X2 T01 09 geometrical representation of complex numbers

Geometrical Representation of Complex Numbers

Geometrical Representation of Complex Numbers

Complex numbers can be represented on the Argand Diagram as vectors.

Geometrical Representation of Complex Numbers

Complex numbers can be represented on the Argand Diagram as vectors.y

x

Geometrical Representation of Complex Numbers

Complex numbers can be represented on the Argand Diagram as vectors.y

x

iyxz

Geometrical Representation of Complex Numbers

Complex numbers can be represented on the Argand Diagram as vectors.y

x

iyxz

Geometrical Representation of Complex Numbers

Complex numbers can be represented on the Argand Diagram as vectors.y

x

iyxz

The advantage of using vectors is that they can be moved around the Argand Diagram

Geometrical Representation of Complex Numbers

Complex numbers can be represented on the Argand Diagram as vectors.y

x

iyxz

The advantage of using vectors is that they can be moved around the Argand Diagram

Geometrical Representation of Complex Numbers

Complex numbers can be represented on the Argand Diagram as vectors.y

x

iyxz

The advantage of using vectors is that they can be moved around the Argand DiagramNo matter where the vector is placed its length (modulus) and the angle made with the x axis (argument) is constant

Geometrical Representation of Complex Numbers

Complex numbers can be represented on the Argand Diagram as vectors.y

x

iyxz

The advantage of using vectors is that they can be moved around the Argand DiagramNo matter where the vector is placed its length (modulus) and the angle made with the x axis (argument) is constant

A vector always

represents

HEAD minus TAIL

Addition / Subtraction

Addition / Subtraction

y

x

Addition / Subtraction

y

x

1z

Addition / Subtraction

y

x

1z

2z

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

21 zz

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

21 zz

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

21 zz 2121 and diagonals; twohas vectors

addingby formed ramparallelog the:

zzzz

NOTE

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

21 zz 2121 and diagonals; twohas vectors

addingby formed ramparallelog the:

zzzz

NOTE

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

21 zz 2121 and diagonals; twohas vectors

addingby formed ramparallelog the:

zzzz

NOTE

Trianglar InequalityIn any triangle a side will be shorter than the sum of the other two sides

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

21 zz 2121 and diagonals; twohas vectors

addingby formed ramparallelog the:

zzzz

NOTE

Trianglar InequalityIn any triangle a side will be shorter than the sum of the other two sides

BCABACABC ;In

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

21 zz 2121 and diagonals; twohas vectors

addingby formed ramparallelog the:

zzzz

NOTE

Trianglar InequalityIn any triangle a side will be shorter than the sum of the other two sides

BCABACABC ;In (equality occurs when AC is a straight line)

Addition / Subtraction

y

x

1z

2z

To add two complex numbers, place the vectors “head to tail”

21 zz

To subtract two complex numbers, place the vectors “head to head” (or add the negative vector)

21 zz 2121 and diagonals; twohas vectors

addingby formed ramparallelog the:

zzzz

NOTE

Trianglar InequalityIn any triangle a side will be shorter than the sum of the other two sides

BCABACABC ;In (equality occurs when AC is a straight line)

2121 zzzz

AdditionIf a point A represents and point B represents then point C representing

is such that the points OACB form a parallelogram.

1z2z

21 zz

AdditionIf a point A represents and point B represents then point C representing

is such that the points OACB form a parallelogram.

1z2z

21 zz

SubtractionIf a point D represents and point E represents then the points ODEB form a parallelogram.

Note:

1z12 zz

12 zzAB

12arg zz

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

zOP is oflength The

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

zOP is oflength ThewOQ is oflength The

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

zOP is oflength ThewOQ is oflength The

wzPQ is oflength The

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

zOP is oflength ThewOQ is oflength The

wzPQ is oflength Thewzwz

OPQ

on inequalityr triangulatheUsing

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

zOP is oflength ThewOQ is oflength The

wzPQ is oflength Thewzwz

OPQ

on inequalityr triangulatheUsing

(ii) Construct the point R representing z + w, What can be said about thequadrilateral OPRQ?

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

zOP is oflength ThewOQ is oflength The

wzPQ is oflength Thewzwz

OPQ

on inequalityr triangulatheUsing

(ii) Construct the point R representing z + w, What can be said about thequadrilateral OPRQ?

R

1995..ge y

x

P

O

Q

The diagram shows a complex plane with origin O.The points P and Q represent the complex numbers z and w respectively.Thus the length of PQ is wz wzwzi that Show

zOP is oflength ThewOQ is oflength The

wzPQ is oflength Thewzwz

OPQ

on inequalityr triangulatheUsing

(ii) Construct the point R representing z + w, What can be said about thequadrilateral OPRQ?

R

OPRQ is a parallelogram

?about said becan what , If zwwzwziii

?about said becan what , If zwwzwziii

wzwz

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

2argarg

zw

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

2argarg

zw

2arg

zw

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

2argarg

zw

2arg

zw imaginarypurely is

zw

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

2argarg

zw

2arg

zw imaginarypurely is

zw

Multiplication

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

2argarg

zw

2arg

zw imaginarypurely is

zw

Multiplication

2121 zzzz

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

2argarg

zw

2arg

zw imaginarypurely is

zw

Multiplication

2121 zzzz 2121 argargarg zzzz

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

2argarg

zw

2arg

zw imaginarypurely is

zw

Multiplication

2121 zzzz 2121 argargarg zzzz

21212211 cisrrcisrcisr

?about said becan what , If zwwzwziii

wzwz i.e. diagonals in OPRQ are =rectanglea is OPRQ

2argarg

zw

2arg

zw imaginarypurely is

zw

Multiplication

2121 zzzz 2121 argargarg zzzz

21212211 cisrrcisrcisr

2

2121

by multiplied islength its and by iseanticlockwrotated isvector the,by multiply weif ..

rzzzei

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note:

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

2by iseanticlockwrotation a is by tion Multiplica i

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAIL

2by iseanticlockwrotation a is by tion Multiplica i

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

2by iseanticlockwrotation a is by tion Multiplica i

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

)1( iC

2by iseanticlockwrotation a is by tion Multiplica i

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

)1( iC( 1) 1B i

2by iseanticlockwrotation a is by tion Multiplica i

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

)1( iC( 1) 1B i

( 1) ( 1)B i

2by iseanticlockwrotation a is by tion Multiplica i

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

)1( iC( 1) 1B i

( 1) ( 1)B i

2by iseanticlockwrotation a is by tion Multiplica i

OR

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

)1( iC( 1) 1B i

( 1) ( 1)B i

2by iseanticlockwrotation a is by tion Multiplica i

OR( 1) ( 1)B i

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

)1( iC( 1) 1B i

( 1) ( 1)B i

2by iseanticlockwrotation a is by tion Multiplica i

OR( 1) ( 1)B i

OR

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

)1( iC( 1) 1B i

( 1) ( 1)B i

2by iseanticlockwrotation a is by tion Multiplica i

OR( 1) ( 1)B i

OR

2 ( 1)4

B cis

If we multiply by the vector OA will rotate by an angle of in an anti-clockwise direction. If we multiply by it will also multiply the length of OA by a factor of r

1z cis

rcis

ii 2

sin2

cos Note: 1iz will rotate OA anticlockwise 90 degrees.

REMEMBER: A vector is HEAD minus TAILy

x

A

O

C

B

)1(D

)1( iC( 1) 1B i

( 1) ( 1)B i

2by iseanticlockwrotation a is by tion Multiplica i

OR( 1) ( 1)B i

OR

2 ( 1)4

B cis

1 ( 1)B i

2000..ge y

x

A

O

C

In the Argand Diagram, OABC is a rectangle, where OC = 2OA.The vertex A corresponds to the complex number

B

2000..ge y

x

A

O

C

In the Argand Diagram, OABC is a rectangle, where OC = 2OA.The vertex A corresponds to the complex number

B

? toscorrespondnumber complex What Ci

2000..ge y

x

A

O

C

In the Argand Diagram, OABC is a rectangle, where OC = 2OA.The vertex A corresponds to the complex number

B

? toscorrespondnumber complex What Ci

iC 2

2000..ge y

x

A

O

C

In the Argand Diagram, OABC is a rectangle, where OC = 2OA.The vertex A corresponds to the complex number

B

? toscorrespondnumber complex What Ci

iC 2

(ii) What complex number corresponds to the point of intersection D of the diagonals OB and AC?

2000..ge y

x

A

O

C

In the Argand Diagram, OABC is a rectangle, where OC = 2OA.The vertex A corresponds to the complex number

B

? toscorrespondnumber complex What Ci

iC 2

(ii) What complex number corresponds to the point of intersection D of the diagonals OB and AC?

iiB21

2

2000..ge y

x

A

O

C

In the Argand Diagram, OABC is a rectangle, where OC = 2OA.The vertex A corresponds to the complex number

B

? toscorrespondnumber complex What Ci

iC 2

(ii) What complex number corresponds to the point of intersection D of the diagonals OB and AC?

iiB21

2

diagonals bisect in a rectangle

2000..ge y

x

A

O

C

In the Argand Diagram, OABC is a rectangle, where OC = 2OA.The vertex A corresponds to the complex number

B

? toscorrespondnumber complex What Ci

iC 2

(ii) What complex number corresponds to the point of intersection D of the diagonals OB and AC?

iiB21

2

diagonals bisect in a rectangle

iD 2121

Examples

Examples

31 cisB

Examples

31 cisB

iB23

21

Examples

31 cisB

iB23

21

iBD

Examples

31 cisB

iB23

21

iBD

iD21

23

Examples

31 cisB

iB23

21

iBD

iD21

23

DBC

Examples

31 cisB

iB23

21

iBD

iD21

23

DBC

iC

231

231

AOiAPi )(

AOiAPi )(

11 0 zizP

AOiAPi )(

11 0 zizP

11 izzP

AOiAPi )(

11 0 zizP

11 izzP 11 ziP

AOiAPi )(

11 0 zizP

11 izzP 11 ziP

BOiBQii )(

AOiAPi )(

11 0 zizP

11 izzP 11 ziP

BOiBQii )(iBBQ

AOiAPi )(

11 0 zizP

11 izzP 11 ziP

BOiBQii )(iBBQ

21 ziQ

AOiAPi )(

11 0 zizP

11 izzP 11 ziP

BOiBQii )(iBBQ

21 ziQ

2QPM

AOiAPi )(

11 0 zizP

11 izzP 11 ziP

BOiBQii )(iBBQ

21 ziQ

2QPM

2

11 21 ziziM

AOiAPi )(

11 0 zizP

11 izzP 11 ziP

BOiBQii )(iBBQ

21 ziQ

2QPM

2

11 21 ziziM

2

2121 izzzzM

Exercise 4K; 1 to 8, 11, 12, 13

Exercise 4L; odd