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Saltsproduct of neutralization reaction
1.00 M NaOH
mol OH-
L0.075 mol1.00 mol
Lx L
x = 0.075L
H+ + Cl- + Na+ + OH- H2O + Na+ + Cl-
NaCl (s)[Na+] = 0.075 mol
.150 L + .075 L
= 0.333 M = [Cl-]
basestrong150 mL 0.500 M HCl
= mol H+
0.500 mol= 0.15 L
acidstrong
=
NaCl (s) HClNaOH
conjugate baseconjugate acid
Cl-Na+
very weak very weak
Cl- + H2O no reactionNa ++ H2O no reaction
Saltsproduct of neutralization reaction
basestrong acidstrong
Li+
K+
Rb+
Ca2+
Sr2+
Ba2+
negligible acidity
Br-
I-
NO3-
ClO4-
negligible basicity
Saltsproduct of neutralization reaction
base acidstrong weak
1.00 M NaOH
mol OH-
L0.075 mol1.00 mol
Lx L
150 mL 0.500 M HF
= mol H+
0.500 mol= 0.15 L=
x = 0.075L
H+ + F- + Na+ + OH- H2O + Na+ + F-
NaF (s)
HF
Ka = 1.5 x 10-11
Saltsproduct of neutralization reaction
base acidstrong weakNaF (s)NaOH HF
conjugate baseconjugate acidvery weak strong
Na ++ H2O no reaction F- + H2O HF + OH-
Ka = 1.5 x 10-11
Ka x Kb = Kw
Kb =6.7 x 10-4hydrolysis
“breaking water”
Na+ F-
basic solution
=[HF] [OH-]
[F-]
Saltsproduct of neutralization reaction
base acidweak strong
HClO4CH3NH2
CH3NH2+ H2O CH3NH3++ OH- + H+ + ClO4
-
CH3NH3ClO4 (s)
H2O
CH3NH3+ ClO4
-
conjugate baseweakconjugate acidstrong
Kb = 4.4 x 10-4
Ka = 2.3 x 10-11
CH3NH3+ + H2O CH3NH2 + H3O+
acidic solutionhydrolysis
Saltsproduct of neutralization reaction
base acidweak weak
NH3HNO2
NH4NO2
NH4+
NO2-
NH3
HNO2
+ H2O + H3O+
+ H2O + OH-
Ka =
Kb =
5.7 x 10-10
1.4 x 10-11
acidic solution
List the following species in order of
C5H5NHCl
K2CO3
LiNO3
NaHCO3
cation anion pH
C2H5NH+ Cl-
K+ CO32-
Li+ NO3-
Na+ HCO3-
w.b.
s.b.
s.b.
s.b.
s.a.
s.a.
w.a.
w.a.
acidic
basic
neutral
basic
I
II
III
IV
0.20 M
increasing pH
Calculate the pH of a
C2H5NH3 NO3+ -
base acid
C2H5NH3+ + H2O C2H5NH2+ H3O+
Kb = 5.6 x 10-4
Ka x Kb = Kw = 1.0 x 10-14 Ka = 1.8 x 10-11
1.8 x 10-11 = [H3O+] [C2H5NH2]
[C2H5NH3+]
= x2
0.1
x = 1.34 x 10-6 pH = 5.87
0.10 M C2H5NH3NO3 solution
weak strong