PENGGUNAAN

KALKULATOR

SAINTIFIK

TOPICS:

Standard Form ( Form 4)

Quadratic Expression and Equation. ( Form 4)

Simultaneous Linear Equation ( Form 3)

Matrices ( Form 5 )

Number Bases ( Form 5 )

STANDARD FORM

•TO ROUND OFF THE NUMBER WITH THE GIVEN SIGNIFICANT FIGURE

Round off 70615 correct to three significant figures.

Bundarkan 70615 betul kepada tiga angka bererti

A. 70 600 C. 70 610

B. 70 620 D. 70 700

MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan

70615 = Answer Tekan ENG sehingga kuasa 10 menjadi

00

2. Round off 0.002496 correct to three significant figures.

Bundarkan 0.002496 betul kepada tiga angka bererti

A 0.02 C 00.00249

B 0.03 D 0.00250

MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan

0.002496 = Answer Tekan Shift ENG sehingga kuasa 10

menjadi 00

6.27 EXP ( - ) 4 Answer Tekan Shift ENG

sehingga kuasa 10 menjadi 00

To Convert Standard Form into Single Number

41027.6

A. 0.0000627 C. 62 700

B. 0.000627 D. 6 270 000

1.

5108.1

A. 180000 C. 18000

B. 1800 D. 1800000

1.8 EXP 5 = Answer

2.

Taip soalan 0.0000203 = Answer

Express 0.0000203 in standa Inrd form

1. Express 0.0000203 in standard form

A C

B D

51003.2 71003.2 61003.2 8103.20

Convert Single Number Into Standard Form

State 7560000 in standard form.

A C

B D

5 10 x 7.56-5 10 x 7.56

-6 10 x 7.566 10 x 7.56

MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan

7560000 = Answer

Operational in Standard Form

MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan

6.35 EXP (-) 5 – 3.2 EXP ( - 6) = Answer

65 102.31035.6

A C

B D

51012.3 61012.3

51003.6 61003.6

004.0

1004.3 14

A C

B D

131060.7 141060.7

151060.7 161060.7

MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan

3.04 EXP (14) ÷ 0.04 = Answer

QUADRATIC EQUATION

* FACTORISATION OF QUADRATIC EXPRESSION

MODE 3 X EQN 1 Tekan arrow menghala ke

kanan Degree ? 2 a? 10 = b ? 1 = c ? (-) 2 = Answer

X = 0.4 Tekan a b/c 2 5 = X = - 0.5

Tekan a b/c =

Factorise 210 2 xx

A C

B D

)2)(110( xx)1)(25( xx

)210)(1( xx

)1)(25( xx

1 2

2

1

( x - ) ( x + ) 5

2

2

1

Paper 2 : Solve the quadratic equations:

Selesaikan persamaan kuadratik:

x

xx

2

11123

Answer/Jawapan :

[4 marks/markah]

2x2 + 5x – 12 = 0

( 2x – 3 ) (x + 4) = 0

x = 3 x = -4

2 1 2

Simultaneous Linear Equation.

p - 4q = 8

3p + 2q = 17

MODE 3 X EQN 1 Unknowns ? 2

a1 ? 1= b1 ? (-) 4 = c 1 ? 8 = a 2 ? 3 = b 2 ? 2 =

c 2 ? 17 = Answer x = 6 = y = - 0.5 @ - 2

1

Answer : p = 6 , q = - 2

1

Matrices

(b) Using matrices, calculate the values of x and y that satisfy

the following matrix equation.

2

1

35

24

y

x

MODE 3 X EQN 1 Unknowns ? 2

a1 ? (-) 4 = b1 ? 2 = c 1 ? 1 = a 2 ? ( - ) 5 =

b 2 ? 3 = c 2 ? 2 = x = 0.5 @ = y = 1.5 @ 2

3

Answer : x = , y = 2

3

2

1

2

1

NUMBER BASES ( F 5)

Convert Base 2 to Base 10 and Vice versa

Express as a number in base ten.

2110111

MODE 2 X Base 3 BIN Taip =

DEC Answer 2110111

A 1310 C 5510

B 3110 D 11010

Express 126 as a number in base two.

A 1111102 C 11111102

B 11101102 D 11111112

MODE 2 X Base 3 DEC Taip 126 = BIN Answer

Convert Base 8 to Base 10 and Vice versa

Express 1548 as a number in base ten.

A 80 C 864

B 108 D 1925

MODE 2 X Base 3 OCT Taip 154 = DEC Answer

Express 342810 as a number in base eight.

A 544 C 2742

B 428 D 6544

8

8 8

8

MODE 2 X Base 3 DEC Taip 3428 = OCT Answer

Convert Base 8 to Base 2 and Vice versa

Express 4028 as a number in base two.

A 1100102 C 10000102

B 1100100102 D 1000000102

MODE 2 X Base 3 OCT Taip 402 = BIN Answer

Express 10 110 1012 as a number in base eight.

A 2358 C 2658

B 2648 D 5518

MODE 2 X Base 3 BIN Taip 10110101 =

OCT Answer

Operational in Base Two

100102 + 1112 =

A 111012 C 101012

B 110012 D 100012

MODE 2 X Base 3 BIN Taip 10010 + 111 = Answer

GURU YANG BIASA

MEMBERITAHU

GURU YANG BAIK

MEMBERI PENJELASAN

GURU YANG TERBAIK

GURU YANG BAGUS

MEMBERI TUNJUK AJAR

MEMBERI INSPIRASI

SEKIAN

TERIMA KASIH

USAGE OF SCIENTIFIC

CALCULATOR

SELF PRACTICE

Exercises :

1- Round off 6 284 correct to 2 significant figures.

A 6 200 C 6 290

B 6 280 D 6 300

2- Round off 0.00035118 correct to 3 significant figures.

A 0.000351 C 0.003512

B 0.0003511 D 0.0003521

3- Round off 0.0368 correct to two significant figures.

A. 0.003 C. 0.036

B. 0.04 D. 0.037

4. Express as single number.

A. 0.007564 C. 0.000007564

B. 0.00007564 D. 0.0000007564

5.

A 6 x 10 C 6 x 10

B 6 x 10 D 6 x 10

6. Express 558000 in standard form.

A 5.58 x 10 C 5.58 x 10

B 5.58 x 10 D 5.58 x 10

610564.7

000 000 5

03.0

34

8

9

3

4

5

6

7. Factorise 7x2 + 26x –8

8. Factorise 3x2 – 7x –20

7. Solve equation x2 - 3x + 2 = 2(x - 1)

10 . 2h - 2m = 7

4h + 6m = -1

Answer : h = m =

11. 3 v + 4 w = - 6

v – 2w = 8

Answer : v = w =

12. Using matrices, calculate the value of k dan

m which satisfy the following matrix equation :

=

85

21

m

k

11

1

13. Express 67 as a number in base two.

A 1000111 B 1001011

C 1000011 D 1000010

14. Express 1010111 as a number in base ten

A 86 B 87

C 88 D 89

15. Express 275 as a number in base ten.

A 198 B 187

C 189 D 178

16. Express 157 as a number in base eight.

A 234 B 235 C 236 D 237

17. Express 110102 as a number in base eight.

A 268 B 328

C 1228 D 11018

2

10

2

2 2

2

8

8 888

18. 11101 + 1110

A 100011 B 111001

C 101111 D 101011

19. 110112 – 1012 =

A. 10102 C. 101102

B. 11102 D. 100102

20. 100102 - 11012 =

A. 1012 C. 10112

B. 1112 D. 11112

2 2

2

2

2

2