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Permutations

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Page 1: Permutations
Page 2: Permutations

Forty-three race cars started the 2004 Daytona 500. How many ways can the cars finish first, second, and third?

Page 3: Permutations

You need to select three race cars from a group of 43, so n = 43 and r = 3. Because the order’s important, the number of ways the cars can finish first, second, or third is:

Page 4: Permutations

nPr = 43P3 = 43! ---------- (43 – 3)!

= 43! ---------

40!

= 43 x 42 x 41

= 74,046