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Diffraction from CrystalsDiffraction from Crystals““Structure FactorStructure Factor””
Lecture 5Lecture 5
Coherent elastic scatteringCoherent elastic scattering
kkdd
DetectorDetector
Ψincident= exp 2πi(
rk
i⋅ ′rr − ωt)⎡⎣ ⎤⎦ = exp 2πi(
rk
i⋅ ′rr )⎡⎣ ⎤⎦Incident plane wave:Incident plane wave:
Scattered wave:Scattered wave:
Ψ
scattered= f k
i,k
d( )exp 2πi
rk
d⋅
rr − ′
rr( )⎡
⎣⎤⎦r
r − ′rr
= f θ( )exp 2πi
rk
d⋅
rr − ′
rr( )⎡
⎣⎤⎦r
r − ′rr
rr’’ss -- position vectorsposition vectors
kk’’ss -- wave vectorswave vectors
kkii
rr’’
r r -- rr’’rr
--kkii
kkddKK
θθ
Scattering from a latticeScattering from a lattice
r R j[ ]- atom locations
r R n
′ r r
′ r r −
r R n
Vatom
r ′ r ( )= Vat
r ′ r −
r R j( )∑
Ψscattered
r K ,
r r ( )=
−m
2πh2
exp 2πir k d ⋅
r r ( )[ ]
r r
Vat ′ r r −
r R j( )∑ exp −2πi
v K ⋅ ′
r r ( )[ ]∫ d3 ′
r r
fel
r R j,
r K ( )≈ fel
r R j( )
Scattering from a latticeScattering from a lattice
r r ≡
r ′ r −
v R j (i.e.
r ′ r = r + ′ R j)
Ψscatt
r K ( )= −m
2πh2Vat,
r R j
r( )∑ exp −2πiv K ⋅
r r +
r R j( )( )[ ]∫ d3 ′
r r
= −m
2πh2Vat,
r R j
r( )∫ exp −2πiv K ⋅
r r ( )[ ]d3 ′
r r
⎛
⎝ ⎜
⎞
⎠ ⎟ exp −2πi
v K ⋅
r R j( )[ ]
v R j
∑
Ignore the 1/rIgnore the 1/r22 term to give:term to give:
r R j[ ]- atom locations
r R n
′ r r
′ r r −
r R n
Scattering from a latticeScattering from a lattice
So scattered wave from an array of N atoms:So scattered wave from an array of N atoms:
Notes:Notes:–– Now have Now have ΨΨ(K) only, (K) only, RRjj are fixed. Means scattered wave are fixed. Means scattered wave
depends on incident wave vector.depends on incident wave vector.–– This is a Fourier Transform (FT) This is a Fourier Transform (FT) Diffracted intensity is proportional to the Fourier Transform ofDiffracted intensity is proportional to the Fourier Transform of the the
scattering factor distribution in the materialscattering factor distribution in the material
Ψscatt
r K ( )= fel
r R j( )exp −2πi
v K ⋅
r R j( )[ ]
j
N
∑
r R j[ ]- atom locations
r R n
′ r r
′ r r −
r R n
Scattering from a latticeScattering from a lattice
In simplest form, a crystal is:In simplest form, a crystal is:
For now, consider a defect free crystal:For now, consider a defect free crystal:
Scattered wave:Scattered wave:
Basis must be same for all unit cells:Basis must be same for all unit cells:
Crystal = lattice + basis + defect displacementsr R j =
r r lattice +
r r basis +
r r defects =
r r l +
r r b +
r r d
Crystal = lattice + basis r R j =
r r lattice +
r r basis =
r r l +
r r b
Ψscatt
r K ( )= fel
r r l +
r r b( )exp −2πi
v K ⋅
r r l +
r r b( )( )[ ]
rb
∑rl
∑
Ψscatt
r K ( )= exp −2πi
v K ⋅
r r l( )[ ]
rl
∑ fel
r r b( )exp −2πi
v K ⋅
r r b( )[ ]
rb
∑ fr r l +
r r b( )= f
r r b( )
Scattering from a latticeScattering from a lattice
Repeating:Repeating:
where:where:
FF(K) same for all lattice points:(K) same for all lattice points:
Ψscatt
r K ( )= exp −2πi
v K ⋅
r r l( )[ ]
r r l
∑ fel rb( )exp −2πiv K ⋅
r r b( )[ ]
r r b
∑
Ψscatt
r K ( )= S
r K ( )F
r K ( )
Sv K ( )= exp −2πi
v K ⋅
r r l( )[ ]
r r l
lattice
∑
Fv K ( )= fel rb( )exp −2πi
v K ⋅
r r b( )[ ]
r r b
basis
∑
““Shape FactorShape Factor””
““Structure FactorStructure Factor””
Ψ
v K ( )= F
v K ( )exp −2πi
v K ⋅
r r l( )[ ]
r r l
lattice
∑
Structure FactorStructure Factor
Structure Factor:Structure Factor:–– Scattering from all atoms in the unit cellScattering from all atoms in the unit cell
F
v K ( )= fel
r r b( )exp −2πi
v K ⋅
r r b( )[ ]
r r b
basis
∑
In essence, Structure Factor determines In essence, Structure Factor determines whether or not constructive interference occurs whether or not constructive interference occurs at a given reciprocal lattice pointat a given reciprocal lattice point
This means our prior condition This means our prior condition -- K = g K = g -- is a is a necessary condition, but is not sufficientnecessary condition, but is not sufficient
–– There may not be intensity at a given g!There may not be intensity at a given g!
Structure factorStructure factorcalculationcalculation
F
v K ( )= fi exp −2πi
v K ⋅
r r i( )[ ]
i
∑
Consider i atoms in the unit cellConsider i atoms in the unit cell
r r i = xi
r a + yi
r b + zi
r c
Location of Location of iithth atom (with respect to real lattice):atom (with respect to real lattice):
Diffraction condition (K = g):Diffraction condition (K = g):
r K = h
r a * +k
r b * +l
r c *
General from:General from:
F
v K ( )= fi exp −2πi hxi +kyi + lzi( )[ ]
i
∑
Using Using defdefnn of a*, of a*, b* & c*b* & c*
Structure FactorStructure Factorsimple cubicsimple cubic
F = fi exp −2πi hxi +kyi + lzi( )[ ]i
∑
One atom basis : r = 0,0,0( )F = f exp −2πi 0 ⋅h+ 0 ⋅k + 0 ⋅ l( )[ ]{ } = f exp −2πi 0( )[ ]{ } = f exp 0[ ]{ } = f
Simple result: intensity at every reciprocal lattice pointSimple result: intensity at every reciprocal lattice point
Structure FactorStructure Factorbodybody--centered cubiccentered cubic
Two atom basis : r = 0,0,0( ) & r =12
,12
,12
⎛
⎝ ⎜
⎞
⎠ ⎟
F = f exp −2πi 0 ⋅h+ 0 ⋅k + 0 ⋅ l( )[ ]+ exp −2πi12
⋅h+12
⋅k +12
⋅ l⎛
⎝ ⎜
⎞
⎠ ⎟
⎡
⎣ ⎢
⎤
⎦ ⎥
⎧ ⎨ ⎩
⎫ ⎬ ⎭
= f 1+ exp −πi h+k + l( )[ ]{ }h, k & l are integers, so h +k + l = N (where N is an integer)
The exponential can then take one of two values:
exp −πi h+k + l( )[ ]= +1 if N = even
exp −πi h+k + l( )[ ]= −1 if N = odd
So :
F = 2f if N = even
F = 0 if N = odd
Structure FactorStructure Factorbodybody--centered cubiccentered cubic
Allowed low order Allowed low order reflections are:reflections are:
–– 110, 200, 220, 310, 222, 321, 110, 200, 220, 310, 222, 321, 400, 330, 411, 420 400, 330, 411, 420 ……
Forbidden reflections are:Forbidden reflections are:–– 100, 111, 210100, 111, 210
Origin of forbidden Origin of forbidden reflections?reflections?
–– Identical plane of atoms Identical plane of atoms halfway between causes halfway between causes destructive interferencedestructive interference
Real bcc lattice has an Real bcc lattice has an fccfccreciprocal latticereciprocal lattice
002002 022022
220220
020020
200200
202202
112112
101101000000
011011
110110
211211
121121
Structure FactorStructure Factorface centered cubicface centered cubic
Four atom basis: r = 0,0,0( ), r =12
,12
,0⎛
⎝⎜⎞
⎠⎟, r =
12
,0,12
⎛
⎝⎜⎞
⎠⎟ & r = 0,
12
,12
⎛
⎝⎜⎞
⎠⎟
F = f 1+ exp −πi h + k( )⎡⎣
⎤⎦ + exp −πi k + l( )⎡
⎣⎤⎦ + exp −πi h + l( )⎡
⎣⎤⎦{ }
So:
F=4f if h,k,l all even or odd
F=0 if h,k,l are mixed even or odd
Structure FactorStructure Factorface centered cubicface centered cubic
Allowed low order Allowed low order reflections are:reflections are:
–– 111, 200, 220, 311, 222, 400, 111, 200, 220, 311, 222, 400, 331, 310331, 310
Forbidden reflections:Forbidden reflections:–– 100, 110, 210, 211100, 110, 210, 211
Real fcc lattice has a bcc Real fcc lattice has a bcc reciprocal latticereciprocal lattice
002002 022022
220220
020020
200200
202202
000000 111111
Structure Factor Structure Factor NaClNaCl (rock salt) structure(rock salt) structure
If h,k,l all odd have If h,k,l all odd have ‘‘chemically chemically sensitivesensitive’’ reflectionsreflections
Na on each fcc site, but with a two atom basis :
rNa = 0,0,0( ) & rCl =12
,12
,12
⎛
⎝ ⎜
⎞
⎠ ⎟
F = fNa + fCl exp −πi h+k + l( )[ ]{ }×
1+ exp −πi h+k( )[ ]+ exp −πi k + l( )[ ]+ exp −πi h+ l( )[ ]{ }F = 4 fNa + fCl( ) if h,k,l all even
F = 4 fNa − fCl( ) if h,k,l all odd
F = 0 if h,k,l mixed
Structure FactorStructure FactorNiNi33Al (L1Al (L122) structure) structure
rAl
= 0,0,0( ), rNi=
1
2,1
2,0
⎛
⎝⎜⎞
⎠⎟ , r
Ni=
1
2,0,
1
2
⎛
⎝⎜⎞
⎠⎟ & r
Ni= 0,
1
2,1
2
⎛
⎝⎜⎞
⎠⎟
F = fal
+ fNi
exp −πi h + k( )⎡⎣
⎤⎦ + exp −πi k + l( )⎡
⎣⎤⎦ + exp −πi h + l( )⎡
⎣⎤⎦
So :
F=fAl
+3fNi
if h,k,l all even or odd
F=fAl
-fNi
if h,k,l are mixed even or odd
Simple cubic lattice, with at four atom basisSimple cubic lattice, with at four atom basis
Again, since simple cubic, intensity at all points. Again, since simple cubic, intensity at all points.
But each point is But each point is ‘‘chemically sensitivechemically sensitive’’..
Chemically sensitive reflectionsChemically sensitive reflections
Dark field images formed from chemically sensitive Dark field images formed from chemically sensitive reflections produce a real space map of (highly) local reflections produce a real space map of (highly) local chemistrychemistry