Matrix Analysis of Structures, SI Edition Aslam Kassimali

9781111426224

Second Edition

Page

Number

Description of Correction Print

Run

Affected

Inside

front

cover

(left

side)

Replace current table with new one:

1

Inside

front

cover

(right

side)

Replace current table with new one:

1

ix Add “ANSWERS TO SELECTED PROBLEMS (Available on book website

at www.cengagebrain.com)” after “INDEX”

1

159 Replace Fig. 4.22 with new figure

1

215 Add partition lines around “21,600” (row 4, column 4) in equation (1). 1

219 Add partition line between “59.375 kN” and “–33.333 kN·m” in equation

(8).

1

219 For the 2nd matrix for Q2 =, add the following units:

5 kN

1 kN · m

6 kN

2 kN · m

1

220 In Q3, remove partition line between “87.5 kN” and “–66.67 kN·m” 1

226 Fig. 5.19 (i): in PM matrix, change “2” (row 3, column 4) to “0” 1

233 In the last line of Fig. 5.23 (continued), change “2.00E+0” to “0.00E+0”. 1

243 Replace Fig. 5.34 with new figure

1

244 Replace Fig. 5.34 (continued) with new figure

1

248 Under Section 5.7, delete “the publisher’s website for this book

(www.cengage.com/engineering),”

1

275 In the last row for the F2 matrix, add a minus sign so the value becomes “–

692.7 kN · m”

1

302 Fig. 6.17 (c): Move “300 cos θ” and “300 sin θ” labels as shown below

1

303 In matrix R, change

“–101.17 kN” to “–101.18 kN”

“–40.25 kN” to “59.76 kN”

“–137.77 kN · m” to “–71.33 kN · m”

1

326 Replace Fig. 6.25 with new version

1

332 Replace Fig. 6.32 with new version

1

336 In Fig. P6.6, P6.12, etc., change

“E = 10,000 ksi” to “E = 70 GPa”

1

337 In Problem 6.15, in u1 change

“–0.0001287 m” to “–0.001287 m”

1

338 In Fig. P6.39, change “ 2.75 r” to “2.75 m” 1

353 In Fig. 7.3, change

“100 kN” to “90.75 kN”

1

355 Replace Fig. 7.3 (continued) with new version

1

357 In K1 matrix, add partition lines around

720 0

0 260,000

1

358 In K3 matrix, add partition lines around

720 0 3,600

0 260,000 0

3,600 0 18,000

1

358 In the “P” matrix, change

“100” to “90.75”

1

359 In Q1 matrix, change both instances of “89.18 kN” to “89.17 kN”

and both instances of “–89.18 kN” to “–89.17 kN”

1

360 In F2 matrix, change “60.84 kN” to “60.83 kN”,

“–60.84 kN” to “–60.83 kN”, and

“–304.15 kN · m” to “–304.16 kN · m”

1

360 In Q3 matrix, change

“210.86 kN” to “210.83 kN” and

“–210.86 kN” to “–210.83 kN”

1

361 In F3 matrix, change “210.86” to “210.83” and

“–210.86” to “–210.83”

1

372 In Fig. 7.8 (continued) (c) change “432.896” to “432.9” 1

372 In Fig. 7.8 (continued) (d) change “432.896 kN” to “432.9 kN” 1

375 In the Ans following the Q3 matrix, change

“Qa3 = –81.732 k = 81.732 k (T)” to

“Qa3 = –270.56 kN = 270.56 kN (T)”

1

382 On the left-hand side of Fig. 7.10 (continued) (c) change

“–51.69 kN” to “51.69 kN”

1

384 For Q1 matrix, change

“126.20 kN” to “126.20 kN · m”

1

400 In Member 3, change “–3 m” to “–3 mm” 1

406 In S matrix, change

“–260,720” (row 1, column 3) to

“–260,000”

1

407 In Fig. 7.21 (a), change both instances of “20 ft” to “5 m” 1

410 In F2 matrix, bottom row, change

“–10.0516” to “–10.0516 kN · m”

1

415 The last line in problem 7.29 should have “2.5” instead of “25” 1

427 In answer for S matrix, change

“18,881.26” to “17,835.7”,

“4,099.46” to “3,402.5” (two instances),

“126,453.02” to “122,271”, and

“14,050.02” to “13,585.4”

1

429 In Member 2, change

“(0 + 3)2” to “(0 – 3)2”

1

429 In Member 3, change

“(0 + 1.5)2” to “(0 – 1.5)2”

1

430 In matrix after Joint Displacements, change

“18,881.26” to “17,835.7”,

“4,099.46” to “3,402.5” (two instances),

“126,453.02” to “122,271”, and

“14,050.02” to “13,585.4”

1

433 For first 3 Checks, change “≈ 0” to “= 0” 1

433 In the final Check above Section 8.2, add “= 0” 1

486 In Fig. 8.23 (a), change

“A = 14,700…” to “A = 73,500…”,

“Iz = 142…” to “Iz = 710…”,

“Iy = 46.8…” to “Iy = 234…”, and

“J = 3.0…” to “J = 15…”

1

488 Replace Fig. 8.23 (continued) (d) with new version

1

491 In K3 matrix, move partition line one column over to the right as shown

below

1

502 In Fig. 9.1 (a), change

“E = 200 kPa” to “E = 200 GPa”

1

503 In P�∗ matrix, change “50” to “150” and

“–112.5” to “–50”

1

504 In the first matrix set after Joint Displacements, change “15,384” (row 3,

column 3) to “7,692”

1

505 For R matrix, change

“218.844 kN” to “318.8 kN” and

“–212.199 kN · m” to “–149.69 kN · m”

1

505 For Q1 matrix, change

“235.648 kN” to “320.01 kN”,

“280.247 kN” to “72.82 kN”,

“122.234 kN · m” to “126.20 kN · m”,

“32.672 kN” to “–51.69 kN”,

“–146.087 kN” to “61.34 kN”, and

“–91.669 kN · m” to “–87.69 kN · m”

1

512 Replace Fig. 9.5 (continued) (c) with new version

1

512 In Fig. 9.5 (continued) (c) change “185.81” to “185.71” 1, 2

513 For Q1 matrix, change

“52.143 kN” to “4.99 kN”,

“–221.429 kN · m” to “64.248 kN · m”,

“–52.143 kN” to “–4.99 kN”, and

–300.000 kN · m” to “–14.286 kN · m”

1

514 For Q3 matrix, change

“22.143 kN” to “35.01 kN”,

“–121.429 kN · m” to “164.33 kN · m”,

“–22.143 kN” to “–35.01 kN”, and

“–100.000 kN · m” to “185.81 kN · m”

1

514 For R matrix, change

“52.143 kN” to “–4.99 kN”,

“–221.429 kN · m” to “64.248 kN · m”,

“–22.143 kN” to “–35.01 kN”, and

“–121.429 kN · m” to “164.33 kN · m”

1

585 In Fig. 10.5 (continued) (d), change

“6576.49 kN” to “1772.934 kN”,

“0.75 m” to “0.67 m”, and

“–3900.76” to “3900.76”

1

586 In the second to last line of Example 10.1, change

“1772.938” to “1772.934” and

delete “–0.004 kN ≈”

1

586 In the last line of Example 10.1, change “6576.49(0.67)” to “–

6576.49(0.67)”,

“1772.938(1.2)” to “1772.934(1.2)”,

“32663.88(2.0)” to “3266.884(2.0)”, and

“0.001 kN · m” to “–0.001 kN · m”

1

611 Eq. (B.13): change “12” to “4” (x3),

“9” to “3” (x2), and “15” to “5” (x2)

1

611 Eq. (B.14): change “–1,800” to “–600” and “–26,649” to “–8,883” 1

611 Eq. (B.15): change “24” to “8”,

“32” to “10.667” (x2), and

“220.33” to “73.444”

1

611 In Qa, change “227.475” to “–227.475” 1