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ISAT 413 - Module IV:Combustion and Power Generation
Topic 1: Combustion Theory and Fundamentals
Introduction Conversion of Mechanical Energy Conversion of Electrical Energy Conversion of Electromagnetic Energy Conversion of Chemical Energy Combustion Mechanics
2
Introduction
Thermal energy is a basic form of energy in that all other energy forms can be completely converted into thermal energy.
Unless the energy stored as some other form, it will eventually be degraded into thermal energy (the term “degraded” is used because the conversion of thermal energy into other energy forms is limited to something less than 100%.)
3
The conversion of mechanical energy into thermal energy occurs in any irreversible process and can be summarized in essentially one word ─ friction.
In many processes, friction is considered to be an undesirable phenomenon and every effort is made to reduce or eliminate it. This is particularly true in most thermodynamic or lubrication processes.
Friction is not always bad, however. If it were not for the friction between the soles of your shoes and the floor, it would be impossible to walk. If it were not for the friction between the brake shoes and the drum of the automobile wheel, it would not be possible to convert the kinetic energy of the automobile into thermal energy and stop the car.
Conversion of Mechanical Energy
4
Electrical energy can be converted into thermal energy in several processes but the principal energy-conversion process is the joule-heating process. This is the iv or i2R loss encountered when an electrical current of i amperes is passed through a resistance of R ohms as the result of a potential difference of v volts. The resulting power loss or thermal energy production rate is in watts.
In most electrical circuits, the joule-heating loss is an undesirable power loss. However, in some systems, such as electric ranges and furnaces, this process is useful in the production of thermal energy.
Conversion of Electrical Energy
5
Another electrical power loss associated with alternating-current systems is the power-factor loss. When electrical energy is passed through a capacitor or an induction coil, part of this energy is stored in the electrostatic and magnetic field associated with each impedance. When the capacitive and inductive impedances are matched (in-phase), there is no power loss. Otherwise, the excess electrical energy generated from the collapse of electrostatic and magnetic fields (when the current reverses) will be converted into thermal energy, which means that the electrical utility must supply more energy to the customers than is actually metered in order to overcome the power-factor, cos(), loss.
cosVIP rmsrmsavg
6
The conversion of electromagnetic energy into thermal energy is accomplished in some sort of absorption process. For high-energy electromagnetic radiation such as gamma radiation and x-rays, the absorption process is a volumetric phenomenon. For low-energy radiation, the absorption process is usually a surface phenomenon. Many materials are transparent to some wavelengths of radiation and opaque to other wavelengths. Glass is transparent to the ultraviolet and visible portions of the thermal radiation spectrum but is opaque to the infrared radiation emitted by most surfaces. This leads to the so-called greenhouse effect and is useful in trapping solar energy.
Conversion of Electromagnetic Energy
7
The primary source of fuel energy is the production of thermal energy from chemical energy. The most important exothermic chemical reaction in the production of this energy is the combustion of fossil fuels. This reaction is an oxidation reaction in which the three combustible elements found in most of the fossil fuels, i.e., carbon, hydrogen, and sulfur, are respectively converted into carbon dioxide (CO2), water (H2O), and sulfur dioxide (SO2).
The following section on the conversion of chemical energy deals primarily with the mechanics of the combustion reaction as well as some of the principal systems and components needed to accomplish the process.
Conversion of Chemical Energy
8
If there is sufficient oxygen, it will be assumed that all the hydrogen burns (582oC ignition temperature) completely to water before any of the carbon or sulfur burns.
Combustion Reactions
]kJ/kg.mol286,470[ 2222 22 HQQOHOH HH
The mass of oxygen requires to completely burn a unit mass of hydrogen is
2
2
2
2
2
2 94701622
32
2
1
H
O.
H.
O
H
O
kg
kg
g
g
mol
mol
The higher heating value of hydrogen (equivalent to QH) is 142,097 kJ/kg and the lower heating value is 120,067 kJ/kg.
9
The product of the oxidation of sulfur (243oC ignition temperature) is sulfur dioxide (SO2), is considered to be a major atmospheric pollutant:
]kJ/kg.mol296,774[ SQQSOOS SS 22
The mass of oxygen requires to completely burn a unit mass of sulfur is
S
O.
S.
O
S
O
kg
kg
g
g
mol
mol 222 99800632
32
1
1
The higher and lower heating values of sulfur are the same and equal to 9257 kJ/kg. Because the low ignition temperature, it will be assumed for combustion with incomplete air that all the sulfur burns after the hydrogen burns and before any carbon burns.
10
Carbon is one of the most important combustible elements and is an essential part of any hydrocarbon compound. Despite its high ignition temperature (407oC), the oxidation of carbon is slower and more difficult than that of either hydrogen or sulfur.
]kJ/kg.mol393,560[ CQQCOOC CC 22
The mass of oxygen requires to completely burn a unit mass of sulfur is
C
O.
C.
O
C
O
kg
kg
g
g
mol
mol 222 6620112
32
1
1
The higher and lower heating values of carbon are the same and equal to 32,778 kJ/kg.
11
Almost all combustion processes rely on air as the source of oxygen. Air is composed of approximately 21% oxygen and 79% nitrogen by volume or mole. These values translate to 23.2% oxygen and 76.8% nitrogen on a gravimetric or mass basis. The molecular weight of air is 28.97 kg/kg.mol (or 28.97 lbm/lbm.mol).
The theoretical or stoichiometric air-fuel ratio gives the minimum air requirements for complete combustion of a fuel.
Theoretical Air-Fuel Ratio
23202
.
O
F
A
D.G.T
fuel kg per air the from needed kg
The factor of 0.232 in the denominator is the mass fraction of oxygen in the air.
12
Since most coal analyses are listed as dry, ash-free values, it is often easier and faster to use the following equation for coals:
2320
19980947662 22
.
AMOS.H.C.
F
A
D.G.T
Where the moisture (M) and ash (A) are as-burned values and all other values are dry, ash-free values.
The theoretical, molar, dry air-fuel ratio can be obtained as
Where Zi is the number of moles of the i th element per mole of fuel, and
21024
.
ZZ
ZZ
F
AO
SH
C
D.M.T
fuel of weightmolecularD.M.T
D.G.T
F
A.
F
A
9728
13
gas air/lbm lbm
gas air/mol of mol
gas of H/mol mol
gas of C/mol mol
60% and 40% Given
50155152
10289728
1028210
20042963
00
291060840
6346034010483
..
..
F
A
..
//..
F
A
;.ZZ
...Z
...Z
HCHC
:Solution
D,G,T
D.M.T
SO
H
C
Example 3.2:
Calculate the theoretical, gravimetric, dry air-fuel ratio when burning a LPG composed of 40% propane and 60% butane, in lbm air/lbm.
14
The five requisites for good combustion are MATT stands for proper mixing (M) of the reactants; sufficient air (A); a temperature (T) above the ignition temperature; sufficient time (T) for the reaction to occur; and a reactant density () sufficient to propagate the flame.
Since perfect mixing is never attained in the actual combustion process, good combustion can only assured by supplying excess air for the process. Care must be exercised to keep the amount of excess air to a minimum because too much excess air increases the losses in the combustion process and increases NOx emissions.
The exhaust or flue gas includes the products of complete (CO2, H2O, and SO2) and incomplete combustion (CO, hydroxyls, aldehydes, ash particles, …)
Actual Combustion Process
15
There are two ways of expressing the amount of air supplied for a given combustion process ─ the dilution coefficient and the percent excess air.
The dilution coefficient is defined as the ratio of the actual to the theoretical air-fuel ratios, or
The percent excess air is defined by the following equations:
Percent Excess Air
theo
act
A/F
A/FDC tcoefficien Dilution
1100
100
DC
A/F
F/AA/F
theo
theoact
air excess Percent
16
A typical orsat gas analyzer is shown in the Figure at right is used to determine the volumetric or molar fractions of carbon dioxide, oxygen, and carbon monoxide in the dry exhaust gas.
A 100-cm3 sample of exhaust gas is taken at room temperature in the burette by using the leveling water bottle to collect and transfer the gas sample.
The Orsat Flue-Gas Analyzer
17
Since the gas is collected at room temperature over water, it is usually assumed that any water vapor in the exhaust gas will have condensed and that any sulfur dioxide in the exhaust gas will have reacted with the water in the exhaust gas and in the collecting bottle. Consequently, it is assumed that the resulting “dry” gas sample is composed of carbon dioxide, oxygen, carbon monoxide, and nitrogen. The process can be divided into 4 stages (with 3 chemical reactions):
1. An aqueous solution of potassium hydroxide (KOH) CO2
2. A solution of pyrogalic acid in KOH O
3. A solution of cuprous chloride in ammonia CO
4. The remaining Nitrogen
An orsat analysis is required and usually is sufficient to determine the actual air-fuel ratio when burning a gaseous fuel or liquid fuel.
18
The refuse analysis is used to evaluate the actual air-fuel ratio when burning a solid fuel such as coal, it is simply an experimental determination of higher heating value, HHV, of the refuse.
The Refuse Analysis
32,778
sekJ/kg.refu HHV,
HHV
HHVecombustibl Percent
carbon
refuse 100100
The refuse mass fraction, R, can be obtained from
rA/R
AR
coal, the in ash of fraction mass
coal of mass
refuse of mass
The mass of unburned carbon in the refuse per mass of fuel consumed, Cr, can be found from either of the following equations:
19
ARCR
CRRC r
rr or
100
ecombustibl percent
Thus, the mass of carbon actually burned per unit mass of fuel, Cb can be obtained from the following equation:
rultb CCC
Where Cult is the carbon mass fraction from the as-burned ultimate fuel analysis.
Once the refuse analysis, the orsat analysis of the flue gas, and the ultimate analysis of the coal are known, the actual air-fuel ratio can be evaluated.
20
Actual Gravimetric Dry Air-Fuel Ratio
7680
1
0112
01628
7680 2
2
.N
.CO%CO%
C.N%
.
N
F
AF
bA
D,G,A
ratio fuel-airdry c,gravimetri Actual,
Where the number of moles of carbon monoxide and carbon dioxide in the exhaust gas per unit mass of coal is Cb/12.01, NF is the gas-burned nitrogen mass fraction of the fuel (from the ultimate analysis), and NA is the mass of nitrogen from the air per unit mass of coal. And
790
1
22
2
.
Z
CO%CO%
ZN%
F
A NC
D,M,A
ratio fuel-airdry molar, Actual,
Where ZC an ZN are the moles of carbon and nitrogen per mole of fuel, respectively.
21
Wet Air-Fuel Ratios
In all of the equations for the air-fuel ratios, the ratio is given for dry air only. In reality, atmospheric air contains water vapor, the “wet” air-fuel ratios can be obtained by multiplying the “dry” gravimetric ratios by 1 + , or multiplying the “dry” molar values by (1 + /0.622) where is the humidity ratio or mass of water vapor per unit mass of dry air, and 0.622 = Ra / Rw. Thus, the ratios become:
D,M,AW,M,AD,G,AW,G,A
D,M,TW,M,TD,G,TW,G,T
F
A
.F
A
F
A
F
A
F
A
.F
A
F
A
F
A
622011
622011
;
;
22
Excess Air Theoretically, oxygen and carbon monoxide cannot appear simultaneously in the exhaust gas but they commonly appear in the exhaust gas because of poor mixing. A common rule of thumb states that the approximate percent excess air is 5 times the oxygen percentage in the orsat analysis, if the %CO is small and the %O2 is less than 5. For O2 concentration greater than 5%, the rule of thumb significantly underestimates the percent excess air.
Burning a fuel with insufficient air gives the maximum power from a limited volume as in the internal combustion engine and also produces higher specific power from rockets. Reducing the combustion air reduces NOx, although it does increase the pollution associated with the emission of CO and unburned fuel.
23
%....
CO%O%CO%
...
AM
SN
OHC
:Solution
35811509335714100
100
7801001201
1
22
2
22
gas exhaust in N %
analysis burned-as a for Multiplier
kJ/kg. 33,422 HHV and , 5.6% , 1.3%
, 8.4% , 5.5% , 79.2% :E Appendix from analysis coal Ultimate
2
Example 3.3:
A certain power plant burns Clay County, Missouri, coal with M = 12% and A = 10%, and an analysis of the refuse pit shows that the higher heating value of the refuse is 4581 kJ/kg. An orsat analysis of the flue gas gives 14.57% CO2, 3.93% O2, and 0.15% CO. Find the dilution coefficient and the percent excess air.
24
coal air/kg kg
:ratio fuel-air ltheoretica The
coal C/kg burned kg
coal C/kg unburned kg
coal refuse/kg kg
refuse ash/kg kg
refuse the in ecombustibl
refuse refuse/kg in C kg
analysis, refuse the From
4578
2320
08400560998005509477920662780
60150016307920780
0163010011630
1163086020100
86020139800101
9813
1398077832
4581
.
.
........
F
A
....CCC
...ARC
../.R/A
AR
...R
C.
R
A
%.
.,R
C
D,G,T
rb
r
r
r
r
r
25
19.7%
:air excess percent for thumb of rule the Using
air excess Percent
DC tcoefficien Dilution
coal air/kg kg
:ratio fuel-air Actual
%.
%.DC
..
.
F/A
F/A
..
..../...
.
NCO%CO%/CN%.
F
A
D,G,T
D,G,A
Fb
D,G,A
9335
2191100
19214578
08110
081107680
013078015057146015035813322
7680
3322 22
26
09020450
060105020050
6340304870
985020301870105010050
..Z
...Z
...Z
.....Z
:Solution
N
O
H
C
analysis, gas the From
Example 3.5:
A natural gas with the following molar analysis is burned in a furnace: CO2 = 0.5%, CO = 5.0%, CH4 = 87.0%, C2H4 = 3.0%, and N2 = 4.5%. An orsat analysis gives the following results: 9.39% CO2, 3.88% O2, and 8.3% CO. Calculate the percent excess air and the actual air-fuel ratio in kilogram of air per kilogram of fuel gas.
27
%.
...
CO%O%CO%N%
.
....
......
..
.
/./..
.
/ZZ/ZZ
F
A OSHC
D,M,T
985
830883399100
100
67817
0162804500528030
0416870012805001440050
83388338
210
206004639850
210
24
222
:analysis orsat From
gas of kg/kg.mol
gas of (MW) weightMolecular
gas air/ft ft gas air/mol mol 33
28
.
.
..
MW
F/A.
F
A
%..DC
..
.
F/A
F/A
..
/.../..
.
/ZCO%CO%/N%Z
F
A
D,M,A
A,G,D
D,M,T
D,M,A
NC
D,M,A
gas air/kg kg
ratio fuel-airdry c,gravimetri Actual,
air excess Percent
DC tcoefficien Dilution
gas air/mole moles
081767817
423109728
9728
018118011001100
18018338
42310
42310790
20908303999859850
790
222
29
The actual combustion process for fossil fuels proceeds in one of two ways:
Blue-Flame Combustion ─ If gaseous hydrocarbon fuel are mixed with some air and heated before the actual combustion takes place, the oxygen reacts with hydrocarbon and formed hydroxylated compounds (aldehydes). The flame resulting from the combustion of these compounds is a “blue” or “nonluminous” flame.
Yellow-Flame Combustion ─ Introduction of fuel and air at the burner with no premixing and heating of the reactants. The flame resulting from this mode of combustion is a “yellow” or “luminous” flame. This is desired in a large power boiler because it increases the radiative heat-transfer rate from the flame to the boiler tubes, reducing the combustion temperature.
Combustion Mechanics
30
Three basic physical methods are utilized for the combustion of fossil fuels:
The burning-bed system ─ it is commonly employed in the combustion of solid fuels, the solid fuel is burned in either a stationary bed or a fluidized-bed.
The traveling-Flame-front combustion system ─ it is applicable where the reactant (fuel and oxidant) are completely mixed before combustion occurs. When ignition takes place, the flame front progressively moves through the mixture (for internal combustion engine, etc.)
The gaseous-torch combustion system ─ it is commonly used in large power installations and, in essence, the fuel and air are mixed and burned at the burner. Heavy fuel oil must be atomized, coal must be pulverized to a texture finer than face powder.
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