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Algebra 1: Solving Equations Review (September 1)
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Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
BellringerSimplify.
1. 15x – 4x
2. 5(x – 7)
Solve.
3. x + 7 = 18
4. 5a – 6 = 44
11x5x - 35
x = 11
x = 10
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides2-4 Solving Equations with
Variables on Both Sides
Holt Algebra 1
•BellringerBellringer
•Review for QuizReview for Quiz
•Wall reviewWall review
•Game (If we have time)Game (If we have time)
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve equations in one variable that contain variable terms on both sides.
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2
Objective
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve the equation. Check your answer.
Review…
16 = m – 8
+ 8 + 824 = m
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve 2a + 3 – 8a = 8.
Check It Out! Example 3a
Use the Commutative Property of Addition.
2a + 3 – 8a = 8
2a – 8a + 3 = 8
–6a + 3 = 8 Combine like terms.
Since 3 is added to –6a, subtract 3 from both sides to undo the addition.
– 3 – 3
–6a = 5Since a is multiplied by –6, divide both
sides by –6 to undo the multiplication.
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve the equation. Check your answer.
Review….
Since 8 is subtracted from y, add 8 to both sides to undo the subtraction.
y – 8 = 24 + 8 + 8
y = 32
Check y – 8 = 24
32 – 8 2424 24
To check your solution, substitute 32 for y in the
original equation.
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve 26 = 4a + 10.
Review…
26 = 4a + 10
–10 – 10
16 = 4a
16 = 4a4 4
4 = a
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve 5t – 2 = –32.
Review…
5t – 2 = –32
+ 2 + 2
5t = –30
5t = –30 5 5
t = –6
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve .
Check it Out! Example 1c
First n is divided by 7. Then 2 is added. Work backward: Subtract 2 from both sides.–2 –2
Since n is divided by 7, multiply both sides by 7 to undo the division.
n = 0
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve 7n – 2 = 5n + 6.
Example 1: Solving Equations with Variables on Both Sides
To collect the variable terms on one side, subtract 5n from both sides.
7n – 2 = 5n + 6
–5n –5n
2n – 2 = 6
Since n is multiplied by 2, divide both sides by 2 to undo the multiplication.
2n = 8
+ 2 + 2
n = 4
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve 4b + 2 = 3b.
Check It Out! Example 1a
To collect the variable terms on one side, subtract 3b from both sides.
4b + 2 = 3b
–3b –3b
b + 2 = 0
b = –2
– 2 – 2
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve 4 – 6a + 4a = –1 – 5(7 – 2a).
Example 2: Simplifying Each Side BeforeSolving Equations
Combine like terms.
Distribute –5 to the expression in parentheses.
4 – 6a + 4a = –1 –5(7 – 2a)
4 – 6a + 4a = –1 –5(7) –5(–2a)
4 – 6a + 4a = –1 – 35 + 10a
4 – 2a = –36 + 10a
+36 +36
40 – 2a = 10a+ 2a +2a
40 = 12a
Since –36 is added to 10a, add 36 to both sides.
To collect the variable terms on one side, add 2a to both sides.Standards: SPI 3102.1.3, 3102.2.2,
CLE 3102.3.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve 4 – 6a + 4a = –1 – 5(7 – 2a).
Example 2 Continued
40 = 12a
Since a is multiplied by 12, divide both sides by 12.
Standards: SPI 3102.1.3, 3102.2.2, CLE 3102.3.2, CLE 3102.3.2
Holt Algebra 1
2-4Solving Equations with Variables on Both Sides
Solve 3x + 15 – 9 = 2(x + 2).
Check It Out! Example 2B
Combine like terms.
Distribute 2 to the expression in parentheses.
3x + 15 – 9 = 2(x + 2)
3x + 15 – 9 = 2(x) + 2(2)
3x + 15 – 9 = 2x + 4
3x + 6 = 2x + 4
–2x –2x
x + 6 = 4 – 6 – 6
x = –2
To collect the variable terms on one side, subtract 2x from both sides.
Since 6 is added to x, subtract 6 from both sides to undo the addition.Standards: SPI 3102.1.3, 3102.2.2,
CLE 3102.3.2, CLE 3102.3.2
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