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5x4 – 405
= 5(x4 – 81)
= 5(x2 + 9)(x2 – 9)
= 5(x2 + 9)(x + 3)(x – 3)by D. Fisherby D. Fisher
x2 + 10x + 16
= (x + 8)(x + 2)
x2 + 4x – 21
= (x + 7)(x – 3)
2x2 + 7x + 3
= (2x + 1)(x + 3)
3x2y + 12xy
= 3xy(x + 4)
x3 + 5x2 – x
= x(x2 + 5x – 1)
x2 – 81
= (x + 9)(x – 9)
4x2 – 121 =
(2x + 11)(2x – 11)
x2 – 14x + 49
= (x – 7)2
x2 + 8x + 16
= (x + 4)2
25x2 – 10x + 1
= (5x – 1)2
x2 – x – 6
= (x – 3)(x + 2)
3x2 +24x + 21
= 3(x + 1)(x + 7)
= 3(x2 + 8x + 7)
x4 – 16
(x2 + 4)(x – 2)(x + 2)
= (x2 + 4)(x2 – 4)
x2y +4xy + 4y
= y(x + 2)2
9x2 + 6x + 1
= (3x + 1)2
2x2 – 18x + 40
= 2(x – 4)(x – 5)
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