Find the probability for X successes in n trials of a binomial experiment

Find the mean, variance, and standard deviation for the variable of a binomial distribution

Situations that have only two outcomes or can be reduced to two outcomes › A coin is tossed (Heads or Tails)› A child is born (Boy or Girl)› Outcome of a basketball game (Win or

Lose)› Answer a true/false question (True or False)› Medical Treatment (Effective or Ineffective)› Answer a multiple choice question (Correct

or Incorrect)

There must be a fixed number of trials› Represented by “n”

Each trial can have only two outcomes or outcomes that can be reduced to two outcomes› Success, p=P(S)› Failure, q =P(F) =1-p

The outcomes of each trial must be independent of each other

The probability of a success must remain the same for each trial

Randomly selecting 12 jurors and recording their nationalities

Recording the genders of 250 newborn babies

Determining whether each of 500 defibrillators is acceptable or defective

Treating 50 smokers with Nicorette and asking them how their mouth and throat feel

In a binomial experiment, the probability of EXACTLY x successes in n trials is:

xnxqpxxn

nxP

!)!(

!)(

Since computing probabilities using the formula can be quite tedious, we will use the TI-83/84 calculator to help us find and interpret the probabilities

Link to instructions: http://www.highlands.edu/academics/divisions/math/lralston/Probability%20Distributions%20--Calculator%20Instructions.htm

KEY WORDS/PHRASES will help to determine

calculator commands› Exactly x successes: Use

command: binompdf(› At most x successes: Use command:

binomcdf(› At least x successes: Use

command: 1 – binomcdf(

The CBS television show, 60 Minutes, has been successful for many years. That show recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to 60 Minutes. Assume that an advertiser wants to verify that 20% share value by conducting its own survey. A pilot survey begins with 10 households having TV sets in use at the time of a 60 Minutes broadcast› Find the probability that none of the households

are tuned to 60 Minutes› Find the probability that at least one household is

tuned to 60 Minutes› Find the probability that at most one household is

tuned to 60 Minutes

Air America has a policy of booking as many as 20 persons on an airplane that can seat only 14. (Past studies have revealed that only 85% of the booked passengers actually arrive for the flight. Find the probability that if Air America books 20 persons, not enough seats will be available. That is, find P(at least 15 persons arrive for flight) Is this probability low enough so that overbooking is not a real concern for passengers?

The Medassist Pharmaceutical Company receives large shipments of aspirin tablets and uses this acceptance sampling plan: Randomly select and test 24 tablets, then accept the whole batch if there is only one or none that doesn’t meet the required specifications. If a particular shipment of thousands of aspirin tablets has a 4% rate of defects, what is the probability that this shipment will be accepted?

=n * p

qpn

Mean – 2(standard deviation)

– 2

Mean + 2(standard deviation)

2

Air America has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that only 85% of the booked passengers actually arrive for the flight. › What is the average number of passengers on

Air America if 15 reservations are accepted? › What is the standard deviation? › What is the “usual” minimum number of

passengers on Air America?› What is the “usual” maximum number of

passengers on Air America?

Several Psychology students are unprepared for a surprise true/false test with 16 questions and all of their answers are guesses. › Find the mean and standard deviation for

the number of correct answers for such students

› Would it be unusual for a student to pass by guessing and getting at least 10 correct answers? Why or why not?

Several Economics students are unprepared for a multiple-choice quiz with 25 questions, and all of their answers are guesses. Each question has five possible answers and only one of them is correct. › Find the mean and standard deviation for the

number of correct answers for such students› Would it be unusual for a student to pass by

guessing and getting at least 15 correct answers? Why or why not?

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