Semiconductor Device Physicseng.staff.alexu.edu.eg/~mmorsy/Courses/Undergraduate/EE...Formation of...

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Lecture 6

Semiconductor Device Physics

http://zitompul.wordpress.com

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Chapter 5pn Junction Electrostatics

Semiconductor Device Physics

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Step junctionidealization

Metallurgical Junction

Chapter 5 pn Junction Electrostatics

Doping profile

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Poisson’s Equation

Chapter 5 pn Junction Electrostatics

S 0K

E v D

D E

S 0K

S 0x K

E

Poisson’s equation is a well-known relationship in electricity and magnetism.

It is now used because it often contains the starting point in obtaining quantitative solutions for the electrostatic variables.

In one-dimensional problems, Poisson’s equation simplifies to:

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Equilibrium Energy Band Diagram

Chapter 5 pn Junction Electrostatics

pn-Junction diode

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Band diagram

c ref

1( )V E E

q

Qualitative Electrostatics

Chapter 5 pn Junction Electrostatics

Equilibrium condition

Electrostatic potential

( )V x dx E

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Electric field

Qualitative Electrostatics

Chapter 5 pn Junction Electrostatics

Equilibrium condition

Charge density

dV

dx E

S 0K

E

x

S 0

( )x xK

E

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Formation of pn Junction and Charge Distribution

Chapter 5 pn Junction Electrostatics

D A( )q p n N N qNA– qND

+

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Formation of pn Junction and Charge Distribution

Chapter 5 pn Junction Electrostatics

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DF i n-side

i i

( ) ln lnNn

E E kT kTn n

bi F i n side i F p side( ) ( )qV E E E E

Ai F p-side

i i

( ) ln lnNp

E E kT kTn n

A Dbi 2

i

lnN N

qV kTn

Built-In Potential Vbi

Chapter 5 pn Junction Electrostatics

For non-degenerately doped material,

• Vbi for several materials:

Ge ≤ 0.66 V

Si ≤ 1.12 V

GeAs ≤ 1.42 V

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A1

S

( )qN

x x c

E

The Depletion Approximation

A

S

qNd

dx E

Dn

S

( ) ( )qN

x x x

E

Ap

S

( ) ( )qN

x x x

E

with boundary E(–xp) 0

with boundary E(xn) 0

Chapter 5 pn Junction Electrostatics

On the p-side, ρ = –qNA

On the n-side, ρ = qND

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A p

D n

, 0

, 0

0,

qN x x

qN x x

otherwise

Ap p

S

Dn n

S

( ), 0

( )

( ), 0

qNx x x x

xqN

x x x x

E

2Ap p

S

2Dbi n n

S

( ) , 02

( )

( ) , 02

qNx x x x

V xqN

V x x x x

Step Junction with VA0

Chapter 5 pn Junction Electrostatics

Solution for ρ

Solution for E

Solution for V

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Relation between ρ(x), E(x), and V(x)

Chapter 5 pn Junction Electrostatics

1.Find the profile of the built-in potential Vbi

2.Use the depletion approximation ρ(x)

With depletion-layer widths xp, xn unknown

3.Integrate ρ(x) to find E(x)

Boundary conditions E(–xp) 0, E(xn)0

4.Integrate E(x) to obtain V(x)

Boundary conditions V(–xp) 0, V(xn) Vbi

5.For E(x) to be continuous at x 0, NAxp NDxn

Solve for xp, xn

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Bonus Question

• Answer the following questions in a report.

• Can the built-in potential of a pn junction in

equilibrium be measured directly. Justify your

answer.

• What happens if VA is increased beyond the built

in potential Vbi in the forward biased region.

– Keep all bonus reports and submit them upon

requesting that.

– Only non-cheated reports will be rewarded while

students who will submit copied reports will be

punished.

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2 2A Dp bi n

S S

( ) ( )2 2

qN qNx V x

A p D nN x N x

Step Junction with VA0

Chapter 5 pn Junction Electrostatics

At x = 0, expressions for p-side and n-side for the solutions of E and V must be equal:

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S An bi

D A D

2

( )

Nx V

q N N N

S Dp bi

A A D

2

( )

Nx V

q N N N

n px x W

Dn

A

Nx

N

Depletion Layer Width

Chapter 5 pn Junction Electrostatics

Eliminating xp,

Eliminating xn,

Summing Sbi

A D

2 1 1V

q N N

Exact solution, try to derive

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S bi Dn p n

D A

2 , 0

V NW x x x

q N N

S bi2 VW

q N

S bi Ap n p

A D

2 , 0

V NW x x x

q N N

One-Sided Junctions

Chapter 5 pn Junction Electrostatics

If NA >> ND as in a p+n junction,

If ND >> NA as in a n+p junction,

Simplifying,

where N denotes the lighter dopant density

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D Abi 2

i

lnN NkT

Vq n

S bi

D

2 VW

qN

n 0.115 mx W

Dp n

A

Nx x

N

Example: Depletion Layer Width

Chapter 5 pn Junction Electrostatics

A p+n junction has NA 1020 cm–3 and ND 1017cm–3, at 300 K.

a) What isVbi?

b) What is W?

c) What is xn?

d) What is xp?

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10 2

10 1025.86 mV ln 1.012 V

(10 )

1/ 214

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2 11.9 8.854 10 1.0120.115 m

1.602 10 10

30.115 m 10 1.15 Å

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Step Junction with VA 0

Chapter 5 pn Junction Electrostatics

• To ensure low-level injection conditions, reasonable current levels must be maintained VA should be small

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Step Junction with VA 0

Chapter 5 pn Junction Electrostatics

In the quasineutral, regions extending from the contacts to the edges of the depletion region, minority carrier diffusion equations can be applied since E ≈ 0.

In the depletion region, the continuity equations are applied.

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A Dbi

i i

ln lnN NkT kT

Vq n q n

Sp n bi A

A D

2 1 1W x x V V

q N N

S D

p bi A

A A D

2,

Nx V V

q N N N

S A

n bi A

D A D

2 Nx V V

q N N N

Step Junction with VA 0

Chapter 5 pn Junction Electrostatics

Built-in potential Vbi (non-degenerate doping):

A D

2

i

lnN NkT

q n

Depletion width W :

,Dp

A D

Nx W

N N

W

NN

Nx

DA

An

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Effect of Bias on Electrostatics

Chapter 5 pn Junction Electrostatics

• If voltage drop , then depletion width

• If voltage drop , then depletion width

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Linearly-Graded Junction

Chapter 5 pn Junction Electrostatics

S

1dx

E V dx E

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