Click here to load reader
Upload
lamnga
View
212
Download
0
Embed Size (px)
Citation preview
Name:_________________________________ Mods:_______________ Partner:________________________________ Date:________________
Lab: ALUMINUM FOIL THICKNESS Purpose: The purpose of this activity is to relate the size of an aluminum atom to the thickness of a piece of aluminum. Procedure:
1. Mass a cylinder of aluminum metal.
2. Measure the volume of the cylinder by displacement
3. Obtain a piece of aluminum foil
4. Measure the length and width of the piece of aluminum foil to the nearest 0.1 cm.
5. Mass the piece of aluminum foil
Data:
A. Mass of metal cylinder B. Volume of water in graduated cylinder C. Volume of water plus metal cylinder D. Volume of metal cylinder (C-B) E. Length of aluminum F. Width of aluminum G. Mass of aluminum foil H. Density of aluminum (A/D) I. Volume of foil (G/H) J. Height of foil (V = L x W x H) K. Moles of aluminum in foil (convert G to moles)
L. Atoms of aluminum foil M. Atoms thick of Aluminum foil
Calculations: 1. Determine the density of aluminum. Record in H.
D = M (A)/V (D)
2. Find the volume of the foil and record it in I. V = M (G)/D (H)
3. Find the height (thickness) of the foil and record it in J. V = l x w x h
Analysis: One aluminum atom is 2.5 x 10-8 cm thick. Find the thickness of the foil in atoms.
Number of height (J) x 1 atom___ Atoms thick = 2.5 x 10-8cm
Calculate the number of moles of aluminum and the total number of atoms of aluminum in your piece of aluminum foil. Conclusion: