6
www.Padasalai.Net www.TrbTnpsc.com http://www.trbtnpsc.com/2017/12/sslc-10th-half-yearly-exam-questions-paper-and-answer-keys-download-2017.html SSLC HALF YEARLY EXAMINATION-2017 ANSWER KEY SECTION-I Q.NO ANSWER MARK 1 one egg and one sperm 1 2 Polio 1 3 thyroid gland 1 4 Aggregate fruit polyalthia 1 5 Camel 1 6 all the above 1 7 Methane 1 8 Colloidal solution 1 9 A and b 1 10 5 1 11 Ethane 1 12 1.467x m 1 13 It is measured using spring balance 1 14 Black 1 15 Both concave 1 SECTION-II 16 i) Genes ii) Allele 1+1=2 17 i) vitamins ii) Stem cells 1+1=2 18 Charles Darwin proposed the theory of Natural Selection. Principles of this theory: 1) Struggle for existence 2) Survival of the fittest. 1+1=2 19 i) BCG ii) tuberculosis 1+1=2 20 1+1=2 21 Anther Filament 1+1=2 22 In summer, we sweat more as a cooling mechanism, to conduct the heat out through the sweating process. This is possible with increased blood supply to the sweat glands. The kidneys expel less urine, since much of water is lost in the form of sweat. 2 23 i) leucocytes ii) diastole 1+1=2 24 1. Matured Red blood cells (RBC) are without nuclei. 2. Advantage : The space occupied by the nucleus is taken by the haemoglobin molecules. Haemoglobin molecules are concerned with carrying of respiratory gases. They carry oxygen from lungs to all cells of the body. 1+1=2 25 1. Plant waste products are stored in cellular vacuoles. 2. Waste products may be stored in leaves that fall. 1+1=2 26 1. Fishes take in water through their mouth and force it out through their gills, where the dissolved oxygen is absorbed by the blood. 2. As the gills cannot absorb oxygen from atmosphere, a fish cannot survive 1+1=2 www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasa www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasa www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasa www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasa www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasala www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasala www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasala www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasalai.Net www.Padasala

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Page 1: SSLC HALF YEARLY EXAMINATION-2017 ANSWER KEY  · PDF file10.12.2017 ·

www.Padasalai.Net www.TrbTnpsc.com

http://www.trbtnpsc.com/2017/12/sslc-10th-half-yearly-exam-questions-paper-and-answer-keys-download-2017.html

SSLC HALF YEARLY EXAMINATION-2017

ANSWER KEY

SECTION-I

Q.NO ANSWER MARK

1 one egg and one sperm 1

2 Polio 1

3 thyroid gland 1

4 Aggregate fruit – polyalthia 1

5 Camel 1

6 all the above 1

7 Methane 1

8 Colloidal solution 1

9 A and b 1

10 5 1

11 Ethane 1

12 1.467x m 1

13 It is measured using spring balance 1

14 Black 1

15 Both concave 1

SECTION-II

16 i) Genes ii) Allele 1+1=2

17 i) vitamins ii) Stem cells 1+1=2

18 Charles Darwin proposed the theory of Natural Selection.

Principles of this theory: 1) Struggle for existence 2) Survival of the fittest.

1+1=2

19 i) BCG ii) tuberculosis 1+1=2

20

1+1=2

21

Anther

Filament

1+1=2

22 In summer, we sweat more as a cooling mechanism, to conduct the heat out

through the sweating process. This is possible with increased blood supply to

the sweat glands. The kidneys expel less urine, since much of

water is lost in the form of sweat.

2

23 i) leucocytes ii) diastole 1+1=2

24 1. Matured Red blood cells (RBC) are without nuclei.

2. Advantage :

The space occupied by the nucleus is taken by the haemoglobin molecules.

Haemoglobin molecules are concerned with carrying of respiratory gases. They carry oxygen from lungs to all cells of the body.

1+1=2

25 1. Plant waste products are stored in cellular vacuoles.

2. Waste products may be stored in leaves that fall.

1+1=2

26 1. Fishes take in water through their mouth and force it out through their

gills, where the dissolved oxygen is absorbed by the blood.

2. As the gills cannot absorb oxygen from atmosphere, a fish cannot survive

1+1=2

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Page 2: SSLC HALF YEARLY EXAMINATION-2017 ANSWER KEY  · PDF file10.12.2017 ·

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for a long time when it is taken out of water.

27 i) contractile vacuole ii) cell membrane iii) excretory tube iv) nephridia 1+1=2

28 i) Carbondioxide ii) carbohydrate 1+1=2

29 i) Petroleum Reason: Petroleum is a fossil fuel while others are bio fuels

ii) Scabies Reason: Scabies is a water washed disease while others are water borne diseases

1+1=2

30 a) Reasons for the disease in city „A‟:

1. Poor hygiene 2. Inadequate quantity and quality of drinking water 3. Lack

of sanitation facilities

4. Contaminated water 5. Stagnant water which can cause mosquitoes to breed b) City „A‟ needs more effective system of waste-disposal and cleaning

1+1=2

31 Sources A B C

Renewable Hydrogen Wind Solar energy

Non-renewable Coal Natural gas Petroleum

1+1=2

32 i) 20g of NaCl in 100g of water Unsaturated solution

ii) 36g of NaCl in 100g of water Saturated solution

1+1=2

33 Tyndall Effect: The phenomenon by which colloidal particles scatter light is called Tyndall Effect. If a beam of light is allowed to pass through a true

solution, some of the light will be absorbed and some will be transmitted.

2

34 Solution: gram molecular mass of CO2 = 44g

Number. of molecules

6.023 x 1023 x 11

= ———————

44 = 1.51 x 1023 molecules

2

35 pOH = – log10 [OH–] = – log10 1.0 × 10–8

= – log10 10–8

= 8 log1010 = 8 pH + pOH = 14 pH = 14 – pOH pH = 14 – 8 = 6

2

36 i) tartaric acid ii) carbonic acid 1+1=2

37 a) assertion and reason are correct and relevant to each other 2

38 • It is extensively used in manufacturing electric cables and other electric

appliances.

• It is used for making utensils, containers, calorimeters and coins.

• It is used in electroplating. • It is alloyed with gold and silver for making coins and jewels.

2

39 In diamond each carbon atom is bonded to four other carbon atoms in

tetrahedral fashion leading to a rigid three dimensional structure, accounting

for its hardness and rigidity.

1+1=2

40 Positive, negative 1+1=2

41 i) One newton is the force that produces an acceleration of 1 ms–2 in an object

of 1 kilo gram mass.

ii) Action and reaction is always acting on two different bodies.

1+1=2

42 i) Electric fuse ii) jule’s law of heating

43 s.no components symbols

1 resistor 2 An electric cell

3 Plug key or

switch (closed)

4 Voltmeter

4x

=2

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44

Copper rod

Zinc rod

Dilute H2So4

Glass vessel

1+1=2

45 v

= – 6.9 cm 2

46 i)electro magnet ii) diaptre 1+1=2

47 Uses of Concave Mirror

i) Concave mirrors are commonly used in torches, search-lights and vehicles

head lights to get powerful parallel beams of light.

ii) They are used as shaving mirrors to see a magnified image of the face.

iii)The dentists use concave mirrors to see large images of the teeth of patients iv) Large concave mirrors are used to focus sun light to produce heat in

solar furnaces.

1+1=2

SECTION-III

48

PART-I

1. The sexual stage of Plasmodium takes place in female Anopheles mosquito whereas the vegetative stage occurs in man.

2. When a female Anopheles mosquito bites an infected person,

these parasites enter the mosquito and undergo further development in the mosquito body.

3. The parasites multiply within the body of the mosquito to form sporozoites that are stored in the salivary glands of

mosquito.

4. When these mosquitoes bite a person, the sporozoites (the infectious stage) are introduced into his body; they multiply

within the liver cells first and enter the RBC of man, resulting in the rupture of RBC.

5. This results in the release of toxic substance called haemozoin which is responsible for the chill and high fever,

recurring three to four days.

5

49 A nerve cell is a microscopic structure consisting of three major parts namely, cell body, dendrites and axon.

Cell body 1. The cell structure is irregular in shape or polyhedral.

2. It is also called cyton.

3. Cell body contains cytoplasm with typical cell organelles and certain granular bodies called Nissle’s granules.

4. Nissle’s granules are a group of ribosomes for protein synthesis. Dendrites 1. Dendrites or Dendrons are short fibres which branch repeatedly and protrude out of the cell body.

2. Dendrites transmit electrical impulses towards the cyton Axon 1. One of the fibres arising from the cell body is very long with a branched distal end and it is called Axon.

2. The distal branch of the axon terminates in bulb-like structures called synaptic knob filled with chemicals called neurotransmitters.

3. The cytoplasm of the axon is known as axoplasm.

4. The axon which is covered by a myelin sheath is formed of many

1+1+1=3

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layers of Schwann cells. The outermost layer of Schwann cells is called Neurilemma.

5. The gaps left by the myelin sheath are called Nodes of Ranvier. Neurilemma is discontinuous at Nodes of Ranvier.

6. The myelin sheath ensures rapid transmission of electric

impulses.

1+1=2

50 PART-II

i) Fertilization ii) The pollen tube enters into the embryo sac

through micropyle. At this time, the pollen tube bursts open,

gametes are released from the pollen tube and enter into the embryo sac. One of the gametes fuses with the egg, and the

other fuses with the secondary nucleus. The fusion of a male

gamete with egg is known as fertilization. The fertilized egg is

known as zygote which develops into embryo.

iii) Process of fertilization:

51 i) Bio-degradable wastes Non-bio-degradable

wastes

Wood, paper, grass. Plastic

ii) Substances that are broken down by biological process or microbial

action are called bio-degradable wastes. e.g. wood, paper, grass and leaves. Substances that are not broken down by biological or microbial

actions are called non-bio-degradable wastes. e.g. Plastic substances and

mineral wastes.

2+3=5

52 PART-III

i)3 moles ii) 1 moles iii) 2.5 moles

5

53 A homologous series is a group or a class of organic compounds having similar

structure and similar chemical properties in which the successive compounds

differ by a CH2 group.

Characteristics of homologous series: 1. Each member of the series differs from the preceding or succeeding member by

a common difference of CH2 and by a molecular mass of 14 amu (amu = atomic mass unit).

2+1+1+1=5

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2. All members of homologous series contain same elements and the same

functional groups.

3. All members of homologous series have same general molecular formula. e.g

Alkane = CnH2n + 2 Alkene = CnH2n Alkyne = CnH2n – 2

4. The members in each homologous series show a regular gradation in their

physical properties with respect to increase in molecular mass.

5. The chemical properties of the members of the homologous series are similar.

6. All members of homologous series can be prepared by using same general

method.

54 PART-IV

Consider two objects (two balls) A and B of masses ‘m1’ and ‘m2’ travelling in the same direction along a straight line at different

velocities ‘u1’ and ‘u2’ respectively. There are no other external unbalanced forces acting on them . Let u1 > u2 and the two balls

collide with each other as shown in Fig. 15.6(b). During collision which last for time ‘t’ , the ball A exerts a force F1 on ball B , and

the ball B exerts a force F2 on ball A. Let v1 and v2 be the velocities of two

balls A and B after collision respectively in the same direction

as before collision.

According to Newton’s second law of motion, The force acting on B (action) F1 = mass of B X acceleration on B

m2 (v2-u2) F1 = ————— ..... (1)

t The force acting on A (reaction) F2 = mass of A Xacceleration on

A m1 (v1-u1)

F2 = ————— ..... (2) t

According to Newton’s third law of motion, F1 = – F2 From equation (1) and (2)

m2 (v2-u2) – m1 (v1-u1) ————— = ————

t t m2 (v2 – u2) = –m1 (v1-u1)

m2v2 – m2u2 = –m1v1 + m1u1

m1v1 + m2v2 = m1u1 + m2u2

Therefore, m1u1 + m2u2 = m1v1 + m2v2

The total momentum before collision is equal to the total momentum after collision. The total momentum of two objects

remain unchanged due to collision in the absence of external force. This law holds good for any number of objects.

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55 a)

b) electric motor

c) S1 , S2 - Slip rings B1 , B2 - Carbon brushes N S - Magnetic field ABCD- Armature R - Resistor d) Fleming’s left hand rule e) split ring

5

Prepared by

M.KUMAR.M.Sc.,B.Ed., - PHYSICAL SCIENCE

G.SIVAPRAKASAM.M.Sc.,B.Ed.,M.Phil., - BIOLOGICAL SCIENCE Pve matric hr sec school - Dharmapuri

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