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Form work design new spreadsheets can be used to analyze formwork for any structure
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subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….
computed PP date …… 9/10/2009
checked ………………………….. page 1 ofpages
REF CALCULATION OUTPUT
DESIGN OF FORM WORK FOR SLAB BOTTOM project : pottuvil
1.0 slab thickness 175 mm
loading
DL sw :- 4.20
IL 1.50
ser. load :- 5.70
ult. load :- 8.28
2.0 Timber design (ply wood)
use 15 mm tk plywood
SF 1.25
spacing 0.38 m
udl -w 2.17 kN/m
sw- kN/m 0.12 density 783
design w 2.28 kN/m E 6300
width-b 1000 mm I 96000
depth-d 15 mm
1020 mm
15.3 mm
M 0.03 kNm
2.43
45.00 section is satisfactory
Deflection
deflec- permissible 2.11 mm
deflec- actual 0.54 mm section is satisfactory
3.0 Design of secondary members
use 25x50 mm timber section
design load 2.28 kN/m
span 0.300 m
BM = 0.03 kNm
SF = 0.34 kN
length - m 0.300 sc8
spacing- m 0.380 m 17.5
sw- kN/m 0.01 sf 2
w - kN/m 2.28 bearing 3.9
design w 2.30 density 1080
b - mm 50 E 10700
d - mm 25
51
25.5
M - kNm 0.03
SF - kN 0.34
kN/m2
kN/m2
kN/m2
kN/m2
kg/m3
N/mm2
mm4
b1
d1
bending stress- pbm N/mm2
bending strength- pbm N/mm2
b1- mm
d1 - mm
subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….
computed PP date …… 9/10/2009
checked ………………………….. page 2 ofpages
REF CALCULATION OUTPUT
4.65 bending is satisfactory 19.635
0.40 shear is satisfactory 2.525
k - factors
m sf bearing
stresses 17.5 2 3.9
k2 0.8 0.9 0.6
k3 1.25 1.25 1.25
k4 1.0 1.0 1.0
k5 1.0 1.0 1.0
k6 1.0 1.0 1.0
k7 1.02 1.02 1.02
k8 1.1 1.1 1.1
19.635 2.525 3.282
deflec- per 0.83 deflection is satisfactory
E 10700
deflec- actu 0.61
Hence the section is 25x50 mm timber section
with 0.380 m spacing.
4.0 Design of primary members
Ref : BS5950 : Part : 1990
use 16 mm dia R/F bars
design load 2.29 kN/m steel p 75.5
span 0.380 m bar wt 0.0152 kN/m
BM = 0.04 kNm
SF = 0.43 kN
shear capacity
275
out side dia. D = 16.00 mm
29.87 kN
SF = 0.43 kN
Section is satisfactory
0.11 kNm
BM = 0.04 kNm
Section is satisfactory
pbm - N/mm2
psf - N/mm2
kN/m3
Check for shear cl: 4.2.3
design strength Py = N/mm2
Pv =
Moment capacity cl:4.2.5
MC =
subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….
computed PP date …… 9/10/2009
checked ………………………….. page 3 ofpages
REF CALCULATION OUTPUT
per. def. = 1.1 mm
actual def. = 0.67 mm section is satisfactory
Hence the section is 16 mm dia R/F bars
with 0.300 m spacing.
5.0 Design of secondary members Ref : BS5950 : Part : 1990
use 50 mm dia medium duty GI pipes
design load 2.90 kN/m
span 1.020 m
BM = 0.38 kNm
SF = 1.48 kN
shear capacity
275
out side dia. D = 59.80 mm
thickness t = 2.2 mm
in side dia. d = 55.40 mm
39.43 kN
SF = 1.48 kN
Section is satisfactory
D/t = 27.18
40 57.0 80
plastic
1.52 kNm
BM = 0.38 kNm
Section is satisfactory
per. def. = 2.8 mm
actual def. = 0.86 mm section is satisfactory
Hence the section is 50 mm dia medium duty GI pipes
with 0.380 m spacing.
Deflection cl:2.5.1
Check for shear cl: 4.2.3
design strength Py = N/mm2
Pv =
Section classification cl: 3.5.2
Moment capacity cl:4.2.5
MC =
Deflection cl:2.5.1
subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….
computed PP date …… 9/10/2009
checked ………………………….. page 4 ofpages
REF CALCULATION OUTPUT
6.0 Design of primary members
FOR JACK SUPPORTS
use 100x100 mm timber section
design load 6.22 kN/m
span 1.600 m
BM = 1.99 kNm
SF = 4.97 kN
length - m 1.600 sc8
spacing- m 1.020 m 17.5
sw- kN/m 0.16 sf 2
w - kN/m 6.22 bearing 3.9
design w 6.38 density 1080
b - mm 100 E 10700
d - mm 150
102
153
M - kNm 1.99
SF - kN 4.97
5.00 bending is satisfactory 19.635
0.48 shear is satisfactory 2.525
k - factors
m sf bearing
stresses 17.5 2 3.9
k2 0.8 0.9 0.6
k3 1.25 1.25 1.25
k4 1.0 1.0 1.0
k5 1.0 1.0 1.0
k6 1.0 1.0 1.0
k7 1.02 1.02 1.02
k8 1.1 1.1 1.1
19.635 2.525 3.282
deflec- per 4.44 deflection is satisfactory
E 10700
deflec- actu 3.5
Hence the section is 100x100 mm timber section
with 1.020 m spacing.
5.0 Jacks should be provided at 1.020 m spacing.
Load on Jack :- 9.9 kN
b1- mm
d1 - mm
pbm - N/mm2
psf - N/mm2
subject FORMWORK DESIGN job ……… POTTUVIL CALCULATION SHEET TOP SLAB job no ……………………….
computed PP date …… 9/10/2009
checked ………………………….. page 5 ofpages
REF CALCULATION OUTPUT
1 Loading
Density of Plywood: 7.83 kN/m3Plywood Thickness: 15 mmLoad Plywood: 0.1 kN/m2Tile: 0.6 kN/m2Services: 0.5 kN/m2
DL: 1.2 kN/m2IL: 4 kN/m2Ser Lo: 5.2 kN/m2Ul.Load: 8.1 kN/m2
2 Timber (Plywood) Design
Density: 783 kg/m3
Sanken Construction (Pvt) Ltd. Record No:SL/DD/CLS/11
Design Office Revision No.00
Design of the formwork System
Subject Formwork for Platform Job GreenpathJob no 001
ComputedUmesh Date 4/20/2023Checked Peiris Page
Reference Calculation
1.0 Information
Slab weight mm
Concrete Density
Concrete Grade
Plywood Density 7.83Plywood Thickness 15 mm
2.0 LoadingsPlywood Sweight 0.12
Vinyl Tile Dead 0.60
Dead Load 0
Imposed Load 2
3.0 Combinations
Servisibility Limit State 2
Ultimate Limit State 3.2
4.0 Timber design for Plywood Sections
Plywood thickness 12 mm
Support Spacing 0.2 m2.00 kN/m
Density 783
Elastic Modulous 6300
I 152813.952
Self weight 0.92Safety factors4.1 Safety factor for Loading 1.25
Effective SpanClear Span+ 50mm for solid rectangular SectionsBredth 1000 mm
CALCULATION SHEET
kN/m3
N/mm2
kN/m3
kN/m2
kN/m2
kN/m2
kN/m2
kN/m2
kN/m2
Uniformly Distributed Load -w (1 m )
kg/m3
N/mm2
mm4
kN/m2
Depth 12 mm
Consider wet exposure conditions
1.02
Effective Bredth 1020 mm
Effective Depth 12.24 mm
BendingBS 5268 : Part 2-1996
Table 1.3 0.80
Table 1.4 1.75
Cl. 2.10.5. 1.00
Cl. 2.10.6. 1.17
Cl. 2.9. 1.00
0.70
Design Load 3.65 kN/m
Admissible Moment 0.02 kNm
Admissible Bending Stress = M x y
I
0.91
Allowable Bending Strength 5.16
Section is Satisfied for bending.
ShearAdmissible Shear Stress = 1.5F Cut Half
A
0.45
Safety Factors
Table 1.3 0.80
Table 1.4 1.75
Cl. 2.10.4. 1.00
Cl. 2.9. 1.00
Built up Secti 0.80
Allowable Shear Stress 4.96
Section is Satisfied for Shear.
DeflectionAdmissible deflection = 0.003 x span
0.60 mmActual deflection = Bending deflection + Shear Deflection
K1
K2
K3
K6
K7
K8
Built up Section K36
N/mm2
N/mm2
N/mm2
K2
K3
K5
K8
K36
N/mm2
Bending Deflection =384EI
0.08 mm
Shear Deflection = 8AG
Shear Modulus 450000.0000 mm
Shear deflection can be neglected.
Actual deflection 0.08 mm
Section is Satisfied for deflection.
Therefore plywood section is OK for the floor.
5.0 Design for GI pipes (Secondary Members)BS 5950-1 : 2000
Use 50mm diameter GI pipesWeight of pipe 6.17 kg/m
Self Weight = 0.06 kN/mService Load = 0.58 kN/mDesign Load = 0.81 kN/m
Span = 450 mm
Bending Moment = 0.02 kNmShear Force = 0.18 kN
Shear
Steel Grade S275
275.00
Outer Diameter 60.80 mmInner Diameter 51.80 mmThickness 4.50 mm
Cl. 4.2.3. Shear Capacity =78.80 kN
Shear Force = 0.18 kN
Section is Satisfied for Shear.
Section ClassificationD/t 13.51Limiting Values
5wL4
Kwl2
N/mm2
Design Strength (Py) N/mm2
.6 x Py x Av
€ 1.00
40.00
50.00
140.00
Table 12 Section is Class 1 Plastic
Moment
Low Shear
Cl.4.2.5
S=6
14293.98
3930844.50 Nmm3.93 kNm
Bending Moment = 0.02 kNm
Section is Satisfied for Bending.
Deflection
Table 8 Allowable Deflection = 1.25 mmActual Deflection = 0.01 mm
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the floor.
6.0 Design for I sections (Primary Members)BS 5950-1 : 2000
Use 150 x 100 x 21.1 kg/m section
Design Load 1.81 kN/mSpan 1.60 m
40 €2
50 €2
140 €2
Moment Capacity (Mc )= Py x S
d13-d2
3
mm3
Mc =
Section 150 x 100 x 21.1Weight = 21.10 kg/m
275D = 148 mmB = 100.0 mmT = 9 mmt = 6 mmr = 11 mm
1020
61.7 mm
23.7 mm
138
Loading
Imposed DL= 1.45 kN/mSelf wt. = 0.21 kN/m
span = 1.60 m
Ult. load = 1.81 kN/mService load = 1.66 kN/mBM = 0.58 kNmSF = 1.45 kN
Shear
Steel Grade S275
275.00
Cl. 4.2.3. Shear Capacity =219.78 kN
Shear Force = 1.45 kN
Section is Satisfied for Shear.
MomentSection Classificationb/T 5.56
Limiting Values
€ 1.00
9 € 9.0010 € 10.0015 € 15.00
Table 12 Section is Class 1 Plastic
Py = N/mm2
IX = cm4
RX =
RY =
ZX = cm3
Design Strength (Py) N/mm2
.6 x Py x Av
Section Classificationd/t 21.67
Limiting Values
€ 1.00
80 € 80.00100 € 100.00120 € 120.00
Table 12 Section is Class 1 Plastic
Moment
Low Shear
Cl.4.2.5
S=
54465.87
14978115.49 Nmm14.98 kNm
Bending Moment = 0.58 kNm
Section is Satisfied for Bending.
Lateral Torsional Buckling
Actual value =
1.00
0.58 kNm
Table 13 Effective Length Multiple Factor = 0.70
Cl. 4.3.6.7. Slenderness ratios (λ) =
18.15
47.26Critical Slenderness ratio = 47.26
Cl. 4.3.6.7.
Moment Capacity (Mc )= Py x S
btf ( d - tf ) + 0.25tw ( d - 2t
mm3
Mc =
mLT x M
mLT =
Both Flanges fully restrained against rotaion on plan.
LE
rx
LE
ry
λLT = uνλ√βW
Cl. 4.3.6.8. u = 0.90Cl. 4.3.6.8. x = 16.44Cl. 4.3.6.7. ν = 1
0.92
λ = 47.26
Cl. 4.3.6.9. 1.00
39.01
275.00
Table 16 270.82
54465.87
14750557.07 Nmm14.75 kNm
Section is Satisfied for Lateral torsional buckling.
DeflectionBeams carrying plaster or other brittle finish 4.44 mmOther Beams 8.00 mm
Actual Deflection = 0.07 mm
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the floorUse 150 x 100 x 21.1 kg/m section
7.0 Props
Slab thickness = 0.45 m
Concrete density = 24.00
Wt. per unit meter = 10.80
[1 + 0.05 (λ/x)2]0.25
βW =
λLT =
Py = N/mm2
Pb = N/mm2
Sx = mm3
Mb = Pb x Sx
Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.
kN/m3
kN/m2
Safe working load of a steel prop = 1900.00 kg18.64 kN
Then load transfer from Slab = 10.80 kN
Therefore spacing of props = 1.73 m
Provide a space of 1.6m everywhere except for special locations.
Punching Shear check
Width of the Support = 200.00 mmUltimate design load = 18.64 kNDepth of the Slab = 85.00 mm
Shear Stress (v) = F4 x ( 3d + c) x d
0.48
Considering nominal steel is used,
0.45
8.0 Scafolding System (Opition 02)
Slab thickness = 1.05 m
Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.
Consider a 1 m2
Previous calculations
for slabs
N/mm2
vc = N/mm2
Therefore need additional timber sections having a width of 200mm to distribute the load through-out the slab.
Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.
Concrete density = 24.00
Wt. per unit meter = 25.20
Allowable working load of a scafolding leg = 1500.00 kgSafe working load of a leg = 750.00 kg
7.36 kN
Then load transfer from Slab = 10.21 kNTributorySlab
for a
Therefore spacing of props = 0.72 m
Provide a space of .9m everywhere except for special locations.This is considering scafoldingarrangements.
Punching Shear check
Width of the Support = 200.00 mmUltimate design load = 7.36 kNDepth of the Slab = 85.00 mm
Shear Stress (v) = F4 x ( 3d + c) x d
0.19
Considering nominal steel is used,
0.45
kN/m3
kN/m2
Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.
Consider a 0.45 x 0.90 m2 area
Previous calculations
for slabs
N/mm2
vc = N/mm2
Therefore no need additional timber sections at the bottom expept 200 mm *200 mm support.
Load transfer to 8th floor = (10.8-2.5)
8.3
Then load transfer from Slab = 6.72 kNTributorySlab
for a
Therefore spacing of props = 1.09 m
Load transfer to 7th floor = (8.3-2.5)
5.8
Then load transfer from Slab = 4.70 kNTributorySlab
for a
Therefore spacing of props = 1.57 m
Load transfer to 6th floor = (5.8-2.5)
3.3
Then load transfer from Slab = 2.67 kNTributorySlab
for a
kN/m2
kN/m2
Consider a 0.45 x 1.80 m2 area
Provide a space of 0.9m everywhere except for special locations. Since the load from 0.45*1.8 m2 cannot taken by the arrangement
kN/m2
kN/m2
Consider a 0.45 x 1.80 m2 area
Provide a space of 0.9m everywhere except for special locations. Since the load from 0.45*1.8 m2 cannot taken by the arrangement
kN/m2
kN/m2
Consider a 0.45 x 1.80 m2 area
Therefore spacing of props = 2.75 m
Provide a space of 1.8m everywhere except for special locations.
Load transfer to 6th floor = (3.3-2.5)
0.8
Then load transfer from Slab = 0.65 kNTributorySlab
for a
Therefore spacing of props = 11.35 m
Provide a space of 1.8m everywhere except for special locations.
DESIGNED BY :-
Chinthana BandaraBSc. Eng. (Hons.), AMIE(SL)Designs DepartmantSanken Construction (Pvt) Ltd.
CHECKED BY :-
P Prasantha PeirisBSc. Eng. (Hons.), CEng., MIE(SL),MSSE(SL)PG Dip in Struct. Eng. Design.Designs Departmant
Sanken Construction (Pvt) Ltd.
17/08/2012
Since 6th floor was designed to a imposed load of 10 kN/m2 minimum no need to support the structure beyond Panel 1,2,3 and 4.
kN/m2
kN/m2
Consider a 0.45 x 1.80 m2 area
Record No:SL/DD/CLS/11
Revision No.00
Output
2 kN/m2
3.2 kN/m2
Section is Satisfied for bending.
Section is Satisfied for Shear.
Section is Satisfied for deflection.
Therefore plywood section is OK for the
floor.
Section is Satisfied for Shear.
Section is Class 1 Plastic
Section is Satisfied for Bending.
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the
floor.
Section is Satisfied for Shear.
Section is Class 1 Plastic
Section is Class 1 Plastic
) + 0.25tw ( d - 2tf )2
Section is Satisfied for Bending.
Both Flanges fully restrained against rotaion on plan.
Effective Length Multiple Factor =
0.70
Section is Satisfied for Lateral torsional
buckling.
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the
floor
Since beams are taking the load from the slab above, only the weight of 450 mm thick
DESIGNED BY :-
Chinthana BandaraBSc. Eng. (Hons.)Designs Departmant
was considered on floors below except in level
Provide a space of 1.6m everywhere except for special
locations.
Therefore need additional timber sections having a width of 200mm to distribute the load
Since beams are taking the load from the slab above, only the weight of 450 mm thick
Sanken Construction (Pvt) Ltd.
CHECKED BY :-
P Prasantha PeirisBSc. Eng. (Hons.), CEng., MIE(SL),MSSE(SL)PG Dip in Struct. Eng. Design.Designs Departmant
Sanken Construction (Pvt) Ltd.
4/20/2023Tributory
panelsleg
was considered on floors below except in level
Provide a space of .9m everywhere except for special
locations.
Therefore no need additional timber sections at the bottom expept 200 mm *200 mm
Tributorypanelsleg
Tributorypanelsleg
Tributorypanelsleg
Provide a space of 0.9m everywhere except for special locations. Since the load from
Provide a space of 0.9m everywhere except for special locations. Since the load from
Provide a space of 1.8m everywhere except for special locations.
Tributorypanelsleg
Provide a space of 1.8m everywhere except for special locations.
Since 6th floor was designed to a imposed load of 10 kN/m2 minimum no need to support
Sanken Construction (Pvt) Ltd. Record No:SL/DD/CLS/11
Design Office Revision No.00
Design of the formwork System
Subject Formwork for transfer floor at Greenpath Job Katunayaka AirportJob no 001
ComputedUmesh Date 4/20/2023Checked Peiris Page
Reference Calculation Output
1.0 Information
Slab weight 0 mm
Concrete Density 24
Concrete Grade
2.0 LoadingsVinyl Tile Dead 0.60
Services 0.5
Dead Load 1.10
Imposed Load 5
3.0 Combinations
Servisibility Limit State 6.10 6.10
Ultimate Limit State 9.54 9.54
4.0 Timber design for Plywood Sections
Plywood thickness 15 mm
Support Spacing 0.35 m6.10 kN/m
Density 783
Elastic Modulous 6300
I 298464.75
Self weight 0.12Safety factors4.1 Safety factor for Loading 1.25
Effective SpanClear Span+ 50mm for solid rectangular SectionsBredth 1000 mm
Depth 15 mm
Consider Covered Building (Wet Exposure)
1.02
Effective Bredth 1020 mm
Effective Depth 15.3 mm
BendingBS 5268 : Part 2-1996
Table 1.3 0.80
Table 1.4 1.25
Cl. 2.10.5. 1.00
Cl. 2.10.6. 1.17
Cl. 2.9. 1.10
Built up Sectio 0.80Design Load 7.77 kN/m
Applied Moment 0.12 kNm
Applied Bending Stress = M x y
I
CALCULATIO
N SHEET
kN/m3
N/mm2
kN/m2
kN/m2
kN/m2
kN/m2
kN/m2
kN/m2
Uniformly Distributed Load -w (1 m )
kg/m3
N/mm2
mm4
kN/m2
K1
K2
K3
K6
K7
K8
K36
2.82
Allowable Bending Strength 4.63
Section is Satisfied for bending.
ShearApplied Shear Stress = 1.5F Cut Half
A
0.27
Safety Factors
Table 1.3 0.80
Table 1.4 1.25
Cl. 2.10.4. 1.00
Cl. 2.9. 1.00
Built up Sectio 0.80
Allowable Shear Stress 3.54
Section is Satisfied for Shear.
DeflectionAdmissible deflection = .003XSpan
1.05 mmActual deflection = Bending deflection + Shear Deflection
Bending Deflection =384EI
0.81 mm
Shear Deflection = 8AG
Shear Modulus 450000.0002 mm
Shear deflection can be neglected.
Actual deflection 0.81 mm
Section is Satisfied for deflection.
Therefore plywood section is OK for the floor.
5.0 Design for GI pipes (Secondary Members)BS 5950-1 : 2000
Use 50mm diameter GI pipesWeight of pipe 5.1 kg/m
Self Weight = 0.05 kN/mTotal Service Load = 2.23 kN/mDesign Load (Service*1.5) = 3.34 kN/m
Span = 1200 mm
Bending Moment = 0.60 kNmShear Force = 2.00 kN
Shear
Steel Grade S275
275.00
Outer Diameter 60.80 mmInner Diameter 53.50 mmThickness 3.65 mm
Cl. 4.2.3. Shear Capacity =
N/mm2
N/mm2
Section is Satisfied for bending.
N/mm2
K2
K3
K5
K8
K36
N/mm2
Section is Satisfied for Shear.
5wL4
Kwl2
N/mm2
Section is Satisfied for deflection.
Therefore plywood section is OK for the
floor.
Design Strength (Py) N/mm2
.6 x Py x Av
64.88 kNShear Force = 2.00 kN
Section is Satisfied for Shear.
Section ClassificationD/t 16.66Limiting Values
€ 1.00
40.00
50.00
140.00
Table 12 Section is Class 1 Plastic
Moment
Low Shear
Cl.4.2.5
S=6
11937.56
3282827.95 Nmm3.28 kNm
Bending Moment = 0.60 kNm
Section is Satisfied for Bending.
Deflection
Table 8 Allowable Deflection = 3.33 mmActual Deflection = 1.64 mm
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the floor.
6.0 Design for I sections (Primary Members)BS 5950-1 : 2000
Use 150 x 75 x 14.0 kg/m section
Design Load 11.44 kN/mSpan 1.60 m
Section 150 x 75 x 14.0Weight = 14.00 kg/m
275D = 150 mmB = 100.0 mmT = 10 mmt = 5 mmr = 7 mm
666
61.1 mm
16.6 mm
Section is Satisfied for Shear.
40 €2
50 €2
140 €2
Section is Class 1 Plastic
Moment Capacity (Mc )= Py x S
d13-d2
3
mm3
Mc =
Section is Satisfied for Bending.
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the
floor.
Py = N/mm2
IX = cm4
RX =
RY =
88.8
Loading
Imposed DL= 9.16 kN/mSelf wt. = 0.14 kN/m
span = 1.60 m
Ult. load = 11.44 kN/mService load = 9.29 kN/mBM = 3.66 kNmSF = 9.16 kN
Shear
Steel Grade S275
275.00
Cl. 4.2.3. Shear Capacity =247.50 kN
Shear Force = 9.16 kN
Section is Satisfied for Shear.
MomentSection Classificationb/T 5.00
Limiting Values
€ 1.00
9 € 9.0010 € 10.0015 € 15.00
Table 12 Section is Class 1 Plastic
Section Classificationd/t 26.00
Limiting Values
€ 1.00
80 € 80.00100 € 100.00120 € 120.00
Table 12 Section is Class 1 Plastic
Moment
Low Shear
Cl.4.2.5
S=
60013.11
16503605.28 Nmm16.50 kNm
Bending Moment = 3.66 kNm
Section is Satisfied for Bending.
Lateral Torsional Buckling
Actual value =
1.00
ZX = cm3
Design Strength (Py) N/mm2
.6 x Py x Av
Section is Satisfied for Shear.
Section is Class 1 Plastic
Section is Class 1 Plastic
Moment Capacity (Mc )= Py x S
btf ( d - tf ) + 0.25tw ( d - 2tf )2
mm3
Mc =
Section is Satisfied for Bending.
mLT x M
mLT =
3.66 kNm
Table 13 Effective Length Multiple Factor = 0.70
Cl. 4.3.6.7. Slenderness ratios (λ) =
18.33
67.47Critical Slenderness ratio = 67.47
Cl. 4.3.6.7.
Cl. 4.3.6.8. u = 0.90Cl. 4.3.6.8. x = 15.00Cl. 4.3.6.7. ν = 1
0.84
λ = 67.47
Cl. 4.3.6.9. 1.00
50.99
275.00
Table 16 228.38
60013.11
13705554.03 Nmm13.71 kNm
Section is Satisfied for Lateral torsional buckling.
DeflectionBeams carrying plaster or other brittle finish 4.44 mmOther Beams 8.00 mm
Actual Deflection = 0.72 mm
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the floorUse 150 x 75 x 14.0 kg/m section
7.0 Props
Slab thickness = 1.05 m
Concrete density = 24.00
Wt. per unit meter = 25.20
Safe working load of a steel prop = 1900.00 kg
Both Flanges fully restrained against rotaion on plan.
Effective Length Multiple Factor = 0.70
LE
rx
LE
ry
λLT = uνλ√βW
[1 + 0.05 (λ/x)2]0.25
βW =
λLT =
Py = N/mm2
Pb = N/mm2
Sx = mm3
Mb = Pb x Sx
Section is Satisfied for Lateral torsional
buckling.
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the
floor
Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.
kN/m3
kN/m2
Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.
18.64 kN
Then load transfer from Slab = 25.20 kN
Therefore spacing of props = 0.74 m
Provide a space of 1.6m everywhere except for special locations.
Punching Shear check
Width of the Support = 200.00 mmUltimate design load = 18.64 kN
Depth of the Slab = 85.00 mm
Shear Stress (v) = F4 x ( 3d + c) x d
0.48
Considering nominal steel is used,
0.45
Consider a 1 m2
Provide a space of 1.6m everywhere except for special
locations.
Previous calculations
for slabs
N/mm2
vc = N/mm2
Therefore need additional timber sections having a width of 200mm to distribute the load through-out the slab.
kN/m2
kN/m2
CALCULATION SHEET
Section is Satisfied for bending.
Section is Satisfied for Shear.
Section is Satisfied for deflection.
Therefore plywood section is OK for the
floor.
Section is Satisfied for Shear.
Section is Class 1 Plastic
Section is Satisfied for Bending.
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the
floor.
Section is Satisfied for Shear.
Section is Class 1 Plastic
Section is Class 1 Plastic
Section is Satisfied for Bending.
Effective Length Multiple Factor = 0.70
Section is Satisfied for Lateral torsional
buckling.
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the
floor
Provide a space of 1.6m everywhere except for special
locations.
job ………………………….. Greenpathjob no ………………………. 3date ………………………….. 20/4/2012page of
pages
Sanken Construction (Pvt) Ltd. Record No:SL/DD/CLS/11
Design Office Revision No.00
Design of the formwork System
Subject Mezzanine Floor Job Toyota WattalaJob no 001
ComputedUmesh Date 4/20/2023Checked Peiris Page
Reference Calculation Output
1.0 Information
Slab weight 0 mm
Concrete Density 24
Concrete Grade
2.0 LoadingsVinyl Tile Dead (Ceiling) 0.00
Services 0.5
Dead Load 0.50
Imposed Load 4
3.0 Combinations
Servisibility Limit State 4.50 4.50 kN/m2
Ultimate Limit State 7.10 7.10 kN/m2
4.0 Timber design for Plywood Sections
Plywood thickness 29 mm
Support Spacing 0.6 m4.50 kN/m
Density 783
Elastic Modulous 1250
I 2032416.666667
Self weight 0.22Safety factors4.1 Safety factor for Loading 1.25
Effective SpanClear Span+ 50mm for solid rectangular SectionsBredth 600 mm
Depth 29 mm
Consider Covered Building (Dry Exposure)
1
Effective Bredth 600 mm
Effective Depth 29 mm
BendingBS 5268 : Part 2-1996
Table 1.3 1.00 Covered Building
Table 1.4 1.00 Long Term
Cl. 2.10.5. 1.00
Cl. 2.10.6. 1.17
Cl. 2.9. 1.10
Built up Sectio 1.00Design Load 5.90 kN/m
Applied Moment 0.27 kNm
Applied Bending Stress = M x y
I
1.90
Allowable Bending Strength 6.40
Section is Satisfied for bending.
CALCULATIO
N SHEET
kN/m3
N/mm2
kN/m2
kN/m2
kN/m2
kN/m2
kN/m2
kN/m2
Uniformly Distributed Load -w (1 m )
kg/m3
N/mm2
mm4
kN/m2
K1
K2
K3
K6
K7
K8
K36
N/mm2
N/mm2
Section is Satisfied for bending.
ShearApplied Shear Stress = 1.5F Cut Half
A
0.18
Safety Factors
Table 1.3 1.00
Table 1.4 1.00
Cl. 2.10.4. 1.00
Cl. 2.9. 1.10
Built up Sectio 1.00
Allowable Shear Stress 1.74
Section is Satisfied for Shear.
DeflectionAdmissible deflection = .003XSpan
1.80 mmActual deflection = Bending deflection + Shear Deflection
Bending Deflection =185EI
1.63 mm
Shear Deflection = 8AG
Shear Modulus 2500.0440 mm
Shear deflection should be conssidered
Actual deflection 1.67 mm
Section is Satisfied for deflection.
Therefore plywood section is OK for the floor.
5.0 Design for GI pipes (Secondary Members-2)BS 5950-1 : 2000
Use 254x 146 x 37.0 kg/m section
Design Load 4.81 kN/mSpan 7.00 mSupport spacing 0.60 m
Section 254 x 146 x 37.0Weight = 37.00 kg/m
275D = 256 mmB = 146.4 mmT = 10.9 mmt = 6.3 mmr = 7.6 mm
5537
108 mm
34.8 mm
433
Loading
span = 7.00 m
Ult. load = 4.81 kN/mService load = 3.20 kN/mBM = 29.43 kNmSF = 16.82 kN
Shear
N/mm2
K2
K3
K5
K8
K36
N/mm2
Section is Satisfied for Shear.
wL4
Kwl2
N/mm2
Section is Satisfied for deflection.
Therefore plywood section is OK for the
floor.
Py = N/mm2
IX = cm4
RX =
RY =
ZX = cm3
Steel Grade S275
275.00
Cl. 4.2.3. Shear Capacity =266.11 kN
Shear Force = 16.82 kN
Section is Satisfied for Shear.
Section Classificationb/T 6.72Limiting Values
€ 1.00
9 € 9.0010 € 10.0015 € 15.00
Table 12 Section is Class 1 Plastic
Moment
Low Shear
Cl.4.2.5
S=
178189.56
49002128.44 Nmm49.00 kNm
Bending Moment = 29.43 kNm
Section is Satisfied for Bending.
Deflection
Table 8 Allowable Deflection = 19.44 mmActual Deflection = 13.24 mm
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the floor.
6.0 Design for I sections (Primary Members)BS 5950-1 : 2000
Use 254x 146 x 43.0 kg/m section
Design Load 26.58 kN/mSpan 3.08 m
Section 254 x 146 x 43.0Weight = 43.00 kg/m
275D = 259.6 mmB = 147.3 mmT = 12.7 mmt = 7.2 mmr = 7.6 mm
6544
109 mm
35.2 mm
Design Strength (Py) N/mm2
.6 x Py x Av
Section is Satisfied for Shear.
Section is Class 1 Plastic
Moment Capacity (Mc )= Py x S
btf ( d - tf ) + 0.25tw ( d - 2tf )2
mm3
Mc =
Section is Satisfied for Bending.
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the
floor.
Py = N/mm2
IX = cm4
RX =
RY =
504
Loading
span = 3.08 m
Ult. load = 26.58 kN/mService load = 17.72 kN/mBM = 31.52 kNmSF = 40.93 kN
Shear
Steel Grade S275
275.00
Cl. 4.2.3. Shear Capacity =308.40 kN
Shear Force = 40.93 kN
Section is Satisfied for Shear.
MomentSection Classificationb/T 5.80
Limiting Values
€ 1.00
9 € 9.0010 € 10.0015 € 15.00
Table 12 Section is Class 1 Plastic
Section Classificationd/t 32.53
Limiting Values
€ 1.00
80 € 80.00100 € 100.00120 € 120.00
Table 12 Section is Class 1 Plastic
Moment
Low Shear
Cl.4.2.5
S=
207207.14
56981964.14 Nmm56.98 kNm
Bending Moment = 31.52 kNm
Section is Satisfied for Bending.
Lateral Torsional Buckling
Actual value =
0.93
29.15 kNm
Table 13 Effective Length Multiple Factor = 0.70
ZX = cm3
Design Strength (Py) N/mm2
.6 x Py x Av
Section is Satisfied for Shear.
Section is Class 1 Plastic
Section is Class 1 Plastic
Moment Capacity (Mc )= Py x S
btf ( d - tf ) + 0.25tw ( d - 2tf )2
mm3
Mc =
Section is Satisfied for Bending.
mLT x M
mLT =
Both Flanges fully restrained against rotaion on plan.
Effective Length Multiple Factor = 0.70
Cl. 4.3.6.7. Slenderness ratios (λ) =
19.78
61.25Critical Slenderness ratio = 61.25
Cl. 4.3.6.7.
Cl. 4.3.6.8. u = 0.90Cl. 4.3.6.8. x = 20.44Cl. 4.3.6.7. ν = 1
0.91
λ = 61.25
Cl. 4.3.6.9. 1.00
50.24
275.00
Table 16 228.38
207207.14
47321138.34 Nmm47.32 kNm
Section is Satisfied for Lateral torsional buckling.
DeflectionAllowable Deflection 8.56 mmActual Deflection = 2.32 mm
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the floorUse 254x 146 x 43.0 kg/m section
7.0 Props
Slab thickness = 1.05 m
Concrete density = 24.00
Wt. per unit meter = 25.20
Safe working load of a steel prop = 1900.00 kg18.64 kN
Then load transfer from Slab = 25.20 kN
Therefore spacing of props = 0.74 m
Provide a space of 1.6m everywhere except for special locations.
LE
rx
LE
ry
λLT = uνλ√βW
[1 + 0.05 (λ/x)2]0.25
βW =
λLT =
Py = N/mm2
Pb = N/mm2
Sx = mm3
Mb = Pb x Sx
Section is Satisfied for Lateral torsional
buckling.
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the
floor
Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.
kN/m3
kN/m2
Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.
Consider a 1 m2
Provide a space of 1.6m everywhere except for special
locations.
Punching Shear check
Width of the Support = 200.00 mmUltimate design load = 18.64 kN
Depth of the Slab = 85.00 mm
Shear Stress (v) = F4 x ( 3d + c) x d
0.48
Considering nominal steel is used,
0.45
Previous calculations
for slabs
N/mm2
vc = N/mm2
Therefore need additional timber sections having a width of 200mm to distribute the load through-out the slab.
job …………………………..job no ……………………….date …………………………..page CALCULATION
SHEET
job ………………………….. Greenpathjob no ………………………. 3date ………………………….. 20/4/2012
ofpages
Sanken Construction (Pvt) Ltd. Record No:SL/DD/CLS/11
Design Office Revision No.00
Design of the formwork System
Subject Mezzanine Floor Job Toyota WattalaJob no 001
ComputedUmesh Date 4/20/2023Checked Peiris Page
Reference Calculation Output
1.0 Information
Slab weight 0 mm
Concrete Density 24
Concrete Grade
2.0 LoadingsVinyl Tile Dead (Ceiling) 0.00
Services 0.5
Dead Load 0.50
Imposed Load 4
3.0 Combinations
Servisibility Limit State 4.50 4.50 kN/m2
Ultimate Limit State 7.10 7.10 kN/m2
4.0 Timber design for Plywood Sections
Plywood thickness 29 mm
Support Spacing 0.6 m4.50 kN/m
Density 783
Elastic Modulous 1250
I 2032416.666667
Self weight 0.22Safety factors4.1 Safety factor for Loading 1.25
Effective SpanClear Span+ 50mm for solid rectangular SectionsBredth 600 mm
Depth 29 mm
Consider Covered Building (Dry Exposure)
1
Effective Bredth 600 mm
Effective Depth 29 mm
BendingBS 5268 : Part 2-1996
Table 1.3 1.00 Covered Building
Table 1.4 1.00 Long Term
Cl. 2.10.5. 1.00
Cl. 2.10.6. 1.17
Cl. 2.9. 1.10
Built up Sectio 1.00Design Load 5.90 kN/m
Applied Moment 0.27 kNm
Applied Bending Stress = M x y
I
1.90
Allowable Bending Strength 6.40
Section is Satisfied for bending.
CALCULATIO
N SHEET
kN/m3
N/mm2
kN/m2
kN/m2
kN/m2
kN/m2
kN/m2
kN/m2
Uniformly Distributed Load -w (1 m )
kg/m3
N/mm2
mm4
kN/m2
K1
K2
K3
K6
K7
K8
K36
N/mm2
N/mm2
Section is Satisfied for bending.
ShearApplied Shear Stress = 1.5F Cut Half
A
0.18
Safety Factors
Table 1.3 1.00
Table 1.4 1.00
Cl. 2.10.4. 1.00
Cl. 2.9. 1.10
Built up Sectio 1.00
Allowable Shear Stress 1.74
Section is Satisfied for Shear.
DeflectionAdmissible deflection = .003XSpan
1.80 mmActual deflection = Bending deflection + Shear Deflection
Bending Deflection =185EI
1.63 mm
Shear Deflection = 8AG
Shear Modulus 2500.0440 mm
Shear deflection should be conssidered
Actual deflection 1.67 mm
Section is Satisfied for deflection.
Therefore plywood section is OK for the floor.
5.0 Design for GI pipes (Secondary Members-2)BS 5950-1 : 2000
Use 254x 146 x 37.0 kg/m section
Design Load 4.81 kN/mSpan 7.00 mSupport spacing 0.60 m
Section 254 x 146 x 37.0Weight = 37.00 kg/m
275D = 256 mmB = 146.4 mmT = 10.9 mmt = 6.3 mmr = 7.6 mm
5537
108 mm
34.8 mm
433
Loading
span = 7.00 m
Ult. load = 4.81 kN/mService load = 3.20 kN/mBM = 29.43 kNmSF = 16.82 kN
Shear
N/mm2
K2
K3
K5
K8
K36
N/mm2
Section is Satisfied for Shear.
wL4
Kwl2
N/mm2
Section is Satisfied for deflection.
Therefore plywood section is OK for the
floor.
Py = N/mm2
IX = cm4
RX =
RY =
ZX = cm3
Steel Grade S275
275.00
Cl. 4.2.3. Shear Capacity =266.11 kN
Shear Force = 16.82 kN
Section is Satisfied for Shear.
Section Classificationb/T 6.72Limiting Values
€ 1.00
9 € 9.0010 € 10.0015 € 15.00
Table 12 Section is Class 1 Plastic
Moment
Low Shear
Cl.4.2.5
S=
178189.56
49002128.44 Nmm49.00 kNm
Bending Moment = 29.43 kNm
Section is Satisfied for Bending.
Deflection
Table 8 Allowable Deflection = 19.44 mmActual Deflection = 13.24 mm
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the floor.
6.0 Design for I sections (Primary Members)BS 5950-1 : 2000
Use 254x 146 x 43.0 kg/m section
Design Load 4.81 kN/mSpan 7.00 m
Section 254 x 146 x 43.0Weight = 37.00 kg/m
275D = 256 mmB = 146.4 mmT = 10.9 mmt = 6.3 mmr = 7.6 mm
5537
108 mm
34.8 mm
Design Strength (Py) N/mm2
.6 x Py x Av
Section is Satisfied for Shear.
Section is Class 1 Plastic
Moment Capacity (Mc )= Py x S
btf ( d - tf ) + 0.25tw ( d - 2tf )2
mm3
Mc =
Section is Satisfied for Bending.
Section is Satisfied for Deflection.
Therefore G.I. section is OK for the
floor.
Py = N/mm2
IX = cm4
RX =
RY =
433
Loading
span = 7.00 m
Ult. load = 4.81 kN/mService load = 3.21 kN/mBM = 29.46 kNmSF = 16.83 kN
Shear
Steel Grade S275
275.00
Cl. 4.2.3. Shear Capacity =266.11 kN
Shear Force = 16.83 kN
Section is Satisfied for Shear.
MomentSection Classificationb/T 6.72
Limiting Values
€ 1.00
9 € 9.0010 € 10.0015 € 15.00
Table 12 Section is Class 1 Plastic
Section Classificationd/t 37.17
Limiting Values
€ 1.00
80 € 80.00100 € 100.00120 € 120.00
Table 12 Section is Class 1 Plastic
Moment
Low Shear
Cl.4.2.5
S=
178189.56
49002128.44 Nmm49.00 kNm
Bending Moment = 29.46 kNm
Section is Satisfied for Bending.
Lateral Torsional Buckling
Actual value =
0.93
27.25 kNm
Table 13 Effective Length Multiple Factor = 0.70
ZX = cm3
Design Strength (Py) N/mm2
.6 x Py x Av
Section is Satisfied for Shear.
Section is Class 1 Plastic
Section is Class 1 Plastic
Moment Capacity (Mc )= Py x S
btf ( d - tf ) + 0.25tw ( d - 2tf )2
mm3
Mc =
Section is Satisfied for Bending.
mLT x M
mLT =
Both Flanges fully restrained against rotaion on plan.
Effective Length Multiple Factor = 0.70
Cl. 4.3.6.7. Slenderness ratios (λ) =
45.37
140.80Critical Slenderness ratio = 140.80
Cl. 4.3.6.7.
Cl. 4.3.6.8. u = 0.90Cl. 4.3.6.8. x = 23.49Cl. 4.3.6.7. ν = 1
0.77
λ = 140.80
Cl. 4.3.6.9. 1.00
97.99
275.00
Table 16 228.38
178189.56
40694218.49 Nmm40.69 kNm
Section is Satisfied for Lateral torsional buckling.
DeflectionAllowable Deflection 19.44 mmActual Deflection = 13.25 mm
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the floorUse 254x 146 x 43.0 kg/m section
7.0 Props
Slab thickness = 1.05 m
Concrete density = 24.00
Wt. per unit meter = 25.20
Safe working load of a steel prop = 1900.00 kg18.64 kN
Then load transfer from Slab = 25.20 kN
Therefore spacing of props = 0.74 m
Provide a space of 1.6m everywhere except for special locations.
LE
rx
LE
ry
λLT = uνλ√βW
[1 + 0.05 (λ/x)2]0.25
βW =
λLT =
Py = N/mm2
Pb = N/mm2
Sx = mm3
Mb = Pb x Sx
Section is Satisfied for Lateral torsional
buckling.
Section is Satisfied for Deflection.
Hence the selected I - section is ok for the
floor
Since beams are taking the load from the slab above, only the weight of 450 mm thick slab should need to be considered.
kN/m3
kN/m2
Since a minimum imposed load of 2 kN/m2 was considered on floors below except in level 6, approximately 5 floors are required for the support.
Consider a 1 m2
Provide a space of 1.6m everywhere except for special
locations.
Punching Shear check
Width of the Support = 200.00 mmUltimate design load = 18.64 kN
Depth of the Slab = 85.00 mm
Shear Stress (v) = F4 x ( 3d + c) x d
0.48
Considering nominal steel is used,
0.45
Previous calculations
for slabs
N/mm2
vc = N/mm2
Therefore need additional timber sections having a width of 200mm to distribute the load through-out the slab.
job …………………………..job no ……………………….date …………………………..page CALCULATION
SHEET
job ………………………….. Greenpathjob no ………………………. 3date ………………………….. 20/4/2012
ofpages