Chapter 7 Lecture Basic Chemistry Fourth Edition 7.3 Calculations Using Molar Mass Learning Goal...

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Chapter 7 Lecture

Basic ChemistryFourth Edition

7.3 Calculations Using Molar Mass

Learning Goal Given the number of moles of a substance, calculate the mass in grams; given the mass, calculate the number of moles.

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Chapter 7 Chemical Quantities

The molar mass

• is a useful conversion factor

• converts moles of a substance to grams

• converts mass in grams of a substance to moles

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Using Molar Mass

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Guide to Calculating Moles from Grams or Grams from Moles

Silver metal is used in the manufacture oftableware, mirrors, dental alloys, and jewelry. If the design for a piece of jewelry requires0.750 mole of silver, how many grams of silverare needed?

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Learning Check

If the design for a piece of jewelry requires0.750 mole of silver, how many grams of silverare needed?

Step 1 State the given and needed quantities.Given: 0.750 mole of AgNeed: grams of Ag

© 2014 Pearson Education, Inc.

Solution

If the design for a piece of jewelry requires0.750 mole of silver, how many grams of silverare needed?

Step 2 Write a plan to convert moles to grams.

0.750 mol of Ag grams of AgMolar MassMolar Mass

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Solution

If the design for a piece of jewelry requires0.750 mole of silver, how many grams of silverare needed?

Step 3 Determine the molar mass and write conversion factors.

© 2014 Pearson Education, Inc.

Solution

© 2014 Pearson Education, Inc.

Solution

If the design for a piece of jewelry requires0.750 mole of silver, how many grams of silverare needed?

Step 4 Set up the problem to convert moles to grams (or grams to moles).

Conversion factors are written for compounds inthe same way as those written for elements.

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Conversion Factors for Compounds

A box of salt contains 737 g of NaCl. How manymoles of NaCl are present in the box?

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Learning Check

A box of salt contains 737 g of NaCl. How manymoles of NaCl are present in the box?

Step 1 State the given and needed quantities. Given: 737 g NaCl Need: moles of NaCl

© 2014 Pearson Education, Inc.

Solution

A box of salt contains 737 g of NaCl. How manymoles of NaCl are present in the box?

Step 2 Write a plan to convert grams to moles.

grams of NaCl moles of NaClMolar MassMolar Mass

© 2014 Pearson Education, Inc.

Solution

© 2014 Pearson Education, Inc.

Solution

A box of salt contains 737 g of NaCl. How many moles of NaCl are present in the box?

Step 3 Determine the molar mass and write conversion factors.

(1 × 22.99) + 1(35.45) = 58.44 g/mol

A box of salt contains 737 g of NaCl. How manymoles of NaCl are present in the box?

Step 4 Set up the problem to convert grams to moles.

© 2014 Pearson Education, Inc.

Solution

© 2014 Pearson Education, Inc.

Summary of Conversions

Grams ofelement or compound

Moles ofelement or compound

Atoms of element or molecules of compound

Molar Massg/mol

Avogadro’sNumber

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Converting Mass to Molecules

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Guide to Calculating Particles from Mass

A 10.00-lb bag of table sugar contains 4536 g ofsucrose, C12H22O11. How many molecules of

sucrose are present?

© 2014 Pearson Education, Inc.

Learning Check

A 10.00-lb bag of table sugar contains 4536 g ofsucrose, C12H22O11. How many molecules of

sucrose are present?Step 1 State the given and needed

quantities.Given: 4536 g sucrose, C12H22O11

Need: molecules of sucrose

© 2014 Pearson Education, Inc.

Solution

A 10.00-lb bag of table sugar contains 4536 g ofsucrose, C12H22O11. How many molecules of

sucrose are present?Step 2 Write a plan to convert grams to

particles.

grams of sucrose

moles of sucrose

molecules of

sucroseMolar MassMolar Mass Avogadro’s

NumberAvogadro’s

Number

© 2014 Pearson Education, Inc.

Solution

A 10.00-lb bag of table sugar contains 4536 g ofsucrose, C12H22O11. How many molecules of

sucrose are present?Step 3 Write the equalities and conversion

factors.

© 2014 Pearson Education, Inc.

Solution

A 10.00-lb bag of table sugar contains 4536 g ofsucrose, C12H22O11. How many molecules of

sucrose are present?Step 4 Set up the problem to convert grams

to particles.

© 2014 Pearson Education, Inc.

Solution

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