2




2
ri= 2.1.4
2
1
Au
2

3.
2

2
2
2
2.
iB=IB+ib
2
iC=IC+ic2.1.2
2
uo=uce 2.1.3

2
1.
1)
uCE=UCC-iCRc
2
uCEiC UCCRc

iCuCE MN 2.2.2(d)
uBE IBQ
M
N

2
IBQ=40μA
ICQ=1.8mA
UCEQ=9V
3)
2
iB, 2.2.3(b) QQ1Q2uiQQ1 QQ2
2

2.2.4(a)UCCRbRcRL2.2.4(b)
2
uce=-icR′L (2.2.4)
2
QK′
2.2.5 MN QM-1/R′LML(OL=UCCR′L) QM′N′MLM′N′-1/R′LQM′N′

2
2.2.12.2.4 Rb=300 kΩ, Rc=4 kΩRL=4 kΩ, UCC=12V, ui=0.02 sinωt(V) 2.2.6(b) 2.2.6(a) RL
(1)
2
uCE=6-3sinωtV

iCLOL=6mAMLQM′N′ML, M′N′
2
(4) RL
uBE=6-1.5 sinωtV
2
2
RLRL→R′L→→iC→uCEuo
3.
2
2
2
2
2

2
2
ΔiB
2
(2.1.1)(2.1.2)ΔiB=ibΔiC=ic
c e
2
ΔiC=βΔiB
2
2.2.10
PN



2
r be=300+(1+β) (2.2.16)
2. h
1 hh
iC=f2(iB, uCE) (2.2.18)
2

2
duBE=hiediB+hreduCE
diC=hfediB+hoeduCE
2) h
2.2.13(a)2.2.13(b) 2.2.13(c)ucehre=02.2.13(c)
2
1) Au
2.2.13(c)
ui=hieib
uo=-hfeibRt
Rt=(1/hoe)R′LR′L=RcRLuo
Au=
Au≈-
2
1RcR′LAuRcR′L≈RLRcAuRc
2hfeICQAu hfehie
3ICQAu(2.2.16)rbe βhiehfe
hie≈rbb′+(1+hfe)
2
2) ri
ri≈hie (2.2.32)
2
2.2.29)rg
2
2.2.22.2.13hie=950Ωhfe=50hoe=25mS(1/hoe=40Ω) rg=1kΩRc=RL=3 kΩRb=280kΩUCC=12 VAu Augriro

2
IBQ=
ICQ≈hfeIBQ
2

hfeib<<hoeuce
(1) Au
2.2.16(b)2.2.38
3 roro2.2.16(c)cr′oRcro2.2.16c
i′c=hfei′b+hoeu′ce=hfei′b+hoe(u′o-u′e)

r′o
2
1.
UCCRbICQβUBEICBO10, ICBO10, UBE2.5mV1β0.5~1.0%ICQ
2.2.4 NPN β=50UBE=0.25VICBO=1μA, UCC=6 VRb=180kΩRc=2kΩ30ICQUCEQ
2
30β′=65, UBE=0.175V, I′CBO=8μA,
I′BQ=32.4μA, I′CQ=2.6 mA, U′CEQ=0.73V


2
ICQ(IEQ)↓
2
UBQ≈
2

2
UE=IEQRe=(1+β)IBQR e

2)
1
2.3.2Rbiiii≈ibR′eR′e=ReRLio=ie
Ai= (2.3.2)

2

R′e =ReRL1+βR′Lrbe 11
3 ui=rbe+1+βR′e]i ′e,,,,Rbbr′i
2
2
u′o=-(rsRb)+βib
r′o
r′o=
Rero
2
2.
1)
UB≈
1
2.3.5Reii ii≈-ieR′LR′L=RcRLio=-ic
2

2
3
Re
2
4
r′o≈(1+β)rce 2.3.16
rce1+β
2
Rcro
R′oRcroRc