View
212
Download
0
Category
Preview:
DESCRIPTION
electrical ckts
Citation preview
Problem 2.23 Determine the amount of power supplied by the independent currentsource in the circuit of Fig. P2.23.
V1
I
2
2
0.2 A4
V1
+
_
Figure P2.23: Circuit for Problem 2.23.
Solution: KCL at top node gives
0.2+ V14 I = 0
Also I = V1/2 (for the 2- resistor).Hence,
0.2+ V14
V12
= 0
V1 = 0.8 V.
The voltage across the 0.2-A source is 2V1 = 1.6 V.Power dissipated is
P = V I = 1.60.2 = 0.32 W.
All rights reserved. Do not reproduce or distribute. c2013 National Technology and Science Press
Recommended