22
PYTHAGOREAN THEOREM WORD PROBLEMS PYTHAGOREAN THEOREM WORD PROBLEMS OBJECTIVE: Students will solve for missing values using the Pythagorean theorem for word problems OBJECTIVE: Students will solve for missing values using the Pythagorean theorem for word problems

PYTHAGOREAN THEOREM WORD PROBLEMS - mpsri.net · PYTHAGOREAN THEOREM WORD PROBLEMS OBJECTIVE: Students will solve for missing values using the Pythagorean theorem for word problems

Embed Size (px)

Citation preview

PYTHAGOREAN THEOREM WORD PROBLEMS

PYTHAGOREAN THEOREM WORD PROBLEMS

OBJECTIVE: Students will solve for missing values using the

Pythagorean theorem for word problems

OBJECTIVE: Students will solve for missing values using the

Pythagorean theorem for word problems

RECALL THE PYTHAGOREAN THEOREMRECALL THE PYTHAGOREAN THEOREM

� THE PYTHAGOREAN THEOREM STATES THAT FOR ANY RIGHT TRIANGLE:

a2 + b2 = c2

� THE PYTHAGOREAN THEOREM STATES THAT FOR ANY RIGHT TRIANGLE:

a2 + b2 = c2

Warm UpWarm Up� Solve for the missing side in each right

triangle below.� Remember: a2 + b2 = c2

� Solve for the missing side in each right triangle below.� Remember: a2 + b2 = c2

1.)2.)

c3

4

7

2

b

Warm Up ANSWERS Warm Up ANSWERS

� Solve for the missing side in each right triangle below.� Remember: a2 + b2 = c2

� Solve for the missing side in each right triangle below.� Remember: a2 + b2 = c2

1.2.

c3

4

7

2

b

32 + 42 = c2

25 = c2

c = 5

b2 + 22 = 72

b2 + 4 = 49b2 = 45b = √45 = 6.7

WORD PROBLEMSWORD PROBLEMS� Many Pythagorean Theorem Questions are given as

word problems.

STEPS FOR SOLVING PYTHAGOREAN THEOREM WORD PROBLEMS:

Step 1: Circle any important numbers in the problem

Step 2: Draw a picture of the situation.

Step 3: Solve using the Pythagorean theorem (a2 + b2 = c2)

� Many Pythagorean Theorem Questions are given as word problems.

STEPS FOR SOLVING PYTHAGOREAN THEOREM WORD PROBLEMS:

Step 1: Circle any important numbers in the problem

Step 2: Draw a picture of the situation.

Step 3: Solve using the Pythagorean theorem (a2 + b2 = c2)

EXAMPLE 1EXAMPLE 1

� Mr. Blonde is measuring his TV. The TV is 12 inches wide and 9 inches tall. What is the length of the diagonal on the TV?

� Mr. Blonde is measuring his TV. The TV is 12 inches wide and 9 inches tall. What is the length of the diagonal on the TV?

Step 1: Circle Important numbers.

Step 2: Draw a picture of the situation.

12 inches

9 in

ches

STEP 3: PYTHAGOREAN THEOREMa2 + b2 = c2

122 + 92 = c2

144 + 81 = c2

225 = c2

C = √ 225 = 15 in

EXAMPLE 2EXAMPLE 2

� Mr. Blue is measuring his TV. The TV is 12 inches wide and 5 inches tall. What is the length of the diagonal on the TV?

� Mr. Blue is measuring his TV. The TV is 12 inches wide and 5 inches tall. What is the length of the diagonal on the TV?

Step 1: Circle Important numbers.

Step 2: Draw a picture of the situation.

12 inches

5 in

ches

STEP 3: PYTHAGOREAN THEOREMa2 + b2 = c2

122 + 52 = c2

144 + 25 = c2

169 = c2

C = √ 169 = 13 in

EXAMPLE 3EXAMPLE 3

Tim & Sal have a 10 meter ladder. It must reach exactly 6 meters up a building, how far away from the building should the ladder be placed?

Tim & Sal have a 10 meter ladder. It must reach exactly 6 meters up a building, how far away from the building should the ladder be placed?

Step 1: Circle Important numbers.

Step 2: Draw a picture of the situation.STEP 3: PYTHAGOREAN THEOREM

a2 + b2 = c2

6 M

eter

s

b

62 + b2 = 102

36+ b2 = 100b2 = 64

b = √64 = 8 feet

EXAMPLE 4EXAMPLE 4

Eric & Emily have a 5 meter ladder. It must reach exactly 3 meters up a building, how far away from the building should the ladder be placed?

Eric & Emily have a 5 meter ladder. It must reach exactly 3 meters up a building, how far away from the building should the ladder be placed?

Step 1: Circle Important numbers.

Step 2: Draw a picture of the situation.STEP 3: PYTHAGOREAN THEOREM

a2 + b2 = c2

3 M

eter

s

b

32 + b2 = 52

9+ b2 = 25b2 = 16

b = √16 = 4 meters

Example 5 Tim rode 3 miles due north, then 3 miles due east. How far, to the nearest mile, is Tim from where he started?

Example 5 Tim rode 3 miles due north, then 3 miles due east. How far, to the nearest mile, is Tim from where he started?

Draw a diagram: Draw a diagram:

3

3x

Ex 5 Ex 5

32 + 32 = x2

9 + 9 = x2

18 = x2

x = √18 = 4.2

Tim is 4.2 miles from where he started.

Example 6 Mary rode 4 miles due north, then 4 miles due east. How far, to the nearest mile, is Mary from where he started?

Example 6 Mary rode 4 miles due north, then 4 miles due east. How far, to the nearest mile, is Mary from where he started?

Draw a diagram: Draw a diagram:

4

4x

Ex 6 Ex 6

42 + 42 = x2

16 + 16 = x2

32 = x2

x = √32 = 5.6

Mary is 5.6 miles from where he started.

Example 7 Town X is 30 miles directly west town Y. Town Z is 40 miles south of town Y. Tom lives in X and wants to get to Z. How much shorter is the direct route from town X to town Z than the longer route traveling through town Y?

Example 7 Town X is 30 miles directly west town Y. Town Z is 40 miles south of town Y. Tom lives in X and wants to get to Z. How much shorter is the direct route from town X to town Z than the longer route traveling through town Y?

X Y

Z

40 miles

30 miles

???

a2 + b2 = c2

302+402=c2

900 +1600 = c2

√2500 = c²50 = c

Did I answer question?

Ex 7Ex 7

Long route = 70 miles

Short route = 50 miles

70 – 50 = 20

20 miles shorter.

Long route = 70 miles

Short route = 50 miles

70 – 50 = 20

20 miles shorter.

A boat sails due East from a Harbour (H), to a marker buoy (B),3 miles away. At B the boat turns due South and sails for 2. miles to a Lighthouse (L). It then returns straight to harbour. What is the total distance travelled by the boat?

∴Total distance travelled = 3 + 2 + 3.6 = 8.6 miles

HB

L

3 miles

2 miles

Example 8

32+ 22 = c2

9 + 4 = c2

13 = c2

C2 = √13 = 3.6

ex 9 The length of a rectangle is 8 in, the length of its diagonal is 10 in. Find the area of the rectangle.ex 9 The length of a rectangle is 8 in, the length of its diagonal is 10 in. Find the area of the rectangle.

8 in

10 in b

Area of rectangleA = L x WWe need the width!

a2 + b2 = c2

82 + b2 = 102

64 + b2 = 100b2 = 100 – 64b2 = 36b = √36 = 6

area = 8 x 6 area = 48 sq inches

� Use your calculator for the rest� Use your calculator for the rest

EXAMPLE 10EXAMPLE 10� You're locked out of your house and the only open

window is on the second floor, 24 feet above the ground. You need to borrow a ladder from one of your neighbors. There's a bush along the edge of the house, so you'll have to place the ladder 7 feet from the house. What length of ladder do you need to reach the window?

� You're locked out of your house and the only open window is on the second floor, 24 feet above the ground. You need to borrow a ladder from one of your neighbors. There's a bush along the edge of the house, so you'll have to place the ladder 7 feet from the house. What length of ladder do you need to reach the window?

Step 1: Circle Important numbers.

Step 2: Draw a picture of the situation.

24 fe

et

7 feet

EXAMPLE 10EXAMPLE 10� You're locked out of your house and the only open

window is on the second floor, 24 feet above the ground. You need to borrow a ladder from one of your neighbors. There's a bush along the edge of the house, so you'll have to place the ladder 7 feet from the house. What length of ladder do you need to reach the window?

� You're locked out of your house and the only open window is on the second floor, 24 feet above the ground. You need to borrow a ladder from one of your neighbors. There's a bush along the edge of the house, so you'll have to place the ladder 7 feet from the house. What length of ladder do you need to reach the window?

24 fe

et

7 feet

STEP 3: PYTHAGOREAN THEOREMa2 + b2 = c2

242 + 72 = c2

576 + 49 = c2

625 = c2

C = √625 = 25 feet

Ex 11 On a regulation baseball field, the bases are 90 ft apart. How far is it on a direct line from 1st base to 3rd base?

3rd base 1st base

home plate

a2 + b2 = c2

902 + 902 = c2

8100 + 8100 = c2

16200 = c2

C2 = √16200 =127.3 ft

EXAMPLE 12EXAMPLE 12

Firefighters have a 40 foot extension ladder. In order to reach 28 feet up a building, how far away from the building should the foot of the ladder be placed?

Firefighters have a 40 foot extension ladder. In order to reach 28 feet up a building, how far away from the building should the foot of the ladder be placed?Step 1: Circle Important numbers.

Step 2: Draw a picture of the situation.STEP 3: PYTHAGOREAN THEOREM

a2 + b2 = c2

28 fe

et

b

282 + b2 = 402

784 + b2 = 1600b2 = 816

b = √816 = 28.6 feet