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Rules : Everyone must attempt to answer each question. Show your work on a separate sheet of paper. Keep track of your points. Winners receive prize. continue. Go BACK. You need to click on a number to proceed to the questions. Click here. continue. Really!! - PowerPoint PPT Presentation
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Rules:
1. Everyone must attempt to answer each question.
2. Show your work on a separate sheet of paper.
3. Keep track of your points.
4. Winners receive prize.
continue
Motion
Projectiles
Newton
ForcesVector
s
100 100 100 100 100
200 200 200 200 200
300 300 300 300 300
400 400 400 400 400
500 500 500 500 500
Go BACK. You need to click on a
number to proceed to the questions.
continueClick here
Really!!
Go BACK. You need to click on a
number to proceed to the questions.
continueClick here
2) Displacement = 27.4m + 3m -3m Distance = 27.4m + 3m +3m
continue
2) This object in freefall accelerates at 9.8 m/s/s. Every second the velocity changes by 9.8 m/s
continue
A ball rolls down an incline from rest. How far does it travel in 3 seconds if it accelerates at 5 m/s2?
Show Work for Creditd = vit + ½ at2
d = 0 + ½ (5 m/s2) (3s)2
d = 22.5 m continue
continue
4) Vavg = (Vf + Vi)/2 Vavg = (10m/s +25m/s)/2 Vavg = 17.5 m/s
1) d = vit + ½ at2
-6m = ½ a (2.7s)2
a = 1.6 m/s/s downcontinue
1) The acceleration of a projectileis always 9.81 m/s2 downward because the only force acting on the object is gravity. continue
2) d = vit + ½ at2
-22m = ½ a (3.0s)2
a = 4.9 m/s/s downcontinue
continueShow Work for Credit
VERTICALd = vit + ½ at2
-45m = 0 + ½ (-9.81m/s2) t2
t = 3.0 s
HORIZONTALd = vit + ½ at2
d = (25 m/s)(3.0 s) + 0d = 75 m
2) v vs. t graphs are
always linear.
Slope = accel. =
-9.81 m/s2
continue
vf = vi + at0 = 98 m/s + (-9.81m/s2)tt = 10. s
continue
continue
3) g = Fg/m
Fnet = ma12 N = (2kg+1kg)aa = 4 m/s2
continue
Which graph(s) depict an object that is accelerating?
B and C only
continue
DAILY DOUBLESelect an amount of points you want to wager before going on
to the question.
You can only wager up to as many points as you currently
have
A B C D E
2) An object in equilibrium has an acceleration equal to zero. continue
Newton’s 3rd Law: the forces are equal in magnitude, opposite in direction.
Fnail on hammer = - Fhammer on nailcontinue
Fnet = ma50N – Ff = (4 kg)(10 m/s2)Ff = 10N
continue
Fnet = ma
Fapplied – Ffriction = 0
Fapplied = Ffriction
Fapplied = μFN = (0.05)(80kg x 9.81m/s2)
Fapplied = 40N
continue
continue
(C) If the net force is zero, the acceleration must also be zero.The slope of the speed graph = accel. = 0. Constant speed = constant slope of distance graph.
Fnet = ma
Fapplied – Ffriction = 0
Fapplied = Ffriction
Fapplied = μFN = (0.67)(60 N)
Fapplied = 40N
continue
Show Work for Credit
continue
Fnet = ma = 0
F – Ffriction – Fparallel = 0
F = Ffriction + Fparallel
F = Ffriction + Fg sinθ
F = 3N + (10N)sin30°
F = 3N + 5N
F = 8N
(4)Add vectors head to tail
continue
B
List 3 scalar quantities and 3 vector quantities. Include units.
Scalar: distance (m), speed (m/s), mass (kg), time (s),temp
(°C)
Vector: displacement (m), velocity (m/s), acceleration
(m/s2), Force (N), impulse (N·s), momentum (kg·m/s)continue
DAILY DOUBLESelect an amount of points you want to wager before going on
to the question.
You can only wager up to as many points as you currently
have
continue
(4)FH = FcosθFH =(24N)cos35°FH = 20. N
FV = FsinθFV =(24N)sin35°FV = 14. N
continue
(1)
B
A R
continue
(4) Arrange 30N vectors to be head-to-tail, resultant starts at the tail of the first and ends at the head of the last.
R
30N
30N