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8/14/2019 The Four Noble Truths and the Hologram of Vision
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The Four Noble Truths of q , The Hologram of Vision
by Parker Matthew Davis Emmerson
Postulates, polar coordinates, etc.
(1)Sin@bD = h ê r
(2)Tan@bD = h ê r1
(3)Cos@bD = r1 ê r
(4)h = r Sin@bDr = h ê Sin@bD
Cos@bD = r1 ê r = r1 ê Hh ê Sin@bDL
In[1]:= Simplify@r1 ê Hh ê Sin@bDLD
Out[1]=
Sin@bD r1
h
Sin@bD r1
h= Cos@bD
Cos@bD ê Sin@bD =r1
h
In[185]:= PolarPlot@Cos@bD ê Sin@bD, 8b, - 13, 13<D
Out[185]=-5 5
-1.0-0.5
0.51.0
In[3]:= Plot@Cos@bD ê Sin@bD, 8b, - 13, 13<D
Out[3]=-10 -5 5 10
-6
-4
-2
2
4
6
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In[6]:= SolveBq r == 2 p HrL - 2 p HHrL^2 -h ^2L , hF
Out[6]= ::h Ø -4 p r2 q- r2 q2
2 p>, :h Ø
4 p r2 q- r2 q2
2 p>>
(5)
==
4 p2 p r Sin@bD
4 p q-q2
2
q-2 p r Sin@bD
4 p q-q2
2
q 2
2 p= rate * time = rate * 6 HH180ê pL qL
(6)::r Ø -
2 p h
4 p q - q2
>,:r Ø2 p h
4 p q - q 2
>>
(7)::r1Ø - r2 -h 2 >, :r1
Ø r2 -h 2 >>
(8)r1= r2 -h 2 = r Cos@bD
h r ar sp c al cas s of th s st m wh n h = r, wh n b = q ,
when r1 = rHthe initial conditionL, and when r1 = h.
(9)Usually, we would think that b § p ê 2, whereas q § 4 p.
We can show that q § 4 p by setting r equal to one in the equation r =2 p h
4 p q - q2
b § p ê 2 com s from th fact that wh n th con folds all th wa up,
it makes a right angle with the x axis.
In[1]:= SolveB1 ==2 p h
4 p q - q2
, hF
Out[1]= ::h ØH4 p-q Lq
2 p>>
In[2]:= Plot BH4 p -qL q
2 p , 8q, -13, 13<F
Out[2]=
-10 -5 5 10
0.2
0.4
0.6
0.8
1.0
Untitled-4
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There is a particularly interesting special case of the system, however,
when the square of the height of the cone is equal to the area of the base of the cone.
So What's the Point? How to Find the Four Noble q Solutions, or Truths of q .
r1 = r2 - h2
h = r Sin@bD
Out[6]= ::h Ø -4 p r2 q - r2 q2
2 p>, :h Ø
4 p r2 q - r2 q2
2 p>>
4 p r2 q - r2 q2
2 p ^ 2 = h ^ 2
In[7]:=
4 p r2 q - r2 q2
2 p
^ 2
Out[7]=
4 p r2 q - r2 q2
4 p2
4 p r2 q - r2 q2
4 p 2= p Hr1 ^ 2L = p Ir2
- h2M = p r2
-4 p r2 q - r2 q2
4 p 2
In[9]:= SolveBp r2-
4 p r2 q - r2 q2
4 p 2==
4 p r2 q - r2 q2
4 p 2, qF
Out[9]= ::q Ø4 p + 4 p2 - 16 p2 + 16 p3
2 + 2 p>, :q Ø
4 p + 4 p2 + 16 p2 + 16 p3
2
H1 + p
L>>
In[11]:= NB4 p + 4 p 2 - 16 p 2 + 16 p 3
2 + 2 p F
Out[11]= 3.19576
In[12]:= NB4 p + 4 p 2 + 16 p 2 + 16 p 3
2 H1 + p LF
Out[12]= 9.37061
In[10]:= SolveBp r2-
4 p r2 q - r2 q2
4 p 2
==4 p r2 q - r2 q2
4 p 2
, rF
Out[10]= 88r Ø 0<, 8r Ø 0<<Thus, we have shown that a point, by definition, is the place at which the square of the height of a cone is equal to the area of the
base of the cone when talking about a transition or even a translation of points along an axis. We have also shown that the point
has an inherent angle of 4 p+4 p2+ 16 p2+16 p3
2 H1+pLand
4 p+4 p2- 16 p2+16 p3
2+2 pradians.
So, what does q r look like now?
Untitled-4 3
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q r = r4 p + 4 p 2 + 16 p 2 + 16 p 3
2 H1 + p L, r
4 p + 4 p 2 - 16 p 2 + 16 p 3
2 + 2 p
v = l n = r H1 ê H1080 ê p L qL = DB4 p r2 q - r2 q2
2 p , qF
The velocity of h is equal to the first derivative of h with respect to time.
In[196]:= DB4 p r2 q - r2 q2
2 p , qF
Out[196]=
4 p r2 - 2 r2 q
4 p 4 p r2 q - r2 q2
In[192]:= SolveB4 p r2 - 2 r2 q
4 p 4 p r2 q - r2 q2
== r H1 ê H1080 ê p L qL, qF
Out[192]= ::q Ø p -1
2 . -194400
p4
+ 4 p2
+1
p4
28343520000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 +
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000 p
12+
253 899 891 671 040 000 p24MM 1ê3
-
1
2. -
388800
p4
+ 8 p2
-1
p4
28343520 000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 -
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000 p
12+
253 899 891 671 040 000 p24MM 1ê3
-4 665 600
p3
+ 64 p3 ì
4 . -194400
p4
+ 4 p2
+1
p4
28343520 000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 +
4 Untitled-4
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1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000
p12
+ 253 899 891 671 040 000 p24MM 1ê3 >,
:q Ø p -
1
2 . -
194400
p4 + 4 p2
+
1
p4 28343520 000 I2 ë I49589822592 000 000 + 503884 800
p12
+ ,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 +
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000 p
12+
253 899 891 671 040 000 p24MM 1ê3
+
1
2. -
388800
p4
+ 8 p2
-1
p4
28343520 000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24
MMM1ê3
-
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000 p
12+
253 899 891 671 040 000 p24MM 1ê3
-4 665 600
p3
+ 64 p3 ì
4 . -194400
p4
+ 4 p2
+1
p4
28343520 000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 +
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000
p12
+ 253 899 891 671 040 000 p24MM 1ê3 >,
:q Ø p +1
2. -
194400
p4
+ 4 p2
+1
p4
28343520 000 I2 ë I49589822592 000 000 + 503884 800
p12
+ ,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 +
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000 p
12+
Untitled-4 5
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253 899 891 671 040 000 p24MM 1ê3
-
1
2. -
388800
p4
+ 8 p2
-1
p4
28343520 000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24
MMM1ê3
-
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000 p
12+
253 899 891 671 040 000 p24MM 1ê3
+4 665 600
p3
+ 64 p3 ì
4 . -194400
p4
+ 4 p2
+1
p4
28343520 000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 +
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000
p12
+ 253 899 891 671 040 000 p24MM 1ê3 >,
:q Ø p +1
2. -
194400
p4
+ 4 p2
+1
p4
28343520 000 I2 ë I49589822592 000 000 + 503884 800
p12
+ ,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 +
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000 p
12+
253 899 891 671 040 000 p24MM 1ê3
+
1
2. -
388800
p4
+ 8 p2
-1
p4
28343520 000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 -
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000 p
12+
253 899 891 671 040 000 p24MM 1ê3
+4 665 600
p3
+ 64 p3 ì
6 Untitled-4
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4 . -194400
p4
+ 4 p2
+1
p4
28343520 000 I2 ë I49589822 592 000 000 + 503884 800 p12
+
,I49975115 677 610 803 200 000 000 p12
+ 253 899 891 671 040 000 p24MMM1ê3 +
1
3 p4
1
2I49589822 592 000 000 + 503884 800 p
12+ ,I49975115 677 610 803 200 000 000
p12
+ 253 899 891 671 040 000 p24MM 1ê3 >>
These are mathematical expressions of the reality of the four noble truths.
In[197]:= DB4 p r2 q - r2 q2
2 p , r, qF
Out[197]= -
I4 p r2 - 2 r2 qM I8 p r q - 2 r q2M8 p I4 p r2 q - r2 q2M3ê2 +
8 p r - 4 r q
4 p 4 p r2 q - r2 q2
In[198]:= SolveB - I4 p r2
- 2 r2
qM I8 p r q - 2 r q2
M8 p I4 p r2 q - r2 q2M3ê2
+8 p r - 4 r q
4 p 4 p r2 q - r2 q2
== r H1 ê H1080 ê p L qL, rF
Out[198]= ::r Ø -
2701
4 p-q+
4 p
q2
-3
q
p2 q
>, :r Ø
2701
4 p-q+
4 p
q2
-3
q
p2 q
>>
In[199]:= PlotB:-
2701
4 p-q+
4 p
q2-
3
q
p 2 q
,
2701
4 p-q+
4 p
q2-
3
q
p 2 q
>, 8q, - 13, 13<F
Out[199]=-10 -5 5 10
-30
-20
-10
10
20
30
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In[209]:= PolarPlotB:-
2701
4 p-q+
4 p
q2-
3
q
p 2 q
,
2701
4 p-q+
4 p
q2-
3
q
p 2 q
>, 8q, - 10, 10<F
Out[209]=-10 -5 5 10
-15
-10
-5
5
10
15
r2- h
2
2 p h
4 p q - q2
= r =
2701
4 p-q+
4 p
q2-
3
q
p 2 q
In[210]:= SolveB2 p h
4 p q - q2
==
2701
4 p-q+
4 p
q2-
3
q
p 2 q
, hF
Out[210]= ::h Ø
1351
4 p-q+
4 p
q2
-3
q4 p q - q2
p3 q >>
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In[211]:= PlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 13, 13<F
Out[211]=
-10 -5 5 10
10
20
30
40
50
60
In[212]:= PolarPlotB135
1
4 p-q
+4 p
q2
-3
q
4 p q - q2
p 3 q
, 8q, - 13, 13<F
Out[212]=-20 -10 10 20 30 40
-40
-20
20
40
Untitled-4 9
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In[217]:= PolarPlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 130, 130<F
Out[217]=-20 -10 10 20 30
-30
-20
-10
10
20
30
In[213]:= PolarPlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 1300, 1300<F
Out[213]=-20 -10 10 20 30
-30
-20
-10
10
20
30
10 Untitled-4
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In[216]:= PolarPlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 13 000, 13 000<F
Out[216]=
-10 -5 5 10 15
-10
-5
5
10
15
In[218]:= PolarPlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 130000, 130000<F
Out[218]=-5 5
-5
5
Untitled-4 11
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In[219]:= PolarPlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 1 300 000, 1300000<F
Out[219]=-5 5
-5
5
In[220]:= PolarPlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 13000000, 13 000 000<F
Out[220]=-5 5
-5
5
12 Untitled-4
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In[221]:= PolarPlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 130000 000, 130 000000<F
Out[221]=-5 5
-5
5
In[222]:= PolarPlotB135
1
4 p-q+
4 p
q2-
3
q4 p q - q2
p 3 q
, 8q, - 1 300 000 000, 1300000000<F
Out[222]=-5 5
-5
5
Untitled-4 13
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SolveB2160 c q
4 p - q
==2 p r Sin@qD
4 p q - q2
, rF
::r Ø1080 c q H4 p - qL q Csc@qD
p4
p - q
>>
::n Øp 4 p - q q Sin@qD
180 H4 p - qL q
>>
In[142]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 1, 1<F
Out[142]=
-0.005 0.005
0.002
0.004
0.006
0.008
0.010
0.012
In[159]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 10, 10<F
Out[159]=
-0.005 0.005
0.005
0.010
0.015
14 Untitled-4
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In[160]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 100, 100<F
Out[160]=
-0.005 0.005
0.005
0.010
0.015
In[161]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 1000, 1000<F
Out[161]=
-0.005 0.005
0.005
0.010
0.015
Untitled-4 15
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In[162]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 10 000, 10 000<F
Out[162]=
-0.005 0.005
0.005
0.010
0.015
In[163]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 100000, 100000<F
Out[163]=
-0.005 0.005
0.005
0.010
0.015
16 Untitled-4
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In[164]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 1 000 000, 1000 000<F
Out[164]=
-0.005 0.005
0.005
0.010
0.015
In[165]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 10000000, 10000000<F
Out[165]=
-0.005 0.005
0.005
0.010
0.015
Untitled-4 17
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In[166]:= PolarPlotBp 4 p - q q Sin@qD
180 H4 p - qL q
, 8q, - 100000 000, 100 000000<F
Out[166]=
-0.005 0.005
0.005
0.010
0.015
Special Case 1, q = b
Some velocity, which is the first derivative of the equation for q r, is the angular velocity, and is equal to a wavelength of
frequency. Some velocity, which is the first derivative of r is the transitional velocity, and is equal to a the distance, r being a
wavelength,
::r Ø -2 p h
4 p q - q2
>, :r Ø2 p h
4 p q - q2
>>
h = r Sin@bD = r Sin@qD
4 p 2 p r Sin@bD
4 p q-q2
2
q -2 p r Sin@bD
4 p q-q2
2
q2
2 p =
4 p 2 p r Sin@qD
4 p q-q2
2
q -2 p r Sin@qD
4 p q-q2
2
q2
2 p =
4 p 2 p HrL Sin@qD
4 p q-q2
2
q -2 p HrL Sin@qD
4 p q-q2
2
q2
2 p
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In[124]:= PlotB
4 p 2 p Sin@qD
4 p q-q2
2
q -2 p Sin@qD
4 p q-q2
2
q2
2 p , 8q, - 13, 13<F
Out[124]=
-10 -5 5 10
0.2
0.4
0.6
0.8
1.0
Untitled-4 19
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In[123]:= PolarPlotB
4 p 2 p Sin@qD
4 p q-q2
2
q -2 p Sin@qD
4 p q-q2
2
q2
2 p , 8q, - 13, 13<F
Out[123]=-0.4 -0.2 0.2 0.4
-1.0
-0.5
0.5
1.0
20 Untitled-4
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In[126]:= PolarPlotB
4 p 2 p Sin@qD
4 p q-q2
2
q -2 p Sin@qD
4 p q-q2
2
q2
2 p , 8q, - 1300, 1300<F
Out[126]=-0.4 -0.2 0.2 0.4
-1.0
-0.5
0.5
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8/14/2019 The Four Noble Truths and the Hologram of Vision
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In[186]:= PolarPlotB
4 p 2 p Sin@qD
4 p q-q2
2
q -2 p Sin@qD
4 p q-q2
2
q2
2 p , 8q, - 13000000, 13 000 000<F
Out[186]=-0.4 -0.2 0.2 0.4
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Contour is said to be the experience of this kind of polar equation from information available in light. Light is interpreted in the
polar coordinate system by a human being when perception occurs. How it is interpreted depends partially on how you see
something. For instance, I can see this graphed contour like a cylinder or two spheres. We call this a conisphilinder. It's holo-
graphic characteristic is the first special case.
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