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Kinematic and Motion. KJS 2233 Mechanic of Machine. Type of Motions. Linear Angular. Linear Motion. Equations. Example. a)Determine the acceleration of a sport car if time taken to hit 100 km/h is 5 second. b)Determine the distance from starting point to achieve 100 km/h. answer. - PowerPoint PPT Presentation
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Kinematic and Motion
KJS 2233Mechanic of Machine
Linear Angular
Type of Motions
Equations
Linear Motion
a)Determine the acceleration of a sport car if time taken to hit 100 km/h is 5 second.
b)Determine the distance from starting point to achieve 100 km/h
Example
a) 5.5 m/s2
b) 69.75m
answer
An object fall from a building, determine its velocity after 1s and 2s.
Example
a) 9.81 m/sb) 19.62 m/s
answer
Example
Answer
Equations
Angular Motion
A gear rotates counter clock wise at constant speed. It moves 300O in 0.5 s. Determine its angular velocity.
Example
= 100 rpm
Answer
The mechanism below show the component used in exhaust port of internal combustion engine. Cam forces rocker arm at point B with velocity of 30mm/s. Determine angular velocity of angular plate and velocity at point C.
Example
W2= vb/rb
=30/20 = 1.5 rad/s Vc= rw =15 mm x 1.5 rad/s =22.5 mm/s
Answer
An electric motor will speed up to 1800 rpm in
2 s when the power is turned on. Assuming the
speed up is at constant rate. Determine the angular acceleration of motor. Also determine the number of revolutions that the wheel
spins before it is at full speed.
Example
188.6 rad or 30 revolutions
answer
Example
Rev= 82 rev
Answer
Component of Angular Motion
A flywheel with diameter of 200 mm accelerates from 2000 rpm to 6000 rpm
within 10 s. Determine its tangent and normal acceleration.
Example
Answer; 2000 rpm= 209.44 rad/s 6000 rpm= 628.32 rad/s 𝜶=41.892 at = (41.892)x( 0.1)=4.1 At 2000 rpm an= (209.44)2x(0.2) = 8773.02 m/s2
At 6000 rpm an= (628.32)2x(0.2) = 78957.2 m/s2
Answer
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