Lesson 3: The Cross Product

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The cross product is an important operation, taking two three-dimensional vectors and producing a three-dimensional vector. It's not a product in the commutative, associative, sense, but it does produce a vector which is perpendicular to the two crossed vectors and whose length is the area of the parallelogram spanned by the them. The direction is chosen again to follow the right-hand rule.

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Section 9.4Cross Products and Planes

Math 21a

February 8, 2008

Announcements

I Homework for Monday 2/11:I Section 9.4. Exercises 4, 6, 8, 10, 19, 22, 30; pp. 664–665.I Section 9.5. Exercise 1*; pp. 673–675.

Outline

Torque and the Cross Product

Properties of the Cross ProductOn a basisIn GeneralBy components

Other applicationsAreaVolume

Torque

When force is applied to a lever fixed to a point, some of the forcegoes towards rotation while the rest goes towards stretching thelever.

r

F|F | sin θ θ

τ

The magnitude of the torque is also proportional to the length ofthe lever, and has a direction depending on which direction thelever pivots.

Torque

When force is applied to a lever fixed to a point, some of the forcegoes towards rotation while the rest goes towards stretching thelever.

r

F|F | sin θ θ

τ

The magnitude of the torque is also proportional to the length ofthe lever, and has a direction depending on which direction thelever pivots.

Example

A bicycle pedal is pushed by a foot with a 60 N force. The crankarm is 180 mm long. Find the magnitude of the torque about P.

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Solution

|τ | = |r| |F| |sin θ| = (0.18 m)(60 N) sin(80◦) ≈ 10.6359 N m

Example

A bicycle pedal is pushed by a foot with a 60 N force. The crankarm is 180 mm long. Find the magnitude of the torque about P.

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Solution

|τ | = |r| |F| |sin θ| = (0.18 m)(60 N) sin(80◦) ≈ 10.6359 N m

In General

DefinitionGiven vectors a and b in space, the cross product of a and b isthe vector

a× b = |a| |b| (sin θ) n,

where n is a vector perpendicular to a and b such that (a,b,n) isa right-handed set of three vectors.

Example

State whether the following position is meaningful. If not, explain.If so, is the expression a scalar or a vector?

1. a · (b× c)

2. a× (b · c)

3. a× (b× c)

4. (a · b)× c

5. (a · b)× (c · d)

6. (a× b) · (c× d)

Outline

Torque and the Cross Product

Properties of the Cross ProductOn a basisIn GeneralBy components

Other applicationsAreaVolume

Cross products of the standard basis vectors

Fill in the table:× i j ki

0 k − j

j

− k 0 i

k

j − i 0

I Is the cross product commutative?

No

i× j = k = −j× i

I Is the cross product associative?

No

i× (i× j) = i× k = −j

(i× i)× j = 0

Cross products of the standard basis vectors

Fill in the table:× i j ki 0 k − jj − k 0 ik j − i 0

I Is the cross product commutative?

No

i× j = k = −j× i

I Is the cross product associative?

No

i× (i× j) = i× k = −j

(i× i)× j = 0

Cross products of the standard basis vectors

Fill in the table:× i j ki 0 k − jj − k 0 ik j − i 0

I Is the cross product commutative?

No

i× j = k = −j× i

I Is the cross product associative?

No

i× (i× j) = i× k = −j

(i× i)× j = 0

Cross products of the standard basis vectors

Fill in the table:× i j ki 0 k − jj − k 0 ik j − i 0

I Is the cross product commutative? No

i× j = k = −j× i

I Is the cross product associative?

No

i× (i× j) = i× k = −j

(i× i)× j = 0

Cross products of the standard basis vectors

Fill in the table:× i j ki 0 k − jj − k 0 ik j − i 0

I Is the cross product commutative? No

i× j = k = −j× i

I Is the cross product associative?

No

i× (i× j) = i× k = −j

(i× i)× j = 0

Cross products of the standard basis vectors

Fill in the table:× i j ki 0 k − jj − k 0 ik j − i 0

I Is the cross product commutative? No

i× j = k = −j× i

I Is the cross product associative? No

i× (i× j) = i× k = −j

(i× i)× j = 0

Algebraic Properties of the Cross Product

If a, b, and c are vectors and c is a scalar, then

1. a× b = −b× a

2. (ca)× b = c(a× b) = a× (cb)

3. a× (b + c) = a× b + a× c

4. (a + b)× c = a× c + b× c

Cross product by components

QuestionIf

a = 〈a1, a2, a3〉= a1i + a2j + a3k

b = 〈b1, b2, b3〉= b1i + b2j + b3k

Find a× b.

Answer

a× b = (a2b3 − b2a3)i + (a3b1 − b3a1)j + (a1b2 − b1a2)k

= 〈a2b3 − b2a3, a3b1 − b3a1, a1b2 − b1a2〉

Cross product by components

QuestionIf

a = 〈a1, a2, a3〉= a1i + a2j + a3k

b = 〈b1, b2, b3〉= b1i + b2j + b3k

Find a× b.

Answer

a× b = (a2b3 − b2a3)i + (a3b1 − b3a1)j + (a1b2 − b1a2)k

= 〈a2b3 − b2a3, a3b1 − b3a1, a1b2 − b1a2〉

Determinant formula

This is only to help you remember, in case you’ve seendeterminants of 3× 3 matrices:∣∣∣∣∣∣

i j ka1 a2 a3

b1 b2 b3

∣∣∣∣∣∣ = i

∣∣∣∣a2 a3

b2 b3

∣∣∣∣− j

∣∣∣∣a1 a3

b1 b3

∣∣∣∣ + k

∣∣∣∣a1 a2

b1 b2

∣∣∣∣= (a2b3 − b2a3)i− (b3a1 − a3b1)j + (a1b2 − b1a2)k

= a× b

Procedure check

Example

Calculate a× b if

1. a = 〈1, 2, 0〉 and b = 〈0, 3, 1〉2. a = 3i + 2j + 4k and b = i− 2j− 3k

3. a = 〈t, t2, t3〉 and b = 〈1, 2t, 3t2〉

Solution

1. 〈2,−1, 3〉2. 2i + 13j− 8k

3.⟨t4,−2t3, t2

Procedure check

Example

Calculate a× b if

1. a = 〈1, 2, 0〉 and b = 〈0, 3, 1〉2. a = 3i + 2j + 4k and b = i− 2j− 3k

3. a = 〈t, t2, t3〉 and b = 〈1, 2t, 3t2〉

Solution

1. 〈2,−1, 3〉2. 2i + 13j− 8k

3.⟨t4,−2t3, t2

Outline

Torque and the Cross Product

Properties of the Cross ProductOn a basisIn GeneralBy components

Other applicationsAreaVolume

Area

The magnitude of the cross product a× b is the area of theparallelogram with sides a and b.

a

b |b| sin θ

Volume

To find the volume of a paralleliped with sides a, b, c:

ab

c

We getV = |a · (b× c)|

Volume

To find the volume of a paralleliped with sides a, b, c:

ab

c

We getV = |a · (b× c)|

More determinants

a · (b× c) = 〈a1, a2, a3〉 · 〈b2c3 − c2b3, b3c1 − c3b1, b1c2 − c1b2〉= a1(b2c3 − c2b3) + a2(b3c1 − c3b1) + a3(b1c2 − c1b2)

=

∣∣∣∣∣∣a1 a2 a3

b1 b2 b3

c1 c2 c3

∣∣∣∣∣∣

Example

Example

Find the volume of the parallelepiped determined by

a = 6i + 3j− k

b = j + 2k

c = 4i− 2j + 5k.

SolutionThe volume is∣∣∣∣∣∣∣∣∣∣∣∣6 3 −10 1 24 −2 5

∣∣∣∣∣∣∣∣∣∣∣∣ = 6(5 + 4)− 3(0− 8)− 1(−4) = 54 + 24 + 4 = 82

Example

Example

Find the volume of the parallelepiped determined by

a = 6i + 3j− k

b = j + 2k

c = 4i− 2j + 5k.

SolutionThe volume is∣∣∣∣∣∣∣∣∣∣∣∣6 3 −10 1 24 −2 5

∣∣∣∣∣∣∣∣∣∣∣∣ = 6(5 + 4)− 3(0− 8)− 1(−4) = 54 + 24 + 4 = 82

Cross product jokes

I What do you get when you cross a lion with a tiger?

I What do you get when you cross a lion with a mountainclimber?

I What do you get when you cross a mosquito with a fishmonger?

I What do you get when you cross an elephant with a banana?

I What do you get when you cross a mathematician with amovie star?

Cross product jokes

I What do you get when you cross a lion with a tiger?

I What do you get when you cross a lion with a mountainclimber?

I What do you get when you cross a mosquito with a fishmonger?

I What do you get when you cross an elephant with a banana?

I What do you get when you cross a mathematician with amovie star?

Cross product jokes

I What do you get when you cross a lion with a tiger?

I What do you get when you cross a lion with a mountainclimber?

I What do you get when you cross a mosquito with a fishmonger?

I What do you get when you cross an elephant with a banana?

I What do you get when you cross a mathematician with amovie star?

Cross product jokes

I What do you get when you cross a lion with a tiger?

I What do you get when you cross a lion with a mountainclimber?

I What do you get when you cross a mosquito with a fishmonger?

I What do you get when you cross an elephant with a banana?

I What do you get when you cross a mathematician with amovie star?

Cross product jokes

I What do you get when you cross a lion with a tiger?

I What do you get when you cross a lion with a mountainclimber?

I What do you get when you cross a mosquito with a fishmonger?

I What do you get when you cross an elephant with a banana?

I What do you get when you cross a mathematician with amovie star?

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