Model:

I(total ions) = I(H+) + I(HCl+) = A(t) Pm

I(H+) = A(H+) Pn

I(H+)/(I(H+)+I(HCl+)) = (A(H+)/A(t)) P(n-m) = A(H+,t) P(n-m)

ln(I(H+)/(I(H+)+I(HCl+))) = (n-m) ln(P) + ln(A)

HCl, F<-<-X, (1,0), J = 6, mass analysis:

agust, www....hcl/HCl,agust07-/HClFJ6model-210807ak.ppt

pnt

we04a we06a we09a we13a

298440 92022,6 53331,6 30513 27

298063 91446,7 52685,6 29347 28

298110 91485,9 52699,6 29396 H+

298337 91848,7 53166,6 30139

298433 92003,9 53329,9 30462 31

30503,5 32

30691 437

300870 92719,2 53727,5 29609,5 438

299556 91075,4 50176,8 22874

274093 71352 30443 5132,5 HCl+

264725 55268,7 17501,6 -4797,5

287575 74992,1 34539,7 6087

296724 86730,1 46695,4 19527,5 443

298949 90090,2 50727,2 25864 444

298440 92022,6 53331,6 30513 bgr.(H+)

300870 92719,2 53727,5 30691 bgr.(HCl+)

-817 -1305,2 -1444,7 -2717,5 I(H+)

-83598 -86806,7 -92281,3 -110540 I(HCl+)

0,009678 0,014813 0,015414 0,023994 I(H+)/(I(H+)+I(HCl+))

-4,63786 -4,21225 -4,17247 -3,72995 ln(ratio)

0,035 0,06 0,09 0,13 power (after autotracker)

-3,35241 -2,81341 -2,40795 -2,04022 ln(P)

-4.6

-4.4

-4.2

-4.0

-3.8

-3.2 -3.0 -2.8 -2.6 -2.4 -2.2

Coefficient values ± one standard deviation a (inters) = -2.5046 ± 0.341 b(slope) = 0.63445 ± 0.127

ln(I

(H+

)/(I

(H+

)+I(

HC

l+))

)

ln(P)

-4.6

-4.4

-4.2

-4.0

-3.8

-3.2 -3.0 -2.8 -2.6 -2.4 -2.2

Coefficient values ± one standard deviation a = -2.3137 ± 0.128 b = 0.68718 ± 0.0459

ln(I

(H+

)/(I

(H+

)+I(

HC

l+))

)

ln(P)

-4.6

-4.5

-4.4

-4.3

-3.3 -3.2 -3.1 -3.0 -2.9

Coefficient values ± one standard deviation a = -1.9907 ± Inf b = 0.78963 ± Inf

ln(I

(H+

)/(I

(H+

)+I(

HC

l+))

)

ln(P)

-4.6

-4.4

-4.2

-4.0

-3.8

-3.2 -3.0 -2.8 -2.6 -2.4 -2.2

Summary:

ln(P)

ln(I

(H+

)/(I

(H+

)+I(

HC

l+))

)

(n-m) = 0.79

(n-m) = 0.69

(n-m) = 0.63

Conclusion:

Slope is resonably close to the value 1, i.e. (n-m) = 1

as to be expected for the case n = 4 and m = 3