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Learn How to create pyramids in c
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How to Create Pyramids in C
Learn Creating Pyramids
2 lines
3 lines
4 lines
Analysis-1.Input – number of lines(n) given by user(4 in
the above case)
2.Output – n number of lines and n number of stars in each line(above shape has 4 lines and each line has 4 stars)
4 lines
Design-1. One loop is needed for n
number of lines2. And other loop is needed for n
stars in each line3. Printing element *4. New line after printing all
elements in line
Coding-
for(lines=1;lines<=n; lines++){
for(elements=1;elements<=n; elements++){
printf(“*”);}printf(“\n”);
}
Coding-
for(lines=1;lines<=n; lines++){
for(elements=1;elements<=n; elements++){
printf(“*”);}printf(“\n”);
}
1 to n means n times(for n lines)
Coding-
for(lines=1;lines<=n; lines++){
for(elements=1;elements<=n; elements++){
printf(“*”);}printf(“\n”);
}
1 to n means n times(for n stars)
Coding-
for(lines=1;lines<=n; lines++){
for(elements=1;elements<=n; elements++){
printf(“*”);}printf(“\n”);
}
New line after printing all stars in line
Coding-
for(lines=1;lines<=n; lines++){
for(elements=1;elements<=n; elements++){
printf(“*”);}printf(“\n”);
} Printing element *
Coding-
for(lines=1;lines<=n; lines++){
for(elements=1;elements<=n; elements++){
printf(“*”);}printf(“\n”);
}
1 to n means n times(for n lines)
1 to n means n times(for n stars)
New line after printing all stars in line
Printing element *
Complete Program#include<stdio.h>main(){ int n, lines, elements; printf("enter how many lines "); scanf("%d", &n); for(lines=1;lines<=n; lines++) { for(elements=1;elements<=n; elements++) { printf("*"); } printf("\n"); }}
How program works?-1Suppose n =31. lines=1, lines<=n means 1<=3(true)
i. elements=1, elements<=n means 1<=3(true)print *elements++ = 2
ii. elements=2, elements<=n means 2<=3(true)print *elements++ = 3
iii. elements=3, elements<=n means 3<=3(true)print *elements++ = 3
iv. elements=4, elements<=n means 4<=3(false)NEW LINE lines++= 2
Output
*** _
How program works?-22. lines=2, lines<=n means 2<=3(true)
i. elements=1, elements<=n means 1<=3(true)print *elements++ = 2
ii. elements=2, elements<=n means 2<=3(true)print *elements++ = 3
iii. elements=3, elements<=n means 3<=3(true)print *elements++ = 3
iv. elements=4, elements<=n means 4<=3(false)NEW LINE
lines++= 3
Output
*** _*** _
How program works?-33. lines=3, lines<=n means 3<=3(true)
i. elements=1, elements<=n means 1<=3(true)print *elements++ = 2
ii. elements=2, elements<=n means 2<=3(true)print *elements++ = 3
iii. elements=3, elements<=n means 3<=3(true)print *elements++ = 3
iv. elements=4, elements<=n means 4<=3(false)NEW LINE
lines++= 4
Output
*** _*** _*** _
How program works?-41. lines=3, lines<=n means 4<=3(false)
LOOP FinishedOutput *** _*** _*** _
Question
Q. What is ‘n’ in Coding Section?A. n is the number of lines and number of stars in each line, given by user. Q. Can we execute loop from n to 1?A. Yes, lines and elements both loop can be run from n to 1. We can also run one loop from 1 to n and other from n to 1. It will create no effect on output.
Run lines loop from n to 1
for(lines=n;lines>=1; lines--){
for(elements=1;elements<=n; elements++){
printf(“*”);}printf(“\n”);
}It will create no effect on output.
Run elements loop from n to 1
for(lines=1;lines<=1; lines++){
for(elements=n;elements>=1; elements--){
printf(“*”);}printf(“\n”);
}It will create no effect on output.
Run both loops from n to 1
for(lines=n;lines>=1; lines--){
for(elements=n;elements>=1; elements--){
printf(“*”);}printf(“\n”);
}It will create no effect on output.
Second Pyramid
4 lines
3 lines
2 lines
Analysis-1. Input – number of lines(n) given by user(4 in the above case)
2. Output –a. n number of lines b. Line 1 -> 1 starLine 2 -> 2 starsLine 3 -> 3 starsLine n -> n stars
4 lines
Design-1. One loop is needed for n number of
lines2. And other loop is needed for
printing elements 3. Number of elements = line number4. Printing element *5. New line after printing all elements
in line
Coding-
for(lines=1;lines<=n; lines++){
for(elements=1;elements<=lines; elements++){
printf(“*”);}printf(“\n”);
}
New Change
Complete Program#include<stdio.h>main(){ int n, lines, elements; printf("enter how many lines "); scanf("%d", &n); for(lines=1;lines<=n; lines++) { for(elements=1;elements<=lines; elements++) { printf("*"); } printf("\n"); }}
How program works?-1Suppose n =41. lines=1, lines<=n means 1<=3(true)
i. elements=1, elements<=lines means 1<=1(true)print *elements++ = 2
ii. elements=2, elements<=lines means 2<=1(false)NEW LINElines++= 2
Output
* _
How program works?-22. lines=2, lines<=n means 2<=3(true)
i. elements=1, elements<=lines means 1<=2(true)print *elements++ = 2
ii. elements=2, elements<=lines means 2<=2(true)print *elements++ = 3
iii. elements=3, elements<=lines means 3<=2(false)
NEW LINElines++= 3
Output
* _** _
How program works?-33. lines=3, lines<=n means 3<=3(true)
i. elements=1, elements<=lines means 1<=3(true)print *elements++ = 2
ii. elements=2, elements<=lines means 2<=3(true)print *elements++ = 3
iii. elements=3, elements<=lines means 3<=3(true)print *elements++ = 4
iv. elements=4, elements<=lines means 4<=3(false)NEW LINElines++= 4
Output
* _** _*** _
How program works?-44. lines=4, lines<=n means 4<=3(false) Output
* _** _*** _
