SKKN ung dung CNTT

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A. M UI. L do chn ti. S bng n ca cng ngh thng tin v truyn thng ang tc ng mnh m, su sc vo mi mt ca i sng kinh t, x hi, trong c gio dc THPT . nh hng i mi phng php dy hc (PPDH) c xc nh trong Ngh quyt Trung ng 4 kha VII (1-1993), Ngh quyt Trung ng 2 kho VIII (12-1996), c th ch ho trong Lut gio dc (2005)[1], c c th ho trong cc ch th ca B gio dc v o to, c bit l ch th s 14 (4-1999), ch th 55 (2008). Vic ng dng CNTT&TT trong i mi PPDH c cp rt r rng trong cc vn bn trn.Tuy nhin, n nay cc ng dng CNTT&TT trong dy hc dy hc hin nay cc trng THPT cn cha nhiu, mang tnh t pht, nh l cha mang tnh h thng. Phn ln cc trng THPT ang cn p dng cc phng php, phng tin dy hc truyn thng, chm i mi v lc hu. M vic ng dng CNTT l rt rng nh: s dng th vin t liu in t, s dng h thng cu hi trc nghim, s dng cc phn mm ha hc, cc phn mm h tr kim tra nh gi, s dng cc bi ging in t trong ging dy .... V vic ng dng bi ging in t l mt phn ca ng dng CNTT & TT. T nhng phn tch trn, gp phn nng cao cht lng dy hc mn Ho hc phn Hu c THPT, ti chn ti nghin cu ng dng bi ging in t trong dy hc ha hc hu c THPT gp phn nng cao cht lng gio dcII. Mc ch ca nghin cu.- ng dng bi ging in t trong dy hc Ha hc Hu c THPT, nhm nng cao cht lng dy hc trong giai on hin nay v trong tng laiIII . Nhim v ca nghin cu.- Nghin cu c s l lun v i mi phng php dy hc theo quan im CNTT v truyn thng.- Su tm & xy dng h thng cu hi trc nghim khch quan v cc thi phn Ha hc Hu c chng trnh THPT nhm h tr vic i mi kim tra, nh gi.- Thc nghim s phm v x l s liu thc nghim nh gi cht lng, hiu qa v tnh kh thi ca vic ng dng bi ging in t trong dy hc phn Ha hc Hu c THPT.IV. Gii hn nghin cu ca ti.ng dng CNTT & TT l rt rng, y ti ch s dng mt phn nh ca ng CNTT & TT l s dng cc bi ging in t vo ging dy phn kin thc hu c chng trnh chun lp 11.B. NI DUNG

I. C s l lun: [2]Th gii bc vo k nguyn mi nh tin b nhanh chng ca vic ng dng cng ngh thng tin vo tt c cc lnh vc. Trong gio dc o to, CNTT gp mt phn hin i ha phng tin, TBDH, gp phn i mi PPDH.Theo quan im thng tin, hc l mt qu trnh thu nhn thng tin c nh hng, c s ti to v pht trin thng tin; dy l pht thng tin v gip ngi hc thc hin qu trnh trn mt cch hiu qu.Thng tin c hiu cng c gi tr nu n gy ra c s bt ng cng ln. Trong khoa hc, ngi ta lng ha thng tin theo quan im ny. Ngi hc nh mt my thu c nhiu ca vo, phi bit tip nhn thng tin qua nhiu ca, phi bit tch thng tin hu ch ra khi nhiu, phi bit bin i, lu tr, ghi nh thng tin trong nhiu b nh khc nhau, mi ca vo ny tip nhn mt loi thng tin c m ha ring bit. Ta cn tn dng tt c cc phng tin a thng tin vo ca ny, cn s dng trang thit b hin i nhm chuyn i, m ha, ch bin thng tin vic chuyn tin t hiu qu nht.Nu ni dung bi hc ch c truyn ti ngi hc di dng vn bn th ngi hc c th s km hng th. Nu ch truyn tin theo mt chiu, khng c s hi p th thng tin thu c ca ngi hc c th phin din, khng y hoc b bin dng, c khi dn n vic hiu sai ni dung.Theo quan im CNTT, i mi phng php dy hc, ngi ta tm nhng Phng php lm tng gi tr lng tin, trao i thng tin nhanh hn, nhiu hn v hiu qu hn. V vy m cc gio vin s dng bi ging in t trn cc phng my vi cc my chiu, th bi ging s sinh ng hn, s tng tc hai chiu c thit lp, hc sinh c gii phng khi nhng cng vic th cng vn vt, tn thi gian, d nhm ln nn c iu kin i su vo bn cht bi hc. y cng l hng i mi nhm nng cao hiu qu ca qu trnh dy hc.II. C s thc tin. ho cng vi nhp pht trin gio dc chung ca cc nc trn th gii, trong khong mi nm gn y, B GD&T a chng trnh tin hc vo nh trng, trnh ging dy v ng dng tin hc c c s vng chc, nhiu PMDH c thc nghim. Nhiu GV p dng PMDH ca nc ngoi lm cng c dy hc, song cc PMDH cn qu t i, cc ng dng cn mang tnh th nghim.i vi b mn ha hc, vic i mi PPDH, phng tin, thit b dy hc ang tng bc ci tin. Hu ht GV thy c vai tr quan trng ca vic khai thc cc phn mm phc v cho vic dy hc. Tuy nhin, kinh ph u t vo cc phng tin, thit b dy hc cn hn hp nn vic ng dng CNTT trong dy hc Ha hc cn gp rt nhiu kh khn, cha c ph bin rng ri.Hu ht cc trng THPT u c trang b my vi tnh, my chiu Projecter, nhiu trng xy dng cc phng hc a nng, nhiu GV c my tnh xch tay, song vic s dng trong dy hc cn hn ch, nhiu GV ln tui ngi thay i, ngi tip cn CNTT, GV cha bit cch khai thc, thit k v s dng cc sn phm v ng dng CNTT trong dy hc Ha hc.Cc gi hc Ha hc c s tr gip CNTT, trong vic s dng bi ging in t u c nh gi l sinh ng, hp dn lm cho HS tch cc tham gia cc hot ng hc tp.Phn ln cc GV tr rt tch cc hng ng vic p dng bi ging in t vo dy hc v u cho rng l mt hng i ng v cn thit cho vic i mi phng php dy hc ni chung v mn Ha hc ni ring cc trng THPT trong giai on hin nay v trong tng lai.T cc c s thc tin trn cho thy vic nghin cu v ng dng bi ging in t vo dy hc l cn thit v ng thi cng l c s cho yu cu i mi phng php dy hc Ha hc trong giai on hin nay.III. Xy dng h thng gio n in t phn ha hc ha c lp 11 chng trnh chun.1. Gio n in t v Bi ging in t

1.1.Khi nima) Gio n in t (ICT lesson plane)[4],[3]

L mt bn k hoch v dn gi ln lp ca GV c bin son c s dng CNTT v c bin son trong giai on chun b ln lp. Gio n in t l bn thit k c th ton b k hoch hot ng dy hc ca gio vin trn gi ln lp, ton b hot ng dy hc c a phng tin (multimedia) ha mt cch chi tit, c cu trc cht ch v logic c quy nh bi cu trc ca bi hc. Gio n in t l mt sn phm ca hot ng thit k bi dy c th hin bng vt cht trc khi bi dy hc c tin hnh v c lu tr di dng mt tp tin (file) in t.

b) Bi ging in t (ICT lesson)[5],[6]

Bi ging in t l mt hnh thc t chc bi ln lp nhm thc thi gio n in t. Khi ton b k hoch hot ng dy hc u c chng trnh ho, do gio vin iu khin thng qua mi trng a phng tin vi s h tr ca CNTT. Nu nh bi ging truyn thng l s tng tc gia thy v tr thng qua cc phng php, phng tin v hnh thc dy - hc truyn thng th BGT l s tng tc gia thy v tr thng qua cc phng php, phng tin v hnh thc dy - hc c s h tr ca CNTT.

Do , c rt nhiu mc tham gia ca CNTT trong mt BGT. Tuy nhin, hin nay vn cha c mt chun mc no nh gi BGT.

+) Bi ging in t l mt phn ca chng trnh dy hc c s h tr ca cng ngh thng tin m trong ton b hot ng dy hc c chng trnh ha thng qua mi trng multimedia.

+) mc thp, GV thc hin bi ging di s h tr ca bn trnh din t chc cc hot ng dy hc nhm p ng c mc tiu t ra ca bi hc.

+) mc cao nht ca BGT l ton b kch bn dy hc ca GV c s ha, to nn mt phn mm dy hc hon chnh c tng tc v kh nng qun l. c bit l n c th thay th vai tr ca GV mt s thi im nht nh.

+) Trong mi trng multimedia, thng tin c truyn di cc dng; vn bn (text), ha (graphics), hot nh (animation), nh chp (image), m thanh (audio) v phim video (video clip).Nh vy, bi ging in t l tp hp cc hc liu in t c t chc theo mt kch bn s phm c th cung cp kin thc v k nng cho ngi hc mt cch c hiu qa thng qua s tr gip ca cc phn mm qun l hc tp. Bi ging in t bt buc phi c cc hc liu in t a phng tin t ti thiu t 30% n 40% thi lng mn hc tnh theo s tit. Bi ging in t c th tng ng vi mt phn ni dung chng trnh ca mn hc.

1.2. Hc liu in t[7]Hc liu in t-courseware l cc ti liu hc tp c s ha theo mt cu trc, nh dng v kch bn nht nh, c lu tr trn my tnh nhm phc v vic dy hc. Dng thc s ha c th l vn bn, slide, bng d liu, m thanh, hnh nh, video s, cc ng dng tng tcv hn hp ca cc dng thc ni trn.Hc liu in t bao gm hc liu tnh v hc liu a phng tin.Hc liu tnh l cc file text, slide, bng d liu.Hc liu a phng tin c th gm nhng loi sau y:

+ Cc file m thanh minh ha hay din ging kin thc;

+ Cc file flash hoc tng t c to ra t cc phn mm ho dng m phng kin thc;

+ Cc file video clip c lu tr trong cc nh dng mpeg, avi hay cc nh dng c hiu ng tng t;

+ Cc file trnh din t hp cc TP trn theo mt cu trc no .

2. Quy trnh xy dng gio n in t

2.1. Chun b kch bn

a) Xc nh mc tiu bi hc;

b) Xc nh ni dung kin thc cho bi ging, thng thng chng ta xc nh theo gio trnh hoc sch gio khoa ca mn hc;

c) Xy dng kch bn dy hc: Phn chia nh kin thc theo phng php dy hc chng trnh ha. Theo cch ny, mi lng kin thc nh s c xc nh mt cu hi chnh v mt cu hi gi m. Kt qa ca bc ny l ta c mt h thng cu hi;

d) Xy dng cc thao tc: Chng ta c nhng chuyn i tng ng gia thao tc ca gio vin v cc thao tc trn my vi tnh;

- Nu vn ( cc cu hi hay cu trc nghim c phn hi trc tip thng qua tng tc;

- Din ging ( kch hot file m thanh ghi li din ging;

- Vit bng ( Hin th vn bn trn mn hnh;

- Trnh din khc ( kch hot cc hc liu a phng tin tng ng.

2.2. Chun b hc liu in t

a) Bi ging vn bn c cc yu cu sau y:

- Thi lng ca BG; Mc tiu ngi hc cn t v kin thc v k nng;

- iu kin tin quyt: kin thc cn phi c tip thu bi ging ny;

- Ton vn BG quy nh vit trong cc nh dng: MS Word, Pdf, Text.

b) Danh mc ti liu tham kho chnh (trong nc v ngoi nc).

c) Cc hc liu a phng tin lin quan n kin thc ca bi ging .

d) H thng bi tp, cu hi trc nghim.

e) Tnh tng tc: Hot ng ca GV, hot ng ca SV, hot ng ca cng c h tr (my tnh).

2.3. Thit k gio n in t

a) Nguyn tc thit k[8]

Khi thit k gio n in t cn m bo cc nguyn tc sau:

- m bo tnh khoa hc: Nguyn tc ny i hi gio n thit k phi c cu trc logic, cht ch v khoa hc. Cc hnh nh, phim t liu... s dng trong bi ging phi ph hp vi ni dung cn truyn t.

- m bo tnh s phm: Nguyn tc ny i hi khi thit k cc trnh phim s dng trong dy hc, b cc phi hp l, r rng, m bo thi gian ca tit hc, ph hp vi chng trnh, gio trnh v ph hp vi phng php dy hc mi. Cc trnh phim thit k phi d s dng, gip ging vin d dng iu khin nhn thc ca sinh vin.

- m bo tnh kh thi: GA thit k phi c kh nng ng dng rng ri.

- m bo tnh thm m: Cc tranh nh, hnh v, s , biu ... a vo bi ging phi hi ho, r nt, mu sc- kch thc hp l, trnh lm dng hnh nh, nh sng, mu sc lo lot hoc qa nhiu hiu ng hot hnh v m thanh trong cc ni dung trnh chiu.

b) Cc bc thit k

Bc 1: Xc nh mc tiu bi hc: Hc xong bi th hc sinh s t c g v? V kin thc, v k nng, v thi , tnh cm.

Bc 2: Xc nh trng tm v kin thc c bn:

- Cn bm st vo chng trnh dy hc v gio trnh;

- Cn phi c thm ti liu, sch bo tham kho m rng hiu bit v vn cn dy hc v kh nng chn ng kin thc c bn;

- Xc nh kin thc c bn ca bi dy hc c th gn vi vic sp xp li cu trc ca bi lm ni bt cc trng tm, trng im ca bi.

Bc 3: Xy dng kch bn dy hc:

- Xc nh cu trc ca kch bn; Chi tit ha cu trc ca kch bn;

- Xc nh cc bc ca qu trnh dy hc;

- Xc nh qu trnh tng tc gia thy, tr v cc i tng khc (phim, nh, text) hot ng ca thy, tr v cng c h tr;

- Xc nh cc cu hi, phn hi trong cc hot ng;

- Hnh dung (lp ghp) thnh tin trnh dy hc.

Bc 4: Xc nh t liu cho cc hot ng:

- Phim (video), nh (image), hot cnh (animation)...;

- Tm kim t liu; X l, lu tr t liu;

- Phn phi t liu cho mi hot ng.

Bc 5: La chn phn mm cng c v s ha kch bn dy hc:

- La chn phn mm cng c thch hp; Ci t (s ha) ni dung;

- To hiu ng trong cc tng tc.

Bc 6: Chy th, chnh sa v hon thin:

- Trnh din th; Kim tra li;

- Kim tra tnh logic, hp l ca cc thnh phn;

- Chnh sa; Hon thin; ng gi.

3. Thit k gio n in t phn Ha hc Hu c chng trnh chun lp 11 - THPT

Gio n in t l bn k hoch dy hc chi tit ca gio vin c s ha v a phng tin ha. Sau khi xem xt mt s phn mm, chn phn mm Microsoft Powerpoint thit k gio n in t vi u im d s dng. 3.1. Phn mm thit k gio n in t

* Khi qut v phn mm.

Microsoft Powerpoint [9] l phn mm ng dng thit k v trnh chiu thng tin. Sn phm l cc Presentation (bi trnh chiu). Trong mi Presentation gm cc Slide, chng c sp xp theo mt trnh t nht nh. Mi Slide cha nhiu loi thng tin khc nhau nh ch (text), hnh nh (image), tranh v (picture), m thanh (sound), hnh nh ng (movie), cc hiu ng hot ha (animation). Cc Slide xut hin t ng hoc tun theo iu khin ca ngi dng. Vi kh nng cha ng nhiu thng tin trong mt Slide, vi s sinh ng khi chuyn i gia cc Slide, vi cc cng c tinh xo, cc biu , cc biu mu ha trang tr p mt v cc phim dng bn c kt ni, to nn cc trnh phim biu din cc c ch, cc qa trnh... Powerpoint thc s l phn mm mnh trong vic h tr i mi phng php dy hc nhm nng cao cht lng dy hc.

Thit k gio n in t trn Powerpoint bao gm cc bc sau:

a) Bc 1: La chn ni dung thng tin cn th hin trong Presentation.

b) Bc 2: Chia nh ni dung thng tin thnh cc moun. Mi moun s c hin th trong mt Slide. Trong bc ny phi nghin cu xem ni dung cn truyn ti c th chia nh bao nhiu, vic ngt ND u l hp l.

c) Bc 3: La chn ti a i tng multimedia c sn (vn bn, hnh nh tnh, ng, m hnh, m thanh...) minh ha cho ni dung thng tin trong mi Slide. y l bc th hin sc mnh ca gio n in t so vi gio n truyn thng (dng bng en, phn trng). Tt c cc hnh nh, m thanh... u c th chn vo cc Slide.

d) Bc 4: Khai thc cc ti nguyn (vn bn, hnh nh tnh, ng, m hnh, m phng, m thanh) trong th vin t liu in t, trong phn mm cng c m phng chuyn dng CircuitMakerPRO hoc cc phng my cng c khc. Trong bc ny c th s dng bt k trnh son tho no to ra ti liu vn bn, sau chn vo cc Slide. C th s dng my qut nh, my nh s, camera to cc ti liu MultiMedia cn thit. C th to cc m hnh ng hin th trong mi Slide mt cch n gin bng cc nh gif ng.

e) Bc 5: S dng Powerpoint tch hp (lin kt) cc ni dung trong mi moun trn vo cc Slide.

g) Bc 6: Quy nh hnh thc th hin ca cc ni dung thng tin trong mi slide.

h) Bc 7: Quy nh hnh thc chuyn i gia cc Slide.

f) Bc 8: Vit cc thng tin gii thch cho mi Slide (nu cn thit).

Da vo nguyn tc, quy trnh thit k gio n in t trn thit k 10 gio n in t trong phn ha hc hu c chng trnh chun - lp 11 THPT. c trnh by trong CD.

Hnh nh Slide mt s gio n in t phn hyrocacbon ca chng trnh ha hc hu c 11.

3.2. Phng php s dng gio n in t

Gio n in t ch s dng hiu qa khi c t liu a phng tin km theo v phi s dng n nh mt phng tin dy hc tch cc. Khng nn lm dng gio n in t m nn s dng phi hp vi cc phng php dy hc tch cc (phng php hc nhm, phng php thuyt trnh c nu vn , ) s thu c hiu qa cao hn.

Cc gio n in t c xy dng theo hng m nn rt linh hot v d s dng cho cc gio vin cc trng THPT. Ty theo yu cu, gio vin c th s dng ngay nu thy hp l hoc sa i li sao cho ph hp vi ni dung ca mi bi ging v vi phng php t chc hot ng dy hc ca mnh.

Trong mi th mc ca mt gio n in t gm: 1 file thit k trn Powerpoint v 3 th mc t liu (nh tnh, m phng v th nghim). Mi th mc t liu c cha cc file c s dng bi gio n nn khi trnh chiu gio vin lu khi thy xut hin siu lin kt (hyperlink) th nhy chut vo ta s xem c ni dung m phng hoc ni dung film.

IV. Tin hnh bi ging bng gio n in t.

Ph hp vi phm vi v ni dung nghin cu ca ti, chng ti tin hnh thc nghim nh sau:

1. Tin hnh bi ging in t trn phng my.Vi cc gio n in t chun b sn, ti s dng bi ging in t vi cc lp 11B2, 11B3 cn hai lp 11B4 v 11B5 th khng s bi ging in t l hai lp i chng. Thc hin trong k II nm hc 2011 2012.

C th nh sau: a) Mt s bi dy. Phn I. i cng v hp cht hu c. Bi 21 Cng thc phn t hp cht hu c

- Phn II. Hyrocacbon: Bi 25 Ankan ( 2 tit ), bi 29 Anken ( tit 2), bi 32 Ankin (1 tit), bi 35 Benzen (2 tit), bi 36 luyn tp v hidrocacbon thm (1 tit ), bi 38 h thng ha v hidrocacbon (1 tit)

- Phn III. Ancol phenol Anehit. Bi 41 Ancol (tit 2), bi 42 Phenol (1tit), bi 44 Anehit - Xeton (2 tit). Tin hnh ging dy theo nh gio n c trnh by a CD. Sau khi dy thc nghim tin hnh ly kin nh gi gi dy v kt qu ca HS.b) Tin trnh mt bi dy c th. y ti ly mt bi ankan (t2) minh ha cho tin trnh bi ging in t (trn phng my), v ti kt hp vic trnh chiu bi ging vi vic s dng phn, bng vit thng thng.Tit: 38Bi 25. Ankan (tit 2)

I. Muc tiu (tit 2)1. V kin thc.

Bit c:

- Tnh cht ha hc, phn ng th, phn ng tch hidro, phn ng crckinh).

- Phng php iu ch metan trong phng th nghim v trong cng nghip. ng dng ca ankan.

2. K nng:

Vit cc phng trnh ha hc biu din tnh cht ha hc ca ankan. Tnh thnh phn phn trm v th tch v khi lng ankan trong hn hp kh, tnh nhit lng ca phn ng chy.3. V tnh cm thi .

- Yu thch mn hc, thm tinh ham hc hi v hp cht hu c.

II - Chun bi

- GV: Gio n, gio n in t, bi kim tra ngn, phng my. - HS: Nghin cu bi nh trc, tm hiu trc cc thng tin v ankan.

III. Tin trnh dy hc.* Lu : Cc slide bi ankan (t 2) c trong phn ph lc 5 v a CD. Hot ng 1: n nh lp hc v Kim tra bi c

Hot ng ca GV v HSNi dung bi hc

GV: Chiu slide 1, yu cu HS lm bi tp

HS: Chun b bi ri ln bng hon thnh.Slide 1.

Bi tp: Vit CTCT ng phn ca C6H14 v gi tn theo IUPAC.

Bi lm: C 5 ng phn c trong slide 1

Hot ng 2. Vo bi miHot ng ca GV v HSNi dung bi hc

GV: Dn dt HS vo bi hc, chiu slide 2, 3, 4.

GV: Cho HS nhn xt v c cu to ca ankan, ri suy ra tnh cht ha hc c bn ca ankan, chiu slide 3, slide 4.

HS: Nhn xt, rt ra tnh cht ha hc ca ankan.Slide 2,3,4.

- T c im cu to => ankan tng i tr v mt ha hc.

- Ch c phn ng th, bn vi axit, baz

- Ankan tng i tr v mt hoa hoc: Ankan co kha nng tham gia cac phan ng th, phan ng tach va phan ng oxi hoa.

Hot ng 3. Phn ng th bi halogen

Hot ng ca GV v HSNi dung bi hc

GV: Chiu slide 5, hng dn HS hon thnh phn ng 1, sau yu cu HS hon thnh cc phn ng cn li, sa sai cho HS.

HS: Theo di, hon thnh phn ngSlide 5, cc phng trnh phn ng trong slide 5.

CH4 + Cl2 CH3Cl + HCl

Hot ng 4. Phn ng th bi halogen (cc ng ng khc ca metan)

Hot ng ca GV v HSNi dung bi hc

GV: Chiu slide 6, hng dn HS hon thnh phn ng Clo vi etan v propan, sa sai cho HS.

HS: Hon thnh phn ng, rt ra nhn xt.Slide 6.

CH3 CH3 + Cl2 CH3 CH2Cl + HCl

CH3 - CH2 - CH3 INCLUDEPICTURE "C:Program FilesUniKey FullVietFlex.2UVConvert.ICO" * MERGEFORMAT d

+ Cl2 CH3-CHCl-CH3 + CH3-CH2-CH2-Cl

2-clopropan, 57% 1- clopropan, 43%

NX: T C3H8 tr i u tin th C bc cao hn.

Hot ng 5. Phn ng tch

Hot ng ca GV v HSNi dung bi hc

GV: Chiu slide 7, dn dt HS hon thnh cc phn ng theo slide.

HS: Hon thnh phn ng.Slide 7.

Cc ankan b tc dng bi nhit .

CH3 CH3 CH2 = CH2 + H2CH3 CH2 CH3 CH2=CH CH3 + CH4.

Hot ng 6. Phn ng oxi ho.

Hot ng ca GV v HSNi dung bi hc

GV: Chiu slide 8, yu cu HS hon thnh phn ng, rt ra nhn xt.

HS: Hon thnh phn ng, ri nhn xtSlide 8.

CnH2n+2 + O2nCO2 + (n+1)H2O

NX: nH2O > nCO2........

Hot ng 7. iu ch - ng dng

Hot ng ca GV v HSNi dung bi hc

GV: Chiu slide 9,10, 11 yu cu HS hon thnh phn ng, dn dt HS khai thc phn ng dng v iu ch.

HS: Hon thnh phn ng, tr li cc cu hi ca GV.Slide 9, 10, 11.

ng dng v iu ch.

1. iu ch.

a) Trong CN (SGK)

b) Trong phng th nghim

CH3COONa + NaOH CH4 + Na2CO3

Hot ng 8. Cng c bi hc

Hot ng ca GV v HS

GV: Chiu slide 12, yu cu HS hon thnh vo ch ;

HS: Hon thnh phn ng.

GV: Kim tra ngn 5 bng vic pht bi thi cho HS.

HS: Hon thnh:Slide 12.

Hon thnh vo ch chm.

Ni dung kim tra ( c ph lc 4)

2. Hnh thc nh gi gi dy.

- Xin kin nhn xt, nh gi gi dy thc nghim c ng dng bi ging in t.

- nh gi cht lng nm vng kin thc ca hc sinh sau mi gi dy thc nghim bng bi tp kim tra kin thc (bi tp kim tra kin thc c chng ti xy dng bng cc bi tp TNKQ vi s lng phong ph, a dng rt st vi ni dung l thuyt ca gi hc. Ni dung cc bi tp kim tra kin thc ny nm phn ph lc 4.

- nh gi cht lng nm vng kin thc ca hc sinh sau tt c cc gi dy thc nghim bng cc bi kim tra vi hnh thc kim tra trc nghim 45 pht (trn giy ). Cc bi kim tra ny c trnh by phn ph lc 4. mi lp ny, ti :

- Cc lp thc nghim v i chng tng ng nhau v s lng hc sinh, trnh nhn thc, ng u v thi gian v ni dung bi dy. Lp thc nghim dy bng GAT, lp i chng dy theo gio n thng thng.- Trc khi tin hnh thc nghim, tm hiu, phn tch v nh gi cht lng ca cc lp ny l tng ng nhau, da trn kt qu hc k I (2011 2012).

- Xin kin nhn xt, nh gi gi dy thc TN c ng dng gio n in t, thng qua gio vin d gi v hc sinh.* i vi GV d gi, xin kin gp ring v sau mi tit dy ti pht phiu s 1 , ni dung phiu c trnh by ph lc 1. Sau tt c cc tit dy thu c 30 phiu, tin hnh thng k v thu c kt qu phn sau.* i vi HS, sau mi tit hc pht bi kim tra nhanh ( khong 5 pht), ni dung bi kim tra c ph lc 4, nhm nh gi kin thc sau mi bi hc.* i vi HS, sau 10 tit dy thc nghim pht phiu s 2, ni dung c ph lc 2.

C. KT QU THC NGIMI. i vi GV d gi.1. kin ca GV:

Ti dy hai lp mi lp 10 tit vi 30 lt GV d gi, nh gi gi dy thc nghim c s dng bi ging in t hai lp 11B2 v 11B3 . Hu ht gio vin u cho rng: 1) Bi dy logic, cht ch, c h thng, m bo tnh khoa hc v tnh thc tin, ngn gn, y , r rng.

2) Bi dy th hin c y ni dung v khc ha c kin thc trng tm, c thit k rt cng phu, kh phong ph, rt p v rt sinh ng.3) Gi hc c s dng bi ging in t lm gi hc tr nn a dng, sinh ng v hp dn hn rt nhiu, HS rt tch cc trao i, tho lun v rt hng th hc tp, GV dnh c nhiu thi gian iu khin hot ng nhn thc ca HS, do cht lng gi hc c nng cao. 4) Khi s dng gio n in t phi hp vi cc phng php dy hc tch cc th thu c hiu qu cao hn rt nhiu, cng lm tng thm tnh sinh ng ca gi hc.5) Nhng vng mc trong vic thc hin gi dy c s dng bi ging in t l:

- GV mt nhiu thi gian trong vic tm t liu hnh nh, thit k GAT

- Cc trang thit b tr gip cho vic ng dng CNTT&TT trong dy hc cn thiu thn.

xut: Cc trng THPT cn trang b tt c cc phng hc a nng, ni mng internet. Cung cp kp thi cho cc trng THPT th vin t liu in t phc v dy hc, gio n in t, mt s gio n mu v dy hc phn ha hc hu c c s dng phi hp CNTT&TT.2. Kt qu iu tra thng qua phiu.

Phiu s 1.(Phiu dnh cho GV)a) - S l s liu: Thu s phiu ca mi GV d gi v thng k, ta thu c 30 phiu cho kt qu bng sau:Bng 1. Kt qu cu 1

S cn thit ng dng bi ging in tS lt GVT l %

Rt cn thit826,46

Cn thit1550

Cha cn thit723,33

Bng 2. Kt qu cu 2nh gi gi hc HHHC c s dng bi ging in tng Khng ng

S lt GV%S lt GV%

Gip HS tch cc nhn thc hn2893,3326,67

Kch tch hng th hc tp ca HS2996,6713,33

Truyn t c nhiu kin thc hn2996,6713,33

Gi hc sinh ng hn, hp dn hn2790310

HS d hiu bi v tip thu bi nhanh2686,67413,33

Cht lng gi hc c nng cao2583,33516,67

3. Nhn xt: Qua kt qu trn ta thy rng vic s dng bi ging in t vo dy hc l cn thit, v n mang li kt cao trong vic dy hc, gp phn i mi dy hc hin nay. Qua cu hi 2 ta thy % GV nh gi gi dy hiu qu, HS tch cc d hiu khong 90%.II. i vi HS.

1. Thng qua phiu s 2.a) S l s liu:

- Sau khi tin hnh dy xong ton b cc bi ging in t, th tin hnh ly kin ca HS hai lp thc nghim l lp 11B2 v lp 11B3, vi tng s 89 phiu thu c kt qu nh sau:

Bng 3. Kt qu cu 1 kin HS v gi hc ha HHHC

c s dng s dng bi ging in tS HST l %

Rt thch6775,28

Bnh thng1921,34

Khng thch33,38

Bng 4. Kt qu cu 2

nh gi vic dy hc bng BGTS HST l %

Kh tip thu22,47

Bnh thng1213,48

D tip thu4752,80

Rt d tip thu2831,25

Bng 5. Kt qu cu 3

Ni dung trong bi ging gy n tngS HST l %

L thuyt32/8935,95

Hnh nh tnh49/8955,05

Cc ni dung m phng74/8983,14

Th nghim78/8987,64

Bi tp65/8973,03

Bng 6. Kt qu cu 4

S cn thit phi ng dng bi ging in t trong dy hcS HST l %

Rt cn thit3842,69

Cn thit4651,68

Cha cn thit55,61

b) Nhn xt. Qua cu hi s 1, ta thy 75,28% HS rt thch gi ging.Qua cu hi 2, d v rt d tip thu trn 85%; cu 4 trn 90% l cn thit s dng bi ging in t. Qua ta thy bi ging in t l cn thit, d hc, sinh ng. Qua cu hi 3 GV rt kinh nghim cho vic son bi ging in t.2. Thng qua kt qu kim tra ngn.a) Kt qu im kim tra ngn. Cc lp thc nghim(TN) (11B2, 11B3) v cc lp i chng (C) (11B4, 11B5) cc gi dy c thng k theo bng sau:

Bng 7. Kt qa im kim tra bi ankanim s0 45 67 89 10(

Phng nCTNCTNCTNCTNCTN

S HS61401342642119089

T l %6,671,1444,4414,648,8871,912,2212,35100100

i vi cc tit dy khc ta cng lp bng thng k nh trn, sau tnh gi tr trung bnh ta c kt qu nh sau:

Bng 8. Tng hp kt qa im kim tra ngn sau tt c cc tit dy.im s0 45 67 89 10(

Phng nCTNCTNCTNCTNCTN

S HS61391043652139089

T l (%)6,671,1443,3311,2347,7773,032,2214,6100100

b) Nhn xt: Qua cc bi kim tra ngn ta thy rng, im thi ca HS cc lp TN (11B2, 11B3) cao hn hn so vi cc lp C (11B4, 11B5). C th HS gii lp TN(14,6%) trong khi lp C (2,22%), HS kh lp TN(73,03%) lp C( 47,77%). Thng qua biu im thi lp thc nghim c % HS t im kh v gii cao hn hn so vi lp i chng, cn % HS t im trung bnh v yu th km hn hn so vi lp i chng. Qua chng t bi ging in t nng cao c cht lng gio dc. 3. Thng qua bi kim tra 45.a) Kt qu.

Bng 9. Kt qa im kim tra 45im s0 45 67 89 10(

Phng nCTNCTNCTNCTNCTN

S HS4045940641169089

T l %4,4405010,1144,4471,911,1117,97100100

b) Nhn xt: Qua kt kim tra 45, ta thy HS lp TN l bi tt hn lp C c th, lp TN c 17,97% HS gii, cn lp C ch c 1,11% HS gii; lp TN c 71,97% HS kh, cn lp C ch c 44,44%. Qua chng t bi ging in t gp phn nng cao cht lng gio dc.D. KT LUN.Vy thng qua ti ny ti mun khng vai tr ca CNTT & TT ni chung ng dng trong dy hc v s bi ging in t ni ring trong dy hc l rt cn thit. V n mang li hiu qu cao trong gio dc, gp phn pht trin ngnh gio dc nc nh.

Thun li ca vic p dng bi ging in t l mang li hiu cao trong gio dc tuy nhin p dng c bi ging in t th phi c phng my, my chiu, GV phi u t nhiu vic son gio n. GV phi p dng linh hot trong vic s dng bi ging, khng p dng my mc hay l thuc hon ton vo my chiu, xem bi ging in t nh l cng c hu hiu gip GV hon thnh mc tiu gio dc ca mnh.E. NGHTuy nhin y ti mi ch nghin cu phm vi hp, hi vng trong thi gian ti ti c th nghin cu phm vi rng hn vi s lng hc sinh nhiu hn v cc phn hc khc ca chng trnh THPT, ch khng dng li phn hu c.

thun li cho vic s dng bi ging in t, th cc trng phi c my chiu, phng chc nng, kt ni internet. M rng ra c th p dng cho cc mn hc khc v cc lp hc khc c nhng lp bc hc khc nh THCS, tiu hc , i hc V vy mi trng phi c chin lc pht trin ring cho mnh, rt mong cc trng, cc c chc nng quan tm hn na n vic u t phng my, my chiu, phng tin dy hc.Yn nh, ngy .thng .nm 2012

Ngi vit bi.

L Vn Thnh* Ti liu tham kho.

[1]. Lut gio dc (2005), NXB Chnh tr quc gia, H Ni.[2]. Nhng vn chung v i mi gio dc THPT Mn Ha Hc, Nh xut bn gio dc (2007)[3] Nguyn Cnh Ton (2006), Gio n in t, con dao hai li, K yu Hi tho khoa hc: Cc gii php cng ngh v qun l trong ng dng CNTT&TT vo i mi dy hc, HSP H Ni, H Ni. [4]. Tn Quang Cng (2006), Mt s vn l lun dy hc trong xy dng bi ging in t, K yu Hi tho khoa hc: Cc gii php cng ngh v qun l trong ng dng CNTT&TT vo i mi dy hc, HSPHN, H Ni.[5] L cng Trim (2004), Bi ging in t v quy trnh thit k bi ging in t trong dy hc, K yu Hi tho khoa hc: i mi phng php dy hc vi s tham gia ca thit b k thut, HSP Hu, Hu.[6]. http://baigiang.bachkim.vn[7] Dng Huy Cn (2010), Tng cng nng lc t hc cho sinh vin ha hc trng HSP bng phng php t hc c hng dn theo m un, Lun n Tin s Gio dc hc, Trng i hc S phm H Ni, H Ni.[8]. Phm Vn Tin (2009), Xy dng bi ging in t mn hc phng php dy hc ha hc thuc chng trnh o to c nhn s phm ca khoa S phm - i hc Quc gia H Ni, Lun vn thc s khoa hc Gio dc, Trng HQG H Ni, H Ni.[9]. L cng Trim (2006), Nghin cu thit k bi ging in t trn Microsoft Power Point v Microsoft Frontpage, ti KH&CN cp B, m s: B2004-09-05, HSP Hu, Hu.[10] . Sch gio khoa ha hc lp 11 chng trnh chun.* Cc t vit tt trong bi:THPT: Trung hc ph thng

CNTT & TT: Cng ngh thng tin v truyn thngBG: Bi ging

GV: Gio vin ; HS: Hc sinh

BGT: Bi ging in t

C: i chng; TN: Thc nghim

MC LC

A. M U. 1

I. L do chn ti1

II. Mc ch nghin cu1

III.Nhim v nghin cu1

IV. Gii hn ca ti2

B. NI DUNG2

I. C s l lun2

II. C s thc tin2III. Xy dng h thng gio n in t31. Gio n in t v bi ging in t31.1 Khi nim31.2 Hc liu in t42. Quy trnh xy dng gio n in t52.1 Chun b kch bn52.2 Chun b hc liu52.3 Thit k gio n in t53. Thit k gio n in t phn Ha hc ha c73.1 Phn mm thit k gio n in t73.2 Phng php s dng gio n in t8IV. Tin hnh bi ging bng gio n in t91. Tin hnh bi ging in t9

2. Hnh thc nh gi gi dy12C. KT QU THC NGHIM13I. i vi GV d gi131. kin ca GV132. Kt qu iu tra thng qua phiu143. Nhn xt14II. i vi HS141. Thng qua phiu s 2142. Thng qua kt qu kim tra ngn153. Thng qua kim tra 4516D. KT LUN17E. NGH17

* Ti liu tham kho18

Mc lc 19

*Phn ph lc20PHN PH LC

Ph lc 1.

Phiu s 1. (Dnh cho GV)

CNG HA X HI CH NGHA VIT NAM

c lp -T do -Hnh phc

....0..

PHIU IU TRA

( kin ca GV d gi v bi ging in t)

Xin ng ( b) vui lng tr li (nh du vo trng) theo cc cu hi sau

I . PHN THNG TIN CHUNG

1. H v tn:.................................................Nam .N

2. Nm sinh:

3. Gio vin dy mn:

II. PHN CU HI

1. Theo /c, vic ng dng bi ging in t trong dy hc ni chung v dy hc ha hc ni ring hin nay l:

Rt cn thit( Cn thit ( Cha cn thit (2. nh gi nh th no v gi hc ha hc hu c c s dng bi ging in t ?

nh ging Khng ng

Gip HS tch cc nhn thc hn

Kch thch hng th hc tp ca HS

Truyn t c nhiu kin thc hn

Gi hc sinh ng hn, hp dn hn

HS d hiu bi v tip thu bi nhanh hn

Cht lng gi hc c nng cao

kin b sung:

3. Nhng kin khc v bi ging in t ?

..............................................................................................................

Xin trn trng cm n !

Ph luc 2.

Phiu s 2. (Dnh cho HS)CNG HA X HI CH NGHA VIT NAM

c lp -T do - Hnh phc

....0..

PHIU IU TRA

(Dnh cho hc sinh )

I. PHN THNG TIN CHUNG

H v tn:............................. Lp:

II. PHN CU HI

1. Hy cho bit kin ca em v nhng gi hc ha hc hu c c s dng bi ging in t?

Rt thch ( Bnh thng ( Khng thch (L do:

2. Dy hc bng cc BGT gip cc em tip thu kin thc nh th no ?

Kh tip thu ( D tip thu ( Bnh thng ( Rt d tip thu ( kin khc:

3. Theo em, ni dung no trong bi ging in t gy n tng v c ngha thit thc i vi vic tip thu kin thc ha hc hu c:

a) L thuyt (b) Tranh nh, hnh v, s , biu (c) Cc ni dung m phng (d) Th nghim (e) Bi tp (4. Theo em, vic ng dng bi ging in t trong dy v hc ha hc l:

Rt cn thit ( Cn thit ( Cha cn thit ( kin khc:

Ph lc 3.

Kim tra 45

I. Phn trc nghim(4)

Chn p n ng nht.1. C4H10 c s ng phn ankan l:

A. 1 B. 2 C. 3D. 4

2. hp cht c tn 2 metylbutan, c cng thc phn t l:

A. C3H8 B. C4H10C. C5H12D. C6H143. Cht no sau y khng lm mt mu dung dch brom.

A. Etan B. EtenC. EtinD. Etilen

4. Cht no sau y lm mt mu dung dch thuc tm.

A. metan B. AxetilenC. etanD. Propan

5. Khi t chy hon ton mt hidrocacbon thu c s mol CO2 bng s mol nc, th hp cht l:

A. Ankan B. AnkinC. AnkadienD. Anken

6. Trong s cc ankin c cng thc phn t C5H8 c my cht tc dng c vi dd AgNO3/NH3.

A. 1 cht B. 2 chtC. 3 cht D. 4 cht

7. ng vi cng thc phn t C5H8 c bao nhiu ankin l ng phn ca nhau.

A. 3 B. 4C. 2D. 5

8. t chy hon ton 3,36 lit axitilen thu c bao nhiu lt CO2 (cc kh ktc).

A. 3,36 lt B. 2,24 lt C. 4,48 lt D. 6,72 lt

II. T lun (6)

Bi 1 (2) Vit tt c cc ng phn ankan c cng thc phn t C5H12 v gi tn.

Bi 2. (3) Hon thnh cc phng trnh phn ng sau:

a) CH2 = CH2 + H2

b) CH2 = CH CH3 + H2O

c) n CH2 = CH2

d) CH CH + H2

e) CH CH + H2

f) CH CH + AgNO3 + NH3

Bi 3 (1) t chy hon ton 2,24 lt kh etilen (ktc) ri cho sn phm qua bnh nc vi trong d c mg kt ta. Tnh m.

(C = 12, O = 16, Ca = 40)

Bi lm t lun

Ma trn kim tra 45 kt hp gia TNKQ v TLNi dung

kin thcMc nhn thcCng

Nhn bitThng hiuVn dngVn dng mc cao

TNTLTNTLTNTLTNTL

1. Cu to halogen11

0,250,25

2. clo v hp cht ca clo12114

0,250,521,54,25

3. Brom v hp cht ca brom112

0,250,250,5

4. flo v iot, hp cht ca chng112

0,250,250,5

5. tng hp chng 511114

0,2520,2524,5

Tng s cu

Tng s im5

3

(30%)5

3

(30%)3

2,5

(25%)1

1,5

15%14

10

100%

p n

I. Trc nghim. Mi cu ng c 0,5

12345678

BCABDBAD

II. T lun.

Bi 1. C 3 ng phn / 2im

Ba 2: s : 1 phn ng ng/ 0,5

Bi3: m = 20g

Ph lc 4.

H thng bi kim tra ngn (5), kim tra sau mi gi dy.

1. Bi CTPT.

Cu 1. t chy hon ton 20mg hp cht hu c X ri dn ln lt sn phm qua cc bnh (1) ng CaCl2 khan v bnh (2) ng dung dch KOH d th thy bnh (1) tng thm 13,8mg v bnh (2) tng thm 67,7mg.

a) Cng thc n gin nht ca X l:

A. C2H2 B. CH4

C. C2H4

D. C3H6b) T khi hi ca X i vi H2 l 39. Cng thc phn t ca X l.

A. C2H4

B. C3H6

C. C4H8

D. C6H6Cu 2. xc nh thnh phn nh tnh v nh lng ca hp cht hu c X ngi ta thc hin th nghim sau:

Th nghim 1: Nung 3,325mg mt hp cht hu c Y trong dng oxi d thu c 6,600mg CO2 v 1,350mg H2O.

Th nghim 2: Nung 2,790mg hp cht Y vi CuO th thu c 0,335ml kh N2 ktc.

Bit t khi hi ca X so vi khng kh l 3,207.

Cng thc phn t ca X l:

A. C6H5N

B.C6H7N

C. C6H7N2

D. C6H5N2p n: 1a) B; 1b) D 2) B

2. Bi ankan (tit 1)

Cu 1. Ankan c cng thc chung l:

A. CnH2n+1 B. CnH2n C. CnH2n+2 D. CnH2n-1

Cu 2. Gc ankin c cng thc chung l:

A. CnH2n+1 B. CnH2n C. CnH2n+2 D. CnH2n-1

Cu 3. C cc ankan sau:

1) 2 metyl propan2) 2,2 imetylpropan

3) 3 etyl 2 metylpentan

4) hexan

5) pentan

Nhm no sau y thuc cc cht ankan phn nhnh:

A. 1,3,4

B. 2,3,5

C.1,2,3

D. 1,2,5

p n: 1.C; 2A; 3C.

3. Bi ankan (tit 2)

Cu 1. nhit v c xc tc thch hp, etan b oxi ha khng hon ton to thnh sn phm l:

A. CO v H2OB. CO2 v H2OC. CH3CH=O v H2OD. HCHO v H2O

Cu 2. t chy hon ton 2,24 ml mt hidrocacbon thu c 8,8g kh CO2 v 5,4g hi nc. Cng thc phn t ca hidrocacbon l:

A. C2H2

B. C2H4

C. C2H6

D. C3H8p n: 1C; 2C

4. Bi anken (t2)

Cu 1. Cho cc cht sau: (1) CH3CH(CH3)2; (2) CH2=CH2; (3) CH3CH=CHCH2CH3.

Cht c ng phn hnh hc l:

A. (1)

B. (2)

C. (3)

D. (2) v (3)

Cu 2. phn bit hai bnh cha kh etan v etilen, c th dng thuc th no sau y?

A. nc

B. Dung dch bromC. Kh HCl

D. Dung dch NaOH

Cu 3. Dn 0,448 lt kh C2H4 vo bnh ng 100ml dung dch KMnO4 0,01M. Hin tng quan st no sau y l ng?

A. Mu tm ca dung dch nht i, khng c kh thot ra.

B. Mu tm ca dung dch khng i, khng c kh thot ra.

C. Mu tm ca dung dch chuyn thnh khng mu, c kh thot ra.

D. Mu tm ca dung dch khng i, khng c kh thot ra.

p n: 1C; 2B; 3C

5. Bi ankin

Cu 1. Dng dung dch brom c th phn bit c cp kh no sau y?

1. metan v axetilen2. metan v etilen

3. etilen v axetilen4. propilen v xiclopropan

A. 1,3

B. 1,2

C. 2,3

D. 2,4

Cu 2. Dn 0,336 lt hn hp axetilen v etilen qua dung dch AgNO3/NH3 d thu c 0,112 lt kh cng iu kin. Phn trm th tch ca axetilen trong hn hp l:

A. 33,33%

B. 30%

C. 66,67%

D. 70%

Cu 3. C eten, etan v etin u c tnh cht ha hc ging nhau l:

A. c phn ng cng H2, halogen, HX.

B. C phn ng lm mt mu dung dch thuc tm.

C. C phn ng th halogen khi chiu sng, phn ng trng hp.

D. C phn ng oxi ha hon ton, ta nhit

p n: 1B; 2C; 3D

6. Bi benzen (t2)Cu 1. Hy ch ra sai.Cng thc cu to ca benzen c biu din bng mt hnh lc gic u v

A. 6 nguyn t C v 6 nguyn t H u nm trn mt mt phng.

B. Cc lin kt gia cc nguyn t C u c di bng nhau.

C. 6 obitan p xen ph bn to thnh mt h obitan lin hp cho c phn t.

D. Cc gc ha tr u bng 108o.

Cu 2. Nhm sn phm no sau y l ca phn ng gia toluen vi brom khan c bt st xc tc?

1. o-bromtoluen2. p-bromtoluen 3. benzen bromua4. etylbrombenzen

A. 1,3

B. 2,3

C. 1,4

D. 1,2

Cu 3. C th dng cht no sau y phn bit hai cht lng l benzen v toluen?

A. brom khan v bt st

B. Dung dch brom

C. Hn hp HNO3 v H2SO4 m c

D. Dung dch thuc tm nng

p n: 1D; 2D; 3D

7. Bi h thng v hiddrocacbon

Cu 1. t chy hon ton 0,65g hidrocacbon Y th lng thu c 1,12 lt kh CO2 ktc. Cng thc phn t ca Y l:

A. C6H12

B. C4H4

C. C6H6

D. C2H2Cu 2. Hn hp X gm hai ankan lin tip nhau trong dy ng ng. t chy hon 1,3 gam hn hp ny thu c 2,016 lt CO2 (ktc). Cng thc phn t hai ankan l:

A. C2H6, C3H8B. C3H8, C4H10C. C4H10, C5H12D. C5H12, C6H14Cu 3. Tng s ng phn ca c C5H12 v C3H6 l:

A. 5

B. 4

C. 3

D. 6

p n: 1C; 2C; 3A

8. Bi ancol (t2)

Cu 1. Cp phn ng ha hc no sau y dng iu ch metanol trong cng nghip?

1. 2CH4 + O2 2CH3OH

2. CO + 2H2 CH3OH

3. CH3Cl + NaOH CH3OH + NaCl

4. CH3ONa + HOH CH3OH + NaOH

A. 1,3

B. 2,3

C. 1,2

D. 2,4

Cu 2. Phn ng no sau y to thnh etilen?

A. C2H5OH tc dng vi H2SO4 m c, lnh

B. C2H5OH tc dng vi H2SO4 m c, nhit 140oC

C. C2H5OH tc dng vi H2SO4 m c, nhit 170oC

D. C2H5OH tc dng vi CuO nung nng

Cu 3. sn xut ancol etylic, ngi ta ly 9,72 kg mn ca c cha 50% xenluloz hiu sut ca c qu trnh l 70%. S gam ancol etylic thu c l:

A. 966

B. 3942,9

C. 2000

D. 1932

p n: 1C; 2C; 3D.

9. Bi phenol

Cu 1. Hp cht no sau y thuc loi phenol?

A. C6H5NH2

B. H3CC6H4OH C. C6H5CH2OH D.C6H5COOH

Cu 2. Cht no sau y phn ng c vi dung dch NaOH, vi dung dch brom ngay nhit thng?

A. C2H5OH

B. C2H5Cl

C. C6H5OH

D. C6H5Cl

Cu 3. phn bit hai dung dch C2H5ONa v C6H5ONa c th dng cht no sau y?

A. Kh CO

B. Kh CO2

C. Kh NH3

D. Kh O2p n: 1B; 2C; 3B

10. Bi anehit xeton (t2)

Cu 1. Dy cht no sau y u gm cc anehit?

A.HCHO, CH3CHO, C2H6O. B.CH3CH2CHO, C2H6O, CH3CH=CHCHO

C. HCHO, CH3CHO, CH3CH=CHCHOD.CH3CH2CHO, C2H6O, C2H4O2

Cu 2. Cng thc cu to (CH3)2CHCH2CH=O c tn gi l:

A. propanal

B. But 2 en 1 al

C. butan 2 on

D. 3 metylbutanal

Cu 3. Hy in cng thc thch hp vo ch c du ... v hon thnh cc PTHH sau:

a. CH3CH=O + H2 ...

b. ... + ... CH3CHOHCH3c. CH3CH2CHO + H2 ...

d. H2C=O + HOH...

p n: 1C; 2D; 3a) CH3CH2OH; 3b) CH3COCH3, H2;

3c) CH3CH2CH2OH; 3d) H2C(OH)2Ph lc 5. Cc hnh nh slide minh ha cho bi ankan - tit 2

Slide 1

Slide 2

Slide 3

Slide 4

Slide 5

Slide 6

Slide 7

Slide 8

Slide 9

Slide 10

Slide 11

Slide 12

0-4 5-6 7-8 9-10

PAGE 19

_1397999285.unknown

_1398031280.unknown

_1398032910.ppt

III. TNH CHAT HOA HOC

Nhan xet:

- Trong phn t ankan ch c lin kt bn vng.- Lin kt CC v CH khng phn cc.- Nguyn t C lin kt vi cc nguyn t khc, ngha l bo ha.

Ankan tr ve mat hoa hoc.

_1398032947.ppt

2. Phn ng tch:

a. Phn ng hy:

b. Phn ng tch hiro

c. Phn ng crackinh (t C3 tr ln)

CH4

CH2= CH2 + H2

800oC 900oC

CH3 CH3

Ni (Fe)

C + 2H2

to

CH3 CH2 CH3

CH2= CH2 + CH4

CnH2n+2

CmH2m+2 + CpH2p (m + p = n)

to

to

_1398032970.ppt

V. IEU CHE VA NG DUNG

1. ieu che:

b. Trong phng th nghim

a. Trong cng nghip

Mtan v ng ng ca n c ly t cc ngun kh thin nhin v du m.

CH3COONa + NaOH CH4 + Na2CO3

Al4C3 + 12H2O 3CH4 + 4Al(OH)3

CaO

to

_1398032991.ppt

Kh cu bay ln nh khng kh c t nng bi propan

Nn, giy nn, giy du

Du thp sng, un nu

Xng du cho ng c

Du m bi trn, chng g

ANKANparafin

_1398033000.ppt

Tnh cht ha hc c bn ca ankan l ..........................., v ..

- Phn ng th tc dng vi

- Phn ng tch

Phn ng th

Phn ng tch

Phn ng oxi ha

Clo/as

tc dng bi nhit

- Phn ng oxi ha .

tc dng vi O2/to

_1398032984.ppt

2. ng dung:

V. IEU CHE VA NG DUNG

_1398032960.ppt

3.Tac dung vi oxi: (phan ng oxi hoa)

CnH2n+2 + O2

n

(n+1)

to

CH4 + 2O2 CO2 + 2H2O + 880KJ

CH4 + O2 HCH=O + H2O

to

xtto

CO2 + H2O

_1398032927.ppt

HCH3 + ClCl

askt

Metyl clorua

HCH2Cl + ClCl

CCl4 + HCl

Metylen clorua

Cloroform

askt

askt

askt

CH2Cl2 + Cl2

CHCl3 + Cl2

H

CH3

Cl

Cl

+

H

Cl

CH2Cl

Cl

+

1. Phn ng th bi halogen

Cacbon tetra clorua

CHCl3 + HCl

_1398032938.ppt

1. Phn ng th bi halogen

CH3 CH3 + Cl2 CH3 CH2 Cl + HCl

askt

CH3 CH2 CH3 + Cl2

askt

CH2 CH2 CH3|Cl

CH3 CH CH3 | Cl

+ HCl

T C3H8 tr i u tin th C bc cao hn

Sn phm chnh

Cc ng ng khc ca Metan nh th no ?

_1398032920.ppt

III. TNH CHAT HOA HOC

ANKAN

Ch cho phn ng th, khng cho phn ng cng

Bn vi axit, kim, cht oxi ha iu kin thng

_1398032858.ppt

Vit CTCT ng phn ca C6H14 v c tn theo IUPAC

2.CH3 CH CH2 CH2 CH3 | CH3

3.CH3 CH2 CH CH2 CH3 | CH3

5.CH3 CH CH CH3 | | CH3 CH3

2 metylpentan

3 metylpentan

2,3 dimetylbutan

2,2 dimetylbutan

CH3 |4.CH3 C CH2 CH3 | CH3

n - hexan

1.CH3 CH2 CH2 CH2 CH2 CH3

_1398032901.ppt

ANKAN: TNH CHT HA HC - IU CH - NG DNG

Bai 25 Tit 2:

I. ng ng, ng phn,danh php.II. Tnh cht vt l

III. Tnh cht ha hcIV. ng dng v iu ch

NI DUNG

_1398031378.unknown

_1398029520.unknown

_1398029566.unknown

_1398031243.unknown

_1398029521.unknown

_1398028170.unknown

_1398029334.unknown

_1397999508.unknown

_1397053019.ppt

Nhc li cu to ca ANKEN?

Lin kt pi km bn

Phn ng cng

Phn ng oxi ha

Phn ng trng hp

M hnh anken

_1397998535.unknown

_1397999226.unknown

_1397998502.unknown

_1397052896.ppt

PHN NG CNG

_1397052974.ppt

Kh cu bay ln nh khng kh c t nng bi propan

Nn, giy nn, giy du

Du thp sng, un nu

Xng du cho ng c

Du m bi trn, chng g

ANKANparafin

_1390592444.unknown

_1390592589.unknown

_1397052739.ppt

DAY ONG ANG CUA METAN (ANKAN)

Bai 25

I. ng ng, ng phn,danh php.II. Tnh cht vt l

III. Tnh cht ha hcIV. ng dng v iu ch

NI DUNG

_1390592646.unknown

_1390592520.unknown

_1386680642.unknown

_1390592396.unknown