Sec 3.5 Increase and Decrease Problems Objectives –Learn to identify an increase or decrease...

Preview:

Citation preview

Sec 3.5 Increase and Decrease Sec 3.5 Increase and Decrease ProblemsProblems

• Objectives–Learn to identify an increase or

decrease problem.

–Apply the basic diagram for increase or decrease problems.

–Use the basic percent formula to solve increase or decrease problems.

Increase ProblemsIncrease Problems

The part equals 100% of the base plus some portion of the base.

Increase ProblemsIncrease Problems

The part equals 100% of the base plus some portion of the base.

Phrases such as after an increase of,

Increase ProblemsIncrease Problems

The part equals 100% of the base plus some portion of the base.

Phrases such as after an increase of, more than,

Increase ProblemsIncrease Problems

The part equals 100% of the base plus some portion of the base.

Phrases such as after an increase of, more than, or greater than

Increase ProblemsIncrease Problems

The part equals 100% of the base plus some portion of the base.

Phrases such as after an increase of, more than, or greater than often indicate an increase problem.

Increase ProblemsIncrease Problems

The part equals 100% of the base plus some portion of the base.

Phrases such as after an increase of, more than, or greater than often indicate an increase problem.

The basic formula for an increase problem is:

Increase ProblemsIncrease Problems

The part equals 100% of the base plus some portion of the base.

Phrases such as after an increase of, more than, or greater than often indicate an increase problem.

The basic formula for an increase problem is:

Original value + Increase = New Value

Example 1Example 1

Base Rate of Part

Inc. (after Inc.)

???? 20% $660

Base plus some portion of the base equals $660.

Base

????

Base

????

Amt. Of Increase

Base

????

Amt. Of Increase

20% of Base

Base

????

Amt. Of Increase

20% of Base

Sum of Base

and increase is

$660

Part Rate of Base

(after Inc.) Inc.

$660 20% ???

100% of Base + 20% of Base = $660

100% of Base + 20% of Base = $660

120% of Base = $660

100% of Base + 20% of Base = $660

120% of Base = $660

R x B = P

100% of Base + 20% of Base = $660

120% of Base = $660

R x B = P

Hence, R = 120%

P = $660

B = ???

R x B = PHence, R = 120% P = $660 B = ??? Thus, P $660 $660B = ----- = ---------- = ----------- = $550 R 120% 1.2

So if we take 100% of the base ($550) + 20% of the base ($110) we get $660 (part).

Decrease ProblemsDecrease Problems

The part equals 100% of the base minus some portion of the base.

Decrease ProblemsDecrease Problems

The part equals 100% of the base minus some portion of the base.

Phrases such as after a decrease of,

Decrease ProblemsDecrease Problems

The part equals 100% of the base minus some portion of the base.

Phrases such as after a decrease of, less than,

Decrease ProblemsDecrease Problems

The part equals 100% of the base minus some portion of the base.

Phrases such as after a decrease of, less than, or after a reduction of

Decrease ProblemsDecrease Problems

The part equals 100% of the base minus some portion of the base.

Phrases such as after a decrease of, less than, or after a reduction of often indicate a decrease problem.

Decrease ProblemsDecrease Problems

The part equals 100% of the base minus some portion of the base.

Phrases such as after a decrease of, less than, or after a reduction of often indicate a decrease problem.

The basic formula for a decrease problem is:

Decrease ProblemsDecrease Problems

The part equals 100% of the base minus some portion of the base, yielding a new value.

Phrases such as after a decrease of, less than, or after a reduction of often indicate a decrease problem.

The basic formula for a decrease problem is:

Original Value - Decrease = New Value

ExampleExample 2 2

The sale price of a new Palm Pilot, after a 15% decrease, was $98.38. Find the price of the Palm Pilot before the decrease.

ExampleExample 2 2

Base Rate of Part Dec. (after Dec.)

??? 15% $98.38

Base minus some portion of the base equals $98.38.

Price Paid = $98.38

(Part)

Price Paid = $98.38

(Part)

Amt. of Decrease

Price Paid = $98.38

(Part)

Amt. of Decrease

15% of Base

Price Paid = $98.38

(Part)

Amt. of Decrease

15% of Base

Orig. Price minus decrease = price paid

Base Rate of Part Dec. (after Dec.)

??? 15% $98.38

100% of Base - 15% of Base = $98.38

100% of Base - 15% of Base = $98.38

85% of Base = $98.38

85% of Base = $98.38

R x B = P

85% of Base = $98.38

R x B = P

Hence, R = 85%

P = $98.38

B = ???

85% of Base = $98.38

R x B = P

Hence, R = 85%

P = $98.38

B = ???

Thus,

P $98.38 $98.38

B = ----- = ---------- = ----------- = $115.74

R 85% 0.85

So, if we take 100% of the base ($115.74) minus 15% of the base ($17.36) we get $98.38.

Homework Sec 3.5: 1, 3, 5, 7, …, 33Homework Sec 3.5: 1, 3, 5, 7, …, 33

Recommended