Ages-1 - I Can

“I Can Competitive Exams Centre” 1

Ages-1

1. The ratio of the age of a mother to that of his son at present is 9:6 and the ratio of the son to that of his father will be

1:2.What is the ratio of the present age of the mother to that of father ?

A.3:4 B.1:3

C.2:5 D.3:2 E.None of these

Answer & Explanation

Answer – A.3:4 Explanation :

9:6 :: 1:2 9:6::6:12 9:6:12 => 3:2:4

2. John’s present age is one fourth of his father’s age two years

ago. John’s father’s age will be twice Raman’s age after 10 years. If Raman’s 12th birthday was celebrated 2 years ago, then what is John’s present age ?

A.5years B.7years

C.9years D.11years E.None of these


Answer – C.9 years

Explanation : Raman = 12+2 = 14


John’s father = X+10 =2(10+14) X = 48-10 = 38 John = 36/4 =9

3. The sum of the age of Father and his daughter is 62years. After

5 years, the age of father will be five times that of the son. What is the age of the Son ?

A.9years B.12years



Answer – D.7years Explanation : Son = 62-5(5-1)/5+1 = 62-20/6 = 42/6 = 7

4. The present age of Sriram is twice that of his brother. Five years hence the ratio of their ages will be 21:13. What is the

present age of his brother ? A.10years

B.8years C.13years

D.21years E.None of these


Answer – B.8years

Explanation : 2x+5/x+5 = 21/13

26x+65 = 21x+105 5x=40 X = 8

5. The sum of ages of Kavi and Sunil at present is 28 years more

than the present age of Yagavi.The present age of Sunil is 6 years more than the age of Yagavi.What is the present age of


Kavi ? A.15years

B.28years C.22 years




Explanation :

S = Y+6 K+S = Y+28 K+Y+6 = Y+28

K = Y+28-Y-6 K = 22

6. 18years ago the ratio of A’s age to B’s age was 8:13.Present age of their ages ratio is 5:7.What is the present age of B ?

A.90years B.70years



Answer – B.70years Explanation :

8x+18/13x+18 =5/7 56x+126 = 65x+90

9x = 36 X =4 B = 13*4 + 18 = 70

7. Average age of a group of 32 students is 26 years. If a teacher is included then the average age rises by 1 year,then the

present age of teacher is A.59 years

B.48years C.37years




Answer – A.59 years Explanation :

Students total age = 32*26 = 832 Students & Teacher total age = 33*27 = 891 Teacher = 891-832 = 59

8. The ages of Sulekha and Arunima are in the ratio of 8 : 5 respectively. After 5 years the ratio of their ages will be 7:5.

What is the difference in years between their ages. A.7 years

B.5 years C.4 years

D.6 years E.None of these


Answer – D.6 years

Explanation : 8:5 => 16:10 =>after 5 years 21:15 = 7:5 16-10 = 6

9. Aswin is younger than Dravid by 9 years. If the ratio of their

ages is 7:9, find the age of Dravid A.43years

B.38years C.41 years D.37years E.None of these



Explanation : x/x+9 = 7/9

9x = 7x+63 2x = 63


X = 63/2 = 31.5 =32 Dravid = 32+9 = 41years

10. Survesh was thrice as old as Sneha 5 years back. Survesh will be 7/3 times as old as Sneha 5 years hence. How old is

Sneha today A.31years

B.17years C.23years

D.26 years E.None of these


Answer – D.26 years Explanation : (7/3) * (X +10) = (3X + 10)

7(x+ 10) = 3(3x+ 10) 7x+70 = 9x+30

2x=40 X = 20 Snehal Age = 20+6 = 26 year

11) If 6 years are subtracted from the present age of Babita and the

remainder is divided by 18, then the present age of her granddaughter

Geeta is obtained. If Geeta is 2 years younger to Sita whose age is 5 years,

then what is Babita’s present age?

A) 77

B) 65

C) 84

D) 43

E) 79

Explanation:

Geeta’s age = (5-2) = 3 years

Let age of Babita = x years

So (x-6)/18 = 3

Solve, x = 60

12) A’s age is twice C’ age. Ratio of age of B 2 years hence to age of C 2

years ago is 5 : 2. C is 14 years younger than D. Difference in ages of D and


A is 4 years. Find the average of their ages.

A) 36

B) 25

C) 27

D) 13

E) 18

Explanation:

A = 2C

(B+2)/(C-2) = 5/2

C = D – 14

D – A = 4

Solve, A = 20, B = 18, C = 10, D = 24

13) When the couple was married the average of their ages was 25 years.

When their first child was born, the average age of family became 18 years.

When their second child was born, the average age of the family became 15

years. Find the average age of the couple now.

A) 31

B) 27

C) 28

D) 29

E) 30

Explanation:

Sum of ages of couple = 25*2 = 50

When 1st child born, total age of 3 = 18*3 = 54 years

At this time the child’s age was 0, so age of father and mother would have

increased by same.

So increased by 2 years each.

So 50 +2 + 2 = 54

Now when 2nd child born, total age of 4 = 15*4 = 60

So this time second child’s age = 0 and age of father, mother and first child

would have increased by same.

So increased by 2 each such that 54 + 2+2+2 = 60

So now this time (after 4 years from age 50),

total age of couple is 50+4+4 = 58

So average = 29 years


14) Ratio of age of A to B is 3 : 2 and that of A to C is 1 : 2. Difference in

ages of B and C is 24 years. Find the average of their present ages.

A) 24

B) 22

C) 14

D) 26

E) 31

Explanation:

B/A = 2/3 and A/C = 1/2

So B : A : C = 2*1 : 3*1 : 3*2 = 2 : 3 : 6

So 6x – 2x = 24, 4x = 24, x = 6

So total of their present ages = (2+3+6)*6.

So average = (2+3+6)*6 / 3 = 22 years

15) Ratio of ages of A 5 years hence to B’s age 3 years ago is 5 : 3. Also ratio

of ages of A 4 years ago to B’s age 2 years hence is 4 : 5. Find the age of the

elder.

A) 15

B) 18

C) 21

D) 20

E) 24

Explanation:

(A+5)/(B-3) = 5/3

(A-4)/(B+2) = 4/5

Solve A = 20, B = 18

16) The ratio of ages of Sneha to Bhavna is 6 : 13. Also ratio between

Kritika’s age two years after and Bhavna’s age 4 years after will be 2 : 3. If

the average age of Sneha and Kritika is 15 years, what will be Kritika’s age

three years hence?

A) 23

B) 19

C) 12

D) 15

E) 8

Explanation:


S/B = 6/13

(K+2)/(B+4) = 2/3

S + K = 2*15 = 30

Solve the equations,

K = 12, So K + 3 = 15

17) Difference between ages of Raman and Preet is 16 years. If Raman’s age

ten years hence will be two times the age of Preet, find Raman’s age.

A) 26

B) 19

C) 42

D) 38

E) 46

Explanation:

R – P = 16

(R + 10) = 2P

Solve, R = 42

18) Three years ago, Pihu was thrice old as Ravi that time. How old is Pihu

today if ratio of age of Pihu six years hence to Ravi’s age four years ago is 9

: 2?

A) 25

B) 30

C) 33

D) 22

E) 28

Explanation:

(P – 3) = 3* (R-3)

(P + 6)/(R – 4) = 9/2

Solve both equations, P = 30

19) The average age of Yogita, Kanika and Prachi is 14 years. The ratio of

Yogita’s age one year ago to Kanika’s age one years hence to Prachi’s age

three years hence is 5 : 6 : 4. Find ratio of Yogita’s age two years hence to

Prachi’s age.

A) 8 : 5

B) 5 : 3


C) 1 : 4

D) 2 : 1

E) 4 : 7

Explanation:

Y + K + P = 42

(Y – 1) : (K + 1) : (P + 3) = 5 : 6 : 4

So (5x + 1) + (6x – 1) + (4x – 3) = 42

Solve, x = 3

So Yogita’s age 1 ago hence = 5x = 15,

so present age = 16

Prachi’s age 3 years hence = 4x = 12,

so present age = 9

So (Y+2)/P = 18/9 = 2/1

20) Sneha’s mother’s age is five years more than twice the age of Sneha.

When Sneha was born, her brother Rahul was four years old and her father

two years older than her mother. If the average age of her mother and

father is 46 years. Find the ratio of age of Rahul to that of Sneha.

A) 3 : 7

B) 7 : 4

C) 6 : 5

D) 8 : 11

E) 3 : 10

Explanation:

Let age of Sneha = x,

So age of Mother = 2x+5,

Rahul = x+4,

Father = 2x+7

(2x+5 + 2x+7) = 2*46

So x = 20

So (x+4)/x = 24/20 = 6/5

21. Four years ago, the ratio of the ages of A and B was 5 : 9. 8 years hence the ratio will be 2 : 3 respectively. Find the present

age of B? A) 25

B) 20 C) 40


D) 60 E) 24


C) 40 Explanation:

Let 4 years ago A’s age = 5x, B’s age = 9x Then 4+8 = 12 years after – (5x+12)/(9x+12) = 2/3

Solve, x = 4 B’s present age = 9x+4 = 40

22. Eight years ago, A was 4 times as old as B. After 8 years A

will be twice as old as B. What are their ages respectively? A) 45, 18

B) 40, 10 C) 42, 18

D) 40, 16 E) 42, 16


D) 40, 16

Explanation: Let B’s age 8 yrs ago = x, then A’s age = 4x

After (8+8) = 16 years: (4x+16) = 2 * (x+8)

Solve, x = 8 A’s present age = 4x+8 = 40 B’s present age = x+8 = 16

23. Present age of B is twice that of A. 4 years hence B’s age will be 4 less than twice the age of A. Find the difference in their

ages? A) 8

B) 10 C) 4

D) 5 E) Cannot be determined



E) Cannot be determined Explanation:

Let A’s present age = x, Then B’s present age = 2x After 4 years, (2x+4) = 2(x+4) – 4 0 = 0

24. After 6 years, A’s age will be 3/7th of B’s age. Also 10 years

ago, ratio of ages of A and B was 1 : 5. What is A’s present age? A) 20

B) 25 C) 24 D) 18 E) 50


D) 18

Explanation: Let 10 years ago, A’s age = x, B’s age = 5x

After (10+6) = 16 years, (x+16) = (3/7) (5x+16) Solve, x = 8 So A’s present age = x+10 = 18

25. B is twice older than C and A is 2 years older than B. If the total of all of their ages is 27, what will be total of the ages of A

and C 6 years hence? A) 17

B) 29 C) 28

D) 23 E) 18


B) 29

Explanation: Let C’s present age = x, then B’s = 2x, and A’s = 2x+2

Given: x+2x+(2x+2) = 27 Solve, x = 5

A’s present age = 2x+2 = 12 C’s present age = x = 5 6 years after A+C)’s age = 12+5+6+6 = 29


26. The sum of the present ages of A and B is 50. After 2 years

B’s age will be 2 more than C’s age then. If A is younger than C by 4 years, find the age of B 8 years ago.

A) 20 B) 40 C) 28

D) 26 E) 22


A) 20 Explanation:

The difference between B and C’s age will remain same Let C’s present age = x, so B’s present age = (x+2)

sum of the present ages of A and B is 50, so A’s age becomes = 50-(x+2) =48-x

now A is younger than C by 4 years, so 48-x = x – 4 Solve, x = 26 B’s present age = x+2 = 28 Before 8 years, B’s age = 28-8 = 20

27. After 10 years, A’s age will be twice that of B’s age. A’s

present age is 6 times that of C. If B’s eighth birthday was celebrated 2 years ago, then what is C’s present age?

A) 8 B) 5

C) 10 D) 15 E) 12


B) 5 Explanation:

Let C’s present age = x, then A’s present age = 6x Let B’s present age is y.

Then after 10 years, (6x+10) = 2 (y+10) Solve, y = 3x-5 = B’s present age

B’s eighth birthday was celebrated 2 years ago, so B’s present age = 10, and also 3x-5 = 10 Solve, x = 5


28. The ratio of the present ages of A to B is 5 : 3. The ratio of

A’s age 4 years ago to B’s age 4 years hence is 1 : 1. What is the ratio of A’s age 4 years hence to B’s age 4 years ago?

A) 3 : 2 B) 5 : 2 C) 3 : 1

D) 2 : 3 E) 1 : 3


C) 3 : 1 Explanation:

Let A’s present age = 5x, and B’s = 3x Ratio of A’s age 4 years ago to B’s age 4 years hence is 1 : 1. So

(5x-4)/(3x+4) = 1/1 Solve x = 4

So A’s present age = 20, and B’s = 12 Required ratio = (20+4) : (12-4)

29. Present age of a father is three times more than his son. 8

years hence, father’s age will be 2 and a half times of his son’s age. After 8 more years, how many times would father be his

son’s age? A) 3 n half times

B) 4 times C) 1 n half times

D) 2 times E) 3 times


D) 2 times

Explanation: three times more than

Let present age of son = x, then of father = x+3x = 4x After 8 years, (4x+8) = (5/2) (x+8)

Solve, x = 8 Required ratio = (4x+16) : (x+16) = 2 : 1


30. Age of A is three times the sum of ages of B and C. 5 years hence, A’s age will be twice the sum of ages of B and C. The

total of their present ages is A) 45

B) 60 C) 30

D) Cannot be determined E) None of these


B) 60 Explanation: Let (B+C)’s present age= x

Then A’s present age = 3x After 5 years, (3x+5) = 2*(x+5+5)

Solve, x = 15 Sum = x+3x = 4x = 60

31. When Rajesh was born, his father age was 29 years older

than his Brother and his Mother was 25 years older than his Sister. If his Brother is 2 years elder than his Sister. After 6 years

the average age of the family is 20. Then what is the age of Mother when Rajesh was born?

1. 27 2. 28

3. 29 4. 30 5. Cannot be determined


Answer – 2. 28 Explanation :

Sister = x; Brother = x+2; Father = 29+x+2; Mother = 25+x Present age – 4x+58

After 6 years 4x+58+30 = 4x+88

4x+88 = 100 x = 3 Mothers age = 25+x = 28.

32. The ratio of Present age of Madhu and Divya is 6:7. Madhu is

7 years younger than Laxmi. Laxmi’s age after 8 years will be


51 years. Then what is the difference between the present ages of Madhu and Divya?

1. 3 Years 2. 4 Years

3. 5 Years 4. 6 Years 5. Cannot be determined


Answer – 4. 6 Years

Explanation : M/D = 6/7 L- M =7

L+8 = 51 L = 43 M = 36

D = 42 D-M = 42-36 = 6

33. Sum of Raju and Ravi age is 1 less than Ramu. After one

year Sum of Raju and Ravi age is equal to Ramu’s age. After

another year Sum of Raju and Ravi is 1 more than Ramu’s age. If the sum of Raju, Ravi and Ramu’s age is 23. Then what is the

age of Ramu? 1. 11 2. 12

3. 13 4. 14 5. Cannot be determined


Answer – 2. 12

Explanation : X+Y+Z = 23

X+Y+1 = Z Z = 12

34. Sridhar has three sons Satish, Ritesh and Nitesh. Satish is

oldest while Nitesh is the Youngest. The present ages of all the three son’s are square numbers. Sum of their ages after 3 years

will be 39. Then what is the present age of Ritesh?


1. 1 2. 4

3. 9 4. 16 5. 25


Answer – 2. 4

Explanation : X+Y+Z = 30

Possible ages ( 1,4,9,16,25) from above ages = (1,4,25)

35. Sum of the twice the age of Surya and his Father age is 79.

Sum of the twice the age of Father and Surya’s age is 104. The average of Surya, his Father and his Mother is 32. Then what is

the age of his Mother? 1.32

2.33 3.34

4.35 5.36


Answer – 4.35

Explanation : 2S+F = 79

2F+S = 104 S =18 F = 43

18+43+M/3 = 32 M =35

36. The ratio of Arun and Varun age is 11:9. After 5 years the

difference between their age is 2. Then Arun is how many years elder than Varun?

1.1 Year 2.2 Years

3.3 years 4.4 Years 5.Cannot be determined



Answer – 2.2 Years

Explanation: A/V = 11/9 11x-9x =2

37. Sum of the Ages of Aruna, Bhaskar, Chaitu and Dinesh is 78. Aruna is 5 years older than Bhaskar. Chaitu is 3 years older

than Dinesh. Aruna age is 9 times the age of Dinesh. Then what is the age of Chaitu?

1.4 2.5

3.6 4.7 5.Cannot be determined


Answer – E. 40 Explanation :

A+B+C+D = 78 B = A-5, C= D+3 , A=9

A = 36 V = 7

38. Present age of Husband and Wife is 28 and 24 Years

respectively. At that age twin babies were born to them. After how many years the average of the family will be same as

before babies were born? 1.10 Years

2.11 Years 3.12 Years

4.13 Years 5.Cannot be determined


Answer – 4.13 Years

Explanation : 28+24/2 =26 = (28+x+24+x+2x)/4


104 = (52+4x) x= 13

39. Six years ago Manisha age was equal to sum of present ages of her Son and Daughter. Four years hence , the ratio of ages of

her Son and Daughter at that time will be 7:6. Manisha is 6 years younger than his Husband. Manisha’s present age is 2.5

times the present age of her Daughter. Then what is the age of Manisha’s Husband?

1.50 2.54 3.56

4.60 5.Cannot be determined


Answer – 3.56 Explanation :

M-6 = S+D M =2.5D

s+4/D+4 = 7/6 D = 20 M = 50 H = 56

40. Sum of Sita and Gita age is 1 less than Rita. After one year Sum of Sita and Gita age is equal to Rita’s age. After another

year Sum of Sita and Gita is 1 more than Rita’s age. If the sum of Sita, Gita and Rita’s age is 19. Then what is the age of Sita?

1.4 2.5

3.6 4.7

5.Cannot be determined


Answer – 5.Cannot be determined Explanation :

X+Y+Z = 19 X+Y+1 = Z

Z =10


X+Y+2 = Z+1 X+Y+4 = Z+2+1. Based on above solution cannot be determined

41. The sum of the present ages of a Suresh and his son is 60

years. Five years ago, Suresh’s age was four times the age of his

son. What will be the age of Suresh’s son? A. 15 B. 17

C. 18 D. 19 E. 16


Answer – A. 15

Explanation : Present ages of son and Suresh be x and (60 -x) years respectively.

(60 – x) – 5= 4(x – 5) 55 – x = 4x – 20

5x = 75 x = 15

42. In a college, the average age of students of a class is 15.8

years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of number of boys to

the number of girls in the class is A. 3:5

B. 2:3 C. 2:1

D. 2:7 E. 3:2


Answer – B. 2:3

Explanation : Number of boys = x

Number of boys = y (x*16.4 + y*15.4)/x + y = 15.8

16.4x + 15.4y = 15.8x + 15.8y 0.6x = 0.4y x:y = 2:3


43. If two times of the Ria’s age in years is included to her mother’s age, the total is 70 and if two times of the mother’s

age is included to the Ria’s age, the total is 95. So what is the age of Ria’s Mother?

A. 55 B. 35

C. 45 D. 40 E. 50


Answer – D. 40 Explanation :

Ria’s age = x ; Ria’s mother age = y 2x+y = 70 and x+2y = 95 y = 40.

44. Eight years ago Ravi’s mother was five times older than her

daughter. After Eight years Ravi’s mother will be twice older than her daughter. Find the present age of Ravi?

A. 18.33 years B. 12.5 years

C. 16.7 years D. 13.33 years E. 14.5 years


Answer – D. 13.33 years Explanation :

Eight years ago, Ravi’s age = x Eight years ago, Ravi’s Mother age = 5x

2(x+16) = 5x+16 2x+32 = 5x+16

x=16/3 Present age of Ravi = 16/3 + 8 = 13.33 years

45. The ratio of Arun’s and Varun’s ages is 4:5. If the difference

between the present age of Varun and the age of Arun 5 years hence is 3 years, then what is the total of present ages of Arun

and Varun?


A. 73 years B. 72 years

C. 75 years D. 69 years E. 68 years


Answer – B. 72 years

Explanation : Arun’s age = x

Varun’s age = y x/y = 4/5 y – (x + 5) = 3

y – x = 8 y = 8 + x

x/8 + x = 4/5 x = 32 years

y = 40 years. x + y = 72 years.

46. The ages of Ashwini, Kavitha and Chitra together are 57

years. Kavitha is thrice as old as Ashwini and Chitra is 12 years

older than Ashwini. Then, what is the ratio of respective age of Ashwini, Kavitha and Chitra is? A. 3 : 9 : 7

B. 3 : 9 : 2 C. 3 : 9 : 4

D. 3 : 9 : 5 E. 3 : 9 : 8


Answer – A. 3 : 9 : 7

Explanation:

Ashwini’s age = X Chitra’s age = x+12 Kavitha’s age = 3x

x + (x+12) + 3x = 57 => 5x = 45

x = 9 Anushka’s age = 9

Kavitha’s age = 3x = 27 Chitra’s age = x+12 = 21; Ratio = 3:9:7


47. 8 years ago, Arun’s age was 4/3 times that of Vinoth. 8

years hence, Arun’s age will be 6/5 times that of Vinoth. What is the present age of Arun?

A. 20 B. 25 C. 30

D. 35 E. 40



Present age of Arun = x Present age of Vinoth = y

x – 8 = 4/3 (y – 8) x + 8 = 6/5 (y + 8)

3/4(x – 8) = y – 8 5/6(x + 8) = y + 8 y = 3/4 (x – 8) + 8 = 5/6 (x + 8) – 8

10 – 20/3 = 10/12 x – 9/12 x 10/3 = x/12 x = 40.

48. When Ramesh was born, his father was 32 years older than

his brother and his mother was 25 years older than his sister. If Ramesh’s brother is 6 years older than Ramesh and his mother

is 3 years younger than his father, how old was Ramesh’s sister when Ramesh was born? A. 15

B. 10 C. 25

D. 20 E. None of the Above


Answer – B. 10

Explanation :

Ramesh’s age = 0 Ramesh’s father age = 38


Ramesh’s mother age = 35 Ramesh’s sister is 25 years younger than his mother; 35 – 25 = 10

49. Suresh got married 8 years ago. His present age is 6/5 times his age at the time of his marriage Suresh’s sister was 10years

younger to him at the time of his marriage. The present age of Suresh’s sister is

A. 36 B. 37

C. 38 D. 35 E. None of these


Answer – C. 38 Explanation :

Suresh’s age at the time of his marriage = X years X + 8 = 6/5 X

X = 40. Present age of Suresh = 48 Suresh’s Sister age = 48 – 10 = 38 years.

50. Ratio of the ages of Mani and Naveen is 5 : A. Mani is 18 years younger to Ravi. After nine years Ravi will be 47 years

old. If the difference between the ages of Mani and Naveen is same as the age of Ravi, what is the value of A?

A. 16.5 B. 18.5

C. 19.5 D. 15.5

E. 14.5


Answer – E. 14.5 Explanation :

Present ages of Mani, Naveen and Ravi be x, y and z respectively. x/y = 5/A —— (1)

x = z – 18 —— (2) z + 9 = 47 —— (3)

x – y = z —– (4)


From (1) (2) (3) and (4) 4A = 58 => A = 14.5

51. This year, the sum of ages of the Suresh’s family members is

78. Currently, there are 4 members namely viz Suresh, Rita,

Deepa and Tarun. Suresh is 4 years older than Rita. Deepa is two years older than Tarun. If Suresh is 7 times as old as Tarun, how old is Deepa?

A. 5 B. 7

C. 8 D. 9 E. 6


Answer – B. 7

Explanation : S+R+D+T = 78 – (i)

S = R + 4 – (ii) D = T + 2 – (iii) S = 7T – (iv)

7T = R+4 R= 7T – 4

h+w+d+s = 78 – (i) 7T+7T-4+T+2+T = 78

16T = 80 T = 5 d = T+2 = 5+2 = 7

52. Three years from now, Deepa will be three times as old as Emma and Emma will be six years younger than Femina. If

Deepa’s age is three years less than twice Femina’s age, how old is Femina?

A. 9 B. 15

C. 21 D. 27 E. 33


Answer – A. 9

Explanation :


D+3=3(E+3) E+3=(F+3)-6

D=2F-3. E+3=F-3 or E=F-6.

D+3=3(F-6+3) D+3=3F-9

D=3F-12. now, we have D=2F-3.

2F-3=3F-12 9=F

53. Ravi is now 4 years older than Emma and half of that

amount older than Ishu. If in 2 years, Ravi will be twice as old as Emma, then in 2 years what would be Ravi’s age multiplied

by Ishu’s age? A. 68

B. 28 C. 48

D. 50 E. 52


Answer – C. 48

Explanation : Ravi – x + 4

Emma – x Ishu – x + 2

(Ravi 4 years older than Emma & 2 years older than Ishu) Ages after 2 yrs

Ravi – x + 6 Emma – x + 2

Ishu – x + 4 x+6 = 2(x + 2)

x = 2 Ravi * Ishu = 8 * 6 = 48

54. Jack is now twice as old as Femina, who is two years older

than Suresh. Four years ago, Jack was four times as old as Suresh. How old is Jack now?

A. 18 B. 12


C. 16 D. 20 E. 24


Answer – D. 20

Explanation : j=2f – (i)

f=s+2.-.(ii) four years ago

j-4=4(s-4) putting (ii) in (iii) we get j-4 =4(f-2-4)

sub (i) in above equation we get j-4=4(j/2-6) =>j=20

55. James is now 12 years younger than Mahesh. If 9 years from now Mahesh will be twice as old as James, how old will James

be in 4 years? A. 3

B. 7 C. 5

D. 9 E. 8


Answer – B. 130

Explanation : James =x years, Mahesh = x+12 years

9 from now, 2(x+9)=x+21

2x+18=x+21 x=3 x+4 =7 years

56. Ravi has three children: two daughters and one son. All were born on the same date in different years. The sum of the ages

of the two daughters today is smaller than the age of the son today, but a year from now the sum of the ages of the

daughters will equal the age of the son. Three years from today,


the difference between the age of the son and the combined ages of the daughters will be

A. 1 B. 2

C. 3 D. –2 E. –1


Answer – D. –2

Explanation: one year from now, D+d=s two years after that, D+2+d+2=s+2 D+d-s=2-4=-2

57. Leena’s age is 5 years more than twice Gayathri’s age.

Vijay’s age is 13 years less than 10 times Gayathri’s age. If Vijay is 3 times as old as Leena, how old is Leena?

A. 17 B. 16

C. 12 D. 14 E. 19



given l = 2g+5 v = 10g-13

v=3l f rom v=3l => 10g-13 = 6g+15

g = 7 l= 2g+5 = 19

58. 8 years ago, Geeta was half as old as Saina. Saina is now 20

years older than Geeta. How old will Geeta be in 10 years? A. 45

B. 40 C. 35




Answer –D. 38 Explanation :

Saina is now 20 years older than Geeta –> S=G+20 –> Saina 8 years ago was G+20-8=G+12 years old. (G-8)*2=G+12 –> G=28. 28+10=38 years.

59. Lilly is 5 years older than Martin, and Catherine is twice as old as Lilly. If the sum of their ages is 95, how old is Lilly?

A. 26 B. 27



Answer – D. 25 Explanation : L=5+M and C=2L and C+M+L=95 => 4L=100 => L=25

60. Arun will be half as old as Lilly in 3 years. Arun will also be

one-third as old as James in 5 years. If James is 15 years older than Lilly, how old is Arun?

A. 6 B. 8

C. 9 D. 5 E. 4


Answer – B. 8 Explanation :

let age of Arun =x, Lilly =y James = z (x+3) =1/2 *(y+3) so we have 2x-y =-3 -(1)

(x+5) =1/3 * (z+5) ; => 3x-z=-10 -(2) From (1)&(2) we get, x+y-z =-7 -(3)


we have z =15+y – (4) from equation 3 and 4 we get x=8

61. The average runs scored by a cricketer is 42 innings, is 40.

The difference between his maximum and minimum scores in an

inning is 100. If these two innings are not taken into consideration, then the average score of remaining 40 inning is 37. Calculate the maximum runs scored by him in an innings?

A. 125 B. 150



Answer – B. 150

Explanation : Let the minimum score = x

∴ Maximum score = x + 100

∴ x + (x + 100) = 42 x 40 – 40 x 37

⇒ 2x + 100 = 1680 – 1480 = 200

⇒ 2x = 200 – 100 = 100

⇒ x = 50

Maximum score = x + 100 = 50 + 100 = 150

62. Silvia was married 8 year ago. Today her age is 9/7 times to that time of marriage. At present his son’s age is 1/6th of her

age. What was her son’s age 3 year ago? A. 4 yr

B. 2 yr C. 3 yr

D. 5 yr E. None of the Above


Answer –B. 2 yr

Explanation : Silvia’s age 8 year ago = x

Present age = x + 8 x + 8 = 9/7 x

7(x + 8)= 9x x = 28; 28 + 8 = 36


Son’s age = 1/6 * 36 = 6 Son’s age 4 year ago = 6-4 =2

63. Eight years ago, Pavi’s age was equal to the sum of the present ages of her one son and one daughter. Five years

hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pavi’s husband is 7 years

elder to her and his present age is three times the present age of their son, what is the present age of the daughter?

A. 15 years B. 23 years C. 19 years

D. 27 years E. 13 years


Answer – B. 23 years Explanation :

P – 8 = S + D —(1) 6D + 30 = 7S + 35 —(2)

H = 7 + P H = 3S

3S = 7 + P —-(3) Solving eqn (1),(2) and (3) D = 23

64. Ravi’s present age is three times his son’s present age and

4/5th of his father’s present age. The average of the present ages of all of them is 62 years. What is the difference between

the Ravi’s son’s present age and Ravi’s father’s present age? A. 62 years

B. 64 years C. 69 years



Answer – E. 66 years

Explanation : Present age of Ravi is = 4/5x

Present age of Ravi’s father is = 4/15x


Ratio = 15: 12 : 4 Difference between the Ravi’s son’s present age and Ravi’s father’s

present age = 62/31 * 3(15 – 4). = 2*3*11 = 66 year.

65. The respective ratio between the present age of Mary and Deepa is x : 42. Mary is 8 years younger than Prema. Prema’s

age after 8 years will be 33 years. The difference between Deepa’s and Mary’s age is same as the present age of Prema.

What is the value of x? A. 18 B. 10

C. 16 D. 11 E. 17


Answer – E. 17

Explanation : Prema’s age after 8 years = 33 years

Prema’s present age = 33 – 8= 25 years Mary’s present age = 25 – 8 = 17 years

Deepa’s present age = 17 + 25 = 42 years Ratio between Mary and Deepa = 17 : 42 X = 17

66. Mr. Sharma has three sons namely Ram, Amit and Karan. Ram is the eldest son of Mr. Sharma while Karan is the

youngest one. The present ages of all three of them are square numbers. The sum of their ages after 5 years is 44. What is the

age of Ram after three years? A. 15 years

B. 13 years C. 19 years D. 17 years E. 16 years


Answer – C. 19 years

Explanation :


Square numbers – x, y, z (x + 5) + (y + 5)+ (z + 5) = 44

x + y + z = 44 – 15 = 29 Possible values of x, y, z = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ram’s present age = 16; after three years = 19

67. One year before, Reshma was six times as old as her

daughter. Six years hence, Reshma’s age will exceed her daughter’s age by 20 years. The ratio of the present ages of

Reshma and her daughter is? A. 5 : 4 B. 9 : 4

C. 5 : 1 D. 7 : 2 E. None of the Above


Answer – C. 5 : 1

Explanation : Ages of Reshma and her daughter = 6x, x

[6x + 1 + 6] – [x + 1 + 6] = 20 5x = 20; x = 4 Ratio = 6x + 1 : x + 1 = 25 : 5 = 5:1

68. The ratio of present ages of Ramya and Karan’s age is 4:5 and the ratio of present ages of Karan and Priya is 2:5

respectively. If Ramya is two-fifth of Priya’s age, What is Ramya’s age?


C. 20 years D. Cannot be determined E. None of the Above


Answer – D. Cannot be determined Explanation : Data Insufficient – Can not be determined.


69. Ravi is as much younger than Surya as he is older than Suresh. If the sum of the ages of Surya and Suresh is 50 years,

what is definitely the difference between Surya and Ravi’s age? A. 12 years


D. 27 years E. Can not be determined


Answer – E. Can not be determined

Explanation : Surya’s age – Ravi’s age = Ravi’s age – Surya’s age

Suresh’s age + Surya’s age = 2 Ravi’s age Surya’s age + Suresh’s age = 50

Ravi’s age = 25; We can not find the difference between Surya and Ravi’s age

70. Amit’s present age is 1.5 times of Hari’s present age. If after

4 years, Amit’s age will be twice of Hari’s age 4 years ago. What

is the sum of the present ages of Amit and Hari? A. 52 years

B. 53 years C. 60 years D. 67 years

E. 63 years


Answer – C. 60 years Explanation : A = 1.5 * H

A + 4 = 2 * (H – 4) A + 4 = 2H – 8

A + 12 = 2H 1.5H + 12 = 2H H = 24

A = 24 * 1.5 = 36 Sum = 36 + 24 = 60

71. The average score of a cricket player after 48 innings is 49

and in the 49th innings the player scores 98 runs. In the 50th

innings the minimum number of runs required to increase his


average score by 2 than it was before the 50th innings? A. 152

B. 150 C. 136

D. 128 E. None of these


Answer – B. 150

Explanation :

Average score of Dhoni after 48th Innings = 49 Average score of Dhoni after 49th Innings = (48*49 + 98)/49 = 50 Average score of Dhoni after 50th Innings => 50 + 2 = 52 Score in 50th Innings = (50 * 52) – (49 * 50) = 150

72. The average age of board of directors of a company having

15 directors was 48 years. When a director aged 56 resigned from the board of directors another director died on the same

day. A new director joined board of directors aged 36. Next year the average age of all 14 directors was found to be 48

years. The age of late director at the time of his death was _______


D. 40 years E. None of these


Answer – B. 42 years Explanation :

Before Death = 48*15 = 720 The age of late director at the time of his death

720 -(56+x) + 36 + 14 = 672 X = 42

73. The average expenditure of the hotel when there are 10

guests is Rs. 80 per guests and the average expenditure is Rs.40 when there are 30 Guests. If it is known that there are

some fixed expenses irrespective of the number of guests then


the average expenditure per guest when there are 50 guests in the hotel.?

A. Rs. 25 B. Rs. 35

C. Rs. 50 D. Rs. 45 E. None of these


Answer – B. Rs. 35

Explanation : x + 30y = 1200 x + 10y = 800

y = 20 Total Expenditure = 600 + 40 * 20 = 1400 Average Expenditure = 1400/40 = 35

74. The average marks of Sumit decreased by one, when he

replaced the subject in which he has scored 40 marks by the other two subjects in which he has just scored 23 and 25 marks

respectively. Later he has also included 57 marks of Computer Science, then the average marks increased by two. How many

subjects were there initially? A. 12 B. 14

C. 10 D. 15 E. 13


Answer – D. 15

Explanation : Total subjects = x ; Average Marks = y

(x + 1)(y – 1) = (xy – 40) + (23 + 25) y – x = 9 –(1) (x + 2)(y + 1) = (xy – 40) + (23 + 25)+ 57

xy + 2y + x + 2 = xy + 65 2y + x = 63 –(2) From Equation (1) and (2) => x = 15; y = 24


75. The average runs scored by a cricketer is 42 innings, is 40. The difference between his maximum and minimum scores in

an inning is 100. If these two innings are not taken into consideration, then the average score of remaining 40 inning is

38. Calculate the maximum runs scored by him in an innings ? A. 125

B. 130 C. 110



Answer – B. 130

Explanation : Let the minimum score = x

∴ Maximum score = x + 100

∴ x + (x + 100) = 40 x 42 – 40 x 38

⇒ 2x + 100 = 1680 – 1520 = 160

⇒ 2x = 160 – 100 = 60

⇒ x = 30

Maximum score = x + 100 = 30 + 100 = 130

76. The average weight of 4 persons, Amit, Bala, Catherine and

David is 65 kg. The 5th person Elina is included and the average weight decreses by 2 kg. Amit is replaced by Francis. The

weight of Francis is 4 kg more than Elina. Average weight decreases because of the replacement of Amit and now the

average weight is 64 kg. Find the weight of Amit. A. 54 kg

B. 66 kg C. 55 kg

D. 68 kg E. None of these


Answer – A. 54 kg

Explanation: Sum of the weight of Amit, Bala, Catherine and David = 65 x 4 = 260

kg Average weight of Amit, Bala, Catherine and David = 65 – 2 = 63kg

Sum of the weight of Amit, Bala, Catherine and David and Elina = 63 x 5 = 315 kg


Weight of Elina = 315 – 260 = 55 kg Weight of Francis = 55 + 4 = 59 kg

Average weight of Francis, Bala, Catherine, David and Elina = 64 kg Sum of the weight of Francis, Bala, Catherine, David and Elina = 64 x 5

= 320 Kg Sum of the weights of Bala, Catherine, David = 320 – 55 – 59 = 206

kg Weight of Amit = 260 – 206 = 54 kg

77. The average weight of the students in four sections Red,

Black, Green and Yellow is 60 kg. The average weight of the students of Red, Black, Green and Yellow individually are 45 kg,

50 kg, 72 kg and 80 kg, respectively. If the average weight of the students of section Red and Black together is 48 kg and that

of Black and Green together is 60 kg. What is the ratio of the number of the students in sections Red and Yellow?

A. 12 : 7 B. 2 : 3

C. 4 : 3 D. 8 : 5 E. None of these


Answer – B. 4 : 3 Explanation :

Average weight of students of sections of Red and Black = 48 kg ⇒ (45a + 50b)/(a + b) = 48

⇒ 15a = 10b

Average weight of students of sections of Black and Green = 60 kg ⇒ 50b + 72c = 60(b + c)

⇒ 10b = 12c

Average weight of students of Red, Black, Green and Yellow = 60 kg

45a + 50b + 72c + 80d = 60(a + b + c + d) ⇒ 15a + 10b – 12c – 20d = 0

⇒ 15a = 20d

⇒ a : d = 4 : 3

78. Out of the three annual examinations, each with a total of

500 marks, a student secured average marks of 45% and 55% in the first and second annual examinations. To have an overall average of 60%, how many marks does the student need to


secure in the third annual examination ? A. 450

B. 400 C. 350



Answer –B. 50 years

Explanation :

Total marks for three examinations = 3x 500 = 1500 Total required marks in three examinations = 60% of 1500 =( 3 x 500 x 60 ) / 100

= 900 Marks secured in first examination = 45 % of 500

=( 500 x 45 ) / 100 =225

Marks secured in third examination = 55 % of 500 =( 500 x 55 ) / 100

=275 Thus, the required marks in third examination

=900 – ( 225 + 275 ) =900 – 500 = 400

79. The average age of women and child workers in a factory was 20 year. The average age of all the 12 children was 8 year

and average age of women workers was 26 year. If 9 women workers were married, then the number of unmarried women

workers was. A. 16

B. 17 C. 18



Answer – D. 15

Explanation : Women workers = x

26x + 12 x 8 = 20 (12+x) ⇒ 26x + 96 = 240 + 20x


⇒ 6x = 144

∴ x = 24

∴ Unmarried women workers = 24 – 9 = 15

80. The average age of all the members of Mr. Ravi’s family is 25 year. The average age of males is 30 year while the average

age of females is 20 year. If the number of females in the family is 10, then find out the number of males?

A. 20 B. 30

C. 15 D. 18 E. 10



Let the number of males = x Total family members = 10 + x

25(10 + x) = 30x + 10*20 ⇒ 250 + 25y = 30x + 200

⇒ 5y = 50

∴ y = 10

81. James’ father was 30 years old when he was born. His mother’s age was 24 when his sister who is 5 years younger to

him, was born. What is the difference between the age of James’ father and mother?

A. 8 B. 10 C. 6

D. 11 E. 9



James’age = F – 30 sister’s age = F – 35

M = 24 + Sister’s age M = 24 + F – 35 F – M = 11


82. The respective ratio between the present age of Monika and

Deepak is 5:x. Monika is 9 years younger than Prem. Prem’s age after 9 years will be 33 years. The difference between Deepak’s

and Monika’s age is same as the present age of Prem. What is the value of x? A. 18

B. 10 C. 16

D. 11 E. 13


Answer – E. 13

Explanation :

Prem’s age after 9 years = 33 years Prem’s present age = 33 – 9 = 24 years

Monika’s present age = 24 – 9 = 15 years Deepak’s present age = 15 + 24 = 39 years Ratio between Monika and Deepak = 15 : 39 = 5 : 13 X = 13

83. Three years ago, Poorvi was thrice as old as his sister

Reena. After three years Poorvi will be twice as old as Reena. What is the present age of Reena?




Answer – C. 9 years Explanation :

P – 3 = 3 *(R – 3) —(1) P + 3 = 2 *(R + 3) —(2) Solving eqn (1) and (2) R = 9


84. Fifteen years ago, Rita’s mother was thrice of Rita’s age and two years ago Rita’s Mother was twice of Rita’s age. What is the

present age of Rita’s Mother ? A. 42 years





Explanation : Rita’s mother age = R1

Rita’s age = R2 R1 – 15 = 3 *(R2 – 15) —(1) R1 – 2 = 2 *(R2 – 2) —(2) From eqn (1) and (2) R1 = 54

85. Mr. Suresh has three daughters namely Ramya, Anita and

Kiran. Ramya is the eldest daughter of Mr. Suresh while Kiran is the youngest one. The present ages of all three of them are

square numbers. The sum of their ages after 5 years is 44. What is the age of Ramya after two years?





Square numbers – a, b, c (a + 5) + (b + 5)+ (c + 5) = 44

a + b + c = 44 – 15 = 29 Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ramya’s present age = 16; after two years = 18

86. If 6 years are subtracted from the present age of Ravi and the remainder is divided by 12, then the present age of his

grandson Pranav is obtained. If Pranav is 2 years younger to


Mohit whose age is 8 years, then what is Ravi’s present age ? A. 78 years


D. 76 years E. None of the Above


Answer – A. 78 years

Explanation :

Present age of Ravi – x x – 6 / 12 = Present age of Pranav = 6 x – 6 = 72 x = 78 years.

87. One year back, Ria was six times as old as her daughter. Six

years hence, Ria’s age will exceed her daughter’s age by 15 years. The ratio of the present ages of Ria and her daughter is?

A. 15 : 4 B. 19 : 4

C. 15 : 2 D. 17 : 2 E. None of the Above


Answer – B. 19 : 4 Explanation :

Ages of Ria and her daughter = 6x, x [6x + 1 + 6] – [x + 1 + 6] = 15

5x = 15; x = 3 Ratio = 6x + 1 : x + 1 = 19 : 4

88. Suresh age is 125% of what it was ten years ago, but

250/3% of what it will be after ten years. What is the present age of Suresh?


C. 40 years D. Cannot be determined E. None of the Above



Answer –B. 50 years

Explanation : Suresh’s age before 10 years = x

125x/100 = x + 10 125x = 100x + 1000 => x = 40 Present age = x + 10 = 50

89. Ajay got married 6 years ago. His present age is 5/4 times his age at the time of his marriage. Ajay’s brother was 5 years

younger to him at the time of his marriage. What is the present age of Ajay’s brother?





Present age of Ajay = x ; Present age of Ajay’s sister = y x = (x-6)(5/4)

x = 30 present age of Ajay’s brother = 30 – 5 = 25

90. Rahul is as much younger than Shyam as he is older than

Suresh. If the sum of the ages of Shyam and Suresh is 60 years, what is definitely the difference between Shyam and Rahul’s

age? A. 12 years


D. 27 years E. Can not be determined


Answer – E. Can not be determined Explanation :


Shyam’s age – Rahul’s age = Rahul’s age – Suresh’s age Suresh’s age + Shyam’s age = 2 Rahul’s age

Shyam’s age + Suresh’s age = 60 Rahul’s age = 30; We can not find the difference between Shyam and Rahul’s age

91. 15 years ago the average age of a family of four members was 40 years. Two children were born in this span of 15 years.

The present average of the family remains unchanged. Among the two children who were born during the 15 years, if the older child

at present is 8 years older than the younger one, what is the ratio of the present age of the older child to the present age of the

younger Child? A. 9:4

B. 7:3 C. 7:6

D. 7:4 E. 9:5


Answer – B. 7:3

Explanation : 15 years ago Total age of a family of four members = 160

Sum of the Present age of a family of four members = 160 + (15*4) = 220

Sum of the Present age of a family of six members = 40*6 = 240 x+x+8 = 20

x=6 present age of the older child to the present age of the younger Child = 14:6 = 7:3

92. James’ present age is 2/7th of his father’s present age. James’ brother is three year older to James. The respective

ratio between present ages of James’ father and James’ brother is 14:5. What is the present age of James?





Answer – A. 12 years Explanation :

James’ father present age = x James’ age = 2/7 x

James’ brother age = 2/7 x + 3 x/(2/7x + 3) = 14/5

x = 42 James’ age = 2/7 x = 2/7 * 42 = 12

93. Eight years ago, Poorvi’s age was equal to the sum of the

present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter

and her son that time will be 7:6. If Poorvi’s husband is 7 years elder to her and his present age is three times the present age

of their son, what is the present age of the daughter? A. 15 years





Explanation : P – 8 = S + D —(1)

6D + 30 = 7S + 35 —(2) H = 7 + P

H = 3S 3S = 7 + P —-(3) Solving eqn (1),(2) and (3) D = 23

94. At present, the respective ratio between the ages of A and B

is 3:4 and that between A and C is 1:2. six years hence, the sum of A, B and C will be 96 years. what is the present age of A? A. 12 years





Answer – E. 18 years Explanation :

The ratio between A, B and C is = 3:4:6 The sum of present age of A,B and C = 96 – 18 = 78

13 x = 78 x = 6 Present age of A = 3x = 18

95. The present age of Ramya is one-fourth that of her father.

After 6 years, the father’s age will be twice the age of Kiran. If kiran celebrated fifth birthday 8 year ago, What is the Ramya’s Present age?




Answer – C. 8 years

Explanation : Kiran’s present age = 8 + 5 = 13

kiran’s age after 6 years = 13 + 6 = 19 Kiran’s father age = 2 * 19 = 38 Father’s present age = 32 Ramya’s present age = 32 / 4 = 8

96. B is eight years older than A and 8 years younger than C. 12

years hence, respective ratio of the ages of A and C will be 5:9. what is the sum of present ages of A, B and C?


C. 48 years D. 60 years E. None of the Above



B = A + 8


B = C – 8 C – 8 = A + 8

C – A = 16 4x = 16

x = 4 12 years hence, A = 5x, C = 9x B = A + C => A= 20, B = 28, C = 36 Sum of present ages of A, B and C = 20 + 28 + 36 – 36 = 48 years.

97. The sum of present ages Ria and Abi is 48 years. Today Abi

is 4 years older than Shweta. The respective ratio of the present ages of Ria and Shweta is 4:7. what was Abi’s age two years ago?


C. 28 years D. 34 years E. None of the Above



Explanation : R + A = 48 —(1)

A = S + 4 –(2) R/S = 4/7 R + S + 4 = 48 => R + S = 44

11x =44 x = 4

Shweta’s age = 28 Abi’s present age = 28 + 4 = 32 Abi’s age two years ago = 30

98. The ratio of present ages of Rani and Kiran’s age is 3:5 and

the ratio of present ages of Kiran and Pooja is 2:3 respectively. If Rani is two-fifth of Pooja’s age, What is Rani’s age? A. 12 years


D. Cannot be determined E. None of the Above



Answer – D. Cannot be determined Explanation : Data Insufficient

99. The sum of the ages of 4 members of a family 5 year ago

was 94 year. Today when the daughter has been married off and replaced by a daughter-in-law, the sum of their ages is 92

year. Assuming that there has been no other change in the family structure and all the people are alive, what is the

difference between the age of daughter and the age of daughter in law? A. 22 years




Answer – A. 22 years

Explanation :

5 year ago, Sum of the ages of 4 members = 94 Present age with daughter = 94 + 20 = 114

Present age with daughter-in-law = 92 Difference between the age of daughter and the age of daughter in law = 114 – 92 = 22 years.

100. Ajay’s present age is 1.5 times of Himanshu’s present age. If after 4 years, Ajay’s age will be twice of Himanshu’s age 4

years ago. What is the difference between the present ages of Ajay and Himanshu?





A = 1.5 * H


A + 4 = 2 * (H – 4) A + 4 = 2H – 8

A + 12 = 2H 1.5H + 12 = 2H

H = 24 A = 24 * 1.5 = 36 Difference = 36 – 24 = 12

101. Veena’s present age is three times her son’s present age and two fifth of her father’s present age. The average of present age

of all of them is 46 yrs.What is the difference between the Veena’s son’s present age and Veena’s father’s present age?

A. 68 yrs B. 88 yrs

C. 58 yrs D. None of the Above


Answer – D. None of the Above

Explanation : Present age of Veena’s son = x

Veena’s present age = 3x Veena’s present age = 2/5 of Father’s present age

Father’s present age = (15/2) x Total present age = x + 3x + (15/2)x = 138

x = 12 Difference between Veena’s father’s present age and Veena’s son’s present age = 90 – 12 = 78 years.

102. Five years ago, the age of Abinav was 4 times the age of Sarita after 10 years, Abinav will be twice as old as Sarita. Find

the Present ages of Abinav and sarita? A. 30 years, 10.5 years

B. 32 years, 11.5 years C. 34 years, 14.5 years D. 35 years, 12.5 years


Answer – D. 35 years, 12.5 years

Explanation : Five years ago,

x – 5/y – 5 = 4/1


x – 4y = – 15 —-(i) After 10 years,

x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5

103. If Saurabh is as much elder than Shyam as he is younger to

Suresh and sum of the ages of Shyam and Suresh is 46 year, then what will be the age of Saurabh after five years?

A. 27 B. 26 C. 25 D. 28


Answer – D. 28

Explanation : Let the present ages of Saurabh is x year and he is younger to Suresh

by y year Then Suresh’s age = x + y

Shyam’s age = x – y (x + y) + (x – y) = 46

x = 23 The age of Saurabh after five years is – 28

104. The ratio of the present age of Palash to that of Arnav is 3 :

11. Arnav is 12 years younger than Rahim. Rahim’s age after 7 years will be 85 years. What is the present age of Palash’s

father, who is 25 years older than Palash? A. 43 years




11x = 85 – 7 – 12 x = 6


Present age of Palash = 18 Present age of Palash’s father = 18 + 25 = 43

105. The present age of Ravi’s father is four times Ravi’s present age. Five years back, Ravi’s father seven times as old as Ravi

was at that time. What is the present age of Ravi’s father? A. 43 years




Present age of Ravi – x Present age of Ravi’s father = 4x

Five years ago, Ravi’s father age = 7 * Ravi’s age

4x – 5 = 7(x – 5) x = 10 Present age of Ravi’s father = 4x = 40 years.

106. The average age of a family of five members is 24. If the present age of the youngest member is 8 year, what was the

average age of the family at the time of birth of youngest member?


C. 18 years D. 14 years



Explanation : Total age of five members = 120

Before 8 years, Total age of the family at the time of birth of youngest member = 120 – 40 (5*8) = 80

Average age of the family at the time of birth of youngest member = 80/4 = 20


107. Five years ago, the average age of Rimi’s age at that time

was 12 years. Three years from now if the respective ratio between Rimi’s age and Ruhi’s age that time will be 5:3, what is

Rimi’s present age? A. 17 years B. 33 years



Answer – D. 22 years Explanation :

The average age of Rimi’s age that time and Ruhi’s age that time = 12 years

Total age at that time = 24 Total age after 8 years = 24 + 16 = 40

Rimi’s age after 8 years = 40 * (5/8) = 25 Rimi’s present age = 25 – 3 = 22

108. The present age of Kiran five times the age of Suji. After 10

years Kiran will be three times as old as Suji. Find out the present ages of Kiran and Suji?

A. 25 years, 5 years B. 30 years, 6 years

C. 35 years, 7 years D. 50 years, 10 years


Answer – D. 50 years, 10 years

Explanation : 5x + 10/ x + 10 = 3/1

x = 10 Kiran – 50 years, Suji – 10 years.

109. Six years from now, the average of Mano’s age that time and

Nita’s age that time will be 29 years. Five years ago, if the ratio of Mano’s age to the Nita’s age that time was 11:7, what is

Nita’s present age ?






Total age after 6 years = 2×29=58 Total age before 5 years = 58−11×2=36

Nita’s age before 5 years = 36 * (7/18) = 14 Nita’s present age = 14 + 5 = 19

110. Five years ago, the average age of Simi’s age that time and

Tia’s age that time was 17 years. Five years from now, the respective ratio between Simi’s age and Tia’s age at that time

will be 4:5, what is Simi’s present age? A. 22

B. 20 C. 18

D. 19



The average age of Simi’s age that time and Tia’s age that time = 17 years

Total age at that time = 34 Total age after 10 years = 34 + 20 = 54

Simi’s age after 5 years = 54 * (4/9) = 24 Simi’s present age = 24 – 5 = 19

111. A said to B – seven years ago I was seven times as old as

you were and three year hence I will be three times as old as you will be. The ages of A and B

a) 52, 12 b) 42, 12

c) 32, 12 d) 54, 14 e) None of these



Answer – b) 42, 12 Explanation :

A – 7 = 7*(B – 7)…….(1) A + 3 = 3*(B + 3)…….. (2) Solve both equations to get A and B

112. The ratio of the ages of priya and riya is 2:5. After 8 years,

their ages will be in the ratio of 2:3. Then the sum of their present ages

a) 12 years b) 14 years c) 16 years

d) 18 years e) None of these


Answer – b) 14 years Explanation :

Let priya age = 2x and riya age = 5x. So, (2x + 8)/(5x + 8) = 2/3, we get x = 2. So sum of priya and riya = 14

113. The sum of the age of mother and daughter is 100 years. 5 years ago their age were in the ratio of 2:1. The ratio of the age

of daughter and mother after 10 years a) 2:5

b) 3:4 c) 3:5

d) 4:5 e) None of these


Answer – c) 3:5

Explanation : M + D = 100 and (M – 5)/(D -5) = 2/1 we get D = 35 and M = 65. So after 10 years ratio = 45/75 = 3/5


114. The ratio of the ages of two persons are in the ratio of 5:7 and the difference between their ages is 18 years. Find the sum

of the ages of the person after 5 years, a) 112 years

b) 115 years c) 117 years

d) 119 years e) None of these


Answer – e) None of these Explanation :7x – 5x = 18…data inadequate

115. If 6 is subtracted from the present age of neha and the

remainder is divided by 6, then the present age of mia is obtained. If Mia is 4 years younger to raj whose age is 12 years,

then find the age of neha a) 50

b) 52 c) 54

d) 58 e) None of these


Answer – c) 54

Explanation : (N – 6)/6 = M = 12 – 4 = 8. We will get N = 54

116. If P age is twice the average age of P, Q and R age’s. Q’s age

is one half the average of P, Q and R’s age. If the age of R is 5 years, then find the sum of ages of P, Q and R.

a) 20 b) 25

c) 30 d) 35 e) None of these



Answer – c) 30 Explanation :

P = 2*(P + Q+ R)/3 Q = (1/2)*(P + Q+ R)/3 and R = 5 solve these equations, we will get P = 20, Q = 5 and R = 5

117. The ratio between the A and B age is 7: 9. If the difference

between the present ages of Q and P’s age after 4 years is 2 then what is the total of the present ages of P and Q?

a) 42 b) 44 c) 46



Answer – d) 48 Explanation :

let age of B is 9x and that of A is 7x. So 9x – (7x +4) = 2, x = 3 So sum will be = 27 + 21 = 48

118. Ritu married 6 years ago. Today her age is 5/4 times her age at the time of her marriage. Her daughter age is 1/5 of her age.

What is the ratio of ritu age to her daughter age after 6 years? a) 2:1

b) 3:1 c) 4:3

d) 5:2 e) None of these


Answer – b) 3:1

Explanation : R = (5/4)*(R – 6)

R = 30 years and daughter age = 30/5 = 6 years. After 6 years ratio will be = 36/12 = 3:1


119. 6 years ago Ram was twice as old as Shyam. If the ratio of their present ages is 9:5 respectively, what is the difference

between their present ages in year? a) 20 year

b) 22 year c) 24 year

d) 26 year e) None of these


Answer – c) 24 year

Explanation : R – 6 = 2*(S – 6)

put R = 9x and S = 5x, we will get x = 6 so difference between ages is 4*6 = 24 years

120. The sum of the ages of a mother and her son is 45 years. Five years ago, the product of their ages was 3 times the

mother age at that time, then the present age of the son, a) 8

b) 10 c) 12



Answer – a) 8 Explanation : M + S = 45 (M -5)*(S – 5) = 3*(M – 5) so, S = 8 years

121. Suman’s age was double that of Kareena’s 10 years ago. Ratio of the present ages of Kareena to Suman is 3 : 5. What will

be Kareena’s age 5 years after? A) 50

B) 30 C) 65

D) 35 E) 40

Answer


D) 35 Explanation:

Let the present ages of Kareena and Suman are 3x and 5x. Then, 10 yrs ago, (5x-10) = 2 * (3x-10)

Solve, x = 10 So Kareena present age = 30, after 5 years = 35

122. 8 years ago, Bhanu’s age was four greater than Ravi’s age

that time. Also the ratio of Ravi’s age to Bhanu’s 8 years after

will be 6 : 7. Find the ratio of Ravi’s age to that of Bhanu’s age 4 years after. A) 2 : 3

B) 4 : 9 C) 7 : 5

D) 6 : 5 E) 5 : 6

Answer

E) 5 : 6

Explanation:

Ravi = x, Bhanu = y 8 years ago, (x-8) + 4 = (y-8) . This gives x – y = -4

After 8 years, (x+8)/ (y+8) = 6/7. This gives 7x – 6y = -8 Solve both equations, x = 16, y = 20 So required ratio = (16+4) : (20+4) = 20 : 24 = 5 : 6

123. Ratio of Rani’s age to Sheena’s age was 5 : 8 four years ago. Sheena’s present age is 6 years greater than Rani’s age 6 years

after. Find the ratio of the present ages of Sheena and Rani. A) 2 : 3

B) 3 : 2 C) 4 : 5

D) 5: 6 E) None of these

Answer

B) 3 : 2

Explanation: Rani = A, Sheena = B

4 yrs ago, A-4/B-4 = 5/8


8A – 5B = 12 After 6 yrs, A + 6 = B – 6 Solve the equations, A = 24, B = 36

124. Kavya’s age is 3 times more than that of Rita. Kavya will be

2 ½ times that of Rita 8 years after. How many times will Kavya’s age be that of Rita 8 more years after?

A) 2 n half B) 2

C) 3 D) 3 n half E) 1 n half


B) 2 Explanation:

Rita = x, Kavya = x+3x = 4x (4x + 8) = 5/2 (x+8)

Solve, x = 8 After 8 years, Kayva = 4x + 16 = 48, Rita = x+16 = 24

125. Ronit’s age is 10 years more than Rohit’s age. Also Ronit

was twice old as Rohit 15 years ago. What will be the age of Ronit 6 years after?

A) 41 B) 40

C) 35 D) 45 E) 38


A) 41 Explanation:

Rohit = x, Ronit = x+10 (x+10) – 15 = 2(x-15)

Solve, x = 25 Ronit’s 6 years after = x+10+6


126. Ravi’s age was one third of his father’s 18 years ago. Now he is half the age of his father. What is the difference in the

present ages of father and Ravi? A) 72

B) 36 C) 25

D) 20 E) 30


B) 36

Explanation: Ravi’s present = x, father’s = 2x

Then, (2x-18) = 3 (x – 18) Solve, x = 36 So difference = 2x-x = x = 36

127. Kirti’s age 4 years ago and Kavita’s 4 years hence is same.

Also the present ages of Kirti and Kavita are in the ratio 5 : 3. Find the ratio of Kirti’s age 4 years hence to Kavita’s age 4

years ago. A) 3 : 2

B) 5 : 2 C) 3 : 1 D) 2 : 3 E) 1 : 3


C) 3 : 1

Explanation: Kirti = A, Kavita = B

Let A’s present age = 5x, and B’s = 3x A’s age 4 years ago to B’s age 4 years hence is same

So (5x-4) = (3x+4) Solve x = 4 So A’s present age = 20, and B’s = 12 Required ratio = (20+4) : (12-4)

128. The sum of ages of Sonu and Monu is 60 at present. Also

Sonu’s age was five time that of Monu 6 years ago. What will be


the age of Monu 5 years after? A) 14

B) 20 C) 18

D) 19 E) 22


D) 19

Explanation:

Monu = x, Sonu = 60-x 60-x – 6 = 5*(x – 6) solve, x = 14 monu’s 5 years after = x+5 = 19

129. Reema’s age will be 7/3 of Tina’s 6 years after. Also the

ratio of their ages was 5 : 1, 10 years ago. What is Reema’s present age?

A) 45 B) 50

C) 30 D) 60 E) None of these


B) 50 Explanation:

Let 10 years ago, Tina = x, Reema = 5x Then, 5x+16 = 7/3 * (x+16)

Solve, x = 8 So Reema’s present age = 5x+10 = 50

130. The ratio of Shruti’s age to Meenu’s age is 5 : 7. The

difference in the present age of Meenu and Shruti’s age 6 years after is 2 years. What is the total of their present ages?

A) 45 B) 48

C) 50 D) 60

E) None of these



B) 48

Explanation: Shruti = 5x, Meenu = 7x

7x – (5x+6) = 2 Solve, x = 4 So sum = 5x+7x = 12x = 48

131. Four years ago, the ratio of the ages of A and B was 5 : 9. 8

years hence the ratio will be 2 : 3 respectively. Find the present

age of B? A) 25 B) 20

C) 40 D) 60 E) 24


C) 40

Explanation: Let 4 years ago A’s age = 5x, B’s age = 9x

Then 4+8 = 12 years after – (5x+12)/(9x+12) = 2/3 Solve, x = 4 B’s present age = 9x+4 = 40

132. Eight years ago, A was 4 times as old as B. After 8 years A will be twice as old as B. What are their ages respectively?

A) 45, 18 B) 40, 10

C) 42, 18 D) 40, 16 E) 42, 16


D) 40, 16 Explanation:

Let B’s age 8 yrs ago = x, then A’s age = 4x After (8+8) = 16 years:

(4x+16) = 2 * (x+8) Solve, x = 8


A’s present age = 4x+8 = 40 B’s present age = x+8 = 16

133. Present age of B is twice that of A. 4 years hence B’s age will be 4 less than twice the age of A. Find the difference in their

ages? A) 8

B) 10 C) 4

D) 5 E) Cannot be determined


E) Cannot be determined

Explanation: Let A’s present age = x, Then B’s present age = 2x

After 4 years, (2x+4) = 2(x+4) – 4 0 = 0

134. After 6 years, A’s age will be 3/7th of B’s age. Also 10 years

ago, ratio of ages of A and B was 1 : 5. What is A’s present age? A) 20

B) 25 C) 24

D) 18 E) 50


D) 18

Explanation: Let 10 years ago, A’s age = x, B’s age = 5x

After (10+6) = 16 years, (x+16) = (3/7) (5x+16) Solve, x = 8 So A’s present age = x+10 = 18

135. B is twice older than C and A is 2 years older than B. If the

total of all of their ages is 27, what will be total of the ages of A and C 6 years hence?


A) 17 B) 29

C) 28 D) 23 E) 18


B) 29

Explanation: Let C’s present age = x, then B’s = 2x, and A’s = 2x+2

Given: x+2x+(2x+2) = 27 Solve, x = 5 A’s present age = 2x+2 = 12

C’s present age = x = 5 6 years after A+C)’s age = 12+5+6+6 = 29

136. The sum of the present ages of A and B is 50. After 2 years B’s age will be 2 more than C’s age then. If A is younger than C

by 4 years, find the age of B 8 years ago. A) 20

B) 40 C) 28

D) 26 E) 22


A) 20

Explanation: The difference between B and C’s age will remain same

Let C’s present age = x, so B’s present age = (x+2) sum of the present ages of A and B is 50, so A’s age becomes = 50-

(x+2) =48-x now A is younger than C by 4 years, so 48-x = x – 4

Solve, x = 26 B’s present age = x+2 = 28 Before 8 years, B’s age = 28-8 = 20

137. After 10 years, A’s age will be twice that of B’s age. A’s present age is 6 times that of C. If B’s eighth birthday was

celebrated 2 years ago, then what is C’s present age?


A) 8 B) 5

C) 10 D) 15 E) 12


B) 5

Explanation: Let C’s present age = x, then A’s present age = 6x

Let B’s present age is y. Then after 10 years, (6x+10) = 2 (y+10) Solve, y = 3x-5 = B’s present age

B’s eighth birthday was celebrated 2 years ago, so B’s present age = 10, and also 3x-5 = 10 Solve, x = 5

138. The ratio of the present ages of A to B is 5 : 3. The ratio of

A’s age 4 years ago to B’s age 4 years hence is 1 : 1. What is the ratio of A’s age 4 years hence to B’s age 4 years ago?

A) 3 : 2 B) 5 : 2

C) 3 : 1 D) 2 : 3 E) 1 : 3


C) 3 : 1 Explanation:

Let A’s present age = 5x, and B’s = 3x Ratio of A’s age 4 years ago to B’s age 4 years hence is 1 : 1. So

(5x-4)/(3x+4) = 1/1 Solve x = 4

So A’s present age = 20, and B’s = 12 Required ratio = (20+4) : (12-4)

139. Present age of a father is three times more than his son. 8

years hence, father’s age will be 2 and a half times of his son’s age. After 8 more years, how many times would father be his

son’s age?


A) 3 n half times B) 4 times

C) 1 n half times D) 2 times E) 3 times


D) 2 times

Explanation: three times more than

Let present age of son = x, then of father = x+3x = 4x After 8 years, (4x+8) = (5/2) (x+8) Solve, x = 8 Required ratio = (4x+16) : (x+16) = 2 : 1

140. Age of A is three times the sum of ages of B and C. 5 years

hence, A’s age will be twice the sum of ages of B and C. The total of their present ages is

A) 45 B) 60

C) 30 D) Cannot be determined

E) None of these


B) 60 Explanation:

Let (B+C)’s present age= x Then A’s present age = 3x

After 5 years, (3x+5) = 2*(x+5+5) Solve, x = 15 Sum = x+3x = 4x = 60

141. Average age of a group of 40 students is 37 yrs. If a teacher is included then the average age rises by 1,then find the age of

the teacher after 2 years ? A)77

B)80 C)78 D)81

Answer


B)80 Explanation :

X = 37*40 = 1480 X = 38*41 = 1558

T age = 1558 – 1480 = 78 Aftr 2 yrs = 78+2 = 80

142. At present Priya is twice Sariga’s age. 8 yrs hence the

respective ratio between Priya and Sariga’s age will be 22 :13,

What is Sariga’s present age ? A)26 B)36

C)18 D)20

Answer

C)18 Explanation :

P = 2S 2s+8/s+8 = 22/13

26s+104 = 22s+176 4s = 72 S= 18yr

143. The ratio between the present ages of X and Y is 4:9 respectively. 2yrs from now, Y’s age will become twice the age

of X.What was the difference between their ages five yrs ago ? A)10

B) 7 C)12 D)9

Answer

A)10 Explanation :

4x+2/7x+2 = ½ 8x+4 = 9x+2

x = 2 x:y = 8:18


5 yrs ago = 3:13 D = 13-3 = 10

144. The ratio of present age of Kaviya and Lakshmi is 6:7, the ratio of their ages after 8yrs would be 8:9, What is Kaviya’s

present age? A)20

B)24 C)28 D)30

Answer

B)24 Explanation :

6x+8/7x+8 = 8/9 54x+72 = 56x+64

2x = 8 x = 4 K=6*4 = 24yrs

145. The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen. Parveen’s age after 9yrs

will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X

A)13 B)10

C)11 D)14

Answer

A)13

Explanation : P present age = 33-9 = 24

M = 24 – 9 =15 D – M = 24

D – 15 = 24 D = 24+15 = 39

15:39 = 5:13 X = 13


146. The present age of Akil is 3 times that of Nirmal. 3 yrs hence

the age of Akil will become 4yrs more than Nirmal. age The present age of Akil is

A)1 B)2 C)4 D)6

Answer

D)6

Explanation : A = 3N

A+3 = N+4+3 3N+3 = N +7

2N = 4 N =4/2

N = 2yrs A = 3*2 = 6yrs

147. The age of Vivek is 54yrs, If sham’s age is 36% more than

that of Vivek, What % is Vivek’s age less than Sham ? A)26%

B)20% C)35% D)30%

Answer

A)26% Explanation :

S = 136*54/100 = 73 % = 73-54/73 = 26%

148. Ashok is 3 years elder than Balu who is now 4 times as old

as Jaswanth. Jaswanth is now 6 years old. What was Ashok’s age when Jaswanth was born?

A)20 B)27


C)21 D)25

Answer

C)21 Explanation :

Let Ashok age A. Age of Balu = A-3

Jaswanth’s age = 6 Balu’s Age = 4* J’s age

i.e., A – 3 = 4 x 6 X = 24 + 3 = 27 Hence, Ashok’s age = 27 – 6 = 21

149. The sum of the ages of 5 children born at the intervals of 3 years each is 50 years.

What is the age of the elder child among 5 childern? A)21

B)15 C)16 D)18

Answer

C)16 Explanation :

X+x+3+x+6+x+9+x+12 = 50 5x+30 =50

X = 50-30/5 = 20/5 =4 4+12 = 16

150. The sum of the present ages of Jai, Prem and Saran is 93

years. Ten years ago, the ratio of their ages was 2:3:4. What is the present age of Sara?

A)31 B)38

C)21 D)28

Answer


B)38 Explanation :

J+P+S = 93 J-10:P-10:S-10 = 2:3:4

93-30 = 63 Saran age = 63*4/9 = 28+10 = 38

151. In 8 years ago P will be twice as old as Q.If A is now 6 years

older than Q,then the present age of Q A)10

B)14 C)13 D)12

Answer

Answer -B) 14

Explanation :

152. The difference between the age of the two persons is 6

years.Twelve years ago, the elder was thrice as old as the younger one.The present age of the elder

A)16 B)10

C)21 D)13

Answer


Answer -C) 21 Explanation :

153. The sum of age of 4 children born at the interval of 2 years each is 48.What is the age of the youngest one?

A)13 B)15

C)11 D)9

Answer

Answer -D) 9

Explanation :

154. The ratio between the present age of A and B is 7:4.The ratio

between the age of A and B four years ago is 2:1.What is the ratio age of A and B four years hence

A)3:4 B)3:5

C)5:8 D)8:5

Answer


Answer -D) 8:5 Explanation :

155. Ram is 42 years old and Rajesh is 58 years old.How many years ago was the ratio of their ages 4:6

A)10 B)16

C)14 D)None of these

Answer

Answer -A) 10

Explanation :

156. The sum of the ages of a father and his son is 70 years.Five

years ago difference between their age is 14.The father’s present age is

A)24 B)42 C)28 D)56

Answer


Answer – B) 42 Explanation :

157. A is 3 years older than B who is twice as old as C .If the total of ages A,B and C is 38,What is the age of C

A)10 B)14

C)9 D)7

Answer

Answer – D) 7

Explanation :

158. The present ages of three persons are in the ratio of 3:4:6.Four years ago the sum of their age was 66.Find their

present age A)18,24,36

B)14,20,32 C)24,36,18 D)None of these

Answer


Answer -A)18,24,36 Explanation :

159. Sam’s present age is two-fifth of the age of his mother age.After 6 years,he will half of the age of his mother.The

mother present age is A)12

B)35 C)30 D)40

Answer

Answer -C) 30 Explanation :

160. The average of ages of three persons is 60 years .Those ages

are in the proportion of 2:4:6.what is the age of the youngest

one among them? A)30 B)15

C)60 D)None of the above

Answer


Answer -A) 30

Explanation :

161. The sum of ages of family members (both children and

parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio

5:7.What will be the age of husband? A.65

B.75 C.72 D.70

Answer

Answer : D (70) Explanation-

Sum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years

Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

162. The ratio between the present ages of A and B is 6:7. If B is

4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7

B.7 : 8 C.8 : 7

D.Data inadequate E.None of these

Answer

Answer – B (7 : 8)

Explanation –

Let A’s age and B’s age be 6X years and 7X years respectively


Then, 7X – 6X = 4 X = 4

Required ratio = (6X + 4) : (7X + 4) = (6*4+4) : (7*4 +4) =28 : 32 = 7 : 8

163. The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are

in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband?

A.65 B.75 C.72 D.70

Answer

Answer : D (70)

Explanation- Sum of ages is 360 years.The ratio of children and parents ages is 2:1.

Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband =

120 x 7 / 12 = 70 Hence the age of husband is 70 years.

164. Sush was thrice as old as Poonam 6 years back. Sush will be

5/3 times as old as Poonam 6 years hence. How old is Poonam today?

A.20 B.14

C.12 D.15 E.None of these

Answer

Answer – C (12) Explanation –

Let Poonam age 6 years back = x. Then, Sush age 6 years back = 3x.

(5/3) * (X + 6 + 6) = (3X + 6 + 6) So 5(x+ 12) = 3(3x+ 12),


so x=6. Poonam Age = (x+ 6) years = 12 years

165. Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will

become 11 : 9 respectively, What is Anu’s present age in years? A.20

B.24 C.28

D.35 E.None of these

Answer

Answer – B (24)

Explanation – Let the present ages of Simmi and Anu be 5x years and 4x years

respectively Then, [5X + 3] / [4X + 3] =11/9

x=6 Anu’s present age = 4X = 24 years

166. If 6 years are subtracted from the present age of Anuj and

the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to

Mohan whose age is 5 years, then what is the age of Anuj? A.44

B.60 C.80 D.92

Answer

Answer : B (60) Explanation –

Let Anuj’s age be X Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 – 2 =

3) If Arun had born 6 years before, his age would had been X – 6. As per

the question, X – 6 should be 18 times as that of Gokul’s age. i.e. (X – 6) /18= 3


X-6 =3 x 18 x = 60

167. Ten years ago, Khush was thrice as old as Sam was but 10 years hence, he will be only twice as old. Find Khush’s present

age? A.30

B.35 C.40


Answer

Answer – A (30)

Explanation – Let Khush’s present age be x years and Sam’s present age be y years

Then, according to the first condition, x – 10 = 3(y – 10)

or, x – 3y = -20 ……..(1) Now. Khush’s age after 10 years = (x + 10) years

Sam’s age after 10 years = (y + 10) (x+10) = 2(y+10)

or, x – 2y = 10 ……..(2) Solving (1) and (2), we get x = 70 and y = 30 Khush’s age = 70 years and Sam’s age = 30 years

168. Father is aged three times more than his son Mohit. After 8

years, he would be two and a half times of Mohit’s age. After further 8 years, how many times would he be of Mohit’s age?

A.4 B.2

C.2.5 D.3 E.None of these

Answer

Answer – B (2) Explanation –

Let Monit’s present age be X years. Then, father’s present age = (X +


3X) years = 4X years. (4X + 8) =5/2 x (X + 8)

8X + 16 = 5X + 40 3X = 24 so, X=8 Hence, required ratio = (4X + 16) / (X + 16)=48 / 24 = 2

169. A father said to his son, “I was as old as you are at present

at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was:

A.14 B.19 C.38


Answer

Answer – A (14) Explanation – Let son’s present age be X years. Then, (38 – X) = X

2X = 38 X = 19 Son’s age 5 years back = (19 – 5) years = 14 years

170. One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the

sum of their present ages in years? A.14

B.16 C.18


Answer

Answer – B (16) Explanation – Let one year ago Sam’s age be 4X years

And, Ash’s age be 3X years Present age of Sam = (4X + 1) years

Present age of Ash= (3X + 1) years One year hence

Sam’s age = (4X + 2) years


Ash’s age = (3X + 2) years According to question,

[4X + 2] divide by [3X + 2] = 5 / 4 16X + 8 = 15X + 10

or, X = 2 Sum of their present ages = 4X + 1 + 3X + 1

= 7X + 2 = 7 x 2 + 2 = 16 years

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