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Processes of Genetics Jeopardy. Meiosis and Mitosis for 100. A human cell containing 23 chromosomes would be described as this (n). What is haploid?. Home. Translation for 100. A codon read in the 5’ to 3’ direction as UAG would have an anticodon read in the 5’ to 3’ direction as this. - PowerPoint PPT Presentation
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Processes of Genetics Processes of Genetics JeopardyJeopardy
Meiosis and Meiosis and MitosisMitosis
TranslationTranslation RNA RNA TranscriptionTranscription
RecombinatioRecombinationn
DNA DNA DuplicationDuplication
100 100 100 100 100
200 200 200 200 200
300 300 300 300 300
400 400 400 400 400
500 500 500 500 500
Meiosis and Mitosis for 100Meiosis and Mitosis for 100
A human cell containing 23 A human cell containing 23 chromosomes would be described as chromosomes would be described as this (n).this (n).
What is haploid?What is haploid?Home
Translation for 100Translation for 100
A codon read in the 5’ to 3’ direction A codon read in the 5’ to 3’ direction as UAG would have an anticodon as UAG would have an anticodon read in the 5’ to 3’ direction as this.read in the 5’ to 3’ direction as this.
What is CUA? What is CUA?
Home
RNA Transcription for 100RNA Transcription for 100
These are removed from the pre-These are removed from the pre-mRNA during RNA processing.mRNA during RNA processing.
What are exons?What are exons?
Home
Recombination for 100Recombination for 100
A parent has the following genotype: AbA parent has the following genotype: Ab
aB aB The genotype of a recombinant The genotype of a recombinant gamete would be this.gamete would be this.
What is AB or ab?What is AB or ab?
Home
DNA Duplication for 100DNA Duplication for 100
This is the term for the short lengths of This is the term for the short lengths of DNA produced by discontinuous DNA produced by discontinuous replication of the lagging strand.replication of the lagging strand.
What are Okazaki fragments?What are Okazaki fragments?
Home
Meiosis and Mitosis for 200Meiosis and Mitosis for 200
There are 250 primary spermatocytes There are 250 primary spermatocytes present. This is the number of mature present. This is the number of mature sperm resulting from those sperm resulting from those spermatocytes.spermatocytes.
What is 1,000?What is 1,000?Home
Translation for 200Translation for 200
When the first position of an anticodon When the first position of an anticodon is U, the third position of its respective is U, the third position of its respective codon could be this (two options).codon could be this (two options).
What is A or G?What is A or G?
Home
RNA Transcription for 200RNA Transcription for 200
Termination of transcription occurs Termination of transcription occurs when a hairpin of inverted repeats when a hairpin of inverted repeats are followed by this.are followed by this.
What is a string of uracil bases?What is a string of uracil bases?
Home
Recombination for 200Recombination for 200
A single crossover event produces this A single crossover event produces this ratio between nonrecombinant ratio between nonrecombinant gametes and recombinant gametes.gametes and recombinant gametes.
What is one to one?What is one to one?
Home
DNA Duplication for 200DNA Duplication for 200
This enzyme adds extra nucleotides to This enzyme adds extra nucleotides to the G-rich DNA strand of the telomere.the G-rich DNA strand of the telomere.
What is telomerase?What is telomerase?
Home
Meiosis and Mitosis for 300Meiosis and Mitosis for 300
This term describes the relationship This term describes the relationship between two chromosomes that between two chromosomes that contain the same genes but different contain the same genes but different alleles.alleles.
What are homologous chromosomes?What are homologous chromosomes?Home
Translation for 300Translation for 300
A string of these bases code for A string of these bases code for detachment of the RNA being detachment of the RNA being synthesized from the DNA template synthesized from the DNA template strand.strand.
What are Uracil bases?What are Uracil bases?Home
RNA Transcription for 300RNA Transcription for 300
This alternative pathway for processing This alternative pathway for processing pre-mRNA has the potential to remove pre-mRNA has the potential to remove introns and exons.introns and exons.
What is alternative splicing?What is alternative splicing?
Home
Recombination for 300Recombination for 300
In a three point testcross there are 67 In a three point testcross there are 67 observed double crossovers and 47 observed double crossovers and 47 expected double crossovers. This is expected double crossovers. This is the value for the interference of the the value for the interference of the cross.cross.
What is -0.43?What is -0.43?Home
DNA Duplication for 300DNA Duplication for 300
This component is required for replication This component is required for replication in bacterial cells. Its function is to move in bacterial cells. Its function is to move along the DNA strand ahead of the along the DNA strand ahead of the replication fork, while breaking and replication fork, while breaking and sealing bonds in the DNA strand in order sealing bonds in the DNA strand in order to reduce the stress of the twisting.to reduce the stress of the twisting.
What is DNA gyrase?What is DNA gyrase?
Home
Meiosis and Mitosis for 400Meiosis and Mitosis for 400
This term describes the meiotic stage This term describes the meiotic stage of the cell shown above.of the cell shown above.
What is meiotic metaphase 1?What is meiotic metaphase 1? Home
Biologycorner.com
Translation for 400Translation for 400
This is another name for stop codons.This is another name for stop codons.
What are nonsense codons?What are nonsense codons?
Home
RNA Transcription for 400RNA Transcription for 400
A = 21%, C = 32%, U = 26%, and G = A = 21%, C = 32%, U = 26%, and G = 21%. This term describes how many 21%. This term describes how many strands make up the RNA described strands make up the RNA described above.above.
What is single-stranded?What is single-stranded?
Home
Recombination for 400Recombination for 400
The following are the FThe following are the F22 progeny resulting from a P progeny resulting from a P generation cross between a tall pea plant with generation cross between a tall pea plant with green leaves and a short pea plant with yellow green leaves and a short pea plant with yellow leaves:leaves:
613 Tall, Green613 Tall, Green
207 Tall, Yellow207 Tall, Yellow
198 Short, Green198 Short, Green
54 Short, Yellow54 Short, Yellow
This is the type of linkage that occurs in the above This is the type of linkage that occurs in the above pea plants.pea plants.
What is independent assortment?What is independent assortment?Home
DNA Duplication for 400DNA Duplication for 400
This large multiprotein complex has the This large multiprotein complex has the ability to move in a 3’ to 5’ direction in ability to move in a 3’ to 5’ direction in order to back up and remove order to back up and remove mismatched nucleotides in a DNA mismatched nucleotides in a DNA sequence.sequence.
What is DNA Polymerase III?What is DNA Polymerase III?Home
Meiosis and Mitosis for 500Meiosis and Mitosis for 500
There are 44 chromosomes present in a There are 44 chromosomes present in a cell in meiotic prophase I. This is the cell in meiotic prophase I. This is the number of chromosomes present in number of chromosomes present in the daughter cell after meiotic the daughter cell after meiotic telophase II.telophase II.
What is 22?What is 22?Home
Translation for 500Translation for 500
A codon sequence for leucine has the A codon sequence for leucine has the code CUA. The C in this sequence code CUA. The C in this sequence undergoes a transversion. This is the undergoes a transversion. This is the new triplet code for the codon and this is new triplet code for the codon and this is its amino acid.its amino acid.
What is AUA (isoleucine) or GUA (valine)?What is AUA (isoleucine) or GUA (valine)?
Home
RNA Transcription for 500RNA Transcription for 500
The following represents a DNA The following represents a DNA template strand: 5’-A A A T C T A G T template strand: 5’-A A A T C T A G T T G C A T-3’. This is the sequence of T G C A T-3’. This is the sequence of the RNA copied from the template.the RNA copied from the template.
What is 5’-A U G C A A C U A G A U U U-What is 5’-A U G C A A C U A G A U U U-3’3’
Home
Recombination for 500Recombination for 500
Home
Progeny Genotype Progeny Number
B r+ I-4 276
B r I-4 79
b r+ i-4 74
b r i-4 273
B r i-4 2
b r I-4 47
b r+ I-4 4
B r+ i-4 53
Total 808
This gene lies in the middle of the chromosome that contains the following three genes.
What is B?
DNA Duplication for 500DNA Duplication for 500
A double-stranded DNA replicates in a A double-stranded DNA replicates in a radioactive medium. This term defines radioactive medium. This term defines the type of replication that would occur the type of replication that would occur if all of the second generation DNA if all of the second generation DNA molecules consisted of 75% radioactive molecules consisted of 75% radioactive DNA and 25% parental DNA.DNA and 25% parental DNA.
What is dispersive replication?What is dispersive replication?
Home
ReferencesReferences
sciencesuperschool.comsciencesuperschool.com
biologycorner.combiologycorner.com
dna.microbiologyguide.comdna.microbiologyguide.com
Pierce, Benjamin. “Genetics: A Pierce, Benjamin. “Genetics: A Conceptual Approach” 2008.Conceptual Approach” 2008.
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