0580 MATHEMATICS - Max Papers | Ultimate resource …maxpapers.com/wp-content/uploads/2012/11/0580_w14_ms_all.pdfMARK SCHEME for the October/November 2014 series 0580 MATHEMATICS 0580/11

® IGCSE is the registered trademark of Cambridge International Examinations.

CAMBRIDGE INTERNATIONAL EXAMINATIONS

Cambridge International General Certificate of Secondary Education

MARK SCHEME for the October/November 2014 series

0580 MATHEMATICS

0580/11 Paper 1 (Core), maximum raw mark 56

This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2014 series for most Cambridge IGCSE

®, Cambridge International A and AS Level components and some

Cambridge O Level components.

Page 2 Mark Scheme Syllabus Paper

Cambridge IGCSE – October/November 2014 0580 11

© Cambridge International Examinations 2014

Abbreviations

cao correct answer only dep dependent FT follow through after error isw ignore subsequent working oe or equivalent SC Special Case nfww not from wrong working soi seen or implied

Qu. Answers Mark Part Marks

1

− 4

7

1

2 (a)

(b)

15.1 cao 20 cao

1

1

3 (a)

(b)

E B A cao Z cao

1

1

4 113 2 M1 for 360 – (98 + 90 + 105) or better

5 137 2 M1 for attempt at ordering to at least 7th term or 132 and 142 indicated

6 3 3.14 π 3.142 7

22

2

B1 for 3.141[5...] to 3.1416 and 3.1428 to 3.1429 or 3.143 seen or SC1 for 4 in correct order

7 12

3 and 12

2

12

5 cao

M1

A1

Equivalent denominators can be used, working must be shown.

8 ( )ywxw 324 −

Final answer

2 B1 for ( )wyxw 3242

−

or ( )ywxw 128 −

or ( )ywxw 642 −

9 651 to 652 2 M1 for π 166.32×× or better

10 (a)

(b)

–3 4

1

1FT

FT their numerical mode

11 4x – 7 Final answer

2 B1 for answer 4x + k or answer jx – 7 where 0≠j

or correct answer seen then spoilt




12 (a)

(b)

91 or 13 2, 7 and 13

1

2

B1 for correct products of primes method or correct factor tree or ladder or 2 correct and 0 wrong or 3 correct and 1 extra

13 (a)

(b)

280

6105×

1

2

B1 for 5 000 000 oe

or B1 for answer 610×k or k

105×

14 (a)

(b)

4 [days] [C=] 15 + 6d Final answer

2

1

M1 for ( ) 61539 ÷−

or 666615 ++++

15 9 [sides] 3 M2 for ( )140180360 −÷

or M1 for 140180 −

16 (a)

(b)

66 42

1

2FT

FT their (a) – 24, only if their (a) > 24 or B1 for either of these, may be on diagram, angle OAC = 24 or angle BAC = their (a)

17 [$] 942.41 3 M2 for 3035.1850× oe

or M1 for 035.1035.1850 ×× oe

or SC2 for answer of interest only

18 0.29 cao 3 M2 for 2378.12430 ×− or 302378.124 −×

or M1 for 2378.124×

19 Correct ruled net drawn 3 B1 for rectangles, even if incorrect or not joined, drawn one on each side of the given one and two triangles opposite sides and B1 for 2 correct ruled rectangles and B1 for 2 correct ruled equilateral triangles

20 [x =] 3, [y =] 0.5 3 M1 for correct method to eliminate one variable A1 for [x =] 3 A1 for [y =] 0.5 If zero scored, SC1 for correct substitution and evaluation to find the other variable




21 (a)

(b)

80

[ ]5

y± or

5

y

Final answer

2

2

M1 for ( )245 −× or 245× or better

M1 for correct first step

i.e. 2

5x

y= or xy 5=

or correct 2nd step after incorrect 1st step seen

22 (a)

(b)

18.4 [0]60.4 to [0]60.73

2

2

M1 for [PQ2 =] 22916 + or better

M1 for [ ]9

16...tan = or better

or [ ](a)their

16...sin = or better

or [ ](a)their

9...cos = or better

If zero scored, SC1 for answer [0]29.3 to [0]29.4





0580 MATHEMATICS








Abbreviations

cao correct answer only

dep dependent

FT follow through after error

isw ignore subsequent working

oe or equivalent

SC Special Case

nfww not from wrong working

soi seen or implied

Qu. Answer Mark Part marks

1 6 + 5 × (10 – 8) = 16 1 One pair of brackets only

2 20 1

3 8 1

4 (a) 5 and −3 or −5 and 3 or

1 and −15 or −1 and 15

1

(b) 60 1

5

729

2 B1 for 81 or 9

1 seen in the working or 0.111.....

or B1 for 36 in the working or on the answer line.

6 95.55 95.65 1, 1 If zero, SC1 for both correct but reversed

or 955.5 [mm] and 956.5 [mm] in correct place

7 (a) 3 6 15 1

(b) 2 3 5 cao 1

8 (a) 6.4 × 105 1

(b) [0].000782 1

9

5

83 −x

oe

2

B1 for 5y = 3x – 8 or −5y = 8 – 3x

If B0 SC1 for 5

83 +x

or 5

83 −− x

10 (a)

−

4

5

1

(b)

−

12

15

1FT

FT for 3 × their (a)

11 40.4% 42

17 37

15 0.41

2

B1 for 3 in correct order or

for 0.405..... , 0.404 and 0.4047.... or 0.4048




12 (a) 2k 1

(b) −1 2 B1 for −16 or −15 or 15 seen in the working.

13 (a) 700 2 M1 for 2800 × 0.325

(b) 0.28 1

14

6

7 oe

7

8

6

7×their oe

or3

4

3

11 cao

must see working

B1

M1

A1

Or M1 for 48

42

48

56÷ or equivalent division with

fractions with common denominators cancelled

15

[x =] 2 [y =] −5

3

M1 for correct method to eliminate one variable

A1 for x

A1 for y

If zero scored SC1 for correct substitution and

evaluation to find the other variable.

16 (a)

360

136oe

1

(b) 19 cao 3 B1 for 76

M1 for 90360

76×

their

17 (a) 4 points correctly plotted 2 B1 for 3 correct

(b) Correct ruled line of best fit 1

(c) Positive 1

18 (a) 9 cao 1

(b) 15 and −15 1, 1

(c) Any multiple of 18 1

(d) 16 1

19 (a)

(b)

(c)

[x =] 66 2 B1 for angle BED = 90° soi

[y =] 24 1

[z =] 48 2FT M1FT for angle ABC = 90° − their y




20 (a) 102 to 106 2 B1 for 5.1 to 5.3 seen

(b) Correct position of F with

correct arcs for angle bisector

5 B2 for Correct ruled angle bisector of A with correct

arcs

or B1 for correct bisector with no/wrong arcs

and

B2 for Arc centre C, radius 8 cm

or B1 for arc centre C with incorrect radius

or correct conversion to 8 cm

and

B1 for marking position of F on their bisector and

8 cm from C or their arc centre C





0580 MATHEMATICS








Abbreviations


dep dependent



oe or equivalent

SC Special Case


soi seen or implied


1 100

13 oe

1

2 (a)

(b)

304 620

305 000

1

1FT

3 (a) 2 1

(b)

1

4 9.61 2 B1 for 9.609[1…]

or for their answer seen rounded to 2 d.p.

5 (a)

(b)

5

0.75 oe

1

1

6 (a)

(b)

23.3

–15.5

1

1

7 (a)

(b)

14

1296

1

1

8 (a)

(b)

4

2

−

18

9

1

1

9 15

1012 − or

15

10

15

12− oe

15

2 oe

M1

A1

Answer must be a fraction




10 6

1+y oe

2 B1 for xy 61=+ or 6

1

6−= x

y

If B0 SC1 for 6

1−y or 1

6+

y

11 6.06.07.034.023 2 M1 for decimal conversion: 0.7[7…] or

0.8 for 6.0 and 0.36 for 0.62 and 0.343

for 0.73

or B1 for three in the correct order

12 8104.2 × 2 B1 for 240 000 000 oe

or B1 for 8

10×k or k

104.2 ×

13 30 2 M1 for 36090432 =+++ xxx oe

14 48 2 M1 for 52 ÷ 65 [× 60] oe implied by 0.8

15 (a)

(b)

1440

1700

2

1

M1 for 18 × 10 × 8

16 (a)

(b)

kj −6

( )25 +p

2

1

B1 for akj ±6 or kbj − (a and b ≠ 0)

17 (a)

(b)

(c)

12

60

Irrational number between 1 and 2

1

1

1

18 9.5 or

2

19

3 M2 for ( ) 5382 −×=x or better oe

or M1 for 3852 ×=+x or better

19 (a)

(b)

(c) (i)

(ii)

16 [kg]

Positive

Ruled line of best fit

Correct reading from ruled line

1

1

1

1FT




20 (a)

(b)

(c)

Complete circle centre E radius 3 cm

Correct ruled bisector with two pairs of

correct arcs

1

2

1

B1 for correct bisector with no/wrong

arcs

dep on attempt at bisector of C and

enclosed region

21 (a)

(b)

58

9.43 to 9.44

2

2

B1 for ACB = 90o soi as angle at C or

M1 for 5

8tan

M1 for [ ] 22258 +=AB

or AB

532sin = or

AB

832cos = oe

22 (a)

(b)

(c)

Trapezium

55o

21.4 or 19.55 to 23.37 nfww

1

1

3

B1 for [AB =] 7.2, [DC =] 4.7, and

[height =] 3.6 seen and

M1 for ( )2.77.46.35.0 +×× theirtheir





0580 MATHEMATICS

0580/21 Paper 2 (Extended), maximum raw mark 70







Abbreviations



1 8.1722 cao 2 B1 for 8.17 or 8.172 or 8.1721 or 8.17215…

2 3 3.14 π 3.142 7

22

2

B1 for 3.141[5...] to 3.1416 and 3.1428 to 3.1429 or 3.143 seen or SC1 for 4 in correct order

3 (a)

(b)

E B A cao Z cao

1

1

4 (a)

(b)

–3 4

1

1FT

FT their numerical mode

5 12

3 and 12

2

12

5 cao

M1

A1

Equivalent denominators can be used, working must be shown.

6 (a)

(b)

15.1 cao

20 cao

1

1

7

2.5[0] or 2.501… nfww

3 M2 for ( )3100

611.2 +× oe

or M1 for ( )n100

611.2 +× oe where 2≥n

or for figs ( )3100

6121 +× oe

8 0.29 cao 3 M2 for ( )2378.12430 ×− or

( ) 302378.124 −×

or M1 for 2378.124×

9 (a)

(b)

280

5 × 106

1

2

B1 for 5 000 000 oe

or B1 for answer 610×k or k

105×




10 3.75 oe 3 M2 for xx 3753 −=× oe

or M1 for ( ) xx 753 =+ or xx3

75 =+

or 3

751 =+

x or better

11 (a)

(b)

x6

3

2x

1

2

B1 for answer kx2 or 3

kx or

3

1

12 5

5

−

nfww

3

M1 for correctly eliminating one variable A1 for x = 5

A1 for y = −5 If zero scored SC1 for correct substitution and evaluation to find the other variable

13

[±] 8 nfww

3 M1 for 5+= xky

A1 for k = [±] 2 or

M2 for 51151

4

+

=

+−

y oe

14

82

164

3 M2 for

246

4812 and

164

328

or M1 for

246

4812 or for

164

328

15 (a) (i)

(ii)

(b)

2

2

1

B2 for correct ruled bisector with correct arcs or B1 for correct bisector with no/incorrect arcs B2 for correct ruled bisector with correct arcs or B1 for correct bisector with no/incorrect arcs correct shading

16 142 or 142.0… 5 B1 for CBD = 30

M2 for [ ]8

sin6sin

theirBD

×

= oe

or M1 for )30sin(

8

sin

6

theirD= oe

A1 for [D =] 22 or 22.0 or 22.02… B1FT for 90 + (their30 + their22) evaluated correctly for their final answer or for 360 – 90 – theirBCD evaluated correctly for their final answer




17

890 or 890.1 to 890.2…

5 M4 for 85π5π3

4

2

1 23 ××+

×××

or M3 for

××× 35π

3

4

2

1 and 85π

2××

or M2 for

××× 35π

3

4

2

1 or 85π

2××

or M1 for 35π

3

4××

18 (a)

8.02.06.0 in correct places

2

B1 for 0.6 in correct place B1 for 0.2 and 0.8 in correct places

(b) 0.52 oe nfww 3 M2FT for 1 – (their 0.6 × their 0.8) oe or M1FT for a correct product from their tree in (a)

19 (a)

(b)

(c) (i) (ii)

CBA and BDA are equilateral oe

67[.0] or 67.02 to 67.03

39.3 or 39.28 to 39.33 78.6 or 78.7 or 78.56 to 78.66

1

2

3

1FT

M1 for 2

360

120 8π ×× oe

M2FT for ( ) 120sin82

2

1××−btheir oe

or M1 for 120sin82

2

1×× oe

FT 2 × their(c)(i) correctly evaluated

20 (a)

(b)

(c)

0.4 or 5

2

–0.8 or 5

4−

63 −x or ( )23 −x nfww

2

2

3

B1 for [f(2) =] 4

or M1 for ( ) 123

2

+−x

or better

M1 for ( )1102 += x or better

M2 for ( ) ( )( )223223 −+−− xx

or M1 for ( )[ ] ( ) 2232f −= xx or

( )[ ] ( ) 2232f −+=+ xx





0580 MATHEMATICS





1

2

3

4

5

6

7

8

P

Ab

cao

dep

FT

isw

oe

SC

nfw

soi

1

2

3

4

5

6

7

8

Pag

bbr

o

p

T

w

C

ww

i

Qu

(a

(b

ge

rev

w

u.

a)

b)

2

viat

c

d

fo

ig

o

S

n

s

tion

corr

dep

follo

gno

or e

Spe

not

een

ns

rect

end

ow

ore

equ

ecia

fro

n or

6 +

20

8

v3 –

95

70

0.2

6

7

the

3

4

mu

ξ

t an

den

w thr

su

iva

al C

om

r im

+ 5

– p

.5

0

28

oe

eir

or

ust

ξ

ξ

nsw

nt

rou

ubse

alen

Case

wr

mpl

× (

p

9

e

6

7×

1

see

A

C

wer

ugh

equ

nt

e

rong

lied

(10

96.

7

8×

3

1

e w

A

Cam

r on

h af

uen

g w

d

0 –

5

oe

cao

work

mb

nly

fter

nt w

wor

8)

in

e

o

kin

brid

r err

work

rkin

An

= 1

cor

ng

dge

©

ror

kin

ng

nsw

16

rrec

B

e IG

Ca

r

ng

wer

ct p

B

B

GC

amb

rs

plac

M

CSE

brid

ces

Mar

E –

dge

s ca

k S

– O

e In

ao

Sch

Oct

nter

hem

ob

rnat

me

ber/

tion

e

/No

nal

M

1

1

1

1

1

2

2

2

1

B

M

A

ove

Ex

Ma

B1

M1

A1

em

xam

ark

mbe

mina

k

er 2

atio

On

M

B1

an

M

Or

wi

20

ons

ne p

1 fo

1 fo

sw

1 fo

r M

ith

14

s 20

pair

for v

or 9

ers

for 2

M1 f

fra

014

r o

v3 =

95.

s re

280

for

ctio

4

f br

= p

.5 o

ver

00

48

56

ons

rac

p +

or 9

rsed

× 0

8

6÷

s w

Pa

cket

r

96.5

d

0.32

4

4÷

with

S

art

ts o

5 in

25

48

42

h co

Syl

0

M

only

n co

or

omm

llab

058

ark

y

orr

equ

mo

bu

80

ks

rect

uiv

n d

s

t pl

vale

den

P

ace

ent

om

Pa

2

e or

div

mina

pe

22

r fo

visi

ato

er

or

ion

r

n




9

9.13 or 9.127 to 9.1271

3 M2 for 3440

1000[1.31] oe

or 3

1000

440[0.761] oe

Or M1 for 440

1000 [2.27] oe

or 1000

440 [0.44] oe

or 31000

440

figs

figs or 3

440

1000

figs

figs

10 97.2[0] 3 M1 for C = kr²

A1 for k = 30

or M2 for 22

8.16.2

8.202 c

= oe

11 (a)

−

−

388

46

2

M1 for a 2 by 2 matrix with two correct

elements

SC1 for

−

−

2818

1416

(b) 14 1

12

3

SC1 for

13

13.5 or 13.45[..]

3 M2 for 110sin

852×

or M1 for ½ × a2 × sin 110 = 85

or 110sin

852×oe [180.9..]

14 (a)

2.47 or 2.474 to 2.4744

2 M1 for 2

25.2360

56××π oe

(b) 0.742 or 0.7422 to 0.74232 1FT FT their (a) × 0.3[0] correctly evaluated.

R 2

2

1 1

2

0

1 2




15 (a) 2 × 3 × 3 × 5 2 B1 for 2, 3, [3] and 5 identified as only

prime factors

or M1 for partial prime factorisation

6 × 3 × 5 or 2 × 9 × 5 or 3 × 3 × 10

or 2 × 3 × 15

(b) 630 2 M1 for 2 × 32 × 5 × 7 oe

or for listing multiples of 90 and 105 at least

up to 630

16 (a) 108

Angle at centre is twice angle at

circumference oe

1

1

(b) (i) 3

4− oe

1

(ii) −1 1

17

[0.]08

4 M3 for 100

22200200

100

21200

2

××−−

+× oe

or M1 for 2

100

21200

+×

and M1 for 100

22200 ××

[+200]

18 (a) 56 2 B1 for 16 soi

or M1 for 72 – their 16

(b) (i) 63 or 63 to 63.5 1

(ii) 22 or 21.6 to 23 nfww 2 B1 for 49.8 to 50.2 seen

or 71.8 to 72.8

19 (a) (i) c – a 1

(ii) –3

1 a +

3

1c

3 M2 for –a + 3

1(c + 2a) oe

e.g. –a + c + 2a –3

2(c + 2a)

Or M1 for a correct route from A to X

(b) AC is a multiple of AX

and

they share a common point [A]

1

1

oe

oe




20 (a) 102 to 106 2 B1 for 5.1 to 5.3 seen

(b) Correct position of F with correct arcs for

angle bisector

5 B2 for Correct ruled angle bisector of A with

correct arcs

or B1 for correct bisector with no/wrong arcs

and

B2 for Arc centre C, radius 8 cm

or B1 for arc centre C with incorrect radius

or correct conversion to 8cm

and

B1 for marking position of F on their

bisector and 8cm from C or on their arc

centre C

21 (a) )2)(12(

7

+−

+

xx

x

Final answer

3

B1 for )12(1)2(3 −−+ xx seen or better

B1 for denominator (2x – 1)(x + 2) oe seen

SC2 for final answer )2)(12(

5

+−

+

xx

x

(b) 7

2

+x

x

Final answer

4

M1 for 4x(x – 4) or partial

factorisation of numerator

and M2 for [2](x + 7)(x – 4) oe

or M1 for [2](x2 + 3x – 28)

or [2](x + a)(x + b) where ab = –28 or

a + b = 3

SC3 for answer 142

4

+x

x

oe





0580 MATHEMATICS








Abbreviations



1 2870 2 M1 for 350 × 8.2

2 6.06.07.034.023

2 M1 for decimal conversion: 0.7 [7…] or 0.8 for 6.0 and 0.36 for 0.62 and 0.343 for 0.73 or B1 for three in the correct order

3 8

104.2 ×

2

B1 for 240 000 000 oe or B1 for 8

10×k or k104.2 ×

4 30 2 M1 for 2x + 3x + 4x + 90 = 360 oe

5 48 2 M1 for 52 ÷ 65 [× 60] oe implied by 0.8

6 9.5 or 2

19

3

M2 for 2x = (8 × 3) – 5 or better oe or M1 for 2x + 5 = 8 × 3 or better

7

160

3 M2 for 18

360180 − or

( )18

218180 −×

oe

or M1 for 180 × (18 – 2) or 18

360

8 8 + (y – 2)2 oe final answer 3 M1 for y – 2 = √(x – 8) M1 for squaring both sides completed correctly

M1 for adding their 8 completed correctly on answer line

9 4 3 M2 for 6(3 + 5) = y(7 + 5) oe or

M1 for 5+

=

x

ky oe

A1 for k = 48

10

13891.5[0]

3 M2 for 3

100

5112000

+× oe

or M1 for n

+×100

5112000 oe 2>n




11 (a)

(b)

608 400 cao 2n2(n + 1)2 oe

2

1

M1 for ( )2213939

4

1+××

12 (a)

(b)

(c)

Complete circle centre E radius 3cm Correct ruled bisector with two pairs of correct arcs

1

2

1

B1 for correct bisector with no/wrong arcs dep on attempt at bisector of C and enclosed region

13 x

xx

6

918162

++final answer

4

M2 for 9 [+] 4x2 [+] 18x [+] 12x2 or better or M1 for 2 of these and M1FT for adding their four ‘numerators’ together correctly and B1 for denominator 6x to a maximum of 3 marks

14 (a)

(b)

ab2

1

2

1− oe

ba4

3

4

1+ oe

2

2

M1 for 2

1 ( AO + OB ) oe or correct unsimplified

route e.g. AO + OB + BP

or –a + b + 2

1 BA = –a + b + 2

1 (a – b)

M1 for OA + AQ oe or correct unsimplified route

15 (a)

(b)

81219

21981

2

2FT

B1 for any two correct

B2FT for a correct ft from (a) or B1FT for any two correct or for any correct two ft from (a)

16 (a)

(b)

(c)

(d)

64 4x + 1 oe

4

13−x

oe final answer

3 nfww

2

2

1

1

B1 for [f(1) =] 4 or M1 for ((x – 3)2)3 or better

M1 for 4

1−=y

x or 4y = x – 1




17 (a)

(b)

(c)

3.08 to 3.22 nfww

200

16oe

18.5 26 3

2

2

2

B1 for 502.5 to 502.62 or 505.7 to 505.8

B1 for 16 soi

or M1 for 200

16their

B1 for 18.5 and 26 B1 for 3

18 (a)

(b)

3 303 to 304

4

3

B3 for 3.536 to 3.54 as an answer or

M2 for 156π3

12000

2××÷

or M1 for 156π3

1 2××

and SC1 for truncating their 3.54 to a whole number

M2 for 2000 – their 3 × their volume or M1 for their 3 × their volume

19 (a)

(b)

(c)

rotation 90 clockwise [about] origin oe

01

10

Triangle at (3, 3), (6, 3) and (3, 5)

3

2

2

B1 for each

M1 for any one column or row correct

M1 for any two vertices correct or correct answer translated horizontally





0580 MATHEMATICS

0580/31 Paper 2 – Core, maximum raw mark 104







Abbreviations



1 (a) (i)

(ii)

(iii)

(b) (i)

(ii)

(iii)

540 ÷ 9 their 60 × (9 + 7 + 4 + 5) 1500 ÷ 1000 300 210 2.25

52.6[0] 46.1

M1

M1FT

A1

2

2FT

1

2

3FT

Alternative method M1 540 ÷ 1000 M1FT their 0.54 ÷ 9 A1 0.06 × (9 + 7 + 4 + 5) If 0 scored SC1 for 0.54 + 0.42 + 0.24 + 0.3

M1 for 5 ÷ (9 + 7 + 4 + 5) × 1500 or (540/9) × 5 or 60 × 5 M1 for 70 ÷ 100 × their (a)(ii) oe

B1 for 14 or (7/8) × 16 × 3.4[0]

M2 for (their (b)(ii) – 36) ÷ 36 × 100 or M1 for their (b)(ii) – 36 M2 for their (b)(ii) ÷ 36 × 100 – 100

M1 for their (b)(ii) ÷ 36 [× 100]

2 (a) (i)

(ii)

(b)

(c) (i)

(ii)

Trapezium

16 cm2

Rotation

90°[anti-clockwise] oe [centre] (–2, –8)

Correct reflection in y = 0

Translation 5 left and 7 up

1

2

1

B1

B1

B1

2

2

M1 for ½(2 + 6) × 4 oe Independent marks SC1 for correct reflection in x = 0

SC1 for one of 5 left or 7 up




(iii)

(d)

Correct Enlargement

Obtuse angle marked

2

1

SC1 for enlargement, SF ½, but incorrectly placed.

3 (a) (i)

(ii)

(iii)

(iv)

(v)

(b) (i)

(ii)

(iii)

4 points correctly plotted.

Correct continuous ruled line of best fit.

Distance on their line of best fit.

Negative

Faster the time, the longer the distance oe

11.7 or 11.69... NFWW

41.7 or 41.66 to 41.67

2.45

2

1

1FT

1

1

2

2

1

B1 for 1 correct Dependent on at least 8 points on graph FT their single straight line in part (ii).

M1 for Attempt at ∑ f ÷ 12

B1 for 12

5 seen

4 (a)

(b)

(c) (i)

(ii)

(iii)

x + x + 180 = 480 2x = 300

1060 [cm]

16 500

2 805 000

44.9 or 44-88

M1

M1

2

2

1FT

2FT

M1 for 2 × 480 + 2 × (20 + 30) oe

M1 for 30 × 150 + 50 × 180 + 20 × 150 oe

FT their (c)(i) × 170

FT their (c)(ii) ÷ 100³ × 16

M1 for their (c)(ii) × 16




5 (a)

(b) (i)

(ii)

(iii)

(c)

(d)

(e) (i)

(ii)

(iii)

6 003 076

–0.375

–2.2

>

3945, 3955

1.667 cao

1

125

1

24x9

1

1

1

1FT

1, 1

2

1

1

2

FT their answers to (i) and (ii)

SC1 for both correct but reversed

B1 for 3

21 or better

B1 for 24xk or kx9

6 (a) (i)

(ii)

(iii)

(iv)

(b) (i)

(ii)

(iii)

4, 7, 4

7 points correctly plotted

Correct curve through the points

x = 0

2.7 to 2.9, –2.7 to –2.9

Points correctly plotted and a ruled line through points and beyond them.

[y =] –2x + 4

( –1.2 to –1.4, 6.4 to 6.6)

2

3FT

1

1

1, 1

2

3

1

B1 for 2 correct

B2 for 5 or 6 correct B1 for 3 or 4 correct

B1 for 1 correct plot. (even if line is not drawn)

B2 for –2x + j or B1 for kx + 4 k ≠ 0

or [gradient =] run

rise correct values

7 (a)

(b) (i)

(ii)

(iii)

106 to 110

Correct bisector of AB constructed with 2 pairs of arcs.

Correct bisector of angle ABC with arcs

T marked at intersection of their bisectors

1

2

2

1FT

B1 for correct bisector

B1 for correct bisector without arcs




(c)

(d)

(e)

24.4[km] to 26.0[km]

Circle, radius 7.5(±0.2)cm centre T.

No It is outside the circle. oe

2FT

2FT

1FT

FT their AT B1 for their AT correctly measured.

FT their intersection SC1 for circle centre T, incorrect radius.

FT their circle.

8 (a) (i)

(ii)

(iii)

(b)

(c) (i)

(ii)

Correct diagram with scale

10 to 12 cao

120

19 or 0.158[3....] or 15.8[3......]%

Probability must be between 0 and 1 oe

20

9 or 0.45 or 45%

0 oe

3

1

1

1

1

1

B1 scale correct. B1 for all widths the same

B1 for all 6 heights correct

9 (a) (i)

(ii)

(iii)

(iv)

(b) (i)

(ii)

18 23 28

Add 5 oe

5n – 2 oe

73

10 14

4n – 2 oe

1, 1, 1

1

2

1FT

1, 1

2

Allow one mark for each addition of 5 to the previous answer

B1 for 5n + j or kn – 2 k ≠ 0

FT their (a)(iii) if linear.

Allow 1 mark for addition of 4 on their value for 3rd diagram.

B1 for 4n + j or kn – 2 k ≠ 0





0580 MATHEMATICS








Abbreviations


Question. Answers Mark Part Marks

1 (a) 4 × 1000 × 1000 or 4 × 10002 1

(b) 0.95 × 4 000 000 oe 1

(c) (i) 3 ÷ 19 × 3 800 000 2 M1 for 3 ÷ (11 + 5 + 3) or 3 800 000 ÷ (11 + 5 + 3)

(ii) 2 200 000 1

(iii) 15 710 2FT M1FT for their 2 200 000 ÷ 140

(d) (i)

+−40

5

40

241

40

11or

k40

k 11 final answer

M2

A1

M1 for 40

5

40

24or or

5×8

5×1

8×5

8×3or

If zero scored,

SC3 for 1 – (0.6 + 0.125) = 0.275 = 1000

275 =

[40

11 or

k40

k 11]

or

SC2 for 1 – (0.6 + 0.125) = 0.275 = 1000

275

followed by incorrect fraction

SC1 for 40

11 or

k40

k 11 final answer

(ii) 165 000 1FT FT their (d)(i) × 600 000

(e) 281 216 cao 3 M2 for 250 000 × 1.043 oe or M1 for 250 000 × 1.042 oe If zero scored, SC1 for 31 216




2 (a) Octagon 1

(b) 135 3 M2 for 180 – (360 ÷ 8) or M2 for

8

180 ×)28( −

or M1 for (360 ÷ 8) or M1 for (8 – 2) × 180

(c) (i) 22 29 36 2 B1 for two terms in correct places or 2 terms with a difference of 7.

(ii) 7n + 1 oe 2 B1 for 7n + j or kn + 1 (k ≠ 0)

(iii) 71 1FT FT for their (c)(ii) if linear

(iv) 13 nfww 2 M1FT for their (c)(ii) = 92 or M1 for (92 – 1) ÷ 7 or 91 ÷ 7 or M1 for 7 × 13 + 1 = 92

3 (a) Reflection [in] AB Rotation 180o oe Midpoint of AB oe

1

1

1

1

1

(b) (i) Translation 2 left and 7 up 2 SC1 for one of 7 up or 2 left

(ii) Correct Enlargement 2 SC1 for enlargement scale factor 3 but incorrectly placed

(c) Correct line of symmetry 1FT FT is their (b)(ii)

4 (a) (i) Line (0700, 0) to (08 40, 310) Horizontal line 2 squares Line their (08 50, 310) to (09 40, 470)

1

1FT

1FT

Lines need not be ruled and could be curves with positive gradients throughout.

(ii) 2[h]40[min] 1

(iii) 176.25 2 M1FT for 470 ÷ their (a)(ii)

(b) (i) 2[h]21[min] 2 M1 for 470 ÷ 200 soi

(ii) Line from (07 45, 470) to (their 10 06, 0)

2FT B1 for (07 45, 470) correctly plotted or B1FT for (their 10 06, 0) correctly plotted

(c) 290 to 300 1FT (Correct or follow through) FT from intersection on their graph.




5 (a) (i) Trapezium 1

(ii) Pentagon 1

(b) (i) [BC =] 222052 − [= 48]

B2

B1 for 522 = BC2 + (70 – 50)2 or 522 = BC2 + 202

or BC2 = 522 – 202

(ii) 3936 or 3940 2 M1 for (70 + 12) × 48 oe

(c) (i) 220 1

(ii) 2880 2 M1 for 0.5(50 + 70) × 48 oe

(d) 108 3 B1 for [AE=] 24 M1 for 0.5 × their AE × 9

(e) 948 1FT FT their (b)(ii) – (their (c)(ii) + their (d))

6 (a) (i) –5 –8 5 2.5 2 B1 for 3 correct

(ii) 8 points correctly plotted Correct curve

B3FT

1

B2FT for 6 or 7 correct points

B1FT for 4 or 5 correct points

(iii) Ruled line y = 6 drawn 3.1 to 3.6

1

1

Independent marks

(b) (i) –5 –1 3 2 B1 for 2 correct

(ii) Ruled correct line 1

(iii)

2

1 oe

1

(c) 7.2 to 7.6 –5.2 to –5.6

1FT

1FT

7 (a) (i) 15.5 2 M1 Sum of the 10 items of data ÷ 10

(ii) 16 2 M1 for ordering at least first or last 6 items or for 14 and 18 indicated

(iii) 26 1

(b) (i) 6 correct bars 2 B1 for 4 or 5 correct bars or 6 correct heights

(ii) Aug[ust] 1

(iii)

12

4 oe

1




8 (a) (i) [0]63 to [0]67 1

(ii) 8 2 B1 for 6 ± 0.2 [cm] seen in working

(b) QR on bearing 123o to 127o 9.3 cm to 9.7 cm continuous ruled line

1

2FT

B1 for bearing of 123o to 127o

M1FT for 76 ÷ their (a)(ii) soi by calculation or distance on diagram

(c) (i) 297 – 270 or 90 – (360 – 297)

1

(ii)

7.6 cao nfww

3 M1 for cos27° = 5.8

PW or sin63° =

5.8

PW or

better A1 for 7.57(...) B1ind for correctly rounding their 7.57(...) to 2 sig figs if their 7.57(…) is to 3 sig figs or more

(d) Correct continuous perpendicular bisector of AB with two pairs of correct arcs

2 B1 for correct continuous bisector without arc or with incorrect arcs

9 (a) (i) 338.4[0] 3 M2 for 5 × 36 + 660 × 0.24 or better or M1 for 5 × 36 or 660 × 0.24 or better

(ii) 389.16 2FT M1FT for 1.15 × their (a)(i) oe

(b) (i) 60 1

(ii) 108 1FT 1.8 × their (b)(i)

(iii) 497.16 1FT FT their (a)(ii) + their (b)(ii)

(c)

31 nfww

2FT M1FT for 1001600

×

(b)(iii)their





0580 MATHEMATICS








Abbreviations



1 (a) (i) 4, 5, 3, 6, 2 2 B1 for 3 correct or for fully correct tally or for 4 5 6 3 2 in tally column

(ii) Correct bar chart 3FT B1 for linear vertical scale to at least 6 B2 for all bars correct height and equal width bars Or B1 for unequal widths or at least four bars correct height and equal width

(b) 24

14 oe or 0.583[3...] or 58.3[3...]%

1

(c) No, 6 of each but different nos of boys and girls questioned oe

1

(d) (i) 2 2 M1 for 12th/13th value used

(ii) 2.28 3 M1 for [0 × 4] + 1 × 6 + 2 × 5 + 3 × 3 + 4 × 5 + [5 × 0] + 6 × 2 M1 dep for their 57 ÷ 25

2 (a) 249.75 cao 1

(b) 1080 × 0.8 [= 864] 1 Or 1080 – 1080 × 0.2

(c) (i) 230.4[0] 2 M1 for 864 ÷ (9 + 4 + 2)

(ii) 5

3 cao

2 B1 for 15

9oe

(d) (i) 488.75 2 M1 for 425 (1 + 0.15) oe

(ii) 19.15 2FT M1 for their (d)(i) × 0.52 [= 254.15]

(e) (i) 12.5 1

(ii) 172.93 3 M2 for 1225 × 1.0453 [= 1397.93] Or M1 for 1225 × 1.045 × 1.045 seen




3 (a) 10 1

(b) Before, steeper gradient oe 1

(c) 11 20 1

(d) (i)

1 hour 48 minutes

2 M1 for 10

18 [× 60] oe

(ii) Correct ruled lines drawn 2 B1 line from (11 20, 18) to (12 10, 18) B1FT for line (their 12 10, 18) to (13 58, 0)

(e) (i) 10 57 1

(ii) 24 1

(f) Bearing 110° Length 3.25 cm

1

1

4 (a) (i) 85 1

(ii) 10 1FT FT 95 – their (i)

(iii) 320 1FT FT 330 – their (ii)

(iv) 95 1

(v) 95 1FT FT their (iv)

(vi) 55 1FT FT 150 – their (iv)

(vii) BCE and GCF or BCD and GCH or CED and CFH

1

(b) (i) 30° 2 M1 for 360 ÷ 12

(ii) 150° 1FT FT 180 – their (i)




5 (a) (i) –2 2 M1 for change in y / change in x for two correct points

(ii) –2x + 3 1FT FT their gradient

(b) (i) 6, 7, 6, –9 3 B2 for 3 correct Or B1 for 2 correct

(ii) 8 points correctly plotted Correct smooth curve

3FT

1

B2FT for 6 or 7 points correctly plotted B1FT for 4 or 5 points correctly plotted

(iii) –3.8 to –3.5 and 1.5 to 1.8 2FT B1FT for one correct

(c) (1.6 to 1,9, –0.7 to –0.2) and (–1.9 to –1.6, 6.2 to 6.7)

2FT FT intersection of line with their curve

B1 for one correct

6 (a) 2x – 3 1

(b) 5x – 4 2 M1FT for 2x – 3 + x + 2 + their (2x – 3) oe

(c) (i) 4x + 4 2 M1 for 2 × [3(x – 4) + 14 – x] oe

(ii) 8 2FT FT correct solution of their equation M1FT for their (5x – 4) = their (4x + 4)

(d) 12, 6 2FT B1FT for each

(e) 72 1FT FT their length × width

7 (a) 10 12 20 14 18 34

5 B4 for 5 correct B3 for 4 correct B2 for 3 correct B1 for 2 correct

(b) (i) 2n + 4 oe final answer 2 B1 for 2n + k or jn + 4 j ≠ 0

(ii) 4n + 2 oe final answer 2 B1 for 4n + k or jn + 2 j ≠ 0

(c) B [by] 15 [tables] 3 M1FT for their (2n + 4) = 66 or their (4n + 2) = 66 and A1FT for n = 31 or n = 16




8 (a) (i) [Triangular] prism 1

(ii) Correct net 3 B1 for 3 rectangles and two triangles, one on each side, even if incorrect sizes B1 for three correct ruled rectangles B1 for two correct ruled equilateral triangles

(iii) 109.86 cao 1

(iv) 115 cao 1

(b) (i) 70.7 or 70.68 to 70.695 3 M2 for π × 1.52 × 10 Or B1 for 1.5 seen Or SC2 for answer 283 or 282.74 to 282.78

(ii) 37.7 or 37.69 to 37.704 3 M2 for π × 3 × 4 Or M1 for π × 3

9 (a) (i) Line x = 1 drawn 1

(ii) Correct reflection 1FT FT reflection in their drawn line

(iii) Correct rotation 2 B1 for clockwise rotation 90° about origin or correct orientation incorrect position

(b) (i) Translation

−

−

4

3

B1

B1

Accept 3 left 4 down

(ii) Enlargement [scale factor] 2 [centre] (6, 0)

B1

B1

B1





0580 MATHEMATICS








Abbreviations


Qu Answers Mark Part Marks

1 (a) (i)

(ii)

(iii)

2

2

3

M1 for 72 ÷ (7 + 2 + 3) M1 for 13.5 ÷ 3 × (7 + 2 + 3) oe M2 for 8.4[0] ÷ 1.12 oe or M1 for 112[%] associated with [$]8.4[0] oe

(b) (i)

(ii)

(iii)

6 × 0.5 × 2 × 2 × sin60 oe 10.38 to 10.39[…] [= 10.4] 4.67 to 4.68 273

M2

A1

2

4

M1 for a correct relevant area inside the hexagon e.g. 0.5 × 2 × 2 sin60 oe Must see 10.38 to 10.39[…]

M1 for 10.4 × figs 45 [figs 467 to 468]

M1 for their (b)(ii) × 1250 ÷ 1000 A1 FT for their (b)(ii) × 1250 ÷ 1000 evaluated to at least 3 sf M1dep on previous M1 for their mass in tonnes (rounded up) × 45.5[0] if between 6 and 10 or for their mass in tonnes (rounded up) × 47[.00] if between 1 and 5 or for their mass in tonnes (rounded up) × 44[.00] if over 10





2 (a) [±] asv 22+ final answer

2

M1 for correct first step, i.e. u2 = v2 + 2as

(b) (i)

(ii)

64

4560=

+

+

xx

oe

60(x + 4) + 45x = 6x(x + 4) or better 60x + 240 + 45x = 6x2 + 24x oe 0 = 2x2 – 27x – 80 16 final answer

M2

M1

A1

3

B1 for either x

60 or

4

45

+x

seen

Dep on M2

[6x2 – 81x – 240 = 0] Dep on M3 and brackets expanded and with no errors or omissions throughout M2 for (x – 16)(2x + 5) [= 0] or M1 for partial factorisation e.g. x(2x + 5) – 16 (2x + 5) or SC1 for (x + a)(2x + b)[ = 0] where ab = –80 or 2a + b = –27

or B2 for 2.2

80.2.4)27(27 2−−−−+−− or

or

4

27

4

2740][2

++−

or B1 for 2.2

27 qor −+−−

or 80.2.4)27( 2−−− or

2

4

27

−x

(c) (i) 0.75 × 20 [=15] 1

(ii) 150 cao 4 M3 for 90 + T = 1800 × 2 ÷ 15 oe or T – 110 = (1800 – (90 × 15) – (20 × 15 ÷ 2)) × 2 ÷ 15 oe or t = (1800 – (90 × 15) – (20 × 15 ÷ 2)) × 2 ÷ 15 oe [t = 40] or M2 for ½ (90 + T) × 15 = 1800 oe

or ½ (T – 110) × 15 + 90 × 15 + ½ (20 × 15) = 1800 oe or 1800 – ½ × 20 × 15 – 90 × 15 oe [300 for area of ‘end’ triangle] or M1 for method for area of triangle or rectangle or trapezium soi





(d) 10 cao nfww 3 M2 for 22.5 ÷ 2.25 or M1 for 21.5 to 22.5 ÷ 2.25 to 2.75 or B1 for 22.5 or 2.25 seen

3 (a) Correct reflection (0, 1) (3, 1) (3, 3)

1

(b) Correct rotation (–5, 1) (–7, 1) (–5, 4)

2 SC1 for rotation of 90º anticlockwise about the wrong centre or 90º clockwise about (–4, 0) or for 3 correct points plotted but not joined

(c) (i)

(ii)

Enlargement [scale factor] 2 [centre] (–7, 7) 1 : 4 or 3 : 12 or ¼ : 1

3

2

B1 for each M1 for 1 : 22 oe, e.g. (3 × 2)/2 : (6 × 4)/2 or SC1 for 4 : 1 or 12 : 3 or 1 : ¼

(d)

10

04

2 B1 for

10

0k, k may be algebraic or numeric

but ≠ 0 or 1

or SC1 for

40

01

(e) (i)

(ii)

(iii)

Correct shear drawn (0, 1) (–3, –5) (–3, –3)

Shear y-axis or x = 0 invariant [factor] 2

− 12

01 oe

3

3

2

B2 for two correct points plotted or if not plotted correctly shown in working or

B1 for

−

3

3

12

01 or

−

1

3

12

01 or

1

0

12

01 or

better B1 for each

B1 for [determinant =] 1 shown or stated

or k

− 12

01 soi, k ≠ 0





4 (a) (i)

(ii)

11 – x final answer 6x2 – xy – 12y2 final answer

2

3

M1 for 8x – 4 – 9x + 15 or B1 for final answer 11 – kx or k – x

M2 for 6x2 + 8xy – 9xy – 12y2 [= 0] or for final answer with one error in a coefficient (includes sign) but otherwise correct or M1 for any two of 6x2, 8xy, –9xy, –12y2

(b)

x(x2 – 5) final answer

1 Condone x(x – 5 ) (x + 5 ) as final answer

(c) x [ 4 or 4 Y x final answer nfww

3 B2 for 4 with no/incorrect inequality or equals sign as answer or M2 for 8x + 4 Y 15x – 24 or better or M1 for 4(2x + 1) Y 3(5x – 8)

(d) (i)

(ii)

(iii)

p = 4.5 oe q = 8.25 oe –8.25 oe x = 4.5 oe

3

1FT

1FT

B2 for one correct answer or for (x – 4.5)2 – 8.25 oe seen or M1 for (x – 4.5)2 oe seen or x2 – px – px + p2 seen and M1 for p2 – q = 12 or 2p = 9

FT – their q

FT x = their p

5 (a) –2, 5.5 2 B1 for each value

(b) Correct curve 5 B5 for correct curve over full domain or B3FT for 9 or 10 points or B2FT for 7 or 8 points or B1FT for 5 or 6 points Point must touch line if exact or be in correct square if not exact (including boundaries) and

B1 independent for one branch on each side of the y-axis and not touching or crossing the y-axis SC4 for correct curve with branches joined

(c) –2.6 Y x Y –2.4 0.6 Y x Y 0.7 1.8 Y x Y 1.9

3 B1 for each value

If B0 then SC1 for y = 5 used

−3 −2 −1 1 2 3

−5

5

10

x

y





(d) y = x + 5 ruled correctly and –2.2 Y x Y –2.0 0.5 Y x Y 0.6 2.4 Y x Y 2.6

4 B1 for y = x + 5 ruled correctly

B1indep for each value

6 (a) 2000 or 1998.75 or 1998.8 or 1999 nfww

4 M1 for midpoints soi (condone 1 error or omission) (500, 1250, 1750, 2250, 3000) and

M1 for use of ∑ fx with x in correct interval

including both boundaries (condone 1 further error or omission) (5000, 37500, 96250, 162000, 99000) and

M1 (dep on 2nd M1) for 200÷∑ fx

(b) (i)

(ii)

(iii)

10, 40, 95, 167, 200 Correct curve or ruled polygon 68 to 80

2

3

2

B1 for 2 correct B1FT their (b)(i) for 5 correct heights within 1mm vertically and B1 for 5 points at upper ends of intervals on correct vertical line and B1FT (dep on at least B1) for increasing curve or polygon through 5 points After 0 scored, SC1FT for 4 correct points plotted

M1 for 120 to 132 seen

(c) 50

21 oe

4 M3 for 5

3

10

1

5

2

10

9×+× oe or better

or

M2 for 5

2

10

9× or

5

3

10

1× or

50

18 oe or

50

3 oe

or

M1 for sight of 10

1 and

5

2





7 (a) (i) Any two of with conclusion

Angle ACD = angle ABD Angle CAB = angle CDB Angle AXC = angle DXB AND

‘triangles have equal angles’ oe OR

All three of without

conclusion

Angle ACD = angle ABD Angle CAB = angle CDB Angle AXC = angle DXB

2 B1 for two pairs without a conclusion e.g. similar and AA or AAA

(ii)

(a) 10

2 M1 for 5.12

DX =

4

2.3 oe

(b) 42 + 3.22 – 2 × 4 × 3.2cos110

34.9 to 35 5.92 or 5.915 to 5.916

M2

A1

B1

or M1 for implicit version

Implied by answer 5.92 or 5.915 to 5.916 after M2

(c) 58.7 or 58.73[…] 2FT FT for ½ × 12.5 × their 10 × sin110 oe correctly evaluated to 3 or more sig figs M1 for ½ × 12.5 × their 10 × sin110 oe or ½ × 4 × 3.2 × sin110 × (12.5/4)2 After 0 scored and 15.6... in (a)(ii)(a), allow SC1 for ½ × 4 × 3.2 × sin110 × (12.5/3.2)2

(b) 7.62 or 7.623 to 7.624 5 B4 for 37.6[2…] or 37.63 or

M2 for [AB =] 31tan

30 or 30 × tan59 oe

or M1 for tan31 = AB

30 or tan59 =

30

AB oe

And

M2 for [BD =] their AB × tan37 oe or

M1 for tan37 = ABtheir

BD oe





8 (a)

2c + 3b

2 M1 for OQ recognised as pos vector.

(b) (i)

(ii)

3c – 6a or 3(c – 2a) 2c – 4a or 2(c – 2a)

1

2

M1 for any valid route from P to Q

e.g. ( ) OQtheiraab +−−− 623

or OQAOPAPQ ++=

or BQPBPQ +=

(c) PQ = 3

2AC oe

and PQ is parallel to AC

2FT

STRICT FT dep on PQ = ACk from (b)(i) and (b)(ii) B1FT for each statement

After 0 scored and PQ = ACk in (b)(i) and (ii), allow SC1FT for correct statement, e.g. PQ is not parallel to AC

9 (a) 36, 9, 45 8n + 4 oe (n – 1)2 oe

2

2

2

B1 for two correct values M1 for 8n + k, for any k M1 for a quadratic expression of form n2 [+ an + b ] oe

(b) 19 2 M1 for (n + 1)(n + 5) = 480 or better or 20 × 24 seen

(c) (i) 3

1+ p + q = 12 and no errors

seen

1 Accept p + q = 12 –3

1 after [ ] [ ] [ ]111

3

1 23qp ++ shown

(ii) 3

1× 8 + 4p + 2q = 12 + 21

2

M1 for 12 + 21 seen or 33 seen

(iii) [p =] 2

7 oe

[q =] 6

49 oe

3

M1 for correct multiplication and subtraction or substitution using the correct given equations

B1 for [p =] 2

7 or [q =]

6

49

After 0 scored, SC1 for 2 values satisfying one of the original correct given equations





0580 MATHEMATICS

0580/42 Paper 4 – Extended, maximum raw mark 130







Abbreviations


Qu. Answer Mark Part marks

1 (a) (i) 49.5[0] 3 M2 for 16.5[0] ÷ 5 × (5 + 3 + 7) or M1 for 16.5[0] ÷ 5

(ii) 66 1FT FT their (a)(i) ÷ 75 × 100 to 3 sf or better

(b) 2 hours 39 mins 45 secs 3 B2 for 159.75 oe, e.g. 2.6625 [h] 9585 [s] or M1 for 3 hrs 33 mins oe / (2 + 9 + 1) oe

(c) 18.75 final answer 3 M2 for 16.5[0] ÷ 0.88 oe or M1 for 16.5[0] associated with 88[%]

2 (a) x > 0.5 oe final answer nfww 3 B2 nfww for 0.5 with no/incorrect inequality or equals sign as answer or M2 for 7x + 15x > 6 + 5 or better or –6 – 5 > –7x – 15x or better or M1 for 6 – 15x seen

(b) (i) (p – 2)(q + 4) final answer 2 M1 for q(p – 2) + 4(p – 2) or p(q + 4) – 2(q + 4)

(ii) (3p – 5)(3p + 5) final answer 1

(c) (5x – 9) (x + 2)

5

9 oe and –2 final answer

M2

B1

M1 partial factorisation, e.g. x(5x – 9) + 2(5x – 9) or SC1 for (5x + a)(x + b) where ab = –18 or a + 5b = 1




3 (a) 35 < t Y 40 1

(b) 22.5, 27.5, 32.5, 37.5, 42.5, 47.5 (2 × 22.5 + 6 × 27.5 + 7 × 32.5 + 19 × 37.5 + 9 × 42.5 + 7 × 47.5)

÷ 50 or their ∑ f

37.3

M1

M1

M1dep

A1

At least 4 correct mid-values soi

∑ fx where x is in the correct interval allow one

further slip [45 + 165 + 227.5 + 712.5 + 382.5 + 332.5 = 1865]

Dependent on second method

SC2 for correct answer with no working

(c) (i) 15, 19, 16 1

(ii) rectangular bars of height 1, 3.8 and 1.6

correct widths of 15, 5,10 and no gaps

B2FT

B1

FT their (c)(i), on correct boundary lines B1FT for 2 correct heights If 0 scored for heights then SC1 for 3 correct frequency densities soi

4 (a) Enlargement [SF] – ½ oe [centre] (2, 5)

3 B1 for each

(b) (i) Image at (–2, 6), (–8, 3), (–4, 3) 2 SC1 for reflection in any vertical line or for 3 correct points not joined

(ii) Image at (3, –2), (3, 2), (6, 4) 2 SC1 for rotation 90° [anti clockwise] around origin at (–3, 2) (–3, –2) (–6, –4) or for 3 correct points not joined

(iii)

Image at (–5, 1), (–3, –2), (1, –2)

2 SC1 for translation by

−

k

1or

− 5

k

or for 3 correct points not joined

(c) (i)

− 01

10

2

B1 for a correct row or column

(ii) Rotation, 90° [anticlockwise] oe origin oe

2 B1 for two elements correct




5 (a) (i) 8 1

(ii)

4

2 M1 for [g(17) =] 14

7 or 2

2

3

7

−x+ 7

− 3

7

x

(b) 4 or – 4 3 M2 for x2 = 16 or x2– 16 = 0 or M1 for 7 = (x – 3)(x + 3) or better

(c) 2x² + 7x – 11 [= 0] soi

)2(2

)11)(2(4)7(7 2 −−±−

–4.68, 1.18 final answers

B1

B1FT

B1FT

B1B1

FT 2x² + 7x ± their k [k ≠ 0] oe

B1FT for )11)(2(47 2−− or better or

2

4

7

+x

oe

If in form r

qp + or

r

qp −,

B1FT for 7− and 2(2) or better or

16

137

4

7−+− or oe

If B0, SC1 for answers –4.7 and 1.2 or –4.676... and 1.176.. seen or for –4.68 and 1.18 seen or for answer 4.68 and –1.18

(d) 5

2+x or

5

2

5+

x

2

M1 for correct first step or better, e.g. 25 += xy

or 5

2+=y

x or x = 5y – 2 or y + 2 = 5x or

5

2

5−= x

y

(e) – 2 1




6 (a) –3, 7.375, 8.875 1, 1, 1 Accept 7.4 or 7.37 or 7.38 for 7.375 and 8.9 or 8.87 or 8.88 for 8.875

(b) Correct curve 4 B3FT for 8 or 9 correct plots

B2FT for 6 or 7 correct plots B1FT for 4 or 5 correct plots Point must touch line if exact or be in correct square if not exact (including boundaries)

(c) (i) Any integer less than 7 or greater than 10

1

(ii) 7, 8 or 9 1

(d) y = 15x + 2 ruled and fit for purpose –1.45 to –1.35 and 0.4 to 0.5

B2

B2

B1 for short line but correct or freehand full length correct line or for ruled line through (0, 2) (but not y = 2) or for ruled line with gradient 15 (acc ±1 mm vertically for 1 horizontal unit)

B1 for each

(e) Tangent ruled at x = 1.5 7 to 12

B1

2

No daylight at point of contact. Consider point of contact as midpoint between two vertices of daylight, the midpoint must be between x = 1.4 and 1.6

Dep on B1 or close attempt at tangent at x = 1.5 M1 for y – step/x – step for their tangent

7 (a) (i) 120 × 55 × 75 [= 495000] ÷ 1000 [= 495] or 495[l] × 1000 = 495000[ml]

M1

M1

(b) (i) 11 2 M1 for 495000 ÷ 750 [÷ 60] oe [660] After 0 scored, SC1 for answer figs 11

(ii)

37.5 or 37.50 to 37.51

3 M2 for π112

495figsoe

or M1 for [112r

2 = ]π

495figsor

[112

495]

2 figsr =π or better




(c) 15 4 B3 for answer 60

or M3 for 75 – )12055(145 222+− oe

M2 for )12055(145 222+− oe

or M1 for 2212055 +

(d) 24.4[4..] to 24.45 3 M2 for cos–1 ( 2212055 + /145) oe, e.g.

or sin 1− (75 – their (c))/145

or tan 1− ((75 – their (c))/ 2212055 + )

or M1 for cos = 2212055 + /145 oe

or sin = (75 – their (c))/145

or tan = (75 – their (c))/ 2212055 +

8 (a) Angle LPQ = 32 soi 582 + 742 – 2 × 58 × 74 cos their P 39.50[1...]

B1

M2

A2

M1 for correct implicit cos rule

A1 for 1560.3 to 1560.4 or 1560

(b) sin PQL = 5.39

sin58 Ptheir oe

51.1 or 51.08 to 51.09

M2

B1

M1 for 5.39

)sin(

58

sin PtheirPQL= oe

(c) (i) 322 2 M1 for 180 + 142 oe

(ii) [0]13[.1] or 13.08 to 13.09 1FT FT their (b) – 38

(d) 17.8 or 17.77 to 17.78 3 M1 for 74 ÷ 2.25 oe soi by 32.888… to 3 sf or better M1 for dist or speed ÷ 1.85

(e) 30.7 or 30.73 to 30.74… 3 M2 for 58 sin their P oe or 39.5 sin their (b)

or M1 for 58

x

= sin their P oe

or 5.39

x

= sin their (b)

9 (a) 28 45 17 21 45 66

1, 1

1

1

(b) (i) 4n – 3 oe 2 M1 for 4n + k

(ii) 237 1

(iii) 50 2FT FT their (b)(i) = 200 solved and then answer truncated dep on linear expression of form an + k M1 for their 4n – 3 = 200 or their 4n – 3 Y 200




(c) p = 2 and q = –5 with some correct supporting working leading to the solutions

5 M2 for any 2 of p + q + 3 = 0 oe, 22 p + 2q + 3 = 1 oe, 32 p + 3q + 3 = 6 oe, 42 p + 4q + 3 = 15 oe , 52 p + 5q + 3 = their 28 oe, etc. or M1 for any one of these M1 indep for correctly eliminating p or q from pair of linear equations A1 for one correct value If 0 scored SC1 for 2 values that satisfy one of their original equations After M0, 2 correct answers SC1

(d) 2n2 – n or n(2n – 1) 2 B1 for answer 2n2 + k[n] or M1 for their quadratic from (c) + their linear from (b)(i)

10 (a) (i) 36

1 final answer

2 M1 for 6

1

6

1×

(ii) 12

1 final answer

3 M2 for

×6

1

6

13 oe

or M1 for identifying 3 correct pairs (4, 6), (6, 4) and (5, 5)

(b) 7 Refers to most combinations oe

1

1

Dependent on previous mark

(c) 1296

141 oe

432

47

5 M4 for

×+

×

−+

36

3

36

1

36

2

36

31

36

2oe

or M3 for 2 correct probabilities shown added from those above

or M1 for 36

2

36

31 ×

− seen oe

And M1 for 36

3

36

1× seen oe

or 6

1×

6

1 ×

6

1 ×

6

1oe alone or added to a

probability not of the form 36

n





0580 MATHEMATICS








Abbreviations


dep dependent



oe or equivalent

SC Special Case


soi seen or implied


1 (a) (i) 5.37[1...] 2 M1 for [AD 2 = ] 2.62 + 4.72 oe or better

(ii)

54.1 or 54.11 to 54.12

3 M2 for tan [BCD =] ( )6.21117

7.4

−−

oe

or

B1 for 3.4 seen

(iii)

65.8

2 M1 for 7.42

1711×

+ oe

(b) 263.2 or 263 3FT FT their (a)(iii) × 4 correctly evaluated

M2 for their (a)(iii) ×

2

7.4

4.9

oe

or

M1 for [scale factor =]

2

7.4

4.9

or

2

4.9

7.4

soi

2 (a) (i) 78

920× [=805] oe

1 726

2990× [= 805]

(ii)

30.8 or 30.76 to 30.77

2 M1 for ( )7811

8

++

[× 100]

(b) 1211 final answer 5 B4 for 13 926.5[0] [area A total sales]

or

B3 for 11 040 [area B] and 10 867.50 [area C] or

21 907.5 [area B + area C]

or

B2 for 11 040 [area B] or 10 867.50 [area C]

or

M1 for 736 [B tickets] and M1 for 483 [C tickets]

After 0 scored

SC2 for answer of 1196

or

SC1 for 13754 (A total sales)




(c)

37 720

3 M2 for 95.0

35834 oe

or

M1 for 35834 associated with 95[%]

3 (a) (i) 52

Angles in same segment

1

1dep

Accept same arc, same side of same chord

(ii) 104

Angle at centre is twice angle at

circumference

1

1

Accept double, 2 × but not middle, edge

(iii) 34

Angle between tangent and radius

= 90°

1

1

Accept right angle, perpendicular

(b) (i) 7.65 to 7.651 4 M2 for 8.92 + 72 – 2 × 8.9 × 7 × cos56

or

M1 for correct implicit formula

and

A1 for 58.5 to 58.6

(ii)

49.3 or 49.33 to 49.34…

3 M2 for [sinBEC =] (b)(i)their

56sin7 oe

or

M1 for 7

sin56sin BEC

their=

(b)(i) oe

4 (a) (i) Ariven with comparable form for

both shown or difference between

the two fractions shown

1 Accept probabilities changed to decimals or

percentages (to 2sf or better)

(ii) 15

6 oe

2 M1 for 3

2

5

3×

(iii) 15

7 oe

3 M2 for 3

2

5

2

3

1

5

3×+× oe

3

1

5

21 ×−− (a)(ii)their

or

M1 for 3

1

5

3× or

3

2

5

2× seen

(b) (i) Completes tree diagram correctly 3 B2 for 5 values correct

or

B1 for 1 value correct

(ii) 350

126 oe

25

9

2 M1 for 10

7

7

6

5

3××




(iii) 350

344 oe

3 M2 for 10

3

7

1

5

21 theirtheirtheir ××− oe

or 10

7

7

1

5

2

7

6

5

2

5

3××+×+

M1 for 10

3

7

1

5

2theirtheirtheir ×× oe

or identifies the 7 routes

or attempt to add 7 probabilities with at least 5 correct

25

1

175

18

25

6

350

9

50

3

175

27

25

9++++++ oe

5 (a) (i)

−

04

40

1

(ii)

−

−

11

11

1

(iii)

−

−

10

01

2 B1 for three correct elements

(iv)

−

5

13

2 B1 for either correct in this form

(b)

10

21

3 M1 for understanding to find the inverse of Q

and M1 for det = 1 or for k

10

21 k≠0

Alternative

=

−

10

01

10

21

dc

ba

Leading to a – 2c = 1 and c = 0 then a = 1

and b – 2d = 1 and d = 1 then b = 2

M2 all four equations, M1 for a pair of correct

equations

6 (a) (i) 3

8x

final answer

1

(ii) 15x7y3 final answer 2 M1 for 2 elements correct

(iii) 16x8 final answer 2 M1 for 16xk or kx8




(b)

[ ] 123.42

7 −−−

or better

and

p = [– –]7 and r = 2(3) oe

3.48, –1.15 cao

B1

B1

B1B1

or for

2

6

7

−x

Must see r

qp + or

r

qp − or both

or for

2

6

74

6

7

+±

After B0,

SC1 for answer 3.5 and –1.1

or 3.482… and –1.149 to –1.148 seen

or for 3.48, –1.15 seen

or for answer –3.48 and 1.15

(c) 2

5

x

x + or

2

51

xx

+ final answer

nfww

3

B1 for (x + 5)(x – 5)

and

B1 for x2(x – 5)

7 (a) 56sin882

1××× oe

26.52 to 26.53

M1

A1

or [½ × 2] 8sin28 × 8cos28 or [½ × 2] × 7.06… ×

3.75…

(b) (i)

72.[0] or 71.87 to 72.0

3 M2 for 26.5/( 25.6×π ) × 360 oe

or M1 for 5.265.6360

2=××π

x

or better

(ii)

21.1 or 21.2 or 21.14 to 21.17

3 M2 for 5.62360

×××πtheir (b)(i)

+ 2 × 6.5 oe

or M1 for 5.62360

×××πtheir (b)(i)

oe or 5.65.0 ×

(a)their

(c) (i) 30sin2

1

360

30 22××−×× rrπ oe

22

4

1

12

1rr ×−××π

−1

3

1

4

1 2πr

M2

A1

A1

M1 for 30sin2

1or

360

30 22×××× rrπ

Dep on M2 A1 and no errors seen

(ii)

20.6 or 20.7 or 20.55 to 20.71

3 M2 for [r2 =] ( )13

14

1

5

−π

or M1 for one correct rearrangement step to r

from

−1

3

1

4

1 2πr = 5




8 (a) (i) (1, 2) 1+1

(ii)

y = 3x – 1 cao final answer

3 M1 for gradient = 13

48

−−

−−

oe

and M1 for substituting (3, 8) or (–1, –4) into their

y = 3x + c or for finding y-intercept is –1

(b) (i) (x + 5)(x – 2) isw solutions 2 SC1 for (x + a)(x + b) where ab = –10 or a + b = 3

(ii) [a =] –5

[b =] 2

[c =] –10

3FT B1FT for each of their 5 and their –2 from (b)(i)

and B1 for c = –10

(iii) x = –1.5 1FT FT x = (their (a + b))/2

(c) Inverted parabola

x-axis intercepts at –2 and 9

y-axis intercept at 18

B1

B2

B1

B1 for each

After B0 allow SC1 for (9 – x)(2 + x) oe

(d) (i) p = 6

q = 43

3 B2 for (x + 6)2 – 43 or p = 6 or q = 43

or M1 for (x + 6)2 or x2 + px + px + p2

and

M1 for –7 – (their 6)2 or p2 – q = –7 or 2p = 12

(ii) –43 1FT FT – their q

9 (a) (i)

7

4 M2 for 7.17841011

8204191810171116=

++++

×+×++×+×

p

p

or better

or

M1 for sum of two correct products or better

or for [total =] 11 + 10 + 4 + 8 + p

and

B1 for 582 + 18p = 17.7 (33 + p)

(ii) 17 1FT STRICT FT median for their p if integer

(b) (i)

64

2 M1 for 4.6

320 × 1.28 oe

(ii)

40

2 M1 for 480

320 × 60 oe

(iii) 1.6[0] 2FT FT their (b)(i) / their (b)(ii) evaluated correctly to 2dp

M1 for their (b)(i) / their (b)(ii) or 4.6

480 × 1.28 ÷ 60




(c) 9.9125 cao 5 B4 for answer 9912.5

or

M1 for 25 to 35 × 290 to 310 oe

and B1 for 32.5 used and B1 for 305 or 5 mins 5 secs

used

and M1 indep for any correct conversion seen m to km

10 (a) (i) 5x + 14 final answer 2 M1 for 5x + k or kx + 14

(ii) 14.2 3 M1 for 5x = 32 – 14 FT their expression in (a)(i)

A1FT for x = 3.6

(b) 8a – 3b + 14 = 32.5 or better

5a + 4b + 13.5 = 39.75 or better

Equates coefficients of either a or b

40a – 15b = 92.5

40a + 32b = 210

or

32a – 12b = 74

15a + 12b = 78.75

Adds or subtracts to eliminate

47b = 117.5

47a = 152.75

[a =] 3.25

[b =] 2.5

B1

B1

M1

M1

A1

A1

8a – 3b = 18.5

5a + 4b = 26.25

or rearranges one of their equations to make a or b the

subject

e.g. 8

5.183 +=

ba

Dep on previous method

or correctly substitutes into the second equation

e.g.( )

25.2648

5.1835=+

+b

b

After M0 scored

SC1 for 2 correct values with no working

or for two values that satisfy one of their original

equations

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