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© T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

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Page 1: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 2: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

3 2?

4 4+ =

54

+ =

5 2?

7 7- =

37

Page 3: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

9 5 4?

16 16 16+ + =

1816

=98

+ +

Page 4: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

9 3 7?

20 20 20+ - =

520

=14

Page 5: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 6: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

3 34 8

- =68

38

Now the denominators are different

1 26 3

+ =16

56

x2

x2

x2

x2

38

- =

46

+ =

Page 7: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Now the denominators are different

3 54 12

- =9

1213

1 320 5

+ =120

1320

x3

x3

x4

x4

512

- =

1220

+ =

412

=

Page 8: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 9: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

3 5?

4 6+ =

4:

6:

4, 8, 12, 16, 20, 24, …

6, 12, 18, 24, 30, …

12 12+ =

9 10

1912

Now the denominators are different

Find the LCM of the denominators

x3

x3

x2

x2

Page 10: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

5 7?

8 12+ =

8:

12:

8, 16, 24, 32, 40, …

12, 24, 36, …

24 24+ =

15

14

2924

Now the denominators are different

Find the LCM of the denominators

x3

x3

x2

x2

Page 11: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

4 3?

5 8+ =

5:

8:

5, 10, 15, 20, 25, 30, 35, 40, …8, 16, 24, 32, 40, …

40 40+ =

32

15

4740

Now the denominators are different

Find the LCM of the denominators

x8

x8

x5

x5

Page 12: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

5 7?

12 18- =

12:

18:

12, 24, 36, 48, 60, …

18, 36, 54, 72, 90, …

36 36- =

15

14

136

Now the denominators are different

Find the LCM of the denominators

x3

x3

x2

x2

Page 13: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 14: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

12 12= + =

How do we add/subtract mixed numbers?

2 31 2

3 4+ = 3

12 12+ + =

98

54

12

Method 1

1 2+23

+34

+ =x4

x4

x3

x3

173

12= + =

Method 2

2 31 2

3 4+ =

53

114

+x4

x4

x3

x333

20

54

12

5312

=

Page 15: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

12 12= - =

How do we add/subtract mixed numbers?

5 32 1

6 4- = 1

12 12+ - =

910

11

12

Method 1

2 1-56

+34

- =x2

x2

x3

x3

Method 2

5 32 1

6 4- =

176

74

-x2

x2

x3

x321

34

11

12

1312

=

Page 16: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

7 7= - =

How do we add/subtract mixed numbers?

43 1

7- =

31

117

-x7

x711

21

31

7

107

=113

7- =

24 24= + =

5 13 2

6 8+ =

236

178

+x4

x4

x3

x351

92

235

24

14324

=

Page 17: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

PracticeAdding & SubtractingFractions

Page 18: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

1 3

8 8+ =

4

81

2=

9 4

13 13- =

5

131 10 3

7 7 7+ + =

14

72=

17 11 1

24 24 24- + =

7

24

1 3

10 10+ =

4

102

5=

9 8

10 10- =

1

102 9 4

5 5 5+ + =

15

53=

17 12 1

25 25 25- + =

6

25

Page 19: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

+ =1 1

2 4

2

4=

3

4+

1

4

+ =1 1

8 4

1

8=

3

8+

2

8

- =2 3

5 10

4

10=

1

10-

3

10

+ =5 1

6 1210

12=

11

12+

1

12

- =2 1

3 6

4

6=

3

6-

1

6

- =5 9

7 14

10

14=

1

14-

9

14

+ =2 1

5 15

6

15=

7

15+

1

15

- =5 7

6 1815

18=

8

18-

7

18

=1

2

=4

9

Page 20: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

+ =1 3

2 8

4

8=

7

8+

3

8

- =5 1

9 3

5

9=

2

9-

3

9

- =7 3

10 20

14

20=

11

20-

3

20

+ =1 7

3 124

12=

11

12+

7

12

- =1 1

2 6

3

6=

2

6-

1

6

- =1 3

2 16

8

16=

5

16-

3

16

+ =3 1

5 20

12

20=

13

20+

1

20

- =5 7

6 3025

30=

18

30-

7

30

=1

3

=3

5

Page 21: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Quick TestonAdding & SubtractingFractions

Page 22: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

1 3

8 8+ =

4

81

2=

9 4

13 13- =

5

131 10 3

7 7 7+ + =

14

72=

17 11 1

24 24 24- + =

7

24

1 3

10 10+ =

4

102

5=

9 8

10 10- =

1

102 9 4

5 5 5+ + =

15

53=

17 12 1

25 25 25- + =

6

25

Page 23: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

+ =1 1

2 4

2

4=

3

4+

1

4

+ =1 1

8 4

1

8=

3

8+

2

8

- =2 3

5 10

4

10=

1

10-

3

10

+ =5 1

6 1210

12=

11

12+

1

12

- =2 1

3 6

4

6=

3

6-

1

6

- =5 9

7 14

10

14=

1

14-

9

14

+ =2 1

5 15

6

15=

7

15+

1

15

- =5 7

6 1815

18=

8

18-

7

18

=1

2

=4

9

Page 24: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

+ =1 3

2 8

4

8=

7

8+

3

8

- =5 1

9 3

5

9=

2

9-

3

9

- =7 3

10 20

14

20=

11

20-

3

20

+ =1 7

3 124

12=

11

12+

7

12

- =1 1

2 6

3

6=

2

6-

1

6

- =1 3

2 16

8

16=

5

16-

3

16

+ =3 1

5 20

12

20=

13

20+

1

20

- =5 7

6 3025

30=

18

30-

7

30

=1

3

=3

5

Page 25: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 26: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Three adverts appear on a page of a newspaper.

The 1st advert covers 1/4 of the page.

The 2nd advert covers 1/8 of the page.

The 3rd advert covers 3/16 of the page.

What fraction of the page is not covered by adverts?14

18+ +

316 =

x 2

x 2

x 4

x 4

416

216+ +

316= 9

16

If is covered by adverts

then is not covered by adverts.

916

716

Page 27: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 28: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

A rectangle is 6⅝ cm long by 3½ cm wide.Calculate its perimeter.

6⅝ cm

cm to find the

perimeter:586 1

23+ 586 1

23++ =

Method 1

5819+ 5

8+ =

10819+ =5419+ =

÷ 2

÷ 2

1419+ =1

1420 cm

Page 29: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

A rectangle is 6⅝ cm long by 3½ cm wide.Calculate its perimeter.

6⅝ cm

cm to find the

perimeter:586 1

23+ 586 1

23++ =

Method 2

538

72+ 53

872++ =

1068

142+

x 4

x 4=

1068

568+ =

1628 =

2820

1420 cm

=

Page 30: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 31: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Edmonton is 3⅝ miles away from Southgate.Barnet is 2¾ miles away from Southgate.How much further from Southgate is Edmonton than Barnet?

583 3

42– = 298

114– = 29

8228– = 7

8

x 2

x 2

Edmonton is ⅞ of a mile further from Southgate than Barnet is.

Page 32: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 33: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Roulla used half of her exercise book in the autumn term.So far this term she has used a further one sixth of it.

1. What fraction of her exercise book has she used so far?2. How many pages does her exercise book have if she has 30 pages left?

12

16+

x 3

x 3= 3

616+ = 4

6 = 23

÷ 2

÷ 2

If she has used of her exercise book

she must have of it left.

If of her exercise book is 30 pages

then the entire exercise book must have 90 pages

23

13

13

Page 34: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Page 35: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas

Johnny spent his monthly allowance as follows:

of it on lunch and food snacks

of it on two music CDs

of it on a new book

1. What fraction of his monthly allowance has he got left?2. If he is left with £6 what is his monthly allowance?

251316

25

13+ +

16 =

x 10

x 10

x 6

x 6

x 5

x 5

1230

1030+ +

530= 27

30 = 910

÷ 3

÷ 3

Johnny has spent of his monthly allowance

so he must have of his monthly allowance left.

If of his monthly allowance is £6

then his monthly allowance must be £60

910

110

110

Page 36: © T Madas. + = + + Now the denominators are different x2x2 x2x2 x2x2 x2x2

© T Madas