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Page 1 of 15
International Indian School, Dammam Upper Primary Sections
2020-2021
Class V Mathematics Class work and Home work to be done in Mathematics Notebook
C.W. 5.4.2020 Addition of Large numbers
Addition of large numbers is the same as for smaller numbers. The numbers we add are
called addends and the answer in addition is called the sum or the total.
The properties of addition of large numbers are also the same as for smaller numbers.
We can add numbers in any order and still the sum will be the same. Eg. 3,092 + 1,200 = 1,200 + 3,092
Zero added to any number gives the same number as the sum. Eg. 7,689 + 0 = 7,689
Example 1: Add 61,327 and 39,855
L TTh Th H T O 1 1 1 6 1 3 2 7
+ 3 9 8 5 5
1 0 1 1 8 2 Answer: Sum = 1,01,182
H.W. of 5.4.2020
Arrange in columns and add: A. 5,087 + 26,542 B. 65,875 + 75,842
C. 45,735 + 69046 D. 93,485 + 48,294 E. 2,87,635 + 26,542
Answers for H.W of 5.4.2020:
A. 5,087 + 26,542 = 31,629 B. 65,875 + 75,842 = 1,41,717
C. 45,735 + 69,046 = 1,14,781 D. 93,485 +48294 = 1,41,779
E. 2,87,635 + 26,542 = 3,14,177
Page 2 of 15
C.W. 6.4.2020 Addition of Large numbers
Example 1: Add 2,753+ 26,932 + 1, 47,841 Example 2: Add 54,567 + 45,765 + 12,636
L TTh Th H T O L TTh Th H T O 1 2 1 1 1 1 1 2 7 5 3 5 4 5 6 7
2 6 9 3 2 4 5 7 6 5
+ 1 4 7 8 4 1 + 1 2 6 3 6
1 7 7 5 2 6 1 1 2 9 6 8 _ Answer: Sum = 1,77,526 Answer: Sum = 1,12,968
H.W. of 6.4.2020
Arrange in columns and add: A. 51,487 + 456 + 2, 39,601
B. 1,11,321 + 56,789 + 45,987 C. 1,08,162 + 59,346 + 18,882
Answers for H.W of 6.4.20:
A. 51,487 + 456 + 2,39, 601 = 2,91,544
B. 1,11,321 + 56,789 + 45,987 = 2,14,097
C. 1, 08,162 + 59,346 + 18,882 = 1,86,390
C.W. 7.4.2020 Subtraction of Large numbers
Recalling what is subtraction and the related terms:
Terms like take away and find the difference imply subtraction. To answer questions like how many left, how many more, how many less, we do subtraction. Terms used in subtraction are minuend, subtrahend and the difference.
The number we subtract from is called the minuend. The number we subtract is called the subtrahend. The answer in subtraction is called the difference. 7 3 9 5 Minuend
- 3 2 8 2 Subtrahend
4 1 1 3 Difference
Page 3 of 15
Example 1: Find the difference: 48,259 – 37,146 and check your answer with addition.
TTh Th H T O Check: 1 1 1 1 3
4 8 2 5 9 + 3 7 1 4 6
- 3 7 1 4 6 4 8 2 5 9 Minuend
1 1 1 1 3
Answer: Difference = 1 1, 1 1 3
H.W of 7.4.2020 Subtract and check your answer with addition:
a) 93,542 – 78,645
b) 9, 38,743 – 78,243
c) 85290 – 74,882
Properties of Subtraction
A number subtracted from itself is equal to zero. 852 - 852 = 0 Zero subtracted from a number is equal to the number itself. 852 – 0 = 852 The properties of subtraction and the method of subtraction of large numbers are the same as they are for smaller numbers.
Example 3:
Page 4 of 15
Answers for H.W of 7.4.2020:
Solution: Check:
b) 9,38,743 – 78,243
Solution: Check:
c) 85,290 – 74,882
Solution: Check:
T Th Th H T O
1 1 1 1
1 4 8 9 7
+ 7 8 6 4 5
9 3 5 4 2
T Th Th H T O
8 12 14 13
9 3 5 4 12
- 7 8 6 4 5
1 4 8 9 7
Ans:
L T Th Th H T O
8
9 13 8 7 4 3
- 7 8 2 4 3
8 6 0 5 0 0
Ans:
L T Th Th H T O
1
8 6 0 5 0 0
+ 7 8 2 4 3
9 3 8 7 4 3
T Th Th H T O
4 8
8 5 12 9 10
- 7 4 8 8 2
1 0 4 0 8
Ans:
T Th Th H T O
1 1
1 0 4 0 8
+ 7 4 8 8 2
8 5 2 9 0
Minuend
Difference: 8,60,500
Minuend
Difference: 10, 408
Minuend
Difference: 14,897
Page 5 of 15
C.W 8.4.2020 Subtraction of Large numbers (Continued)
Example 1: Find the difference: 4, 39,235 - 1, 45,987 and check your answer with addition.
L TTh Th H T O
4 3 9 2 3 5
- 1 4 5 9 8 7
2 9 3 2 4 8
Answer: Difference = 2, 93,248
Example 2: Find the difference: 30,000 - 18,603 and check your answer with addition
TTh Th H T O
3 0 0 0 0
- 1 8 6 0 3
1 1 3 9 7
Answer: Difference = 11,397
Example 3: Find the difference: 40,001 - 27,505 and check your answer with addition.
TTh Th H T O
4 0 0 0 1
- 2 7 5 0 5
1 2 4 9 6
Answer: Difference = 12,496 H.W of 8.4.2020
Subtract and check your answer with addition
a) 21,976 – 8,756 b) 50,001 – 39,846 c) 20,106 – 15,302 d) 81,065 – 21,952
Check: 2 9 3 2 4 8
+ 1 4 5 9 8 7
4 3 9 2 3 5 Minuend
Check: 1 1 3 9 7
+ 1 8 6 0 3
3 0 0 0 0 Minuend
Check: 1 2 4 9 6
+ 2 7 5 0 5
4 0 0 0 1 Minuend
Page 6 of 15
Solutions / Answers for H.W of 8.4.2020
Subtract and check your answer with addition:
a) 21,976 – 8,756
Check:
b) 50,001 – 39,846
Check:
c) 20,106 – 15,302 Check:
d) 81,065 – 21,952 Check:
T Th Th H T O
1
2 11 9 7 6
- 8 7 5 6
1 3 2 2 0
Ans:
T Th Th H T O
1
1 3 2 2 0
+ 8 7 5 6
2 1 9 7 6
T Th Th H T O
4 9 9 9
5 10 0 0 11
- 3 9 8 4 6
1 0 1 5 5
Ans:
T Th Th H T O
1 1 1 1
1 0 1 5 5
+ 3 9 8 4 6
5 0 0 0 1
T Th Th H T O
1 1
4 8 0 4
+ 1 5 3 0 2
2 0 1 0 6
T Th Th H T O
1 9 8
2 10 11 0 6
- 1 5 3 0 2
0 4 8 0 4
Ans:
T Th Th H T O
7 10
8 1 10 6 5
- 2 1 9 5 2
5 9 1 1 3
Ans:
T Th Th H T O
1 1
5 9 1 1 3
+ 2 1 9 5 2
8 1 0 6 5
Difference: 10, 155
Minuend
Difference: 13,220
Minuend
Minuend
Difference: 4, 804
Difference: 59,113
Minuend
Page 7 of 15
9.4.2020 C.W. Problem Solving in Addition and Subtraction
Page 8 of 15
Solution for H.W given on 9.4.2020
No. of motorbikes produced by a factory in the year 2015 = 28,900 No. of motorbikes not sold in the year 2015 = 4,795 No. of motorbikes sold in the year 2015 = 24,105 (28,900 – 4,795) Answer: No. of motor bikes sold in 2015 were = 24,105
C.W. 12.4.2020 Problem Solving (Continued)
a) Sushil’s car travelled 25,384 km in one year and Suraj’s car travelled 30,001 km in the
same year. How many kilometres less did Sushil’s car run?
Solution
Distance Sushil’s car travelled in a year = 25,384 km 3 0 0 10 1 Distance Suraj’s car travelled in that year = 30,001 km Distance Sushil’s car travelled less by = 4,617 km (30,001 km – 25,384 km) Answer: Sushil’s car ran less by 4,617 km
H.W of 9.4.2020
Write Correct Statements and solve the following in your Math Notebook.
1) A factory produced 28,900 motorbikes in the year 2015. Out of these 4,795 motorbikes were not sold. Find out how many motorbikes were sold in 2015.
1 1
2 8 9 0 0 - 4 7 9 5 2 4 1 0 5 Check: 4795 + 24105
28900
1
9 2
1
9 9
1
30001 - 25384 4617 Check: 4617 + 25384
30001
Page 9 of 15
b) Mr. Shenoy had Rs. 3, 25,765. He borrowed Rs.1, 12,700 to buy a new car. How much did
the car cost?
Solution
Amount Mr.Shenoy had = Rs. 3, 25,765 Amount he borrowed to buy a car = Rs. 1, 12,700 The cost of the car = Rs. 4, 38,465 (Rs. 3,25,765 + Rs. 1,12,700)
Answer: The cost of the car = Rs.4, 38,465
H.W of 12.4.2020
Write correct statements and solve the following :
1) In an examination 3, 59,089 boys and 4, 23, 085 girls participated. Find the number of students participated in the examination. 2) The population of a town in the year 1995 was 6, 80,301 and it increased by 1,52,028 in the year 2000. Find the population in the year 2000.
Solution for H.W of 12.4.2020
1) In an examination 3, 59,089 boys and 4, 23, 085 girls participated. Find the number of students participated in the examination. No. of boys participated in an examination = 3,59,089 No. of girls participated in the examination = 4, 23,085 Total No. of students participated = 7, 82,174 (3,59,089 + 4,23,085) Answer: No. of students participated in the exam = 7, 82,174 2) The population of a town in the year 1995 was 6, 80,301 and it increased by 1, 52,028 in the year 2000. Find the population in the year 2000.
Solution The population of a town in 1995 = 6, 80,301 Increase of the population in 2000 = 1, 52,028 The population in 2000 = 8, 32,329 (6,80,301 + 1,52,028) Answer: The population of the town in 2000 = 8,32,329
1
325765
+ 112700
438465
3,59,089 + 4,23,085 7,82,174
6 8 0 3 0 1
+ 1 5 2 0 2 8
8 3 2 3 2 9
680301 + 152028 832329
Page 10 of 15
C.W 13.4.2020 Missing Addend
Missing Addend = Sum – Given Addend Solve:-
Example 1: A pen drive can hold 530 songs. So far 391 songs have been copied on to it. How many more songs can be copied on to the pen drive?
Example 2: What must you add to 7,328 to make it 14,095?
7,328 + ___________ = 14,095
Missing Addend = Sum - Given Addend
= 14,095 - 7,328
= 6,767
Answer: 6,767 must be added to 7,328 to make it 14,095.
Example 3:
Solve :- 7,394 + _________ = 12,642
Missing Addend = Sum - Given Addend
= 12,642 - 7,394
= 5,248
Answer: 7,394 + 5,248 = 12,642
H.W of 13.4.2020
Solve following questions in your note book:-
a) 612 + _______ = 948 b) What must you add to 18,345 to make it 19,624? c) The sum of two numbers is 40,132. If one number is 29,184, find the other number.
Total number of songs a pen drive can hold
530
391 + ______ = 530
Number of songs already copied
391 530
- 391
Number of songs yet to be copied(530 – 391)
139 139
Answer: 139 more songs can be copied on to the pen drive.
14095 - 7328 6767
12642 - 7394 5248
Page 11 of 15
Solutions for H.W of 13.4.2020
a) 612 + _______ = 948
Solution:
Missing Addend = Sum - Given Addend 948 = 948 - 612 -612 = 336 336 Ans:- 612 + 336 = 948 b) What must you add to 18,345 to make it 19,624? Solution:-
Given Addend = 18,345 19624
Sum = 19,624 -18345
Missing Addend = Sum – Given Addend 01279 = 19,624 – 18,345
= 1,279
Ans:- 1,279 must be added to 18,345 to make it 19,624
c) The sum of two numbers is 40,132. If one number is 29,184, find the other number.
Solution:-
Sum of 2 numbers = 40,132 Given number = 29,184 40132 Missing Addend = Sum - Given Addend -29184 10948 = 40,132 – 29,184
= 10,948 Answer:- 29,184 + 10,948 = 40,132
C.W 14.4.2020 Missing Minuend
Missing Minuend = Subtrahend + Difference Solve:- a) _______ - 847 = 1,238
Solution:-
Missing Minuend = Subtrahend + Difference = 847 + 1,238 1238 = 2,085 + 847 Answer:- 2,085 - 847 = 1,238 2085
Page 12 of 15
b) If you subtract 23,146 from a number, you are left with 35,906. Find the number.
Solution:-
Number subtracted (Subtrahend) 23,146 ______ - 23,146 = 35,906
Number left (Difference) 35,906
Missing Minuend
Subtrahend + Difference = 23,146 + 35,906 = 59,052
23146 +35906 59052
Answer:- 59,052 - 23,146 = 35,906
c) A large library has lent out 1,785 books. It has 7,816 books left. How many books does the library have in all?
Solution:-
Number of books lent out (Subtrahend)
1,785
____ - 1,785 = 7,816
Number of books left (Difference)
7,816
1785 +7816 9601
Total number of books in the library (Minuend)
Subtrahend + Difference = 1,785 + 7,816 = 9,601
Answer: The library has 9,601 books in all
H.W of 14.4.2020
Solve:-
a) _________ - 9,162 = 1,811
Solution for the H.W of 14.04.2020
Solve:-
a) _________ - 9,162 = 1,811
Solution:- 9162
Missing Minuend = Subtrahend + Difference +1811
= 9,162 + 1,811 10973
= 10,973
Answer:- 10,973 - 9,162 = 1,811
Page 13 of 15
C.W 15.4.2020 Missing Subtrahend
Missing subtrahend = Minuend - Difference
Solve:-
a) 9,408 - __________ = 1,138
Solution:- 9408
Missing Subtrahend = Minuend - Difference -1138
= 9,408 - 1,138 8270
= 8,270
b) Find the number which must be subtracted from 83,196 to leave 11,422
Solution:-
Minuend
83,196
83196 - ______ = 11422
Difference
11,422
Subtrahend
Minuend – Difference
= 83,196 - 11,422 = 71,774
83196 - 11422 71774
Ans:- 71,774 must be subtracted from 83,196 to leave 11,422
c) An art exhibition had 915 pieces of art on show. Some of them got sold but there
were 211 unsold pieces. How many pieces were sold?
Total number of pieces of art on show (Minuend)
915
915 - _____ = 211
Number of unsold pieces (Difference)
211
Number of sold pieces (Subtrahend)
Minuend - Difference = 915 - 211 = 704
915 -211 704
Answer:- 704 pieces of art were sold.
Page 14 of 15
H.W of 15.4.2020
Solve :- 1) 49,584 - __________ = 23175
Solution for H.W of 15.04.2020
Solve:-
1) 49,584 - __________ = 23,175 49584 Solution:- -23175
Missing Subtrahend = Minuend - Difference 26409 = 49,584 - 23175 = 26,409
Ans:- 49,584 - 26,409 = 23,175
C.W 16.04.2020 Solve:-
a) Harshita’s stamp album can hold 1,500 stamps. So far she has pasted 785 stamps in it. How many more stamps can she paste in it?
No. of stamps Harshita’s stamp album can hold
1,500
1500 = 785+ _____
No of stamps she pasted 785
No. of more stamps she can paste = 1,500 - 785 = 715
1500 -785 715
Ans:- Harshita can paste 715 more stamps .
b) 1,328 people were waiting to enter an exhibition. At noon 737 people were still waiting to enter, how many people had already entered?
Total number of people waiting to enter an exhibition
1,328 1328 - _____ = 737
Number of people still waiting to enter 737
Number of people had already entered
= 1,328 - 737 = 591
1328 -737 591
Answer:- 591 people had already entered .
Page 15 of 15
c) A truck was carrying a load of mangoes. It deposited 302 kg at the first market. It is still carrying 942 kg. How many kilograms of mangoes did it have in the beginning?
Weight of mangoes deposited at the first market
302 kg
____ - 302kg = 942kg
Weight of mangoes the truck is still carrying (left in the truck)
942 kg
Weight of mangoes the truck had in the beginning
= 302 kg+ 942 kg = 1,244 kg
302 +942 1244
Answer:- The truck had 1,244 kg of mangoes in the beginning.
H.W of 16.4.2020
Write statements and solve the following:
a) Khalid wants to buy a board game that costs ₹ 501. He has ₹ 479. How much more money does he need?
Solution for H.W of 16.04.2020
Ans :- Khalid need ₹22 more to buy the board game
Cost of a board game that Khalid wants to buy
₹501
₹ 501 = ₹ 479 + _____
Money he has
₹479
Money he needs more
= ₹ 501 - ₹ 479
= ₹ 22
501 -479 022
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