(p)Threads Libraries Math 442 es Jim Fix. Life cycle of a thread

Preview:

Citation preview

(p)Threads Libraries

Math 442 es

Jim Fix

Life cycle of a thread

Creation/Joining/Exit

When a process is first created, it has one thread of execution.

(C) executes main

That thread spawns other threads(pthread) specify initial code for new thread

Each, in turn, can spawn more threads

Any thread can wait for a specified thread to ``join” it

(pthread) blocks until other other thread terminates

Using libpthread.a: creation

Creating a thread (in Terminal:``man pthread_create”):int pthread_create(pthread_t *thread, pthread_attr_t *attr, void *(*start_routine)(void *), void *arg);

thread: reference to a thread descriptor; will get filled with new thread’s info

attr: reference to a thread attribute struct

start_routine: proc that new thread executes

arg: parameter for that start routine

Using libpthread.a: join/exit

To wait for a another thread to terminate:int pthread_join(pthread_t *other_thread, void **value_h);

other_thread: descriptor of thread to wait for

ret_value: handle to value returned by other thread

Other thread joins this join-caller when:

• it calls int pthread_exit(void *value_p)

• it returns (a value) from its start routine

Simple example: patrub.clong pat() { for (long i=0; i<1000000L; i++)

printf("pat #%d\n",i); return i; }long rub() { for (long i=0; i<1000000L; i++) printf("rub #%d\n",i); } return i; }int main(int argc, char **argv) { pthread_t id1, id2; long val1, val2;pthread_attr_t a;pthread_attr_init(&a);pthread_create(&id1,&a,(void *(*)(void *))(&pat),NULL); pthread_create(&id2,&a,(void *(*)(void *))(&rub),NULL);pthread_join(id1,(void **)&val1); pthread_join(id2,(void **)&val2); printf("Completed pats: %d ...rubs:%d\n",val1,val2); pthread_exit(NULL);}

other_thread: descriptor of thread to wait for

ret_value: handle to value returned by other thread

Other thread joins this join-caller when:

• it calls int pthread_exit(void *value_p)

• it returns (a value) from its start routine

The Trouble w/ Concurrency

Suppose one thread executes this code:1. void count1(int *c) {2. while (1) {3. (*c) = (*c) + 1;4. }5. }

...and another executes this code:1. void count2(int *c) {2. while (1) {3. (*c) = (*c) + 1;4. }5. }... and the main driving code looks like this:

static int shared_counter = 0;...{... pthread_create(&id1,NULL,&count1,&shared_counter); pthread_create(&id2,NULL,&count2,&shared_counter); ...}

What can go wrong?

What’s Really Happening

The code:...(*c) = (*c) + 1;...

...is really code like:mov r28,r24mov r29,r25...ld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1...

...

The increment op is not an ``atomic” one.

When two threads run concurrently, say, (even) on a single processor (with preemption), their execution could be interleaved.

One Possible Interleavingld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1ld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1ld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1ld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1ld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)

mov.w @r0,r1adds #1,r1mov.w r1,@r0

thread 1

thread 2

An Different Interleavingld r18,Yldd r19,Y+1ld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1ld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1 subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1ld r18,Yldd r19,Y+1subi r18,lo8(-1)sbci r19,hi8(-1)st r18,Ystd r19,Y+1

What happens? (remember: registers are unshared)

thread 1

thread 2

A test: counters.c (part I)

The main driver:1. int main(int argc, char **argv) {2. long counter = 0;3. pthread_t id1, id2;4. long rv1, rv2;5. pthread_attr_t a; pthread_attr_init(&a);6. pthread_create(&id1,&a,(void *(*)(void *))(&count),7. (void *)&counter);8. pthread_create(&id2,&a,(void *(*)(void *))(&count),9. (void *)&counter);10. pthread_join(id1,(void **)&val1); 11. pthread_join(id2,(void **)&val2);12. printf("%d + %d = %d?\n",val1,val2,counter);13. return 0;14. }

A test: counters.c (part II)

Each counter thread’s code:1. long count(long *c) {2. long i;3. for (i=0; i<1000000L; i++) {4. int j = (*c);5. (*c) = j+1;6. }7. return i;8. }

Let’s run it and see ( go to Terminal )

Increment is a critical section of the code:

long i; for (i=0; i<1000000L; i++) { int j = (*c); (*c) = j+1; } return i;

The counter is shared by both threads.• When they increment, they should

have exclusive access to it.• }

The Problem

MutexesMost thread libraries (including POSIX) provide mutex variables for locking critical sections:pthread_mutex_t m;pthread_mutexattr_t m_attr;

pthread_mutex_init(&m,&m_attr);// initializes a mutex variable

pthread_mutex_lock(&m);// gives access to m, other threads block or wait.

pthread_mutex_unlock(&m);// releases m, gives to a waiting thread.

The mutex variable provides mutual exclusion.

Locking a Crit. Sect.Here is the new version of the counter code:1. long count(counter_m *cm) {2. long *c = cm->counter;3. pthread_mutex_t *m = cm->mutex;4. long i;5. for (i=0; i<1000000L; i++) {6. pthread_mutex_lock(m); // acquire the lock7. int j = (*c);8. (*c) = j+1;9. pthread_mutex_unlock(m); // release the lock10. }11. return i;12. }

Let’s run it. (go to Terminal)

A question for your consideration:

How does one build a mutex????

(i.e. a mutex library for a threading system????)

Thread SynchronizationSynchronizing concurrent threads’ access to shared data/resources is crucial.

See: (thanks to UCB’s cs16x)space shuttle (Garman, 1981)

Therac-25 (Leveson, 1995)

Recommended