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Gas Laws used in Chemistry
Ms. Ciceraro
Chemistry The Gas
LawsThe following PowerPoint
presentation will explore, explain, and elaborate on three of the Gas
Laws. By engaging in exercise problems Charles’, Boyle’s and the
Ideal Gas Law will be evaluated.
Let’s take a look at some of the Gas Laws:
Boyle’s Law
Charles’ Law
Ideal Gas Law
Boyle’s LawExplanation
FormulaPictureVideo
ProblemsExcel
Main Menu
Boyle’s LawExplanation: The volume of a gas at a given temperature varies inversely with
the applied pressure.
As the pressure increases the volume decreases.
Main Menu
Boyle’s LawFormula:
PIVI= PFVF
Where: PI= Initial Pressure VI= Initial Volume PF= Final Pressure VF= Final Volume
Main Menu
Boyle’s Law
A picture is worth a thousand words…
Main Menu
Boyle’s Law
What is this Boyle’s Law thing all about??
Boyle’s Law Video
Main Menu
Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Boyle’s Law
Main Menu
Problem 1:
A final volume of air occupies 0.50 L and it has a final
pressure of 3 atm. If your initial volume is 0.250 L, what is your initial pressure in atm?
a. 60.0 atm
b. 0.6 atm
c. 6.0 atm
Boyle’s LawMain Menu
Boyle’s Problems
Problem 2:
A final volume of air occupies 0.50 L and it has a final
pressure of 3 atm. What is your initial volume is, if your initial pressure is 1.5 atm?
a. 1.0 L
b. 10.10L
c. 0.10 L
Boyle’s Law
Boyle’s Problems
Main Menu
Problem 3:
A final volume of air occupies 0.50 L. If your initial volume is 1.00 L, and your initial pressure is 4.75 atm, what is your pressure final?
a. 9.5 atm
b. 0.95 atm
c. 95.0 atm
Boyle’s Law
Boyle’s Problems
Main Menu
Problem 4:
What is the final volume if you have a final pressure of 3 atm, your initial volume is 1.50 L, and your initial pressure is 17 atm?
a. 8.5L
b. 0.85 L
c. 85.0 L
Boyle’s LawMain Menu
Boyle’s Problems
Problem 5:
A final volume of air occupies 0.50 L and it has a final
pressure of 3 atm. If your initial volume is 1.75 L, what is your
initial pressure in atm?
a. 1.00 atm
b. 0.86 atm
c. 0.92 atm
Boyle’s LawMain Menu
Boyle’s Problems
Problem 6:
What is the final volume of air if it initially occupies 0.50 L and 3 atm and your final pressure is
2.00 atm.
a. 14.00 atm
b. 7.50 atm
c. 0.75 atm
Boyle’s LawMain Menu
Boyle’s Problems
Problem 7:
What is the final pressure of air if it initially occupies 0.50L and a pressure of 3atm and your final volume is 2.75 L, what is your
final pressure in atm?
a. 0.55 atm
b. 5.20 atm
c. 1.5 atm
Boyle’s LawMain Menu
Boyle’s Problems
Problem 8:
What is the initial volume if you have a final volume of air occupying 0.50 L and a
pressure of 3 atm, and your initial pressure is 4.50atm?
a. 3.00 L
b. 2.36 L
c. 0.33 L
Boyle’s Law
Boyle’s Problems
Main Menu
Problem 9:
What is the initial pressure if air occupies at the end 0.50 L and it
5 atm. If your initial volume is 6.00 L?
a. 0.42 atm
b. 4.20 atm
c. 42.0 atm
Boyle’s Law
Boyle’s Problems
Main Menu
Problem 10:
What is the final volume of air if it initially occupies 0.32 L and
7.25 atm and in the end has a pressure is 9.80 atm?
a. 2.36 L
b. 23.6 L
c. 0.24 L
Boyle’s Law
Boyle’s Problems
Main Menu
Charles’ LawExplanation
FormulaPictureVideo
ProblemsExcel
Main Menu
Charles’ LawExplanation:The volume occupied by any sample of
gas at a constant pressure is directly proportional to the absolute temperature.
As the temperature increases the volume increases.
Main MenuCharles’ Law
Charles’ LawFormula:
VI/TI= VF/TF
Where:
VI= Initial Volume TI= Initial Temperature
VF= Final Volume TF= Final Temperature
Main MenuCharles’ Law
Charles’ Law
A picture is worth a thousand words…
Main MenuCharles’ Law
Charles’ Law
What is this Charles’ Law thing all about??
Charles’ Law Video
Main MenuCharles’ Law
Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Charles’ Law
Main MenuCharles’ Law
Problem 1:
What is the initial volume of oxygen that can be obtained from a
particular tank at 1.0 atm and that has a final volume and
temperature of 305 K and 1.52 L (including the volume remaining
in the tank). With an initial temperature of 273.89 K.
Charles’ Law
A) 1.36 L
B) 1.24 L
C) 1.14 L
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Charles’ Law Charles’ Problems
Problem 2:
What is the initial temperature of oxygen that can be obtained from a particular tank at 1.73 atm and
that has a final volume and temperature of 305 K and 1.52 L (including the volume remaining
in the tank). With an initial volume of 73.89 L.
Charles’ Law
A) 1.4827 K
B) 148.27 K
C) 14826.61 K
Main Menu
Charles’ Law Charles’ Problems
Problem 3:
What is the final volume of oxygen that can be obtained from a
particular tank at 3.86 atm and that had a inital volume and
temperature of 325 K and 3.58 L (including the volume remaining
in the tank). With an final temperature of 273.89 K.
Charles’ Law
A) 1.337 L
B) 3.017 L
C) 1.627 L
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Charles’ Law Charles’ Problems
Problem 4:
What is the final temperature of oxygen that can be obtained from a particular tank at 4.37 atm and its initial temperature and volume
are 305 K and 1.52 L (including the volume remaining in the tank)
and its final volume is 3.28L.
Charles’ Law
A) 658.16K
B) 65.816 K
C) 6.5816 K
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Charles’ Law Charles’ Problems
Problem 5:
What is the initial volume of oxygen that can be obtained from a
particular tank at 1.0 atm and its final temperature and volume are 423.86 K is 13.21 L (including the volume remaining in the tank) and the initial temperature was 257.49
K?
Charles’ Law
A) 8.02 K
B) 80.2 K
C) 0.802K
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Charles’ Law Charles’ Problems
Problem 6:
What is the initial temperature. If the final temperature and
volume of oxygen that can be obtained from a particular tank at 1.0 atm and 285 K is 5.23 L
(including the volume remaining in the tank), and the initial volume had been 4.73 L.
Charles’ Law
A) 2.57 L
B) 257.75 L
C) 25.75 L
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Charles’ Law Charles’ Problems
Problem 7:
The total volume of oxygen that can be obtained from a particular tank at 1.0 atm and 305 K is 1.52 L (including the volume remaining in the tank). What would be this volume of oxygen if the temperature had been 358.40 K.
Charles’ Law
A) 1.59 L
B) 1.29 L
C) 1.32 L
Main Menu
Charles’ Law Charles’ Problems
Problem 8:
The total volume of oxygen that can be obtained from a particular tank at 1.0 atm and 305 K is 1.52 L (including the volume remaining in the tank). What would be this volume of oxygen if the temperature had been 361.52 K.
Charles’ Law
A) 1.33 L
B) 1.48 L
C) 1.28 L
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Charles’ Law Charles’ Problems
Problem 9:
The total volume of oxygen that can be obtained from a particular tank at 1.0 atm and 305 K is 1.52 L (including the volume remaining in the tank). What would be this volume of oxygen if the temperature had been 365.17 K.
Charles’ Law
A) 1.27 L
B) 1.14 L
C) 1.60 L
Main Menu
Charles’ Law Charles’ Problems
Problem 10:
The total volume of oxygen that can be obtained from a particular tank at 1.0 atm and 305 K is 1.52 L (including the volume remaining in the tank). What would be this volume of oxygen if the temperature had been 373.15 K.
A) 1.29 L
B) 1.33 L
C) 1.24 L
Charles’ Law
Charles’ Law Charles’ Problems
Main Menu
Ideal Gas LawExplanation
FormulaPictureVideo
ProblemsExcel
Back to Main Menu
Ideal Gas LawExplanation:The ideal gas law is the combination of not only
Charles’ and Boyle’s laws but also of Avogadro’s law.
As long as you know 3 out of the 5 variables- and R (universal gas constant) is always constant you can algebraically manipulating the ideal gas law formula you can see the different relationships between Temperature, Volume, Pressure, and amount of moles.
Ideal Gas Law Main Menu
Ideal Gas LawFormula:
PV= nRTWhere:
P= Pressure V= Volume T= Temperature n= moles
R= Gas Constant 8.314 J/k*mol
R= Gas Constant 0.0821 (L*atm)/(mol*K)
R= Gas Constant 8.314 (Pa*m3)/(k*mol)
Main MenuIdeal Gas Law
Ideal Gas Law
A picture is worth a thousand words…
Main MenuIdeal Gas Law
Ideal Gas Law
What is this Ideal Gas Law thing all about??
Ideal Gas Law Video
Main MenuIdeal Gas Law
Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Ideal Gas Law
Main MenuIdeal Gas Law
Problem 1:
A balloon contains 0.76 moles of He. He is at 305 K and 25 atm. What is the volume of the gas in the balloon?
i) 0.70124 L
ii) 0.7124 L
iii) 0.7612 L
Ideal Gas Problems
Main Menu
Ideal Gas Law
Ideal Gas Law
i) 1.35 atm
ii) 1.27 atm
iii) 1.11 atm
Problem 2:
A balloon contains 1.11 moles of He, He is at 305 K and 25 L. What is the pressure of the gas in the balloon?
Main Menu
Ideal Gas Law Ideal Gas Problems
Ideal Gas Law
i) 2.47 moles
ii) 2.67 moles
iii) 2.53 molesProblem 3:
A balloon contains 2.67 liters of He, He is at 305 K and 25 atm. How many moles of the gas are in the balloon?
Main Menu
Ideal Gas Law Ideal Gas Problems
Ideal Gas Law
i) 0.041 (L*atm)/(mol*K)
ii) 0.021 (L*atm)/(mol*K)
iii) 0.039 (L*atm)/(mol*K)Problem 4:
A balloon contains 3.92 moles of He, He is at 305 K, 1.0L and 25 atm. What is the gas constant of the gas in the balloon?
Main Menu
Ideal Gas Law Ideal Gas Problems
Ideal Gas Law
i) 20278.28K
ii) 25573.21 K
iii) 24628.43KProblem 5:
A balloon contains 4.58 moles of He, He is at 305 L and 25 atm. What is the temperature of the gas in the balloon?
Main Menu
Ideal Gas Law Ideal Gas Problems
Ideal Gas Law
i) 530.48 L
ii) 427.96 L
iii) 503.84 LProblem 6:
A balloon contains 5.23 moles of He, He is at 305 K and 25 atm. What is the volume of the gas in the balloon?
Main Menu
Ideal Gas Law Ideal Gas Problems
Ideal Gas Law
i) 541.73 L
ii) 637.78 L
iii) 650.17 LProblem 7:
A balloon contains 6.41 moles of He, He is at 305 K and 25 atm. What is the volume of the gas in the balloon?
Main Menu
Ideal Gas Law Ideal Gas Problems
Ideal Gas Law
i) 795.22 L
ii) 802.37 L
iii) 692.12 LProblem 8:
A balloon contains 7.84 moles of He, He is at 305 K and 25 atm. What is the volume of the gas in the balloon?
Main Menu
Ideal Gas Law Ideal Gas Problems
Ideal Gas Law
Ideal Gas Law
i) 824.11 L
ii) 844.92 L
iii) 854.73 LProblem 9:
A balloon contains 8.33 moles of He, He is at 305 K and 25 atm. What is the volume of the gas in the balloon?
Main Menu
Ideal Gas Law Ideal Gas Problems
Ideal Gas Law
i) 993.47 L
ii) 888.95 L
iii) 986.92 LProblem 10:
A balloon contains 9.73 moles of He, He is at 305 K and 25 atm. What is the volume of the gas in the balloon?
Main Menu
Ideal Gas ProblemsIdeal Gas Law
Excelling with the Gas LawsClick on the Excel icon and
input your own values. You will be able to see graphs
of the various Gas Law relationships.
ReferencesPicture images:
http://mw.concord.org/modeler1.3/mirror/chemistry/piston.gif http://thumbs.dreamstime.com/thumb_140/1176816767U4ZEZ2.jpg http://sciencestage.com/pictures/gx3fwekvp85r0ks7qc6gwmekzdwwh8w
mwqrhvz38wxpp85kp7huttw2hzp35mqh76wfqm7oChemistry%20wizard.gif
http://www.leadfoots.com/images/Awesome%5B1%5D.jpg http://byebyebigguy.files.wordpress.com/2009/07/sadface.jpg http://www.contrib.andrew.cmu.edu/~iclanton/CCM-Website/images/Exce
lLogo.png http://worldofweirdthings.com/wp-content/uploads/2009/06/sad_face_44
0.jpg
References
Picture Images: http://media.giantbomb.com/uploads/0/2241/663872-vault_boy_manip
_super.jpg http://www.clevelandseniors.com/images/clipart/smiley-face.jpg http://media.photobucket.com/image/super%20job/pimpoographics/gli
ttergraphics/Congradulations/superjob.gif http://rlv.zcache.com/chemistry_smiley_photosculpture-p15343449834
2421078qif5_210.jpg http://www.calctool.org/CALC/chem/c_thermo/ideal_gas.png http://4.bp.blogspot.com/_LbfH6nnGyvU/RhSDBTfogDI/AAAAAAAAAAw
/vgJBkFftiEU/s400/sadface.jpg
Picture Images:http://www.astronomynotes.com/starsun/idealgas-anim.gifhttp://upload.wikimedia.org/wikipedia/commons/thumb/c/cb/Travel
_problem.svg/350px-Travel_problem.svg.pnghttp://kaffee.50webs.com/Science/images/KTG.PV.constant.nT.gifhttp://www.chemistryland.com/CHM130/Web-PowerPoints/Gases_P
V_nRT.jpghttp://www.ttlearning.com/images/jp_boyle.jpg
References
Videos:http://video.google.com/videoplay?docid=-914214099352708812
&ei=4qvpSvKIFsLrlQeWnujQAw&q=boyles+law&hl=enhttp://video.google.com/videoplay?docid=-450646154717340120
4&ei=dqzpSr38E5PllQfs18H1Dw&q=Charle%27s+Law&hl=enhttp://www.youtube.com/watch?v=xwKpXEUds0c&feature=related
References
Ebbing, Darrell, and Steven Gammon. General Chemsitry 6th Edition. New York: Houghton Mifflin Company, 1999.
References
WOOHOO! You are correct.
Main MenuIdeal Gas Problems
Charles’ Problems Boyle’s Problems
AWESOME!
Main MenuIdeal Gas Problems
Charles’ Problems Boyle’s Problems
You are a real Gas Law Wizard!
Main MenuIdeal Gas Problems
Charles’ Problems Boyle’s Problems
Excellent!
Main MenuIdeal Gas Problems
Charles’ Problems Boyle’s Problems
Super!
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Charles’ Problems Boyle’s Problems
Way to go!
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Charles’ Problems Boyle’s Problems
Good Job!Main Menu
Boyle’s ProblemsCharles’ Problems
Ideal Gas Problems
Correct!
Main MenuIdeal Gas Problems
Charles’ Problems Boyle’s Problems
Boyle’s Law
Let us look at that calculation again...
PIVI= PFVF
Where:
PI= Initial Pressure VI= Initial Volume
PF= Final Pressure VF= Final Volume
Boyle’s Problems
Main Menu
Charles’ Law
Let us look at that calculation again...
VI/TI= VF/TF
Where:
VI= Initial Volume TI= Initial Temperature VF= Final Volume TF= Final Temperature
Charles’ Law Charles’ Problems
Main Menu
Ideal Gas Law
Let us look at that calculation again...
PV= nRTWhere:
P= Pressure V= Volume T= Temperature n= moles R= Gas Constant 8.314 J/k*mol
Ideal Gas Law Ideal Gas Problems
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