Supplemental Worksheet Problems To Accompany: …€¦ · Section 15 – Adding and Subtracting Polynomials Page 1 Supplemental Worksheet Problems To Accompany: Math Video Tutor DVD

© 2008 Jason Gibson / MathTutorDVD.com Math Video Tutor Fractions Thru Algebra Section 15 – Adding and Subtracting Polynomials

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Supplemental Worksheet Problems To Accompany:

Math Video Tutor DVD – Fractions Thru Algebra Section 15 – Adding and Subtracting Polynomials

Please watch Section 15 of this DVD before working these problems.

The DVD is located at:

http://www.mathtutordvd.com/products/item8.cfm


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1) Simplify the expression, if possible.





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10) Perform the indicated operation and simplify.




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Page 7

Question

Answer


Begin.

These are like terms because they each have an ‘x’ in them. Because of this, we can just add the coefficients. Since -2+3=1, the final answer is 1x, which is simply written as ‘x’.

Ans:


Page 8

Question

Answer


Begin.

These are like terms because they each have an ‘ ’ in them. Because of this, we can just add the coefficients.

Ans:


Page 9

Question

Answer


Begin.

These are like terms because they each have an ‘ ’ in them. Because of this, we can just subtract the coefficients.

Ans: 18xy2


Page 10

Question

Answer


Begin.

These are unlike terms because one term contains a’ ’ and the other contains a . In order for two terms to be like terms, the variables and exponents in the terms must match exactly. Because of this, can’t add anything and so this expression is already simplified.

Ans:


Page 11

Question

Answer


Begin.

These are like terms because they each have an ‘ ’ in them. Because of this, we can just subtract the coefficients.

Ans:


Page 12

Question

Answer


Begin.

These are all like terms because they each have an ‘ ’ in them. Because of this, we can just add/subtract the coefficients. First, add the first two terms.

Next, subtract the final two terms since they are like terms as well.

Ans:


Page 13

Question

Answer


Begin.

In this case only the last two terms are like terms because those terms contain ’ in them. So, add the coefficients of the last two terms. We can’t do any further simplification because these remaining terms are unlike.

Ans:


Page 14

Question

Answer


Begin.

First, we notice that we can “distribute” the exponent in the first term inside the parenthesis.

Now all terms are like terms because all terms have a in them. Add the first two terms.

Since these terms are also like, subtract the final two terms.

Ans:


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Question

Answer


Begin.

First, we notice that we can “distribute” the exponent in the first term inside the parenthesis. Do this first.

Since , rewrite the coefficient of the first term as ‘16’.

“Distribute” the exponent into the parenthesis of the second term. Remember when you raise an exponent to another exponent, you multiply the exponents.

Perform the multiplication in the exponent and rewrite as ‘9’.

These terms are like terms because each term has an in it. As a result, we can just subtract the coefficients.

Ans:


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Question

Answer


Begin.

We are adding two binomials here. Since they are just added together, we can drop the parenthesis.

We need to add like terms. ‘2y’ and ‘4y’ are like terms because they each have a ‘y’. Add these terms.

Next, add the numbers together. Since ‘6y’ and ‘4’ are not like terms, they can’t be added further. We are done.

Ans:


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Question

Answer


Begin.

We are subtracting two binomials here. Since the second binomial, (3b+5), is subtracted from the first, we need to distribute the implied “-1” into the second binomial.

Drop the first set of parenthesis.

We need to add like terms. ‘5b’ and ‘-3b’ are like terms because they each have a ‘b’. Add these terms. Since 5-3=2, the new coefficient of ‘b’ is ‘2’.

Next, perform the subtraction with the numbers. -7-5 = -12. Since the remaining terms are not like terms, they can’t be added further. We are done.

Ans:


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Question

Answer


Begin.

We are subtracting two binomials here. Since the second binomial, (2x+5y), is subtracted from the first, we need to distribute the implied “-1” into the second binomial.


We need to add like terms. ‘5x’ and ‘-2x’ are like terms because they each have a ‘x’. Add these terms. Since 5-2=3, the new coefficient of ‘x’ is ‘3’.

Now, “-8y” and “-5y” are also like terms. Combine these terms. Since -8-5 = -13, this is the new coefficient of ‘y’.

Ans:


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Question

Answer


Begin.

We are subtracting two trinomials here. Since the second trinomial is subtracted from the first, we need to distribute the implied “-1” into the second trinomial. You will end up multiplying each term in the second trinomial by “-1”.


We need to add like terms. Add with .

Add with .

Add “4” and “-7” together. All of these are unlike terms so we are done.

Ans:


Page 20

Question

Answer


Begin.

We are adding two trinomials here. We can drop all parenthesis.


Add with .

Add “-2” and “2” together. All of these remaining terms are unlike terms so we are done.

Ans:


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Question

Answer


Begin.

First, distribute the ‘5’ into the first set of parenthesis.

Distribute the ‘7’ into the second set of parenthesis.


Add with . These remaining terms are unlike terms so we are done.

Ans:


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Question

Answer


Begin.

First, distribute the ‘-4’ into the first set of parenthesis.

Distribute the ‘-5’ into the second set of parenthesis.


Add with . These remaining terms are unlike terms so we are done.

Ans:


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Question

Answer


Begin.

2x3 + 2x2 − 3x + 5+ 3x3 − 4x2 − x − 7

Since we are just adding these polynomials, we can drop the parenthesis and begin to look for like terms to add together.

Add and

Add with .

Add with .

Add ‘5’ with ‘-7’.

Ans:


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Question

Answer


Begin.

Since we are just adding these polynomials, we can drop the parenthesis and begin to look for like terms to add together.

Add and

Add with .

Add with .

Ans:


Page 25

Question

Answer


Begin.

Since we are subtracting one polynomial from the other, distribute the implied “-1” into the second polynomial.


Add and

Add with .

Add with .

Ans:

Documents

Supplemental Worksheet Problems To Accompany: …€¦ · Section 15 – Adding and Subtracting Polynomials Page 1 Supplemental Worksheet Problems To Accompany: Math Video Tutor DVD