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Page 1: Relations and Functions 1

Physics Helpline

L K Satapathy

Relations & Functions Theory 1

Page 2: Relations and Functions 1

Physics Helpline

L K Satapathy

Cartesian Product of Sets :

Cartesian Product of two non-empty Sets A and B is the set of all

ordered pairs (x , y) , such that x A and y B

In set notation we write A B = { (x , y) : x A , y B }

Properties :

(i) Two ordered pairs are equal if and only if the two elements of one is equal to

the corresponding elements of the other.

(x , y) = (a , b) x = a and y = b [ (x , y) (y , x) ]

(ii) n(AB) = n(A).n(B)

If A has (p) elements and B has (q) elements , then (AB) has (pq) elements

(iii) A A A = { (x , y , z) : x , y , z A }

Here (x , y , z) is called an ordered triplet

Relations & Functions Theory 1

Page 3: Relations and Functions 1

Physics Helpline

L K Satapathy

2 5 11 , ,

3 3 3 3

xy

Example : Find the values of x and y , if

Answer :

Two ordered pairs are equal if and only if the corresponding elements are equal

2 5 11 , ,

3 3 3 3

xy

51 3 5 2 [ ]

3 3Anx x s

x

2 1 1 21

3 3 3 3[ ]and y y Ans

5 2 11

3 3 3 3

xand y

Relations & Functions Theory 1

Page 4: Relations and Functions 1

Physics Helpline

L K Satapathy

Answer :

Example : The cartesian product A A has 9 elements which includes the

ordered pairs (– 1 , 0) and (0 , 1) . Then find AA

It is given that

2( ) ( )Let n A p n A A p p p

2( ) 9 9 3n A A p p

Also ( 1 , 0) 1 0A A A and A

(0 , 1) 1A A A

{ 1 , 0 , 1}A

{( 1 , 1),( 1,0),( 1,1),(0, 1),

(0,0),(0,1),(1, 1),(1,0),( ) ]1,1 } [Ans

A A

Relations & Functions Theory 1

And

Page 5: Relations and Functions 1

10/11/2015

Physics Helpline

L K Satapathy

If (x , y) R , then y is called the image of x in R

Relation : A relation R from a non-empty set A to a Non-empty set B

is a subset of the cartesian product A B

Relations & Functions Theory 1

Domain of R : It is the set of the 1st elements of the ordered pairs in R

Range of R : It is the set of the 2nd elements of the ordered pairs in R

Co-domain of R : If R (A B) , then set B is the co-domain of R

2pq

If A has (p) elements and B has (q) elements , then (AB) has (pq) elements

Number of Subsets of A B =

Total number of Relations from Set A to Set B = 2pq

Page 6: Relations and Functions 1

10/11/2015

Physics Helpline

L K Satapathy

(iii) Arrow diagram :

Relations & Functions Theory 1

Domain of R = { 1 , 2 , 3 , 4 , 5 }1

2

3

4

5

6

1

2

3

4

5

6

Range of R = { 2 , 3 , 4 , 5 , 6 }

Co-domain of R = { 1 , 2 , 3 , 4 , 5 , 6 }

Representation of a relation : Consider a set A = { 1 , 2 , 3 , 4 , 5 , 6 }

A relation on set A may be represented as follows :

(i) Set builder form : R = { (x , y) : y = x + 1 ; x , y A }

(ii) Roster form : R = { (1 , 2) , (2 , 3) , (3 , 4) , (4 , 5) , (5 , 6) }

Page 7: Relations and Functions 1

10/11/2015

Physics Helpline

L K Satapathy

Example : Consider a relation R on N , in set builder form , given by

Relations & Functions Theory 1

R = { (x , y) : y = x + 5 ; x , y N , x < 4 }

Represent this relation in Roster form. Write its domain and range.

Answer :

In Roster form R = { (1 , 6) , (2 , 7) , (3 , 8) }

Domain of R = { 1 , 2 , 3 }

Range of R = { 6 , 7 , 8 }

Let us draw the Arrow diagram for better understanding:

1

2

3.

.

.

.

.

.

.

6

7

8.

.

.

NN

Page 8: Relations and Functions 1

Physics Helpline

L K Satapathy

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