana BandaraBSc. Eng. (Hons.)Designs Departmant

was considered on floors below except in level

Provide a space of 1.6m everywhere except for special

locations.

Therefore need additional timber sections having a width of 200mm to distribute the load

Since beams are taking the load from the slab above, only the weight of 450 mm thick

Page 27: Form Work Design New

Sanken Construction (Pvt) Ltd.

CHECKED BY :-

P Prasantha PeirisBSc. Eng. (Hons.), CEng., MIE(SL),MSSE(SL)PG Dip in Struct. Eng. Design.Designs Departmant

Sanken Construction (Pvt) Ltd.

4/20/2023Tributory

panelsleg

was considered on floors below except in level

Provide a space of .9m everywhere except for special

locations.

Therefore no need additional timber sections at the bottom expept 200 mm *200 mm

Page 28: Form Work Design New

Tributorypanelsleg

Tributorypanelsleg

Tributorypanelsleg

Provide a space of 0.9m everywhere except for special locations. Since the load from

Provide a space of 0.9m everywhere except for special locations. Since the load from

Page 29: Form Work Design New

Provide a space of 1.8m everywhere except for special locations.

Tributorypanelsleg

Provide a space of 1.8m everywhere except for special locations.

Since 6th floor was designed to a imposed load of 10 kN/m2 minimum no need to support

Page 30: Form Work Design New
Page 31: Form Work Design New

Sanken Construction (Pvt) Ltd. Record No:SL/DD/CLS/11

Design Office Revision No.00

Design of the formwork System

Subject Formwork for transfer floor at Greenpath Job Katunayaka AirportJob no 001

ComputedUmesh Date 4/20/2023Checked Peiris Page

Reference Calculation Output

1.0 Information

Slab weight 0 mm

Concrete Density 24

Concrete Grade

2.0 LoadingsVinyl Tile Dead 0.60

Services 0.5

Dead Load 1.10

Imposed Load 5

3.0 Combinations

Servisibility Limit State 6.10 6.10

Ultimate Limit State 9.54 9.54

4.0 Timber design for Plywood Sections

Plywood thickness 15 mm

Support Spacing 0.35 m6.10 kN/m

Density 783

Elastic Modulous 6300

I 298464.75

Self weight 0.12Safety factors4.1 Safety factor for Loading 1.25

Effective SpanClear Span+ 50mm for solid rectangular SectionsBredth 1000 mm

Depth 15 mm

Consider Covered Building (Wet Exposure)

1.02

Effective Bredth 1020 mm

Effective Depth 15.3 mm

BendingBS 5268 : Part 2-1996

Table 1.3 0.80

Table 1.4 1.25

Cl. 2.10.5. 1.00

Cl. 2.10.6. 1.17

Cl. 2.9. 1.10

Built up Sectio 0.80Design Load 7.77 kN/m

Applied Moment 0.12 kNm

Applied Bending Stress = M x y

I

CALCULATIO

N SHEET

kN/m3

N/mm2

kN/m2

kN/m2

kN/m2

kN/m2

kN/m2

kN/m2

Uniformly Distributed Load -w (1 m )

kg/m3

N/mm2

mm4

kN/m2

K1

K2

K3

K6

K7

K8

K36

Page 32: Form Work Design New

2.82

Allowable Bending Strength 4.63

Section is Satisfied for bending.

ShearApplied Shear Stress = 1.5F Cut Half

A

0.27

Safety Factors

Table 1.3 0.80

Table 1.4 1.25

Cl. 2.10.4. 1.00

Cl. 2.9. 1.00

Built up Sectio 0.80

Allowable Shear Stress 3.54

Section is Satisfied for Shear.

DeflectionAdmissible deflection = .003XSpan

1.05 mmActual deflection = Bending deflection + Shear Deflection

Bending Deflection =384EI

0.81 mm

Shear Deflection = 8AG

Shear Modulus 450000.0002 mm

Shear deflection can be neglected.

Actual deflection 0.81 mm

Section is Satisfied for deflection.

Therefore plywood section is OK for the floor.

5.0 Design for GI pipes (Secondary Members)BS 5950-1 : 2000

Use 50mm diameter GI pipesWeight of pipe 5.1 kg/m

Self Weight = 0.05 kN/mTotal Service Load = 2.23 kN/mDesign Load (Service*1.5) = 3.34 kN/m

Span = 1200 mm

Bending Moment = 0.60 kNmShear Force = 2.00 kN

Shear

Steel Grade S275

275.00

Outer Diameter 60.80 mmInner Diameter 53.50 mmThickness 3.65 mm

Cl. 4.2.3. Shear Capacity =

N/mm2

N/mm2

Section is Satisfied for bending.

N/mm2

K2

K3

K5

K8

K36

N/mm2

Section is Satisfied for Shear.

5wL4

Kwl2

N/mm2

Section is Satisfied for deflection.

Therefore plywood section is OK for the

floor.

Design Strength (Py) N/mm2

.6 x Py x Av

Page 33: Form Work Design New

64.88 kNShear Force = 2.00 kN

Section is Satisfied for Shear.

Section ClassificationD/t 16.66Limiting Values

€ 1.00

40.00

50.00

140.00

Table 12 Section is Class 1 Plastic

Moment

Low Shear

Cl.4.2.5

S=6

11937.56

3282827.95 Nmm3.28 kNm

Bending Moment = 0.60 kNm

Section is Satisfied for Bending.

Deflection

Table 8 Allowable Deflection = 3.33 mmActual Deflection = 1.64 mm

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the floor.

6.0 Design for I sections (Primary Members)BS 5950-1 : 2000

Use 150 x 75 x 14.0 kg/m section

Design Load 11.44 kN/mSpan 1.60 m

Section 150 x 75 x 14.0Weight = 14.00 kg/m

275D = 150 mmB = 100.0 mmT = 10 mmt = 5 mmr = 7 mm

666

61.1 mm

16.6 mm

Section is Satisfied for Shear.

40 €2

50 €2

140 €2

Section is Class 1 Plastic

Moment Capacity (Mc )= Py x S

d13-d2

3

mm3

Mc =

Section is Satisfied for Bending.

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the

floor.

Py = N/mm2

IX = cm4

RX =

RY =

Page 34: Form Work Design New

88.8

Loading

Imposed DL= 9.16 kN/mSelf wt. = 0.14 kN/m

span = 1.60 m

Ult. load = 11.44 kN/mService load = 9.29 kN/mBM = 3.66 kNmSF = 9.16 kN

Shear

Steel Grade S275

275.00

Cl. 4.2.3. Shear Capacity =247.50 kN

Shear Force = 9.16 kN

Section is Satisfied for Shear.

MomentSection Classificationb/T 5.00

Limiting Values

€ 1.00

9 € 9.0010 € 10.0015 € 15.00

Table 12 Section is Class 1 Plastic

Section Classificationd/t 26.00

Limiting Values

€ 1.00

80 € 80.00100 € 100.00120 € 120.00

Table 12 Section is Class 1 Plastic

Moment

Low Shear

Cl.4.2.5

S=

60013.11

16503605.28 Nmm16.50 kNm

Bending Moment = 3.66 kNm

Section is Satisfied for Bending.

Lateral Torsional Buckling

Actual value =

1.00

ZX = cm3

Design Strength (Py) N/mm2

.6 x Py x Av

Section is Satisfied for Shear.

Section is Class 1 Plastic

Section is Class 1 Plastic

Moment Capacity (Mc )= Py x S

btf ( d - tf ) + 0.25tw ( d - 2tf )2

mm3

Mc =

Section is Satisfied for Bending.

mLT x M

mLT =

Page 35: Form Work Design New

3.66 kNm

Table 13 Effective Length Multiple Factor = 0.70

Cl. 4.3.6.7. Slenderness ratios (λ) =

18.33

67.47Critical Slenderness ratio = 67.47

Cl. 4.3.6.7.

Cl. 4.3.6.8. u = 0.90Cl. 4.3.6.8. x = 15.00Cl. 4.3.6.7. ν = 1

0.84

λ = 67.47

Cl. 4.3.6.9. 1.00

50.99

275.00

Table 16 228.38

60013.11

13705554.03 Nmm13.71 kNm

Section is Satisfied for Lateral torsional buckling.

DeflectionBeams carrying plaster or other brittle finish 4.44 mmOther Beams 8.00 mm

Actual Deflection = 0.72 mm

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the floorUse 150 x 75 x 14.0 kg/m section

7.0 Props

Slab thickness = 1.05 m

Concrete density = 24.00

Wt. per unit meter = 25.20

Safe working load of a steel prop = 1900.00 kg

Both Flanges fully restrained against rotaion on plan.

Effective Length Multiple Factor = 0.70

LE

rx

LE

ry

λLT = uνλ√βW

[1 + 0.05 (λ/x)2]0.25

βW =

λLT =

Py = N/mm2

Pb = N/mm2

Sx = mm3

Mb = Pb x Sx

Section is Satisfied for Lateral torsional

buckling.

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the

floor

Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.

kN/m3

kN/m2

Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.

Page 36: Form Work Design New

18.64 kN

Then load transfer from Slab = 25.20 kN

Therefore spacing of props = 0.74 m

Provide a space of 1.6m everywhere except for special locations.

Punching Shear check

Width of the Support = 200.00 mmUltimate design load = 18.64 kN

Depth of the Slab = 85.00 mm

Shear Stress (v) = F4 x ( 3d + c) x d

0.48

Considering nominal steel is used,

0.45

Consider a 1 m2

Provide a space of 1.6m everywhere except for special

locations.

Previous calculations

for slabs

N/mm2

vc = N/mm2

Therefore need additional timber sections having a width of 200mm to distribute the load through-out the slab.

Page 37: Form Work Design New
Page 38: Form Work Design New

kN/m2

kN/m2

CALCULATION SHEET

Page 39: Form Work Design New

Section is Satisfied for bending.

Section is Satisfied for Shear.

Section is Satisfied for deflection.

Therefore plywood section is OK for the

floor.

Page 40: Form Work Design New

Section is Satisfied for Shear.

Section is Class 1 Plastic

Section is Satisfied for Bending.

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the

floor.

Page 41: Form Work Design New

Section is Satisfied for Shear.

Section is Class 1 Plastic

Section is Class 1 Plastic

Section is Satisfied for Bending.

Page 42: Form Work Design New

Effective Length Multiple Factor = 0.70

Section is Satisfied for Lateral torsional

buckling.

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the

floor

Page 43: Form Work Design New

Provide a space of 1.6m everywhere except for special

locations.

Page 44: Form Work Design New
Page 45: Form Work Design New

job ………………………….. Greenpathjob no ………………………. 3date ………………………….. 20/4/2012page of

pages

Page 46: Form Work Design New

Sanken Construction (Pvt) Ltd. Record No:SL/DD/CLS/11

Design Office Revision No.00

Design of the formwork System

Subject Mezzanine Floor Job Toyota WattalaJob no 001

ComputedUmesh Date 4/20/2023Checked Peiris Page

Reference Calculation Output

1.0 Information

Slab weight 0 mm

Concrete Density 24

Concrete Grade

2.0 LoadingsVinyl Tile Dead (Ceiling) 0.00

Services 0.5

Dead Load 0.50

Imposed Load 4

3.0 Combinations

Servisibility Limit State 4.50 4.50 kN/m2

Ultimate Limit State 7.10 7.10 kN/m2

4.0 Timber design for Plywood Sections

Plywood thickness 29 mm

Support Spacing 0.6 m4.50 kN/m

Density 783

Elastic Modulous 1250

I 2032416.666667

Self weight 0.22Safety factors4.1 Safety factor for Loading 1.25

Effective SpanClear Span+ 50mm for solid rectangular SectionsBredth 600 mm

Depth 29 mm

Consider Covered Building (Dry Exposure)

1

Effective Bredth 600 mm

Effective Depth 29 mm

BendingBS 5268 : Part 2-1996

Table 1.3 1.00 Covered Building

Table 1.4 1.00 Long Term

Cl. 2.10.5. 1.00

Cl. 2.10.6. 1.17

Cl. 2.9. 1.10

Built up Sectio 1.00Design Load 5.90 kN/m

Applied Moment 0.27 kNm

Applied Bending Stress = M x y

I

1.90

Allowable Bending Strength 6.40

Section is Satisfied for bending.

CALCULATIO

N SHEET

kN/m3

N/mm2

kN/m2

kN/m2

kN/m2

kN/m2

kN/m2

kN/m2

Uniformly Distributed Load -w (1 m )

kg/m3

N/mm2

mm4

kN/m2

K1

K2

K3

K6

K7

K8

K36

N/mm2

N/mm2

Section is Satisfied for bending.

Page 47: Form Work Design New

ShearApplied Shear Stress = 1.5F Cut Half

A

0.18

Safety Factors

Table 1.3 1.00

Table 1.4 1.00

Cl. 2.10.4. 1.00

Cl. 2.9. 1.10

Built up Sectio 1.00

Allowable Shear Stress 1.74

Section is Satisfied for Shear.

DeflectionAdmissible deflection = .003XSpan

1.80 mmActual deflection = Bending deflection + Shear Deflection

Bending Deflection =185EI

1.63 mm

Shear Deflection = 8AG

Shear Modulus 2500.0440 mm

Shear deflection should be conssidered

Actual deflection 1.67 mm

Section is Satisfied for deflection.

Therefore plywood section is OK for the floor.

5.0 Design for GI pipes (Secondary Members-2)BS 5950-1 : 2000

Use 254x 146 x 37.0 kg/m section

Design Load 4.81 kN/mSpan 7.00 mSupport spacing 0.60 m

Section 254 x 146 x 37.0Weight = 37.00 kg/m

275D = 256 mmB = 146.4 mmT = 10.9 mmt = 6.3 mmr = 7.6 mm

5537

108 mm

34.8 mm

433

Loading

span = 7.00 m

Ult. load = 4.81 kN/mService load = 3.20 kN/mBM = 29.43 kNmSF = 16.82 kN

Shear

N/mm2

K2

K3

K5

K8

K36

N/mm2

Section is Satisfied for Shear.

wL4

Kwl2

N/mm2

Section is Satisfied for deflection.

Therefore plywood section is OK for the

floor.

Py = N/mm2

IX = cm4

RX =

RY =

ZX = cm3

Page 48: Form Work Design New

Steel Grade S275

275.00

Cl. 4.2.3. Shear Capacity =266.11 kN

Shear Force = 16.82 kN

Section is Satisfied for Shear.

Section Classificationb/T 6.72Limiting Values

€ 1.00

9 € 9.0010 € 10.0015 € 15.00

Table 12 Section is Class 1 Plastic

Moment

Low Shear

Cl.4.2.5

S=

178189.56

49002128.44 Nmm49.00 kNm

Bending Moment = 29.43 kNm

Section is Satisfied for Bending.

Deflection

Table 8 Allowable Deflection = 19.44 mmActual Deflection = 13.24 mm

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the floor.

6.0 Design for I sections (Primary Members)BS 5950-1 : 2000

Use 254x 146 x 43.0 kg/m section

Design Load 26.58 kN/mSpan 3.08 m

Section 254 x 146 x 43.0Weight = 43.00 kg/m

275D = 259.6 mmB = 147.3 mmT = 12.7 mmt = 7.2 mmr = 7.6 mm

6544

109 mm

35.2 mm

Design Strength (Py) N/mm2

.6 x Py x Av

Section is Satisfied for Shear.

Section is Class 1 Plastic

Moment Capacity (Mc )= Py x S

btf ( d - tf ) + 0.25tw ( d - 2tf )2

mm3

Mc =

Section is Satisfied for Bending.

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the

floor.

Py = N/mm2

IX = cm4

RX =

RY =

Page 49: Form Work Design New

504

Loading

span = 3.08 m

Ult. load = 26.58 kN/mService load = 17.72 kN/mBM = 31.52 kNmSF = 40.93 kN

Shear

Steel Grade S275

275.00

Cl. 4.2.3. Shear Capacity =308.40 kN

Shear Force = 40.93 kN

Section is Satisfied for Shear.

MomentSection Classificationb/T 5.80

Limiting Values

€ 1.00

9 € 9.0010 € 10.0015 € 15.00

Table 12 Section is Class 1 Plastic

Section Classificationd/t 32.53

Limiting Values

€ 1.00

80 € 80.00100 € 100.00120 € 120.00

Table 12 Section is Class 1 Plastic

Moment

Low Shear

Cl.4.2.5

S=

207207.14

56981964.14 Nmm56.98 kNm

Bending Moment = 31.52 kNm

Section is Satisfied for Bending.

Lateral Torsional Buckling

Actual value =

0.93

29.15 kNm

Table 13 Effective Length Multiple Factor = 0.70

ZX = cm3

Design Strength (Py) N/mm2

.6 x Py x Av

Section is Satisfied for Shear.

Section is Class 1 Plastic

Section is Class 1 Plastic

Moment Capacity (Mc )= Py x S

btf ( d - tf ) + 0.25tw ( d - 2tf )2

mm3

Mc =

Section is Satisfied for Bending.

mLT x M

mLT =

Both Flanges fully restrained against rotaion on plan.

Effective Length Multiple Factor = 0.70

Page 50: Form Work Design New

Cl. 4.3.6.7. Slenderness ratios (λ) =

19.78

61.25Critical Slenderness ratio = 61.25

Cl. 4.3.6.7.

Cl. 4.3.6.8. u = 0.90Cl. 4.3.6.8. x = 20.44Cl. 4.3.6.7. ν = 1

0.91

λ = 61.25

Cl. 4.3.6.9. 1.00

50.24

275.00

Table 16 228.38

207207.14

47321138.34 Nmm47.32 kNm

Section is Satisfied for Lateral torsional buckling.

DeflectionAllowable Deflection 8.56 mmActual Deflection = 2.32 mm

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the floorUse 254x 146 x 43.0 kg/m section

7.0 Props

Slab thickness = 1.05 m

Concrete density = 24.00

Wt. per unit meter = 25.20

Safe working load of a steel prop = 1900.00 kg18.64 kN

Then load transfer from Slab = 25.20 kN

Therefore spacing of props = 0.74 m

Provide a space of 1.6m everywhere except for special locations.

LE

rx

LE

ry

λLT = uνλ√βW

[1 + 0.05 (λ/x)2]0.25

βW =

λLT =

Py = N/mm2

Pb = N/mm2

Sx = mm3

Mb = Pb x Sx

Section is Satisfied for Lateral torsional

buckling.

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the

floor

Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.

kN/m3

kN/m2

Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.

Consider a 1 m2

Provide a space of 1.6m everywhere except for special

locations.

Page 51: Form Work Design New

Punching Shear check

Width of the Support = 200.00 mmUltimate design load = 18.64 kN

Depth of the Slab = 85.00 mm

Shear Stress (v) = F4 x ( 3d + c) x d

0.48

Considering nominal steel is used,

0.45

Previous calculations

for slabs

N/mm2

vc = N/mm2

Therefore need additional timber sections having a width of 200mm to distribute the load through-out the slab.

Page 52: Form Work Design New

job …………………………..job no ……………………….date …………………………..page CALCULATION

SHEET

Page 53: Form Work Design New

job ………………………….. Greenpathjob no ………………………. 3date ………………………….. 20/4/2012

ofpages

Page 54: Form Work Design New

Sanken Construction (Pvt) Ltd. Record No:SL/DD/CLS/11

Design Office Revision No.00

Design of the formwork System

Subject Mezzanine Floor Job Toyota WattalaJob no 001

ComputedUmesh Date 4/20/2023Checked Peiris Page

Reference Calculation Output

1.0 Information

Slab weight 0 mm

Concrete Density 24

Concrete Grade

2.0 LoadingsVinyl Tile Dead (Ceiling) 0.00

Services 0.5

Dead Load 0.50

Imposed Load 4

3.0 Combinations

Servisibility Limit State 4.50 4.50 kN/m2

Ultimate Limit State 7.10 7.10 kN/m2

4.0 Timber design for Plywood Sections

Plywood thickness 29 mm

Support Spacing 0.6 m4.50 kN/m

Density 783

Elastic Modulous 1250

I 2032416.666667

Self weight 0.22Safety factors4.1 Safety factor for Loading 1.25

Effective SpanClear Span+ 50mm for solid rectangular SectionsBredth 600 mm

Depth 29 mm

Consider Covered Building (Dry Exposure)

1

Effective Bredth 600 mm

Effective Depth 29 mm

BendingBS 5268 : Part 2-1996

Table 1.3 1.00 Covered Building

Table 1.4 1.00 Long Term

Cl. 2.10.5. 1.00

Cl. 2.10.6. 1.17

Cl. 2.9. 1.10

Built up Sectio 1.00Design Load 5.90 kN/m

Applied Moment 0.27 kNm

Applied Bending Stress = M x y

I

1.90

Allowable Bending Strength 6.40

Section is Satisfied for bending.

CALCULATIO

N SHEET

kN/m3

N/mm2

kN/m2

kN/m2

kN/m2

kN/m2

kN/m2

kN/m2

Uniformly Distributed Load -w (1 m )

kg/m3

N/mm2

mm4

kN/m2

K1

K2

K3

K6

K7

K8

K36

N/mm2

N/mm2

Section is Satisfied for bending.

Page 55: Form Work Design New

ShearApplied Shear Stress = 1.5F Cut Half

A

0.18

Safety Factors

Table 1.3 1.00

Table 1.4 1.00

Cl. 2.10.4. 1.00

Cl. 2.9. 1.10

Built up Sectio 1.00

Allowable Shear Stress 1.74

Section is Satisfied for Shear.

DeflectionAdmissible deflection = .003XSpan

1.80 mmActual deflection = Bending deflection + Shear Deflection

Bending Deflection =185EI

1.63 mm

Shear Deflection = 8AG

Shear Modulus 2500.0440 mm

Shear deflection should be conssidered

Actual deflection 1.67 mm

Section is Satisfied for deflection.

Therefore plywood section is OK for the floor.

5.0 Design for GI pipes (Secondary Members-2)BS 5950-1 : 2000

Use 254x 146 x 37.0 kg/m section

Design Load 4.81 kN/mSpan 7.00 mSupport spacing 0.60 m

Section 254 x 146 x 37.0Weight = 37.00 kg/m

275D = 256 mmB = 146.4 mmT = 10.9 mmt = 6.3 mmr = 7.6 mm

5537

108 mm

34.8 mm

433

Loading

span = 7.00 m

Ult. load = 4.81 kN/mService load = 3.20 kN/mBM = 29.43 kNmSF = 16.82 kN

Shear

N/mm2

K2

K3

K5

K8

K36

N/mm2

Section is Satisfied for Shear.

wL4

Kwl2

N/mm2

Section is Satisfied for deflection.

Therefore plywood section is OK for the

floor.

Py = N/mm2

IX = cm4

RX =

RY =

ZX = cm3

Page 56: Form Work Design New

Steel Grade S275

275.00

Cl. 4.2.3. Shear Capacity =266.11 kN

Shear Force = 16.82 kN

Section is Satisfied for Shear.

Section Classificationb/T 6.72Limiting Values

€ 1.00

9 € 9.0010 € 10.0015 € 15.00

Table 12 Section is Class 1 Plastic

Moment

Low Shear

Cl.4.2.5

S=

178189.56

49002128.44 Nmm49.00 kNm

Bending Moment = 29.43 kNm

Section is Satisfied for Bending.

Deflection

Table 8 Allowable Deflection = 19.44 mmActual Deflection = 13.24 mm

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the floor.

6.0 Design for I sections (Primary Members)BS 5950-1 : 2000

Use 254x 146 x 43.0 kg/m section

Design Load 4.81 kN/mSpan 7.00 m

Section 254 x 146 x 43.0Weight = 37.00 kg/m

275D = 256 mmB = 146.4 mmT = 10.9 mmt = 6.3 mmr = 7.6 mm

5537

108 mm

34.8 mm

Design Strength (Py) N/mm2

.6 x Py x Av

Section is Satisfied for Shear.

Section is Class 1 Plastic

Moment Capacity (Mc )= Py x S

btf ( d - tf ) + 0.25tw ( d - 2tf )2

mm3

Mc =

Section is Satisfied for Bending.

Section is Satisfied for Deflection.

Therefore G.I. section is OK for the

floor.

Py = N/mm2

IX = cm4

RX =

RY =

Page 57: Form Work Design New

433

Loading

span = 7.00 m

Ult. load = 4.81 kN/mService load = 3.21 kN/mBM = 29.46 kNmSF = 16.83 kN

Shear

Steel Grade S275

275.00

Cl. 4.2.3. Shear Capacity =266.11 kN

Shear Force = 16.83 kN

Section is Satisfied for Shear.

MomentSection Classificationb/T 6.72

Limiting Values

€ 1.00

9 € 9.0010 € 10.0015 € 15.00

Table 12 Section is Class 1 Plastic

Section Classificationd/t 37.17

Limiting Values

€ 1.00

80 € 80.00100 € 100.00120 € 120.00

Table 12 Section is Class 1 Plastic

Moment

Low Shear

Cl.4.2.5

S=

178189.56

49002128.44 Nmm49.00 kNm

Bending Moment = 29.46 kNm

Section is Satisfied for Bending.

Lateral Torsional Buckling

Actual value =

0.93

27.25 kNm

Table 13 Effective Length Multiple Factor = 0.70

ZX = cm3

Design Strength (Py) N/mm2

.6 x Py x Av

Section is Satisfied for Shear.

Section is Class 1 Plastic

Section is Class 1 Plastic

Moment Capacity (Mc )= Py x S

btf ( d - tf ) + 0.25tw ( d - 2tf )2

mm3

Mc =

Section is Satisfied for Bending.

mLT x M

mLT =

Both Flanges fully restrained against rotaion on plan.

Effective Length Multiple Factor = 0.70

Page 58: Form Work Design New

Cl. 4.3.6.7. Slenderness ratios (λ) =

45.37

140.80Critical Slenderness ratio = 140.80

Cl. 4.3.6.7.

Cl. 4.3.6.8. u = 0.90Cl. 4.3.6.8. x = 23.49Cl. 4.3.6.7. ν = 1

0.77

λ = 140.80

Cl. 4.3.6.9. 1.00

97.99

275.00

Table 16 228.38

178189.56

40694218.49 Nmm40.69 kNm

Section is Satisfied for Lateral torsional buckling.

DeflectionAllowable Deflection 19.44 mmActual Deflection = 13.25 mm

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the floorUse 254x 146 x 43.0 kg/m section

7.0 Props

Slab thickness = 1.05 m

Concrete density = 24.00

Wt. per unit meter = 25.20

Safe working load of a steel prop = 1900.00 kg18.64 kN

Then load transfer from Slab = 25.20 kN

Therefore spacing of props = 0.74 m

Provide a space of 1.6m everywhere except for special locations.

LE

rx

LE

ry

λLT = uνλ√βW

[1 + 0.05 (λ/x)2]0.25

βW =

λLT =

Py = N/mm2

Pb = N/mm2

Sx = mm3

Mb = Pb x Sx

Section is Satisfied for Lateral torsional

buckling.

Section is Satisfied for Deflection.

Hence the selected I - section is ok for the

floor

Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.

kN/m3

kN/m2

Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.

Consider a 1 m2

Provide a space of 1.6m everywhere except for special

locations.

Page 59: Form Work Design New

Punching Shear check

Width of the Support = 200.00 mmUltimate design load = 18.64 kN

Depth of the Slab = 85.00 mm

Shear Stress (v) = F4 x ( 3d + c) x d

0.48

Considering nominal steel is used,

0.45

Previous calculations

for slabs

N/mm2

vc = N/mm2

Therefore need additional timber sections having a width of 200mm to distribute the load through-out the slab.

Page 60: Form Work Design New

job …………………………..job no ……………………….date …………………………..page CALCULATION

SHEET

Page 61: Form Work Design New

job ………………………….. Greenpathjob no ………………………. 3date ………………………….. 20/4/2012

ofpages