dx = x + y - Los Angeles Mission College...(c) Sketch the curve ๐‘ฆ๐‘ฆ(๐‘ฅ๐‘ฅ) if the initial...

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1 dy . . - = -y - sm xdx

....

3 2

0

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ '.' , ' . ' , โ€ข I " , " " " " .... ...... ..... ..... , "

/ / 1 1 / / /

- 1 I ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ

I I I I I I \ I I I I I I I I I I I 1.1 I I . I I . 1 I I I I I I I I , \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

1 1 1 1 1 1 1 1 / / / / "" "" "" ""' / /

- 2 ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ๏ฟฝ ๏ฟฝ ๏ฟฝ j ๏ฟฝ }.; ๏ฟฝ ;๏ฟฝ ๏ฟฝ ๏ฟฝI I I I I I I I I 1 1 1 / / / 1 / 1I I I I I I I I I I 1 1 1 1 1 1 1 1

-๏ฟฝ3 -2 - 1 0 2

dy 2. dx = x + y

- - / / / / 1 1 1- - - / / / / / /

2 ""-= ::: :::: ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ ๏ฟฝ

x

I I I I I I II I I I I I I lei I . I Ie I I I I I I I I I I I I I I I I I I I I I I I I I I / / 1 1 1 1 1 1 1/ / 1 1 1 1 1 1 1/ / / / / 1 1 1 1

3

.... o ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ-+--๏ฟฝ๏ฟฝ+ยฅ๏ฟฝ๏ฟฝ

- 1

- 2

3 dy . . - = y - sm xdx

2

I I I I I I I I I I I I I I I I I I Ie I lei I I I I I I I I I I I I I I I I I I I I

x

I I I I 1 I 1 1 11 1 / / / / 1 1 1I I ,. / / /., / I / / / / / / / / /

/ I I I I I I / I / 1 1 1 1 1 1 / // / / I / / / / .;/๏ฟฝ-๏ฟฝ๏ฟฝ

- 1 " ..... ...... ...... ..... , , '

-2 \ ๏ฟฝ ๏ฟฝ๏ฟฝ ๏ฟฝ ๏ฟฝ๏ฟฝ ๏ฟฝ ๏ฟฝ \ \ \ \ \ \ \ \ \\ \ \ \ \ \ \ \ \ -๏ฟฝ3 -2 - 1 0

x 2

3

3

dy 4. - = x - ydx

2

- 1

-2 : :: :': :: ;๏ฟฝ ๏ฟฝ j - - - / / / / 1 1- - / / / / 1 1 1

-๏ฟฝ3 -2 - 1

dy 5. - = Y - x + 1dx

I I 2 I I I I

๏ฟฝ.๏ฟฝ I I .... 0

I I

o 2 x

- - - ..... , ' \ \ \ ./ - - ..... , ' \ \ \ \

- 1

- 2

- 1

dy 6. - = x - y + ldx

2

\ I I I I I \ \ \ I I I I 1 \ ' 1 .1 I . \ \ . ' \ \ \ \ \ \ \ \ , \ \ \ \ \ \ \ " \ \ \ \ \ \ " " .....

o x

- ..... " " \ '.' \ \ ...... , ' \ \ \ \ \ \ " \ \ \ \ \ \ \, \ \ \ \ \ \ \ \ , 1ยท 1 I I e.. I I , I I I I I \ \ I , \ I I I I \ I I

2

, ... , \ \ ' , ...... -\ \ \ \ ' , ..... - - ./

\ ,

- 1 : : _ _ ๏ฟฝ ; ๏ฟฝ ๏ฟฝ j- - - / / / 1 1 1

-2 :: ; ๏ฟฝ๏ฟฝ ๏ฟฝ ๏ฟฝ๏ฟฝ ๏ฟฝ ๏ฟฝ / / / / 1 1 1 1 /./ / I I I I I I I

-๏ฟฝ3 -2 - 1 0 x

3

3

Differential Equation - Spring 2015 - Classwork 1Instructor: Emil Sargsyan

Name: _____________________________

In problems 1-6 one of the solutions of the differentialequation is given. Sketch additional solutions through the given points.

7. Suppose the differential equation ๐‘‘๐‘‘๐‘‘๐‘‘๐‘‘๐‘‘๐‘‘๐‘‘

= ๐‘“๐‘“(๐‘ฅ๐‘ฅ,๐‘ฆ๐‘ฆ) has ๐‘”๐‘”(๐‘ฅ๐‘ฅ) as its solution. We know that the slope of the graph of ๐‘”๐‘” at the point (๐‘ฅ๐‘ฅ,๐‘ฆ๐‘ฆ) is the product of ๐‘ฅ๐‘ฅ and ๐‘ฆ๐‘ฆ. What is ๐‘“๐‘“(๐‘ฅ๐‘ฅ,๐‘ฆ๐‘ฆ)?

8. (a) Sketch the slope field of the differential equation ๐‘‘๐‘‘๐‘‘๐‘‘๐‘‘๐‘‘๐‘‘๐‘‘

= ๐‘ฆ๐‘ฆ. The vectors donโ€™t have to be precise, and be sure to produce the vectors at the positions (0,0), (1,0), (0,1), (-1,0), (0,-1),(0,3), (3,0), (0,-3), (-3,0).

(b) Solve the differential equation ๐‘ฆ๐‘ฆโ€ฒ = ๐‘ฆ๐‘ฆ

(c) Sketch the curve ๐‘ฆ๐‘ฆ(๐‘ฅ๐‘ฅ) if the initial value is ๐‘ฆ๐‘ฆ(0) = 0.5.

(The curve does not have to be precise.)

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