Ph.D. Seminar, University of Genoav - DIMA · 2017. 4. 6. · Extremal Behaviour in Sectional...

Preview:

Citation preview

Extremal Behaviour in Sectional Matrices

Elisa Palezzato1

joint work with Anna Maria Bigatti1 and Michele Torielli2

1University of Genova, Italy2Hokkaido University, Japan

arXiv:1702.03292

Ph.D. Seminar,University of Genova

6 March 2017

Elisa Palezzato Ph.D. Seminar 6 March 2017 1 / 27

Extremal Behaviour in Sectional Matrices

1 PREQUEL

2 Introduction

3 Sectional matrix and its algebraic properties

4 Geometrical properties

5 Examples

Elisa Palezzato Ph.D. Seminar 6 March 2017 2 / 27

1 PREQUEL

2 Introduction

3 Sectional matrix and its algebraic properties

4 Geometrical properties

5 Examples

Elisa Palezzato Ph.D. Seminar 6 March 2017 3 / 27

From Wikipedia I

A Computer Algebra System

is a software program that allows computation over mathematicalexpressions in a way which is similar to the traditional manualcomputations of mathematicians and scientists.

The development of the computer algebra systems started in the secondhalf of the 20th century and this discipline is called �computer algebra�or �symbolic computation�.

Computer algebra systems may be divided in two classes:

The specialized ones are devoted to a speci�c part of mathematics,such as number theory, group theory, etc. [CoCoA, Macaulay2,Singular, ...]

General purpose computer algebra systems aim to be useful to auser working in any scienti�c �eld that requires manipulation ofmathematical expressions. [Matlab, Maple, Magma, ...]

Elisa Palezzato Ph.D. Seminar 6 March 2017 4 / 27

From Wikipedia II

A Gröbner basis

is a particular kind of generating set of an ideal in a polynomial ringover a �eld K[x1, . . . , xn].

Gröbner basis computation is one of the main practical tools for solvingsystems of polynomial equations and computing the images of algebraicvarieties under projections or rational maps.

Gröbner basis computation can be seen as a multivariate, non-lineargeneralization of both Euclidian algorithm for computing polynomialgreatest common divisors, and Gaussian elimination for linear systems.

What you need to compute a Gröbner Basis:

polynomial ring

monomial ordering

reduction algorithm

Elisa Palezzato Ph.D. Seminar 6 March 2017 5 / 27

1 PREQUEL

2 Introduction

3 Sectional matrix and its algebraic properties

4 Geometrical properties

5 Examples

Elisa Palezzato Ph.D. Seminar 6 March 2017 6 / 27

Hilbert Function

The computation of Hilbert function is available in most computeralgebra systems.

De�nition

Let K be a �eld of characteristic 0. Given a homogeneous ideal I inP = K[x1, . . . , xn], we de�ne the Hilbert function of I to be the function

HI(d) := dimK(Id).

Similarly, we de�ne the Hilbert function of P/I to be the function

HP/I(d) := dimK((P/I)d).

The Hilbert function is important in computational algebraic geometry,as it is the easiest known way for computing the dimension and thedegree of an algebraic variety de�ned by explicit polynomial equations.

Elisa Palezzato Ph.D. Seminar 6 March 2017 7 / 27

Hilbert Function

The computation of Hilbert function is available in most computeralgebra systems.

De�nition

Let K be a �eld of characteristic 0. Given a homogeneous ideal I inP = K[x1, . . . , xn], we de�ne the Hilbert function of I to be the function

HI(d) := dimK(Id).

Similarly, we de�ne the Hilbert function of P/I to be the function

HP/I(d) := dimK((P/I)d).

The Hilbert function is important in computational algebraic geometry,as it is the easiest known way for computing the dimension and thedegree of an algebraic variety de�ned by explicit polynomial equations.

Elisa Palezzato Ph.D. Seminar 6 March 2017 7 / 27

Hilbert Function

The computation of Hilbert function is available in most computeralgebra systems.

De�nition

Let K be a �eld of characteristic 0. Given a homogeneous ideal I inP = K[x1, . . . , xn], we de�ne the Hilbert function of I to be the function

HI(d) := dimK(Id).

Similarly, we de�ne the Hilbert function of P/I to be the function

HP/I(d) := dimK((P/I)d).

The Hilbert function is important in computational algebraic geometry,as it is the easiest known way for computing the dimension and thedegree of an algebraic variety de�ned by explicit polynomial equations.

Elisa Palezzato Ph.D. Seminar 6 March 2017 7 / 27

Hilbert Function

The computation of Hilbert function is available in most computeralgebra systems.

De�nition

Let K be a �eld of characteristic 0. Given a homogeneous ideal I inP = K[x1, . . . , xn], we de�ne the Hilbert function of I to be the function

HI(d) := dimK(Id).

Similarly, we de�ne the Hilbert function of P/I to be the function

HP/I(d) := dimK((P/I)d).

The Hilbert function is important in computational algebraic geometry,as it is the easiest known way for computing the dimension and thedegree of an algebraic variety de�ned by explicit polynomial equations.

Elisa Palezzato Ph.D. Seminar 6 March 2017 7 / 27

Question

Can the Hilbert function characterize also some of the geometrical

behaviour of algebraic variety in the projective space?

Answer

In general no.

Elisa Palezzato Ph.D. Seminar 6 March 2017 8 / 27

Question

Can the Hilbert function characterize also some of the geometrical

behaviour of algebraic variety in the projective space?

Answer

In general no.

Elisa Palezzato Ph.D. Seminar 6 March 2017 8 / 27

Example in P2

x

y

Elisa Palezzato Ph.D. Seminar 6 March 2017 9 / 27

Example in P3

zx

y

Elisa Palezzato Ph.D. Seminar 6 March 2017 10 / 27

Question

Can we �nd an other algebraic invariant that characterize some of the

geometrical behaviour of algebraic variety in the projective space?

Answer

Yes, the sectional matrix.

Elisa Palezzato Ph.D. Seminar 6 March 2017 11 / 27

Question

Can we �nd an other algebraic invariant that characterize some of the

geometrical behaviour of algebraic variety in the projective space?

Answer

Yes, the sectional matrix.

Elisa Palezzato Ph.D. Seminar 6 March 2017 11 / 27

1 PREQUEL

2 Introduction

3 Sectional matrix and its algebraic properties

4 Geometrical properties

5 Examples

Elisa Palezzato Ph.D. Seminar 6 March 2017 12 / 27

Sectional Matrix

De�nition

Let K be a �eld of characteristic 0. Given a homogeneous ideal I inP = K[x1, . . . , xn], we de�ne the sectional matrix of I to be thefunction

MI(i, d) := dimK(I + (L1, . . . , Ln−i)/(L1, . . . , Ln−i))d

where L1, . . . , Ln−i are general linear forms, i = 1, . . . , n and d ≥ 0.

Similarly, we de�ne the sectional matrix of P/I to be the function

MP/I(i, d) := dimK(P/(I + (L1, . . . , Ln−i)/(L1, . . . , Ln−i)))d

=

(d+ i− 1

i− 1

)−MI(i, d)

where L1, . . . , Ln−i are general linear forms, i = 1, . . . , n and d ≥ 0.

Elisa Palezzato Ph.D. Seminar 6 March 2017 13 / 27

Sectional Matrix

De�nition

Let K be a �eld of characteristic 0. Given a homogeneous ideal I inP = K[x1, . . . , xn], we de�ne the sectional matrix of I to be thefunction

MI(i, d) := dimK(I + (L1, . . . , Ln−i)/(L1, . . . , Ln−i))d

where L1, . . . , Ln−i are general linear forms, i = 1, . . . , n and d ≥ 0.Similarly, we de�ne the sectional matrix of P/I to be the function

MP/I(i, d) := dimK(P/(I + (L1, . . . , Ln−i)/(L1, . . . , Ln−i)))d

=

(d+ i− 1

i− 1

)−MI(i, d)

where L1, . . . , Ln−i are general linear forms, i = 1, . . . , n and d ≥ 0.

Elisa Palezzato Ph.D. Seminar 6 March 2017 13 / 27

Strongly Stable Ideal

De�nition

Let I be a homogenous ideal in P = K[x1, . . . , xn]. We say that I is astrongly stable ideal if T = xi11 · · ·xinn ∈ I, then xi · T/xj ∈ I for alli < j ≤ max{k | ik 6= 0}.

Example

The ideal I = (x3, x2y, xy2, xyz) is not a strongly stable in Q[x, y, z]because x · xyz/y = x2z 6∈ I. The ideal I + (x2z) is strongly stable.

Remark

If I is a strongly stable ideal, then in the de�nition of the sectional

matrix we can take Li = xn−i+1.

Elisa Palezzato Ph.D. Seminar 6 March 2017 14 / 27

Strongly Stable Ideal

De�nition

Let I be a homogenous ideal in P = K[x1, . . . , xn]. We say that I is astrongly stable ideal if T = xi11 · · ·xinn ∈ I, then xi · T/xj ∈ I for alli < j ≤ max{k | ik 6= 0}.

Example

The ideal I = (x3, x2y, xy2, xyz) is not a strongly stable in Q[x, y, z]because x · xyz/y = x2z 6∈ I. The ideal I + (x2z) is strongly stable.

Remark

If I is a strongly stable ideal, then in the de�nition of the sectional

matrix we can take Li = xn−i+1.

Elisa Palezzato Ph.D. Seminar 6 March 2017 14 / 27

Strongly Stable Ideal

De�nition

Let I be a homogenous ideal in P = K[x1, . . . , xn]. We say that I is astrongly stable ideal if T = xi11 · · ·xinn ∈ I, then xi · T/xj ∈ I for alli < j ≤ max{k | ik 6= 0}.

Example

The ideal I = (x3, x2y, xy2, xyz) is not a strongly stable in Q[x, y, z]because x · xyz/y = x2z 6∈ I. The ideal I + (x2z) is strongly stable.

Remark

If I is a strongly stable ideal, then in the de�nition of the sectional

matrix we can take Li = xn−i+1.

Elisa Palezzato Ph.D. Seminar 6 March 2017 14 / 27

Generic Initial Ideal

Theorem (Galligo '74)

Let I be a homogeneous ideal in K[x1, . . . , xn], σ a term-ordering such

that x1 >σ x2 >σ · · · >σ xn. Then there exists a Zariski open set

U ⊆ GL(n) and a strongly stable ideal J such that for each g ∈ U ,LTσ(g(I)) = J .

De�nition

The strongly stable ideal J given in the previous Theorem will be calledthe generic initial ideal with respect to σ of I and it will be denoted byginσ(I). In particular, ginDegRevLex(I) is denoted by many authors withrgin(I).

Example

Consider the ideal I = (z5, xyz3) in Q[x, y, z], thenrgin(I) = (x5, x4y, x3y3).

Elisa Palezzato Ph.D. Seminar 6 March 2017 15 / 27

Generic Initial Ideal

Theorem (Galligo '74)

Let I be a homogeneous ideal in K[x1, . . . , xn], σ a term-ordering such

that x1 >σ x2 >σ · · · >σ xn. Then there exists a Zariski open set

U ⊆ GL(n) and a strongly stable ideal J such that for each g ∈ U ,LTσ(g(I)) = J .

De�nition

The strongly stable ideal J given in the previous Theorem will be calledthe generic initial ideal with respect to σ of I and it will be denoted byginσ(I). In particular, ginDegRevLex(I) is denoted by many authors withrgin(I).

Example

Consider the ideal I = (z5, xyz3) in Q[x, y, z], thenrgin(I) = (x5, x4y, x3y3).

Elisa Palezzato Ph.D. Seminar 6 March 2017 15 / 27

Generic Initial Ideal

Theorem (Galligo '74)

Let I be a homogeneous ideal in K[x1, . . . , xn], σ a term-ordering such

that x1 >σ x2 >σ · · · >σ xn. Then there exists a Zariski open set

U ⊆ GL(n) and a strongly stable ideal J such that for each g ∈ U ,LTσ(g(I)) = J .

De�nition

The strongly stable ideal J given in the previous Theorem will be calledthe generic initial ideal with respect to σ of I and it will be denoted byginσ(I). In particular, ginDegRevLex(I) is denoted by many authors withrgin(I).

Example

Consider the ideal I = (z5, xyz3) in Q[x, y, z], thenrgin(I) = (x5, x4y, x3y3).

Elisa Palezzato Ph.D. Seminar 6 March 2017 15 / 27

Properties of the Sectional Matrix

Proposition

Let I be a homogeneous ideal in P = K[x1, . . . , xn] with minimal

generators of degree ≤ δ. Then

1 MI(n,−) coincides with the Hilbert function of I, andMP/I(n,−)with the one of P/I.

2 MI =Mrgin(I), andMP/I =MP/rgin(I).

3 MP/I(k, d+ 1) ≤∑k

i=1MP/I(i, d), for all k and d. If we have

MP/I(k, δ + 1) =∑k

i=1MP/I(i, δ), thenMP/I(s, d+ 1) =

∑si=1MP/I(i, d), for all s ≤ k and d ≥ δ.

4 If I is a strongly stable ideal (I = rgin(I)), thenMP/I(k, d+ 1) =

∑ki=1MP/I(i, d), for all d > δ and for all k.

5 If δ = reg(I), thenMP/I(k, d+ 1) =∑k

i=1MP/I(i, d), for alld > δ and for all k.

Elisa Palezzato Ph.D. Seminar 6 March 2017 16 / 27

Properties of the Sectional Matrix

Proposition

Let I be a homogeneous ideal in P = K[x1, . . . , xn] with minimal

generators of degree ≤ δ. Then1 MI(n,−) coincides with the Hilbert function of I, andMP/I(n,−)

with the one of P/I.

2 MI =Mrgin(I), andMP/I =MP/rgin(I).

3 MP/I(k, d+ 1) ≤∑k

i=1MP/I(i, d), for all k and d. If we have

MP/I(k, δ + 1) =∑k

i=1MP/I(i, δ), thenMP/I(s, d+ 1) =

∑si=1MP/I(i, d), for all s ≤ k and d ≥ δ.

4 If I is a strongly stable ideal (I = rgin(I)), thenMP/I(k, d+ 1) =

∑ki=1MP/I(i, d), for all d > δ and for all k.

5 If δ = reg(I), thenMP/I(k, d+ 1) =∑k

i=1MP/I(i, d), for alld > δ and for all k.

Elisa Palezzato Ph.D. Seminar 6 March 2017 16 / 27

Properties of the Sectional Matrix

Proposition

Let I be a homogeneous ideal in P = K[x1, . . . , xn] with minimal

generators of degree ≤ δ. Then1 MI(n,−) coincides with the Hilbert function of I, andMP/I(n,−)

with the one of P/I.

2 MI =Mrgin(I), andMP/I =MP/rgin(I).

3 MP/I(k, d+ 1) ≤∑k

i=1MP/I(i, d), for all k and d. If we have

MP/I(k, δ + 1) =∑k

i=1MP/I(i, δ), thenMP/I(s, d+ 1) =

∑si=1MP/I(i, d), for all s ≤ k and d ≥ δ.

4 If I is a strongly stable ideal (I = rgin(I)), thenMP/I(k, d+ 1) =

∑ki=1MP/I(i, d), for all d > δ and for all k.

5 If δ = reg(I), thenMP/I(k, d+ 1) =∑k

i=1MP/I(i, d), for alld > δ and for all k.

Elisa Palezzato Ph.D. Seminar 6 March 2017 16 / 27

Properties of the Sectional Matrix

Proposition

Let I be a homogeneous ideal in P = K[x1, . . . , xn] with minimal

generators of degree ≤ δ. Then1 MI(n,−) coincides with the Hilbert function of I, andMP/I(n,−)

with the one of P/I.

2 MI =Mrgin(I), andMP/I =MP/rgin(I).

3 MP/I(k, d+ 1) ≤∑k

i=1MP/I(i, d), for all k and d. If we have

MP/I(k, δ + 1) =∑k

i=1MP/I(i, δ), thenMP/I(s, d+ 1) =

∑si=1MP/I(i, d), for all s ≤ k and d ≥ δ.

4 If I is a strongly stable ideal (I = rgin(I)), thenMP/I(k, d+ 1) =

∑ki=1MP/I(i, d), for all d > δ and for all k.

5 If δ = reg(I), thenMP/I(k, d+ 1) =∑k

i=1MP/I(i, d), for alld > δ and for all k.

Elisa Palezzato Ph.D. Seminar 6 March 2017 16 / 27

Properties of the Sectional Matrix

Proposition

Let I be a homogeneous ideal in P = K[x1, . . . , xn] with minimal

generators of degree ≤ δ. Then1 MI(n,−) coincides with the Hilbert function of I, andMP/I(n,−)

with the one of P/I.

2 MI =Mrgin(I), andMP/I =MP/rgin(I).

3 MP/I(k, d+ 1) ≤∑k

i=1MP/I(i, d), for all k and d. If we have

MP/I(k, δ + 1) =∑k

i=1MP/I(i, δ), thenMP/I(s, d+ 1) =

∑si=1MP/I(i, d), for all s ≤ k and d ≥ δ.

4 If I is a strongly stable ideal (I = rgin(I)), thenMP/I(k, d+ 1) =

∑ki=1MP/I(i, d), for all d > δ and for all k.

5 If δ = reg(I), thenMP/I(k, d+ 1) =∑k

i=1MP/I(i, d), for alld > δ and for all k.

Elisa Palezzato Ph.D. Seminar 6 March 2017 16 / 27

Properties of the Sectional Matrix

Proposition

Let I be a homogeneous ideal in P = K[x1, . . . , xn] with minimal

generators of degree ≤ δ. Then1 MI(n,−) coincides with the Hilbert function of I, andMP/I(n,−)

with the one of P/I.

2 MI =Mrgin(I), andMP/I =MP/rgin(I).

3 MP/I(k, d+ 1) ≤∑k

i=1MP/I(i, d), for all k and d. If we have

MP/I(k, δ + 1) =∑k

i=1MP/I(i, δ), thenMP/I(s, d+ 1) =

∑si=1MP/I(i, d), for all s ≤ k and d ≥ δ.

4 If I is a strongly stable ideal (I = rgin(I)), thenMP/I(k, d+ 1) =

∑ki=1MP/I(i, d), for all d > δ and for all k.

5 If δ = reg(I), thenMP/I(k, d+ 1) =∑k

i=1MP/I(i, d), for alld > δ and for all k.

Elisa Palezzato Ph.D. Seminar 6 March 2017 16 / 27

Example

Let I be the zero-dimensional homogeneous ideal

(x2+y2−25z2, y4−3xy2z−4y3z+12xyz2−25y2z2+100yz3, xy3−16xyz2)

and rgin(I) =(x2, xy3, y4).

The sectional matrix of I is

0 1 2 3 4 5 . . .HI+〈L1,L2〉(d) =MI(1, d) : 0 0 1 1 1 1 . . .HI+〈L1〉(d) =MI(2, d) : 0 0 1 2 5 6 . . .

HI(d) =MI(3, d) : 0 0 1 3 8 14 . . .

The sectional matrix of P/I is

0 1 2 3 4 5 . . .HP/(I+〈L1,L2〉)(d) =MP/I(1, d) : 1 1 0 0 0 0 . . .

HP/(I+〈L1〉)(d) =MP/I(2, d) : 1 2 2 2 0 0 . . .

HP/I(d) =MP/I(3, d) : 1 3 5 7 7 7 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 17 / 27

Example

Let I be the zero-dimensional homogeneous ideal

(x2+y2−25z2, y4−3xy2z−4y3z+12xyz2−25y2z2+100yz3, xy3−16xyz2)

and rgin(I) =(x2, xy3, y4).

The sectional matrix of I is

0 1 2 3 4 5 . . .HI+〈L1,L2〉(d) =MI(1, d) : 0 0 1 1 1 1 . . .HI+〈L1〉(d) =MI(2, d) : 0 0 1 2 5 6 . . .

HI(d) =MI(3, d) : 0 0 1 3 8 14 . . .

The sectional matrix of P/I is

0 1 2 3 4 5 . . .HP/(I+〈L1,L2〉)(d) =MP/I(1, d) : 1 1 0 0 0 0 . . .

HP/(I+〈L1〉)(d) =MP/I(2, d) : 1 2 2 2 0 0 . . .

HP/I(d) =MP/I(3, d) : 1 3 5 7 7 7 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 17 / 27

Example

Let I be the zero-dimensional homogeneous ideal

(x2+y2−25z2, y4−3xy2z−4y3z+12xyz2−25y2z2+100yz3, xy3−16xyz2)

and rgin(I) =(x2, xy3, y4).

The sectional matrix of I is

0 1 2 3 4 5 . . .HI+〈L1,L2〉(d) =MI(1, d) : 0 0 1 1 1 1 . . .HI+〈L1〉(d) =MI(2, d) : 0 0 1 2 5 6 . . .

HI(d) =MI(3, d) : 0 0 1 3 8 14 . . .

The sectional matrix of P/I is

0 1 2 3 4 5 . . .HP/(I+〈L1,L2〉)(d) =MP/I(1, d) : 1 1 0 0 0 0 . . .

HP/(I+〈L1〉)(d) =MP/I(2, d) : 1 2 2 2 0 0 . . .

HP/I(d) =MP/I(3, d) : 1 3 5 7 7 7 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 17 / 27

Example

Let I be the zero-dimensional homogeneous ideal

(x2+y2−25z2, y4−3xy2z−4y3z+12xyz2−25y2z2+100yz3, xy3−16xyz2)

and rgin(I) =(x2, xy3, y4).

The sectional matrix of I is

0 1 2 3 4 5 . . .HI+〈L1,L2〉(d) =MI(1, d) : 0 0 1 1 1 1 . . .HI+〈L1〉(d) =MI(2, d) : 0 0 1 2 5 6 . . .

HI(d) =MI(3, d) : 0 0 1 3 8 14 . . .

The sectional matrix of P/I is

0 1 2 3 4 5 . . .HP/(I+〈L1,L2〉)(d) =MP/I(1, d) : 1 1 0 0 0 0 . . .

HP/(I+〈L1〉)(d) =MP/I(2, d) : 1 2 2 2 0 0 . . .

HP/I(d) =MP/I(3, d) : 1 3 5 7 7 7 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 17 / 27

Additional Algebraic Properties I

Proposition (Bigatti-P.-Torielli)

Let I be a homogeneous ideal in P = K[x1, . . . , xn] and δ = reg(I).Suppose that

MP/I(i, δ) 6= 0 butMP/I(i− 1, δ) = 0 for some i = 2, . . . , n.

Then dim(P/I) = n− i+ 1 and deg(P/I) =MP/I(i, δ).

Elisa Palezzato Ph.D. Seminar 6 March 2017 18 / 27

Additional Algebraic Properties I

Proposition (Bigatti-P.-Torielli)

Let I be a homogeneous ideal in P = K[x1, . . . , xn] and δ = reg(I).Suppose that

MP/I(i, δ) 6= 0 butMP/I(i− 1, δ) = 0 for some i = 2, . . . , n.

Then dim(P/I) = n− i+ 1 and deg(P/I) =MP/I(i, δ).

Elisa Palezzato Ph.D. Seminar 6 March 2017 18 / 27

Additional Algebraic Properties II

Proposition (Bigatti-P.-Torielli)

Let I be a homogeneous ideal in P = K[x1, . . . , xn] such that the

minimal generators of I have degree ≤ δ. Suppose that

there exist i = 2, . . . , n and d ≥ δ such thatMP/I(k, d) = 0 for all

k = 1, . . . , i− 1;

MP/I(i, d) =MP/I(i, d+ 1) 6= 0.

Then dim(P/I) = n− i+ 1 and deg(P/I) =MP/I(i, d).

Elisa Palezzato Ph.D. Seminar 6 March 2017 19 / 27

Additional Algebraic Properties II

Proposition (Bigatti-P.-Torielli)

Let I be a homogeneous ideal in P = K[x1, . . . , xn] such that the

minimal generators of I have degree ≤ δ. Suppose that

there exist i = 2, . . . , n and d ≥ δ such thatMP/I(k, d) = 0 for all

k = 1, . . . , i− 1;

MP/I(i, d) =MP/I(i, d+ 1) 6= 0.

Then dim(P/I) = n− i+ 1 and deg(P/I) =MP/I(i, d).

Elisa Palezzato Ph.D. Seminar 6 March 2017 19 / 27

Additional Algebraic Properties II

Proposition (Bigatti-P.-Torielli)

Let I be a homogeneous ideal in P = K[x1, . . . , xn] such that the

minimal generators of I have degree ≤ δ. Suppose that

there exist i = 2, . . . , n and d ≥ δ such thatMP/I(k, d) = 0 for all

k = 1, . . . , i− 1;

MP/I(i, d) =MP/I(i, d+ 1) 6= 0.

Then dim(P/I) = n− i+ 1 and deg(P/I) =MP/I(i, d).

Elisa Palezzato Ph.D. Seminar 6 March 2017 19 / 27

1 PREQUEL

2 Introduction

3 Sectional matrix and its algebraic properties

4 Geometrical properties

5 Examples

Elisa Palezzato Ph.D. Seminar 6 March 2017 20 / 27

Geometrical Properties I

Theorem (Bigatti-P.-Torielli)

Let I be a saturated ideal of P = K[x1, . . . , xn] such that (I)δ 6= 0.Assume that one of the following holds

MP/I(2, δ) =MP/I(2, δ + 1) 6= 0.

MP/I(2, δ) 6= 0 andMP/I(n, δ + 1) =∑n

i=1MP/I(i, δ).

Then the ideals (I)≤δ and (I)≤δ+1 are saturated and their elements

have a GCD of degreeMP/I(2, δ).

Elisa Palezzato Ph.D. Seminar 6 March 2017 21 / 27

Geometrical Properties I

Theorem (Bigatti-P.-Torielli)

Let I be a saturated ideal of P = K[x1, . . . , xn] such that (I)δ 6= 0.Assume that one of the following holds

MP/I(2, δ) =MP/I(2, δ + 1) 6= 0.

MP/I(2, δ) 6= 0 andMP/I(n, δ + 1) =∑n

i=1MP/I(i, δ).

Then the ideals (I)≤δ and (I)≤δ+1 are saturated and their elements

have a GCD of degreeMP/I(2, δ).

Elisa Palezzato Ph.D. Seminar 6 March 2017 21 / 27

Geometrical Properties I

Theorem (Bigatti-P.-Torielli)

Let I be a saturated ideal of P = K[x1, . . . , xn] such that (I)δ 6= 0.Assume that one of the following holds

MP/I(2, δ) =MP/I(2, δ + 1) 6= 0.

MP/I(2, δ) 6= 0 andMP/I(n, δ + 1) =∑n

i=1MP/I(i, δ).

Then the ideals (I)≤δ and (I)≤δ+1 are saturated and their elements

have a GCD of degreeMP/I(2, δ).

Elisa Palezzato Ph.D. Seminar 6 March 2017 21 / 27

Geometrical Properties I

Theorem (Bigatti-P.-Torielli)

Let I be a saturated ideal of P = K[x1, . . . , xn] such that (I)δ 6= 0.Assume that one of the following holds

MP/I(2, δ) =MP/I(2, δ + 1) 6= 0.

MP/I(2, δ) 6= 0 andMP/I(n, δ + 1) =∑n

i=1MP/I(i, δ).

Then the ideals (I)≤δ and (I)≤δ+1 are saturated and their elements

have a GCD of degreeMP/I(2, δ).

Elisa Palezzato Ph.D. Seminar 6 March 2017 21 / 27

Geometrical Properties II

Theorem (Bigatti-P.-Torielli)

Let I be a saturated ideal of P = K[x1, . . . , xn]. Suppose that exists δsuch that

0 =MP/I(1, δ) = · · · =MP/I(i− 1, δ);

MP/I(i, δ) 6= 0 for some n ≥ i ≥ 2;

MP/I(n, δ + 1) =∑n

k=iMP/I(k, δ).

Then the ideal (I)≤δ is a saturated, dim(P/(I)≤δ) = (n− i+ 1), and of

degreeMP/I(i, δ) and it is δ-regular. Moreover, dim(P/I) ≤ n− i+ 1.

Elisa Palezzato Ph.D. Seminar 6 March 2017 22 / 27

Geometrical Properties II

Theorem (Bigatti-P.-Torielli)

Let I be a saturated ideal of P = K[x1, . . . , xn]. Suppose that exists δsuch that

0 =MP/I(1, δ) = · · · =MP/I(i− 1, δ);

MP/I(i, δ) 6= 0 for some n ≥ i ≥ 2;

MP/I(n, δ + 1) =∑n

k=iMP/I(k, δ).

Then the ideal (I)≤δ is a saturated, dim(P/(I)≤δ) = (n− i+ 1), and of

degreeMP/I(i, δ) and it is δ-regular. Moreover, dim(P/I) ≤ n− i+ 1.

Elisa Palezzato Ph.D. Seminar 6 March 2017 22 / 27

Geometrical Properties II

Theorem (Bigatti-P.-Torielli)

Let I be a saturated ideal of P = K[x1, . . . , xn]. Suppose that exists δsuch that

0 =MP/I(1, δ) = · · · =MP/I(i− 1, δ);

MP/I(i, δ) 6= 0 for some n ≥ i ≥ 2;

MP/I(n, δ + 1) =∑n

k=iMP/I(k, δ).

Then the ideal (I)≤δ is a saturated, dim(P/(I)≤δ) = (n− i+ 1), and of

degreeMP/I(i, δ) and it is δ-regular. Moreover, dim(P/I) ≤ n− i+ 1.

Elisa Palezzato Ph.D. Seminar 6 March 2017 22 / 27

Geometrical Properties II

Theorem (Bigatti-P.-Torielli)

Let I be a saturated ideal of P = K[x1, . . . , xn]. Suppose that exists δsuch that

0 =MP/I(1, δ) = · · · =MP/I(i− 1, δ);

MP/I(i, δ) 6= 0 for some n ≥ i ≥ 2;

MP/I(n, δ + 1) =∑n

k=iMP/I(k, δ).

Then the ideal (I)≤δ is a saturated, dim(P/(I)≤δ) = (n− i+ 1), and of

degreeMP/I(i, δ) and it is δ-regular. Moreover, dim(P/I) ≤ n− i+ 1.

Elisa Palezzato Ph.D. Seminar 6 March 2017 22 / 27

1 PREQUEL

2 Introduction

3 Sectional matrix and its algebraic properties

4 Geometrical properties

5 Examples

Elisa Palezzato Ph.D. Seminar 6 March 2017 23 / 27

Example in P2

x

y

Consider the points

(0, 5), (0,−5), (5, 0), (−5, 0)(−3, 4), (3, 4), (−3,−4)

The de�ning ideal is I =

(x2+ y2− 25z2, y4+ . . . , . . . )

and rgin(I) =

(x2, xy3, y4).

The sectional matrix is

0 1 2 3 4 5 . . .1 1 0 0 0 0 . . .1 2 2 2 0 0 . . .1 3 5 7 7 7 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 24 / 27

Example in P2

x

y

Consider the points

(0, 5), (0,−5), (5, 0), (−5, 0)(−3, 4), (3, 4), (−3,−4)

The de�ning ideal is I =

(x2+ y2− 25z2, y4+ . . . , . . . )

and rgin(I) =

(x2, xy3, y4).

The sectional matrix is

0 1 2 3 4 5 . . .1 1 0 0 0 0 . . .1 2 2 2 0 0 . . .1 3 5 7 7 7 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 24 / 27

Example in P2

x

y

Consider the points

(0, 5), (0,−5), (5, 0), (−5, 0)(−3, 4), (3, 4), (−3,−4)

The de�ning ideal is I =

(x2+ y2− 25z2, y4+ . . . , . . . )

and rgin(I) =

(x2, xy3, y4).

The sectional matrix is

0 1 2 3 4 5 . . .1 1 0 0 0 0 . . .1 2 2 2 0 0 . . .1 3 5 7 7 7 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 24 / 27

Example in P3

zx

yConsider the points

(0, 0, 0), (0, 1, 0), (0, 2, 0)

(0, 3, 0), (0, 4, 0), (0, 5, 0)

(2, 1, 0), (1, 1, 0), (0, 0, 3)

The de�ning ideal I issuch that rgin(I) =

(x2, xy, xz, y2, yz2, z6).

The sectional matrix is

0 1 2 3 4 5 6 . . .1 1 0 0 0 0 0 . . .1 2 0 0 0 0 0 . . .1 3 2 1 1 1 0 . . .1 4 6 7 8 9 9 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 25 / 27

Example in P3

zx

yConsider the points

(0, 0, 0), (0, 1, 0), (0, 2, 0)

(0, 3, 0), (0, 4, 0), (0, 5, 0)

(2, 1, 0), (1, 1, 0), (0, 0, 3)

The de�ning ideal I issuch that rgin(I) =

(x2, xy, xz, y2, yz2, z6).

The sectional matrix is

0 1 2 3 4 5 6 . . .1 1 0 0 0 0 0 . . .1 2 0 0 0 0 0 . . .1 3 2 1 1 1 0 . . .1 4 6 7 8 9 9 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 25 / 27

Example in P3

zx

yConsider the points

(0, 0, 0), (0, 1, 0), (0, 2, 0)

(0, 3, 0), (0, 4, 0), (0, 5, 0)

(2, 1, 0), (1, 1, 0), (0, 0, 3)

The de�ning ideal I issuch that rgin(I) =

(x2, xy, xz, y2, yz2, z6).

The sectional matrix is

0 1 2 3 4 5 6 . . .1 1 0 0 0 0 0 . . .1 2 0 0 0 0 0 . . .1 3 2 1 1 1 0 . . .1 4 6 7 8 9 9 . . .

Elisa Palezzato Ph.D. Seminar 6 March 2017 25 / 27

H-SM-gin-res

Hilbert function

sectional matrix

generic initial ideal (gin)

resolution

(Example)

Elisa Palezzato Ph.D. Seminar 6 March 2017 26 / 27

H-SM-gin-res

Hilbert function

sectional matrix

generic initial ideal (gin)

resolution

(Example)

Elisa Palezzato Ph.D. Seminar 6 March 2017 26 / 27

The End

Elisa Palezzato Ph.D. Seminar 6 March 2017 27 / 27