(0999DJA110319005) )) Test Pattern DISTANCE LEARNING … · vks- vkj- ,l- esa gsj&Qsj@foÏfr u djsaA vks-vkj-,l- dk dPps dke ds fy , iz;ksx u djsaA 9. Wit yo nam, fo numbe sig it

READ THE INSTRUCTIONS CAREFULLY / Ïi;k bu funsZ'kks a dks /;ku ls i<+ s aGENERAL / lkekU; %1. This sealed booklet is your Question Paper. Do not break the seal till you are told to do so.

;g eksgjcU/k iqfLrdk vkidk iz'ui= gSA bldh eqgj rc rd u rksM+s tc rd bldk funsZ'k u fn;k tk;sA2. Use the Optical Response sheet (ORS) provided separately for answering the questions.

iz'uksa dk mÙkj nsus ds fy, vyx ls nh x;h vkWfIVdy fjLikal 'khV (vks- vkj- ,l-) (ORS) dk mi;ksx djsaA3. Blank spaces are provided within this booklet for rough work.

dPps dk;Z ds fy, bl iqfLrdk esa [kkyh LFkku fn;s x;s gSaA4. Write your name, form number and sign in the space provided on the back cover of this booklet.

bl iqfLrdk ds fiNys i`"B ij fn, x, LFkku esa viuk uke o QkWeZ uEcj fyf[k, ,oa gLrk{kj cukb;sA5. After breaking the seal of the booklet, verify that the booklet contains 42 pages and that all the

18 questions in each subject and along with the options are legible. If not, contact the invigilator forreplacement of the booklet.bl iqfLrdk dh eqgj rksM+us ds ckn Ïi;k tk¡p ysa fd blesa 42 i`"B gSa vkSj izR;sd fo"k; ds lHkh 18 iz'u vkSj muds mÙkj fodYi Bhdls i<+ s tk ldrs gSaA ;fn ugha] rks iz'ui= dks cnyus ds fy, fujh{kd ls lEidZ djsaA

6. You are allowed to take away the Question Paper at the end of the examination.ijh{kkFkhZ iz'ui= dks ijh{kk dh lekIrh ij ys tk ldrs gSaA

OPTICAL RESPONSE SHEET / vkWfIVdy fjLikal 'khV (vks-vkj-,l-) %7. The ORS will be collected by the invigilator at the end of the examination.

vks- vkj- ,l- dks ijh{kk ds lekiu ij fujh{kd ds }kjk ,d= dj fy;k tk,xkA8. Do not tamper with or mutilate the ORS. Do not use the ORS for rough work.

vks- vkj- ,l- esa gsj&Qsj@foÏfr u djsaA vks-vkj-,l- dk dPps dke ds fy, iz;ksx u djsaA9. Write your name, form number and sign with pen in the space provided for this purpose on the ORS.

Do not write any of these details anywhere else on the ORS. Darken the appropriate bubbleunder each digit of your form number.viuk uke vkSj QkWeZ uEcj vks-vkj-,l- esa fn, x, [kkuksa esa dye ls fy[ksa vkSj vius gLrk{kj djsaA buesa ls dksbZ Hkh fooj.kvks-vkj-,l- esa dgha vkSj u fy[ks aA QkWeZ uEcj ds gj vad ds uhps vuq:i cqycqys dks dkyk djsaA

DARKENING THE BUBBLES ON THE ORS / vks-vkj-,l- ij cqycqyks a dks dkyk djus dh fof/k %10. Use a BLACK BALL POINT PEN to darken the bubbles on the ORS.

vks-vkj-,l- ds cqycqyksa dks dkys ckWy ikWbUV dye ls dkyk djsaA

11. Darken the bubble COMPLETELY. / cqycqys dks iw.k ± :i ls dkyk djsaA

12. The correct way of darkening a bubble is as : / cqycqys dks dkyk djus dk mi;qDr rjhdk gS : 13. The ORS is machine-gradable. Ensure that the bubbles are darkened in the correct way.

vks-vkj-,l- e'khu tk¡P; gSA lqfuf'pr djsa dh cqycqys lgh fof/k ls dkys fd, x;sa gSaA14. Darken the bubbles ONLY IF you are sure of the answer. There is NO WAY to erase or

"un-darken" a darkened bubble.cqycqys dks rHkh dkyk djsa tc vki mÙkj ds ckjs esa fuf'pr gksA dkys fd, gq, cqycqys dks feVkus vFkok lkQ djus dk dksbZ rjhdk ugha gSA

15. Take g = 10 m/s2 unless otherwise stated. / g = 10 m/s2 iz;qDr djsa] tc rd fd vU; dksbZ eku ugha fn;k x;k gksAQUESTION PAPER FORMAT AND MARKING SCHEME / iz'ui= dk izk:i vkSj vadu ;kstuk %16. The question paper has three parts : Physics, Chemistry and Mathematics.

bl iz'ui= esa rhu Hkkx gSa % HkkSfrd foKku] jlk;u foKku ,oa xf.krA17. Each part has two sections as detailed last page in table.

izR;sd Hkkx esa nks [k.M gSa ftudk fooj.k vfUre i`"B ij rkfydk esa fn;k x;k gSAPlease see the last page of this booklet for rest of the instructions / Ïi;k 'ks"k funsZ'kk s a ds fy, bl iqfLrdk ds vfUre i`"B dks i<+ s aA

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Time : 3 Hours Maximum Marks : 186

)0999DJA110319005)(0999DJA110319005) Test Pattern

DISTANCE LEARNING PROGRAMME(Academic Session : 2019 - 2020)

JEE(Advanced)MINOR TEST # 04

18-08-2019

JEE(Main + Advanced) : LEADER TEST SERIES / JOINT PACKAGE COURSE

Test Type : Unit Test # 01, 02 & 0312th Undergoing/Pass Students

LTS-2/42

Target : JEE (Main + Advanced) 2020/18-08-2019

0999DJA110319005

Note : In case of any correction in the test paper, please mail to [email protected] within 2 days along with Paper Code& Your Form No.(uksV % ;fn bl iz'u i= esa dksbZ Correction gks rks Ïi;k Paper Code ,oa vkids Form No. ,oa iw.kZ Test Details ds lkFk 2 fnu ds [email protected] ij mail djsaA)

Space for Rough Work / dPps dk;Z ds fy, LFkku

SOME USEFUL CONSTANTSAtomic No. : H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16,

Cl = 17, Br = 35, Xe = 54, Ce = 58Atomic masses : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,

Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,Xe = 131, Ba=137, Ce = 140

· Boltzmann constant k = 1.38 × 10–23 JK–1

· Coulomb's law constant pe9

0

1 = 9×104

· Universal gravitational constant G = 6.67259 × 10–11 N–m2 kg–2

· Speed of light in vacuum c = 3 × 108 ms–1

· Stefan–Boltzmann constant s = 5.67 × 10–8 Wm–2–K–4

· Wien's displacement law constant b = 2.89 × 10–3 m–K· Permeability of vacuum µ0 = 4p × 10–7 NA–2

· Permittivity of vacuum Î0 = 20

1

cm· Planck constant h = 6.63 × 10–34 J–s

SYLLABUS :PHYSICS : Basic Mathematics used in Physics, Vectors, Units, Dimensions and Measurement,

Electrostatics, Kinematics, Current electricity, Laws of Motion and Friction &Capacitors

CHEMISTRY : Mole Concept, Atomic structure, Organic nomenclature, Basic principles of practicalorganic chemistry, Periodic properties, Basic inorganic nomenclature, Chemicalthermodynamics, Thermochemistry & GOC(complete)

MATHEMATICS : Logarithms, Trigonometric Ratios and Identities, Matrices, Determinants, QuadraticEquations & Linear Inequilities, Functions and Inverse Trignometric Function,Trigonometric Equations, Solution of Triangles, Height and Distance, DifferentialCalculus (Limit, Continuity, Differentiability, Differentiation)

ALLEN

0999DJA110319005

Leader Test Series/Joint Package Course/18-08-2019

LTS-3/42

ALLEN

BEWARE OF NEGATIVE MARKINGHAVE CONTROL ¾® HAVE PATIENCE ¾® HAVE CONFIDENCE Þ 100% SUCCESS

PART-1 : PHYSICS Hkkx-1 : HkkSfrd foKku

SECTION–I(i) : (Maximum Marks : 32) [k.M–I(i) : (vf/kdre vad : 32)

� This section contains EIGHT questions.� Each question has FOUR options for correct answer(s). ONE OR MORE THAN ONE of

these four option(s) is (are) correct option(s).� For each question, choose the correct option(s) to answer the question.� Answer to each question will be evaluated according to the following marking scheme:

Full Marks : +4 If only (all) the correct option(s) is (are) chosen.Partial Marks : +3 If all the four options are correct but ONLY three options are chosen.Partial Marks : +2 If three or more options are correct but ONLY two options are chosen,

both of which are correct options.Partial Marks : +1 If two or more options are correct but ONLY one option is chosen

and it is a correct option.Zero Marks : 0 If none of the options is chosen (i.e. the question is unanswered).Negative Marks : –1 In all other cases.

� For Example : If first, third and fourth are the ONLY three correct options for a question withsecond option being an incorrect option; selecting only all the three correct options will resultin +4 marks. Selecting only two of the three correct options (e.g. the first and fourth options),without selecting any incorrect option (second option in this case), will result in +2 marks.Selecting only one of the three correct options (either first or third or fourth option), withoutselecting any incorrect option (second option in this case), will result in +1 marks. Selectingany incorrect option(s) (second option in this case), with or without selection of any correctoption(s) will result in –1 marks.

� bl [kaM esa vkB iz'u gSaA� izR;sd iz'u ds lgh mÙkj (mÙkjksa) ds fy, pkj fodYi fn, x, gSaA bl pkj fodYiksa esa ls ,d ;k ,d ls vfèkd

fodYi lgh gS(gSa)A� izR;sd iz'u ds fy,] iz'u dk (ds) mÙkj nsus gsrq lgh fodYi (fodYiksa) dks pqusA� izR;sd iz'u ds mÙkj dk ewY;kadu fuEu vadu ;kstuk ds vuqlkj gksxk %

iw.kZ vad : +4 ;fn dsoy (lkjs) lgh fodYi (fodYiksa) dks pquk x;k gSAvkaf'kd vad : +3 ;fn pkjksa fodYi lgh gSa ijUrq dsoy rhu fodYiksa dks pquk x;k gSAvkaf'kd vad : +2 ;fn rhu ;k rhu ls vf/kd fodYi lgh gSa ijUrq dsoy nks fodYiksa dks pquk x;k gS vkSj

pqus gq, nksuks a fodYi lgh fodYi gSaAvkaf'kd vad : +1 ;fn nks ;k nks ls vf/kd fodYi lgh gSa ijUrq dsoy ,d fodYi dks pquk x;k gS vkSj

pquk gqvk fodYi lgh fodYi gSaA'kwU; vad : 0 ;fn fdlh Hkh fodYi dks ugha pquk x;k gS (vFkkZr~ iz'u vuqÙkfjr gS)A½.k vad : –1 vU; lHkh ifjfLFkfr;ksa esaA

� mnkgj.k Lo:i % ;fn fdlh iz'u ds fy, dsoy igyk] rhljk ,oa pkSFkk lgh fodYi gSa vkSj nwljk fodYi xyrgS_ rks dsoy lHkh rhu lgh fodYiks a dk p;u djus ij gh +4 vad feysax s aA fcuk dksbZ xyr fodYi pqus(bl mnkgj.k esa nwljk fodYi ) rhu lgh fodYiksa esa ls flQZ nks dks pquus ij (mnkgj.kr% igyk rFkk pkSFkk fodYi)+2 vad feysaxsA fcuk dksbZ xyr fodYi pqus (bl mnkgj.k esa nwljk fodYi)] rhu lgh fodYiksa esas ls flQZ ,ddks pquus ij (igyk ;k rhljk ;k pkSFkk fodYi) +1 vad feysaxsA dksbZ Hkh xyr fodYi pquus ij (bl mnkgj.kesa nwljk fodYi ), –1 vad feysaxs] pkgs lgh fodYi (fodYiksa) dks pquk x;k gks ;k u pquk x;k gksA

0999DJA110319005


LTS-4/42

ALLEN1. The energy of a particle is given by

,d d.k dh ÅtkZ fuEu izdkj nh tkrh gS]

( )2 FxAE Cx e

x x B-= +

+Where x is a distance from fixed point. Which of the following has dimension of energy ?tgk¡ x fLFkj fcUnq ls nwjh gSA fuEu esa ls fdldh foek;sa ÅtkZ ds leku gksxh\

(A) A

B x (B) CB2 (C) ABC (D) 2

CF

2. Twelve identical capacitors each of capacitance C are connected as shown in figure.

(A) The effective capacitance between P and T is 6C5

(B) The effective capacitance between P and U is 4C3

(C) The effective capacitance between P and V is 12C7

(D) All of the above statements are incorrectR

Q

T

S

UW

P V

izR;sd C /kkfjrk ds 12 le:i la/kkfj=ksa dks fp=kuqlkj tksM+k x;k gSA

(A) P o T ds e/; izHkkoh /kkfjrk 6C5

gSA (B) P o U ds e/; izHkkoh /kkfjrk 4C3

gSA

(C) P o V ds e/; izHkkoh /kkfjrk 12C7

gSA (D) mijksä lHkh dFku xyr gSA


0999DJA110319005


LTS-5/42

ALLEN3. In the figure shown a ring has uniformly distributed charge. Along its axis an oppositely

charged rod of small length is kept. It is released from the position shown. Only electric forcedue to ring acts on the rod. Ring is kept fixed. Which of the following is wrong ?(A) The rod will perform oscillation but not SHM.(B) The rod will perform SHM if it is uniformly charged.(C) The rod may perform SHM if it is non-uniformly charged.(D) The rod will perform oscillations only if the rod is uniformly charged.

,d oy; esa vkos'k ,dleku :i ls forjhr gSA bldh v{k ds vuqfn'k vYi yEckbZ dh ,d foijhr vkos'k okyh NM+

j[kh gqbZ gSA bls iznf'kZr fLFkfr ls fojkekoLFkk ls NksM+k tkrk gSA oy; ds dkj.k NM+ ij dsoy fo|qr cy dk;Z djrk gSA

oy; fLFkj j[kh xbZ gSA xyr dFku pqfu;s %&(A) NM+ nksyu djsxh ijUrq ljy vkorZ xfr ughA(B) NM+ ljy vkorZ xfr djsxh ;fn ;g ,dleku :i ls vkosf'kr gksA(C) NM+ ljy vkorZ xfr dj ldrh gS ;fn ;g vleku :i ls vkosf'kr gSA(D) NM+ nksyu djsxh dsoy ;fn ;g ,dleku :i ls vkosf'kr gksA

4. The angle between two vectors b&arr is q and the magnitude of b

r is half of magnitude of ar .

If bacrrr

-= & a|a| =r then choose the correct statements

(A) if a 5c2

= then q will be 90° (B) if a 3c2

= then q will be 60°

(C) if ac2

= then q will be 45° (D) if 3ac2

= then q will be 180°

nks lfn'kksa ar o br

ds e/; dks.k q gS rFkk br

dk ifjek.k ar ds ifjek.k ls vk/kk gSA ;fn bacrrr

-= rFkk a|a| =r gS rks

lgh dFkuksa dks pqfu;s :

(A) ;fn a 5c

2= gS rks q dk eku 90° gksxkA (B) ;fn

a 3c2

= gS rks q dk eku 60° gksxkA

(C) ;fn ac2

= gS rks q dk eku 45° gksxkA (D) ;fn 3ac2

= gS rks q dk eku 180° gksxkA


0999DJA110319005


LTS-6/42

ALLEN5. A part of circuit is shown in figure. Choose the correct option(s) :

fp= esa iznf'kZr ifjiFk ds ,d Hkkx ds fy;s lgh fodYi@fodYiksa dks pqfu;s%&

2V 3V

3A

4A

3ohm

3ohm

I2

I1

2A

(A) I1 = 1/3 A (B) I2 = 2/3 A (C) I1 = –1/3A (D) I2 = –2/3 A6. To measure the capacitance of a conductor, it is first charged to a potential V0 = 1350 V. It is

then connected by a conducting wire to a distant uncharged metal sphere of radius r = 3cm.As a result the conductor potential drops to V1 = 900 V. Choose the CORRECT option (s)(A) Initial charge on the conductor is 9nC

(B) Capacitance of the conductor is 1

150nF

(C) Charge on the metal sphere after connection is 6nC(D) Electrostatic potential energy decreases after redistribution of charges.fdlh pkyd dh /kkfjrk dks ekius ds fy, bls igys foHko V0 = 1350 V rd vkosf'kr fd;k tkrk gSA vc bls ,d

pkyd rkj }kjk nwj j[ks r = 3cm f=T;k okys vukosf'kr /kkfRod xksys ls tksM + nsrs gSaA blds QyLo:i pkyd dk foHko

V1 = 900 V rd fxj tkrk gSA lgh dFku@dFkuksa dks pqfu, :-(A) pkyd ij izkjfEHkd vkos'k 9nC gSA

(B) pkyd dh /kkfjrk 1

150nF gSA

(C) la;kstu djus ds ckn /kkfRod xksys ij vkos'k 6nC gksrk gSA

(D) vkos'kksa ds iquZforj.k ds ckn fLFkjoS|qr fLFkfrt ÅtkZ ?kV tkrh gSA


0999DJA110319005


LTS-7/42

ALLEN7. Acceleration of blocks at given instant are as shown in the figure. Coefficient of friction

between 10kg block and ground is 0.1. There is no friction between 5kg blocks and ground.Which of the following statements is/are CORRECT.(A) Force in spring A is 5N(B) Force in spring B is 15 N(C) Acceleration of block of mass 10 kg is 1 m/s2.(D) Spring A is in state of compression

5kg 10kg 5kgA BF=20N

5m/s2 3m/s2

fp= esa fdlh fn;s x;s {k.k ij CykWdksa ds Roj.k n'kkZ;s x;s gSA 10kg okys CykWd rFkk /kjkry ds e/; ?k"kZ.k xq.kkad 0.1gS rFkk 5kg okys CykWdksa ,oa /kjkry ds e/; dksbZ ?k"kZ.k fo|eku ugh gSA lgh dFku@dFkuksa dks pqfu;s%&

(A) fLçax A esa cy dk eku 5N gSA (B) fLçax B esa cy dk eku 15N gSA

(C) 10 kg æO;eku okys CykWd dk Roj.k 1 m/s2 gSA (D) fLizax A laihM+u dh voLFkk esa gSA8. An electric kettle heater has two coils. When one coil is switched on, the water in the kettle

begins to boil after 15 minutes, when the other coil is switched on the water boils in30 minutes.(A) The water will boil in 45 minutes if the coils are connected in series.(B) The water will boil in 10 minutes if the coils are connected in parallel.(C) Water boils in 22.5 minutes if coils are connected in series.(D) Water boils in 20 minutes if coils are connected in parallel.,d fo|qr dsryh ghVj esa nks dq.Mfy;k¡ yxh gqbZ gSA tc ,d dq.Myh dks pkyw fd;k tkrk gS rks dsryh eas Hkjk ikuh

15 feuV ckn mcyuk izkjEHk dj nsrk gSA tc nwljh dq.Myh dks pkyw fd;k tkrk gS rks ikuh 30 feuV esa mcyrk gS %&

(A) ;fn dq.Mfy;ksa dks Js.khØe esa tksM+k tk, rks ikuh 45 feuV esa mcysxkA

(B) ;fn dq.Mfy;ksa dks lekUrj Øe esa tksM+k tk, rks ikuh 10 feuV esa mcysxkA

(C) ;fn dq.Mfy;ksa dks Js.khØe esa tksM+k tk, rks ikuh 22.5 feuV esa mcysxkA

(D) ;fn dq.Mfy;ksa dks lekUrj Øe esa tksM+k tk, rks ikuh 20 feuV esa mcysxkA


0999DJA110319005


LTS-8/42

ALLENSECTION–I(ii) : (Maximum Marks : 12)

[kaM-I(ii) : (vf/kdre vad : 12)� This section contains TWO List-Match sets.� Each List-Match set has Two Multiple Choice Questions.� Each List-Match set has two lists : List-I and List-II� List-I has Four entries (I), (II), (III) and (IV) and List-II has Six entries (P), (Q), (R), (S), (T)

and (U)� FOUR options are given in each Multiple Choice Question based on List-I and List-II and

ONLY ONE of these four options satisfies the condition asked in the Multiple ChoiceQuestion.

� Answer to each question will be evaluated according to the following marking scheme :Full Marks : +3 If ONLY the option corresponding to the correct combination ischosen.Zero Marks : 0 If none of the options is chosen (i.e., the question is unanswered);Negative Marks : –1 In all other cases

� bl [kaM esa nks lwph-lqesyu (List-Match) lsV~l (sets) gSaA

� izR;sd lwph lqesyu lsV (set) esa nks ,dkf/kd fodYi iz'u (Multiple Choice Questions) gSaA

� izR;sd lwph&lqesyu lsV esa nks lwfp;k¡ gSa : lwph-I vkSj lwph-II� lwph-I esa pkj izfof"V;k¡ (I), (II), (III) vkSj (IV) gSa ,oa lwph-II esa N% izfof"V;k¡ (P), (Q), (R), (S), (T) vkSj (U)

gSaA

� izR;sd ,dkf/kd fodYi iz'u esa lwph-I vkSj lwph-II ij vk/kkfjr pkj fodYi fn;s x, gSa vkSj bu fodYiksa esa lsdsoy ,d fodYi gh ,dkf/kd fodYi iz'u dh 'krZ iwjk djrk gSA

� izR;sd iz'u ds mÙkj dk ewY;kadu fuEu ;kstuk ds vuqlkj gksxk :

iw.kZ vad : +3 ;fn flQZ lgh fodYi dks gh pquk x;k gSA

'kwU; vad : 0 ;fn dksbZ Hkh fodYi ugha pquk x;k gS (vFkkZr~ iz'u vuqÙkfjr gS)A

½.k vad : –1 vU; lHkh ifjfLFkfr;ksa esaA


0999DJA110319005


LTS-9/42

ALLEN9. Answer the following by appropriately matching the lists based on the information

given in the paragraph.vuqPNsn esa nh x;h tkudkjh ds vk/kkj ij lwfp;ks a dk mfpr feyku djds iz'u dk mÙkj nsaAConsider the situation shown in diagram. Both capacitors are having same capacitance C.Capacitors are initially uncharged. List-I represents value of r and List-II represents chargepassing through r during complete process. Now match the followings :fp= esa iznf'kZr fLFkfr ij fopkj dhft,A nksuksa la/kkfj = leku /kkfjrk C okys gSaA ;s la/kkfj= izkjEHk esa vukosf'kr gSaA

lwph&I esa r ds eku fn, x, gSa tcfd lwph-II esa lEiw.kZ izfØ;k ds nkSjku r ls izokfgr vkos'k dks n'kkZ;k x;k gSA

lwph feyku dhft;sA

VC

KR 2R

r

C

Switch K is closed at time = 0. After a long time capacitors are fully charged.t = 0 le; ij fLop K dks can dj fn;k tkrk gSA ,d yEcs le; i'pkr~ la/kkfj= iw.kZr;k vkosf'kr gks tkrs gSaA

List–I/lwph&I List–II/lwph&II

(I) r = 0 (P)CV6

(II) r = R (Q)CV5

(III) r = 2R (R)CV4

(IV) r = 3R (S)CV3

(T) Zero

(U)CV2

(A) I ® S, II ® T, III ® Q, IV ® U (B) I ® P, II ® R, III ® T, IV ® S(C) I ® P, II ® T, III ® Q, IV ® T (D) I ® S, II ® R, III ® Q, IV ® P


0999DJA110319005


LTS-10/42


given in the paragraph.vuqPNsn esa nh x;h tkudkjh ds vk/kkj ij lwfp;ks a dk mfpr feyku djds iz'u dk mÙkj nsaAConsider the situation shown in diagram. Both capacitors are having same capacitance C.Capacitors are initially uncharged. List-I represents value of r and List-II represents chargepassing through r during complete process. Now match the followings :fp= esa iznf'kZr fLFkfr ij fopkj dhft,A nksuksa la/kkfj = leku /kkfjrk C okys gSaA ;s la/kkfj= izkjEHk esa vukosf'kr gSaAlwph&I esa r ds eku fn, x, gSa tcfd lwph-II esa lEiw.kZ izfØ;k ds nkSjku r ls izokfgr vkos'k dks n'kkZ;k x;k gSA lwphfeyku dhft;sA

VC

KR 2R

r

C

Switch K is opened after reaching steady state.LFkk;h voLFkk esa igq¡pus ds i'pkr~ fLop K dks [kksy fn;k tkrk gSA

List- I /lwph&I List - II/lwph&II

(I) r = 0 (P)CV6

(II) r = R (Q)CV5

(III) r = 2R (R)CV4

(IV) r = 3R (S)CV3

(T) Zero

(U)CV2

(A) I ® S, II ® T, III ® Q, IV ® U (B) I ® T, II ® T, III ® T, IV ® T(C) I ® P, II ® P, III ® R, IV ® R (D) I ® S, II ® Q, III ® R, IV ® P


0999DJA110319005


LTS-11/42


given in the paragraph.vuqPNsn esa nh x;h tkudkjh ds vk/kkj ij lwfp;ks a dk mfpr feyku djds iz'u dk mÙkj nsaAIn the figure shown a block of mass 10 kg is resting on the inclined plane of inclination 37°.Two forces F1 and F2 parallel to incline plane are applied on the block in the directionsshown. If coefficient of friction is 0.5, a is acceleration of block and f is the value of friction,match the following :-fp= esa 10 kg æO;eku okyk ,d CykWd 37° vkur dks.k okys urry ij fojkekoLFkk esa j[kk gqvk gSA bl CykWd ij nks

cy F1 o F2 vkur ry ds lekUrj iznf'kZr fn'kkvksa esa yxk;s tkrs gSaA ;fn ?k"kZ.k xq.kkad 0.5 gks] a CykWd dk Roj.k gks rFkk

f ?k"kZ.k dk eku gks rks lwph feyku dhft;sA

37°F2

F1

List-I /lwph&I List-II /lwph&II(I) a = 0 (P) F1 = 20 N, F2 = 10 N(II) a = 1 m/s2 (Q) F1 = 30 N, F2 = 10 N(III) a = 2 m/s2 (R) F1 = 40 N, F2 = 40 N(IV) a = 4 m/s2 (S) F1 = 100 N, F2 = 70 N

(T) F1 = 80 N, F2 = 100 N(U) F1 = 110 N, F2 = 0

(A) I ® S; II ® T, U; III ® Q; IV ® R (B) I ® P; II ® T,U; III ® R; IV ® S(C) I ® Q, S; II ® P,U; III ® R; IV ® T (D) I ® S; II ® Q,U; III ® R; IV ® P


0999DJA110319005


LTS-12/42


given in the paragraph.vuqPNsn esa nh x;h tkudkjh ds vk/kkj ij lwfp;ks a dk mfpr feyku djds iz'u dk mÙkj nsaAIn the figure shown a block of mass 10 kg is resting on the inclined plane of inclination 37°.Two forces F1 and F2 parallel to incline plane are applied on the block in the directionsshown. If coefficient of friction is 0.5, a is acceleration of block and f is the value of friction,match the following :-fp= esa 10 kg æO;eku okyk ,d CykWd 37° vkur dks.k okys urry ij fojkekoLFkk esa j[kk gqvk gSA bl CykWd ij nks

cy F1 o F2 vkur ry ds lekUrj iznf'kZr fn'kkvksa esa yxk;s tkrs gSaA ;fn ?k"kZ.k xq.kkad 0.5 gks] a CykWd dk Roj.k gks rFkk

f ?k"kZ.k ds eku gks rks lwph feyku dhft;sA

37°F2

F1

List-I /lwph&I List-II /lwph&II(I) f = 10 N (P) F1 = 140 N, F2 = 20 N(II) f = 0 N (Q) F1 = 120 N, F2 = 30 N(III) f = 30 N (R) F1 = 70 N, F2 = 20 N(IV) f = 40 N (S) F1 = 120 N, F2 = 60 N

(T) F1 = 100 N, F2 = 70 N(U) F1 = 110 N, F2 = 0 N

(A) I ® S, II ® T, III ® Q, IV ® R,U (B) I ® P, II ® T, III ® R, IV ® S,U(C) I ® Q, S, II ® P, III ® R, IV ® T,U (D) I ® R, II ® S, III ® Q, T IV ® P,U


0999DJA110319005


LTS-13/42

ALLENSECTION-II : (Maximum Marks: 18)

[kaM-II : (vf/kdre vad : 18)� This section contains SIX questions.� The answer to each question is a NUMERICAL VALUE.� For each question, enter the correct numerical value (in decimal notation, truncated/rounded-

off to the second decimal place; e.g. 6.25, 7.00, –0.33, –.30, 30.27, –127.30, if answer is11.36777..... then both 11.36 and 11.37 will be correct) by darken the corresponding bubblesin the ORS.For Example : If answer is –77.25, 5.2 then fill the bubbles as follows.

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••

� Answer to each question will be evaluated according to the following marking scheme:Full Marks : +3 If ONLY the correct numerical value is entered as answer.Zero Marks : 0 In all other cases.

� bl [kaM esa N% iz'u gSaA

� izR;sd iz'u dk mÙkj ,d la[;kRed eku (NUMERICAL VALUE) gSA

� izR;sd iz'u ds mÙkj ds lgh la[;kRed eku (n'keyo vadu esa] n'keyo ds f}rh; LFkku rd :f.Mr@fudfVr_

mnkgj.k 6.25, 7.00, –0.33, –.30, 30.27, –127.30, ;fn mÙkj 11.36777..... gS] rks 11.36 vkSj 11.37 nksuksa lgh

gksxsa) dks izfo"B djus ds fy , vks-vkj-,l- esa vuq:i cqycqys dks dkyk djsaA

mnkgj.k ds fy , : ;fn mÙkj –77.25, 5.2 gS] rks cqycqyksa dks fuEu izdkj ls dkyk djsaA

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••

� izR;sd iz'u ds mÙkj dk ewY;kadu fuEu vadu ;kstuk ds vuqlkj gksxk %&

iw.kZ vad : +3 ;fn flQZ lgh la[;kRed eku (Numerical value) gh mÙkj Lo:i ntZ fd;k x;k gSA

'kwU; vad : 0 vU; lHkh ifjfLFkfr;ksa esaA


0999DJA110319005


LTS-14/42

ALLEN

1. If ˆ ˆ Â 2i j k= + +r

and ˆ ˆ ˆB 10i 5j 5k= + +r

, if the magnitude of component of ( )B A-rr

along Ar

is

4 x . Then x will be.

;fn ˆ ˆ Â 2i j k= + +r

rFkk ˆ ˆ ˆB 10i 5j 5k= + +r

gks ,oa Ar

ds vuqfn'k ( )B A-rr

ds ?kVd dk ifjek.k 4 x gks rks x dk

eku gksxkA2. Consider the E versus x graph. What is the minimum velocity that should be given to a point

charge –Q of mass M so that it can reach the origin? Take Q = 1 mC, mass of the charge as1 mg, E0 = 20 N/C, L = 5 m & 10 3.162= . (Assume particle is starting from x = 3L and movingtowards origin along X axis )E rFkk x ds e/; vkjs[k ij fopkj dhft;sA æO;eku M okys ,d fcUnq vkos'k –Q dks fdruk U;wure osx fn;k tkukpkfg;s rkfd ;g ewyfcUnq ij igq¡p lds\ Q = 1 mC, vkos'k dk æO;eku 1 mg, E0 = 20 N/C, L = 5 m rFkk

10 3.162= yhft;sA (ekuk d.k x = 3L ls izkjEHk gksdj X v{k ds vuqfn'k ewy fcUnq dh vksj xfr'khy gS)

3L2LL

E0

–E0

x


0999DJA110319005


LTS-15/42

ALLEN3. For the arrangement of the potentiometer shown in the figure, the balance point is obtained

at a distance 75 cm from A when the key k is open. The second balance point is obtained at60 cm from A when the key k is closed. Find the internal resistance (in W) of the battery E1.foHkoekih ds iznf'kZr ifjiFk esa tc dqath k [kqyh gqbZ gS rks larqyu fcUnq A ls 75 cm dh nwjh ij izkIr gksrk gSAtc k dks can dj fn;k tkrk gS rks nwljk larqyu fcUnq A ls 60 cm dh nwjh ij izkIr gksrk gSA cSVjh E1 dk vkarfjdizfrjks/k (W esa) Kkr dhft;sA

k

A B

G

E =2V0

.E =1.5V1

®24W

r

4. Three dielectric of relative primitivities e =1r

6 , e =2r

2 and e =3r

3 are introduced in a parallelplate capacitor of plate area A and separation d. The effective capacitance between P and Q

is 0x A

d

e. Then

5x

7 will be.

lkisf{kd fo|qr'khyrk (relative primitivities) e =1r

6 , e =2r

2 rFkk e =3r

3 okys rhu ijkoS|qrksa dks ,d lekUrjiê la/kkfj= esa izfo"V djk;k tkrk gSA bl la/kkfj= dh IysVksa dk {ks=Qy A rFkk buds e/; nwjh d gSA fp= esa iznf'kZr

fcUnq P rFkk Q ds e/; ;fn izHkkoh /kkfjrk 0x A

d

e gks rks

5x

7 dk eku gksxkA

P Q

A2

A2

d/2 d/2

e1 = 6

e2 = 2 e3 = 3


0999DJA110319005


LTS-16/42

ALLEN5. In the system shown the acceleration of the wedge of mass 5m is zero. If angle 'q' of wedge is

x

p, then calculate x (all surfaces are smooth).

iznf'kZr fudk; esa æO;eku 5m okys ost dk Roj.k 'kwU; gSA ;fn ost ds dks.k 'q' dk eku x

p gks rks x Kkr dhft;sA

(lHkh lrgas fpduh gS)

q

5m

m

2m

6. Two blocks are connected over a massless pulley as shown in fig. The mass of block A is 10kgand the coefficient of kinetic friction is 0.5. Block A slides down the incline at constant speed.The mass of block B in kg is __________.nks CykWdksa dks nzO;ekughu f?kjuh ij ls fp=kuqlkj tksM+k x;k gSA CykWd A dk nzO;eku 10kg rFkk xfrt ?k"kZ.kxq.kkad 0.5 gSA CykWd A ur&ry ij ls fu;r pky ls uhps dh vksj fQlyrk gSA CykWd B dk nzO;eku kg esa Kkr dhft,A


0999DJA110319005


LTS-17/42

ALLENPART-2 : CHEMISTRY

Hkkx-2 : jlk;u foKkuSECTION–I(i) : (Maximum Marks : 32)

[k.M–I(i) : (vf/kdre vad : 32)� This section contains EIGHT questions.� Each question has FOUR options for correct answer(s). ONE OR MORE THAN ONE of

these four option(s) is (are) correct option(s).� For each question, choose the correct option(s) to answer the question.� Answer to each question will be evaluated according to the following marking scheme:

Full Marks : +4 If only (all) the correct option(s) is (are) chosen.Partial Marks : +3 If all the four options are correct but ONLY three options are chosen.Partial Marks : +2 If three or more options are correct but ONLY two options are chosen,

both of which are correct options.Partial Marks : +1 If two or more options are correct but ONLY one option is chosen

and it is a correct option.Zero Marks : 0 If none of the options is chosen (i.e. the question is unanswered).Negative Marks : –1 In all other cases.

� For Example : If first, third and fourth are the ONLY three correct options for a question withsecond option being an incorrect option; selecting only all the three correct options will resultin +4 marks. Selecting only two of the three correct options (e.g. the first and fourth options),without selecting any incorrect option (second option in this case), will result in +2 marks.Selecting only one of the three correct options (either first or third or fourth option), withoutselecting any incorrect option (second option in this case), will result in +1 marks. Selectingany incorrect option(s) (second option in this case), with or without selection of any correctoption(s) will result in –1 marks.

� bl [kaM esa vkB iz'u gSaA� izR;sd iz'u ds lgh mÙkj (mÙkjksa) ds fy, pkj fodYi fn, x, gSaA bl pkj fodYiksa esa ls ,d ;k ,d ls vfèkd

fodYi lgh gS(gSa)A� izR;sd iz'u ds fy,] iz'u dk (ds) mÙkj nsus gsrq lgh fodYi (fodYiksa) dks pqusA� izR;sd iz'u ds mÙkj dk ewY;kadu fuEu vadu ;kstuk ds vuqlkj gksxk %

iw.kZ vad : +4 ;fn dsoy (lkjs) lgh fodYi (fodYiksa) dks pquk x;k gSAvkaf'kd vad : +3 ;fn pkjksa fodYi lgh gSa ijUrq dsoy rhu fodYiksa dks pquk x;k gSAvkaf'kd vad : +2 ;fn rhu ;k rhu ls vf/kd fodYi lgh gSa ijUrq dsoy nks fodYiksa dks pquk x;k gS vkSj

pqus gq, nksuks a fodYi lgh fodYi gSaAvkaf'kd vad : +1 ;fn nks ;k nks ls vf/kd fodYi lgh gSa ijUrq dsoy ,d fodYi dks pquk x;k gS vkSj

pquk gqvk fodYi lgh fodYi gSaA'kwU; vad : 0 ;fn fdlh Hkh fodYi dks ugha pquk x;k gS (vFkkZr~ iz'u vuqÙkfjr gS)A½.k vad : –1 vU; lHkh ifjfLFkfr;ksa esaA

� mnkgj.k Lo:i % ;fn fdlh iz'u ds fy, dsoy igyk] rhljk ,oa pkSFkk lgh fodYi gSa vkSj nwljk fodYi xyrgS_ rks dsoy lHkh rhu lgh fodYiks a dk p;u djus ij gh +4 vad feysax s aA fcuk dksbZ xyr fodYi pqus(bl mnkgj.k esa nwljk fodYi) rhu lgh fodYiksa esa ls flQZ nks dks pquus ij (mnkgj.kr% igyk rFkk pkSFkk fodYi)+2 vad feysaxsA fcuk dksbZ xyr fodYi pqus (bl mnkgj.k esa nwljk fodYi)] rhu lgh fodYiksa esas ls flQZ ,ddks pquus ij (igyk ;k rhljk ;k pkSFkk fodYi) +1 vad feysaxsA dksbZ Hkh xyr fodYi pquus ij (bl mnkgj.kesa nwljk fodYi), –1 vad feysaxs] pkgs lgh fodYi (fodYiksa) dks pquk x;k gks ;k u pquk x;k gksA

0999DJA110319005


LTS-18/42

ALLEN1. Solid KClO3 is taken in a container maintained at constant pressure of 1 atm. Upon heating

following equilibria is set :2KClO3(s) 2KCl(s) + 3O2(g)If DH° = 25 kcal/mol and DS° = 50 cal/K, at what temperature equilibrium will be establishedin the container.(Ignore variation of DH° and DS° with temperature.)(A) 298 K (B) 500 K (C) 5000 K (D) Data insufficient,d ik= esa Bksl KClO3 fy;k x;k gS o 1 atm dk nkc fu;r j[kk x;k gSA xeZ djus ij fuEu lkE; LFkkfir

gksrk gS&2KClO3(s) 2KCl(s) + 3O2(g);fn DH° = 25 kcal/mol rFkk DS° = 50 cal/K gks rks ik= esa] fdl rki ij lkE; LFkkfir gksxkA

(rki ds lkFk DH° rFkk DS° ds ifjorZu dks ux.; ekusa)(A) 298 K (B) 500 K (C) 5000 K (D) vkadM+s vi;kZIr

2. Which among the following order of radius of given species is (are) INCORRECT :-nh xbZ Lih'kht dh f=T;k dk] fuEu esa ls dkSulk Øe xyr gS ?(A) N3– > P3– (B) S2– > O2– (C) Mg2+ > Na+ (D) Ca2+ > Sr2+

3. Select the CORRECT option(s)(A) E.A. order : O > Se(B) I.E. order : Ne > Mg2+

(C) E.N. of N-atom in : NO2 > N2O3 (symmetrical)(D) Atomic radius order : Rb > Brlgh fodYi pqfu,&

(A) E.A. Øe : O > Se(B) I.E. Øe : Ne > Mg2+

(C) N-ijek.kq dh E.N. : NO2 > N2O3 (lefer)(D) ijekf.o; f=T;k dk Øe : Rb > Br


0999DJA110319005


LTS-19/42

ALLEN4. Consider the IE1 of the following elements, whose electronic configurations correspond to

the following :-rRoksa ds IE1 ij fopkj dhft, ftuds bysDVªkWuh; foU;kl fuEu ls lEcfU/kr gSa :-(P) [Ne]3s23p3 (Q) [Ne]3s23p4 (R) [Ar]4s2 (S) [Ar]3d104s2

The CORRECT order of ionisation energy is :-vk;uu ÅtkZ dk lgh Øe gS :-(A) R > S (B) R < S (C) P > Q (D) P < Q

5. Find out the correct statement(s) about the following compound(A) Principle functional group is carboxylic acid(B) Maximum carbons in selected principle carbon chain is five(C) Principle functional group is alcohol(D) 4-[1-amino ethyl]-2-ethyl-3-hydroxy pent-4-en-1-oic acid is correct IUPAC name

CO OH

CH2

OH NH2

fuEu ;kSfxd ds ckjs es lgh dFkuks dk p;u dhft;s

(A) eq[; fØ;kRed lewg dkcksZfDlfyd vEy gSA

(B) p;u dh x;h ewy dkcZu Ük` a[kyk es dkcZuks dh vf/kdre la[;k 5 gSA

(C) eq[; fØ;kRed lewg ,sYdksgkWy gSA

(D) 4-[1-vehuks ,sfFky]-2-,sfFky-3-gkbMªk WDlh isUV-4-bZu-1-vksbZd vEy lgh IUPAC uke gSA


0999DJA110319005


LTS-20/42

ALLEN6. Bhopal treagedy gas is

(A) Methyl isocyanate (B) Methyl isocyanide(C) CH3–NC (D) CH3 – N = C = OHkksiky xSl =klnh (treagedy) gS

(A) esfFky vkblkslk;usV (B) esfFky vkblkslk;ukbM(C) CH3–NC (D) CH3 – N = C = O

7. Which of the following is/are correctly matched with their IUPAC name?

(A) C – HO

C – OHO 4-formyl pentanoic acid

(B) C – O – CH3

O

methyl cyclo hexanoate

(C) CH – CNCH – CN2

CH – CN propane-1,2,3-tricarbonitrile

(D) C – ClO

benzene carbonyl chloride


0999DJA110319005


LTS-21/42

ALLEN

fuEu es ls dkSuls ;kSfxd muds IUPAC uke ds lkFk lgh :i ls lqesfyr gS\

(A) C – HO

C – OHO 4-QkfeZy isUVsuksbZd vEy

(B) C – O – CH3

O

esfFky lkbDyks gsDlsuks,V

(C) CH – CNCH – CN2

CH – CN izksisu-1,2,3-VªkbZdkcksZukbVªkbZy

(D) C – ClO

csathu dkcksZfuy DyksjkbM

8. Which of the following has correct numbering for IUPAC naming?fuEu es ls dkSu ls fodYi es IUPAC ukedj.k ds fy;s dkcZu ijek.kqvks ij lgh vadu fd;k x;k gS\

(A)

C – OHO

Br12

34

56 (B)

Br

12

3

45

6

Cl(C)

C – HO

Br

1 2

34

5

6Cl

(D)

H C2

NH2

1

2

3 45


0999DJA110319005


LTS-22/42

Space for Rough Work /

SECTION–I(ii) : (Maximum Marks : 12)

-I(ii) : ( : 12)

This section contains TWO List-Match sets. Each List-Match set has Two Multiple Choice Questions. Each List-Match set has two lists : List-I and List-II List-I has Four entries (I), (II), (III) and (IV) and List-II has Six entries (P), (Q), (R), (S), (T)

and (U) FOUR options are given in each Multiple Choice Question based on List-I and List-II and


Answer to each question will be evaluated according to the following marking scheme :Full Marks : +3 If ONLY the option corresponding to the correct combination ischosen.Zero Marks : 0 If none of the options is chosen (i.e., the question is unanswered);Negative Marks : –1 In all other cases

- (List-Match) (sets) (set) (Multiple Choice Questions) : -I -II

-I (I), (II), (III) (IV) -II (P), (Q), (R), (S), (T) (U)

-I -II

:

: +3 : 0 : –1

0999DJA110319005


LTS-23/42


given in the paragraphvuqPNsn es a nh xbZ tkudkjh ds vk/kkj ij lwfp;ks a dk mfpr feyku djds iz'u dk mÙkj ns aA‘x’ gm of a compound A3B2C5 contains ‘y’ gm A atoms, ‘z’ gm B atoms & ‘W’ gm atomsof C. Using above information match the following :-‘x’ gm ;kSfxd A3B2C5 esa ‘y’ gm A ijek.kq, ‘z’ gm B ijek.kq rFkk ‘W’ gm- C ijek.kq mifLFkr gSa rks mijksDrlwpuk dk iz;k sx djrs gq, fuEu dks lqesfyr dhft, &

List–I/lwph–I List–II/lwph–II

(I) Atomic weight of A (P)5 y3 W

A dk ijek.kq Hkkj

(II) Atomic weight of B (Q)z

WB dk ijek.kq Hkkj

(III) Atomic weight of C (R)5xW

C dk ijek.kq Hkkj

(IV) Molecular weight of A3B2C5 (S)x y z

W- -

A3B2C5 dk vkf.od Hkkj (T)5z

2W

(U)5W3y

Which is the CORRECT match considering List I & List II?lwph–I rFkk lwph–II esa ls dkSulk feyku lgh gS?(A) I – T (B) II – S (C) III – P (D) IV – R


0999DJA110319005


LTS-24/42

ALLEN


10. Answer the following by appropriately matching the lists based on the informationgiven in the paragraphvuqPNsn es a nh xbZ tkudkjh ds vk/kkj ij lwfp;ks a dk mfpr feyku djds iz'u dk mÙkj ns aA‘x’ gm of a compound A3B2C5 contains ‘y’ gm A atoms, ‘z’ gm B atoms & ‘W’ gm-atomsof C. Using above information match the following :-‘x’ gm ;kSfxd A3B2C5 esa ‘y’ gm A ijek.kq, ‘z’ gm B ijek.kq rFkk ‘W’ gm- C ijek.kq mifLFkr gSa rks mijksDrlwpuk dk iz;k sx djrs gq, fuEu dks lqesfyr dhft, &

List–I/lwph–I List–II/lwph–II

(I) Atomic weight of A (P)5 y3 W

A dk ijek.kq Hkkj

(II) Atomic weight of B (Q)z

WB dk ijek.kq Hkkj

(III) Atomic weight of C (R)5xW

C dk ijek.kq Hkkj

(IV) Molecular weight of A3B2C5 (S)x y z

W- -

A3B2C5 dk vkf.od Hkkj (T)5z

2W

(U)5W3y

Which is the INCORRECT match considering List I & List II?lwph–I rFkk lwph–II esa ls dkSulk feyku xyr gS?(A) I – P (B) II – T (C) III – S (D) IV – Q

0999DJA110319005


LTS-25/42

ALLEN11. List-I/lwph-I List-II/lwph-II

Compound/;kSfxd Characteristic/vfHky{k.k

(I) CO H

OH

CO Cl

(P) Double bond equivalent is 2}ca/k rqY;kad 2 gSA

(II)O

(Q) 6 carbons are selected in selection of principlecarbon chain for IUPACIUPAC ds fy, eq[; dkcZu Ükà[kyk ds p;u es 6 dkcZu p;furgksrs gSA

(III)

H2N O

C – HO

(R) 5 carbons are selected in selection of principlecarbon chain for IUPACIUPAC ds fy, eq[; dkcZu Ükà[kyk ds p;u es 5 dkcZu p;furgksrs gSA

(IV) C – OCH3

O

(S) Double bond equivalent is 3f}ca/k rqY;kad 3 gSA

(T) Total functional groups in compound is 2;kSfxd es dqy fØ;kRed lewg 2 gSA

(U) Total functional groups in compounds is 3;kSfxdks es dqy fØ;kRed lewg 3 gSA

Which of the following options has correct combination considering list-I and list-II?lwph-I rFkk lwph-II ij fopkj djrs gq;s dkSuls fodYi es lgh la;kstu n'kkZ;k x;k gS\(A) (IV), (R), (S), (T) (B) (III), (R), (S), (U)(C) (IV), (Q), (P), (T) (D) (III), (Q), (S), (U)


0999DJA110319005


LTS-26/42

ALLEN

12. List-I/lwph-I List-II/lwph-IICompound/;kSfxd Characteristic/vfHky{k.k

(I) CO H

OH

CO Cl

(P) Double bond equivalent is 2f}ca/k rqY;kad 2 gSA

(II)

O

(Q) 6 carbons are selected in selection of principlecarbon chain for IUPACIUPAC ds fy, eq[; dkcZu Ükà[kyk ds p;u es 6 dkcZu p;fur

gksrs gSA

(III)

H2N O

C – HO

(R) 5 carbons are selected in selection of principlecarbon chain for IUPACIUPAC ds fy, eq[; dkcZu Ükà[kyk ds p;u es 5 dkcZu p;fur

gksrs gSA

(IV) C – OCH3

O

(S) Double bond equivalent is 3f}ca/k rqY;kad 3 gSA

(T) Total functional groups in compound is 2;kSfxd es dqy fØ;kRed lewg 2 gSA

(U) Total functional groups in compounds is 3;kSfxdks es dqy fØ;kRed lewg 3 gSA

Which of the following option has correct combination considering list-I and list-II?lwph-I rFkk lwph-II ij fopkj djrs gq;s dkSuls fodYi es lgh la;kstu n'kkZ;k x;k gS\(A) (I), (P), (R), (U) (B) (II), (P), (Q), (T)(C) (I), (P), (Q), (U) (D) (II), (R), (S), (T)


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LTS-27/42

ALLENSECTION-II : (Maximum Marks: 18)

[kaM-II : (vf/kdre vad : 18)� This section contains SIX questions.� The answer to each question is a NUMERICAL VALUE.� For each question, enter the correct numerical value (in decimal notation, truncated/rounded-


0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

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•

•

•

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•

•

••

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••


� bl [kaM esa N% iz'u gSaA� izR;sd iz'u dk mÙkj ,d la[;kRed eku (NUMERICAL VALUE) gSA� izR;sd iz'u ds mÙkj ds lgh la[;kRed eku (n'keyo vadu esa] n'keyo ds f}rh; LFkku rd :f.Mr@fudfVr_

mnkgj.k 6.25, 7.00, –0.33, –.30, 30.27, –127.30, ;fn mÙkj 11.36777..... gS] rks 11.36 vkSj 11.37 nksuksa lghgksxsa) dks izfo"B djus ds fy, vks-vkj-,l- esa vuq:i cqycqys dks dkyk djsaAmnkgj.k ds fy, : ;fn mÙkj –77.25, 5.2 gS] rks cqycqyksa dks fuEu izdkj ls dkyk djsaA

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

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••

� izR;sd iz'u ds mÙkj dk ewY;kadu fuEu vadu ;kstuk ds vuqlkj gksxk%&iw.kZ vad : +3 ;fn flQZ lgh la[;kRed eku (Numerical value) gh mÙkj Lo:i ntZ fd;k x;k gSA'kwU; vad : 0 vU; lHkh ifjfLFkfr;ksa esaA


0999DJA110319005


LTS-28/42

ALLEN


1. Calculate magnitude of enthalpy of combustion of benzene (l) at 1 atm & 298 K from thefollowing data :

Bond C – H C – C C = C C = O O – H O = OBond enthalpy (kJ/mole) 400 350 600 700 450 500DHvap. [C6H6(l)] = 30 kJ / moleDHvap. [H2O(l)] = 40 kJ / moleResonance energy of benzene = –150 kJ / moleResonance energy of CO2 = –140 kJ / molefuEu vk¡dM+ks dh lgk;rk ls 1 atm rFkk 298 K ij csUthu (l) dh ngu dh ,UFkSYih ds ifjek.k dh x.kuk dhft;s :

Bond C – H C – C C = C C = O O – H O = OBond enthalpy (kJ/mole) 400 350 600 700 450 500

DHvap. [C6H6(l)] = 30 kJ / moleDHvap. [H2O(l)] = 40 kJ / molecsUthu dh vuqukn ÅtkZ = –150 kJ / moleCO2 dh vuqukn ÅtkZ = –140 kJ / mole

2. Gas A taken in a closed rigid container is allowed to decompose partially to the reaction.A(g) 2B(g) 3C(g)¾¾® +The gaseous mixture formed effuses 1.5 times faster then a gas having molecular weight 105under similar condition. Find the mole fraction of C in the gaseous mixture formed.Given : Mol. wt. of A = 140

Mol. wt. of B = 64Mol. wt. of C = 4

Write your answer by multiplying with 10.xSl A dks ,d cUn n`< ik= esa fuEu vfHkfØ;k ds vuqlkj vkaf'kd fo;ksftr gksus fn;k x;k

A(g) 2B(g) 3C(g)¾¾® +

leku ifjfLFkfr;ksa esa 105 vkf.od Hkkj okyh ,d xSl dh rqyuk esa cuus okyk xSlh; feJ.k dk fu%lj.k 1.5 xquk

rsth ls gksrk gSA cuus okys xSlh; feJ.k esa C dk eksyizHkkt Kkr dhft,A

fn;k gS : A dk vkf.od Hkkj = 140B dk vkf.od Hkkj = 64C dk vkf.od Hkkj = 4

vius mÙkj dks 10 ls xq.kk djds fyf[k,A

0999DJA110319005


LTS-29/42

ALLEN3. A H-like species is excited (may be from ground state or excited state) by a photon

wavelength l.When electrons return back to ground state photons of six different wavelengthare observed. Out of six '3' photons have wavelength less than l. Find the 'n' of energy levelin which electrons are present intially.,d H-ds leku Lih'kht dks l rjaxnS/; Z okys ,d QksVk Wu }kjk mÙksftr (vk| voLFkk ;k mÙk sftr voLFkk ls)fd;k x;kA tc bysDVªkWu iqu% vk| voLFkk esa ykSVrk gS rks N% fofHkUu rjaxnS/; Z ds QksVkWuks a dks izsf{kr fd;k x;kA

N% esa ls '3' QksVkWuksa dh rjaxnS/; Z l ls de gSA ÅtkZ Lrj dk 'n' crkb;sa ftlesa izkjEHk esa bysDVªkWu mifLFkr gSaA4. Which of the following having electronegativity greater than 'O' :-

fuEu esa ls fdldh fo|qr½.krk 'O' dh rqyuk esa vf/kd gS :-S , N , Cl , Na , K , Fe , Mn , Y , Ac


0999DJA110319005


LTS-30/42

ALLEN


5. Maximum carbons in selected principle carbon chain in following compound for IUPAC nameis?IUPAC uke ds fy;s fuEu ;kSfxd es p;u dh x;h ewy dkcZu Ük` a[kyk es dkcZuks dh vf/kdre la[;k gS\

CH = C – CH – CH – CH – CH2 2 32

O = C – Cl

CH – CH3 2

6. How many 1°–amine (primary amine) are present among the given belowuhps fn;s x;s ;kSfxdks es fdrus 1°–,ehu (izkFkfed ,ehu) mifLFkr gS\

(i)

NH2

(ii) NH

(iii) NH2

(iv) NH2

(v) CH – CH – N – CH3 2 3

H(vi)

NH2

(vii) CH – N – CH3 3

CH3(viii) Ph – NH – CH3

0999DJA110319005


LTS-31/42

PART-3 : MATHEMATICS

-3 : SECTION–I(i) : (Maximum Marks : 32)

–I(i) : ( : 32)

This section contains EIGHT questions.

Each question has FOUR options for correct answer(s). ONE OR MORE THAN ONE of

these four option(s) is (are) correct option(s).

For each question, choose the correct option(s) to answer the question.

Answer to each question will be evaluated according to the following marking scheme:

Full Marks : +4 If only (all) the correct option(s) is (are) chosen.

Partial Marks : +3 If all the four options are correct but ONLY three options are chosen.

Partial Marks : +2 If three or more options are correct but ONLY two options are chosen,

both of which are correct options.

Partial Marks : +1 If two or more options are correct but ONLY one option is chosen

and it is a correct option.

Zero Marks : 0 If none of the options is chosen (i.e. the question is unanswered).

Negative Marks : –1 In all other cases.

For Example : If first, third and fourth are the ONLY three correct options for a question with

second option being an incorrect option; selecting only all the three correct options will result

in +4 marks. Selecting only two of the three correct options (e.g. the first and fourth options),

without selecting any incorrect option (second option in this case), will result in +2 marks.

Selecting only one of the three correct options (either first or third or fourth option), without

selecting any incorrect option (second option in this case), will result in +1 marks. Selecting

any incorrect option(s) (second option in this case), with or without selection of any correct

option(s) will result in –1 marks.

() ()

: +4 : +3 : +2

: +1

: 0 : –1

+4 +2 +1 , –1

0999DJA110319005


LTS-32/42

ALLEN

1. ƒ (x) =

2 2 k cos ec xcos x sin xe 2

, x 0e 1

k , x 0

ìæ ö-ïç ÷ ¹ïç ÷-íè øï=ïî

If ƒ (x) is discontinuous at x = 0, then k can be equal to:-;fn ƒ (x), x = 0 ij larr~ ugha gS] rks k gks ldrk gS :-(A) 2 (B) 1 (C) 3 (D) e

2. If 1 1 1 1 1

2 2 2 2 2

3 3 3 3 3

a b x a x b c

a b x a x b c 0

a b x a x b c

+ ++ + =+ +

, then possible conditions is/are -

(A) x = 1 " ai, bi, where 1 £ i, j £ 3 (B) x = –1 " ai, bi, where 1 £ i, j £ 3

(C) 1 1 1

2 2 2

3 3 3

a b c

a b c 0

a b c

= (D) x = ± 2 " ai, bi, where 1 £ i, j £ 3

;fn 1 1 1 1 1

2 2 2 2 2

3 3 3 3 3

a b x a x b c

a b x a x b c 0

a b x a x b c

+ ++ + =+ +

, rks laHko izfrca/k gksaxs&

(A) x = 1 " ai, bi, tgk¡ 1 £ i, j £ 3 (B) x = –1 " ai, bi, tgk¡ 1 £ i, j £ 3

(C) 1 1 1

2 2 2

3 3 3

a b c

a b c 0

a b c

= (D) x = ± 2 " ai, bi, tgk¡ 1 £ i, j £ 3

3. If ƒ (x) = tan–1(cotx) + cot–1(tanx) for all x in domain of ƒ, then -(A) range of ƒ (x) is (0, p)(B) function is discontinuous at infinite number of points

(C) range of ƒ (x) is ,2pé ù-pê úë û

(D) ƒ (x) is odd functionSpace for Rough Work / dPps dk;Z ds fy, LFkku

0999DJA110319005


LTS-33/42

ALLEN

;fn ƒ (x) = tan–1(cotx) + cot–1(tanx), ƒ ds izkUr ds lHkh x ds fy, gS] rks -(A) ƒ (x) dk ifjlj (0, p) gksxk

(B) Qyu vuUr fcUnqvksa ij vlarr~ gksxk

(C) ƒ (x) dk ifjlj ,2pé ù-pê úë û gksxk

(D) ƒ (x) fo"ke Qyu gS4. Let A be a square matrix with B as its adjoint & C be the adjoint of B.

If |A| = 1 then |C –1B + BA| is equal to -eku A ,d oxZ vkO;wg rFkk B bldk lg[k.Mt gS rFkk C, B dk lg[k.Mt gSA ;fn |A| = 1, rks |C –1B + BA| dk

eku gksxk -(A) |A + B| (B) |B + C| (C) |A + C| (D) |A + adjC|

5. If f(x) = ( )2x log cos x x 0log 1 x

0 x 0

ì ¹ï +íï =î

then :

(A) f(x) is not continuous at x = 0(B) f(x) is continuous at x = 0(C) f(x) is continuous at x = 0 but not differentiable at x = 0(D) f(x) is differentiable at x = 0

;fn f(x) = ( )2x log cos x x 0log 1 x

0 x 0

ì ¹ï +íï =î

gks] rks :

(A) x = 0 ij f(x) lrr ugha gSA

(B) x = 0 ij f(x) lrr gSA

(C) x = 0 ij f(x) lrr gS ijUrq x = 0 ij vodyuh; ugha gSA

(D) x = 0 ij f(x) vodyuh; gSA


0999DJA110319005


LTS-34/42

ALLEN


6. If –1 & –2 lie between the real roots of kx4 + x3 + 2kx2 + x + k = 0, then k can be equal to :-;fn –1 rFkk –2 lehdj.k kx4 + x3 + 2kx2 + x + k = 0 ds okLrfod ewyksa ds e/; fLFkr gS] rks k dk laHkkfor eku

gksxk :-

(A) 15

(B) 13

(C) 37

(D) 59

7. If a, b, c are in A.P. and a, b, g are positive real numbers in G.P., then the equation2

2

2

x a x log k

x b x log k 0

x c x log k

+ + a+ + b =+ + g

:-

(A) is an identity (B) has a root x = 1(C) has a root x = 0 (D) has real & identical roots;fn a, b, c lekUrj Js.kh esa rFkk a, b, g /kukRed okLrfod la[;k;s a xq.kk sÙkj Js.kh esa gS] rks lehdj.k

2

2

2

x a x log k

x b x log k 0

x c x log k

+ + a+ + b =+ + g

:-

(A) loZlfedk gksxh (B) dk ,d ewy x = 1 gksxk

(C) dk ,d ewy x = 0 gksxk (D) ds okLrfod rFkk leku ewy gksaxs

8. The value(s) of x for which ƒ (x) = sin x

2

e

4 x 9- - is continuous, is (are) -

(A) 3 (B) –3 (C) 5 (D) all x Î (–¥, –3] È [3, ¥)

x dk eku ftlds fy, ƒ (x) = sinx

2

e

4 x 9- - larr~ gS] gksaxs -

(A) 3 (B) –3 (C) 5 (D) lHkh x Î (–¥, –3] È [3, ¥)

0999DJA110319005


LTS-35/42

ALLENSECTION–I(ii) : (Maximum Marks : 12)

[kaM-I(ii) : (vf/kdre vad : 12)� This section contains TWO List-Match sets.� Each List-Match set has Two Multiple Choice Questions.� Each List-Match set has two lists : List-I and List-II� List-I has Four entries (I), (II), (III) and (IV) and List-II has Six entries (P), (Q), (R), (S), (T)

and (U)� FOUR options are given in each Multiple Choice Question based on List-I and List-II and


� Answer to each question will be evaluated according to the following marking scheme :Full Marks : +3 If ONLY the option corresponding to the correct combination ischosen.Zero Marks : 0 If none of the options is chosen (i.e., the question is unanswered);Negative Marks : –1 In all other cases

� bl [kaM esa nks lwph-lqesyu (List-Match) lsV~l (sets) gSaA

� izR;sd lwph lqesyu lsV (set) esa nks ,dkf/kd fodYi iz'u (Multiple Choice Questions) gSaA

� izR;sd lwph&lqesyu lsV esa nks lwfp;k¡ gSa : lwph-I vkSj lwph-II� lwph-I esa pkj izfof"V;k¡ (I), (II), (III) vkSj (IV) gSa ,oa lwph-II esa N% izfof"V;k¡ (P), (Q), (R), (S), (T) vkSj (U)

gSaA

� izR;sd ,dkf/kd fodYi iz'u esa lwph-I vkSj lwph-II ij vk/kkfjr pkj fodYi fn;s x, gSa vkSj bu fodYiksa esa ls

dsoy ,d fodYi gh ,dkf/kd fodYi iz'u dh 'krZ iwjk djrk gSA

� izR;sd iz'u ds mÙkj dk ewY;kadu fuEu ;kstuk ds vuqlkj gksxk :iw.kZ vad : +3 ;fn flQZ lgh fodYi dks gh pquk x;k gSA

'kwU; vad : 0 ;fn dksbZ Hkh fodYi ugha pquk x;k gS (vFkkZr~ iz'u vuqÙkfjr gS)A

½.k vad : –1 vU; lHkh ifjfLFkfr;ksa esaA


0999DJA110319005


LTS-36/42

ALLEN


List-1 contains ƒ(x).List-2 contains range of function ƒ(x).lwph-1 esa ƒ(x) fo|eku gSA

lwph-2 esa ƒ(x) dk ifjlj fo|eku gSA

List-I/lwph-I List-II/lwph-II

(I) - ++

3x(x 3x 2)x 1 (P)

é ö¥÷êë ø

3 ,4

(II) cot–1(2x – x2) (Q) R – {0}(III) 4x – 2x + 1 (R) R

(IV) log8(x2 + 2x + 1) (S)pé öp÷êë ø

,4

(T)p pé ö

÷êë ø

3,2 2

(U) pæ öpç ÷è ø

,2

9. Which of the following is the only correct combination ?fuEu esa ls dkSulk dsoy lgh la;kstu gksxk\(A) (II), (S) (B) (IV), (Q) (C) (III), (R) (D) (I), (Q)

10. Which of the following is the only correct combination ?fuEu esa ls dkSulk dsoy lgh la;kstu gksxk\(A) (II), (R) (B) (III), (P) (C) (II), (P) (D) (IV), (Q)

0999DJA110319005


LTS-37/42

Space for Rough Work /

Let incircle of ABC with B = C, touches AB, BC, CA at R, P, Q respectively. If inradius

'r' is integer and perimeter of ABC is smallest possible integer such that 2 5 5 6

AR BP CQ r

then

ABC B = C AB, BC, CA R, P, Q

'r' ABC 2 5 5 6

AR BP CQ r

Match the entries listed in List-I to the corresponding values in List-II.

-I -II

List-I/-I List-II/-II

(I) r (P) 1

(II) Area of ABC (Q) 2

ABC (III) Absolute value of tanA (R) 3

tanA

(IV)B

cot2

(S)24

7

(T)27

4

(U) 27

11. Which of the following is the only correct combination ?

(A) (I), (P) (B) (III), (S) (C) (II), (T) (D) (IV), (Q)

12. Which of the following is the only correct combination ?

(A) (II), (U) (B) (I), (S) (C) (IV), (Q) (D) (III), (R)

0999DJA110319005


LTS-38/42

ALLEN


SECTION-II : (Maximum Marks: 18) [kaM-II : (vf/kdre vad : 18)

� This section contains SIX questions.� The answer to each question is a NUMERICAL VALUE.� For each question, enter the correct numerical value (in decimal notation, truncated/rounded-


0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••


� bl [kaM esa N% iz'u gSaA

� izR;sd iz'u dk mÙkj ,d la[;kRed eku (NUMERICAL VALUE) gSA

� izR;sd iz'u ds mÙkj ds lgh la[;kRed eku (n'keyo vadu esa] n'keyo ds f}rh; LFkku rd :f.Mr@fudfVr_

mnkgj.k 6.25, 7.00, –0.33, –.30, 30.27, –127.30, ;fn mÙkj 11.36777..... gS] rks 11.36 vkSj 11.37 nksuksa lgh

gksxsa) dks izfo"B djus ds fy, vks-vkj-,l- esa vuq:i cqycqys dks dkyk djsaA

mnkgj.k ds fy, : ;fn mÙkj –77.25, 5.2 gS] rks cqycqyksa dks fuEu izdkj ls dkyk djsaA

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••

0 0 0

+

0

–

0 01 1 1 1 1 12 2 2 2 2 23 3 3 3 3 34 4 4 4 4 45 5 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

•

•

•

•

•

•

•

•

••

� izR;sd iz'u ds mÙkj dk ewY;kadu fuEu vadu ;kstuk ds vuqlkj gksxk%&

iw.kZ vad : +3 ;fn flQZ lgh la[;kRed eku (Numerical value) gh mÙkj Lo:i ntZ fd;k x;k gSA

'kwU; vad : 0 vU; lHkh ifjfLFkfr;ksa esaA

0999DJA110319005


LTS-39/42

ALLEN


1. Let a, b, c, l, m, n Î R such that al + bm + cn = 0, bl + cm + an = 0, cl + am + bn = 0. If a, b & c are

distinct & ƒ (x) = ax3 + bx2+ cx + 5, then the value of ƒ(1)4 is

ekuk a, b, c, l, m, n Î R bl izdkj gS fd al + bm + cn = 0, bl + cm + an = 0, cl + am + bn = 0 gSA ;fn a,

b rFkk c fHkUu gS rFkk ƒ (x) = ax3 + bx2+ cx + 5 gS] rks ƒ(1)4 dk eku gksxk

2. The number of solutions of the equation 6cos5q – 6cos4q – 5cos3q + 5cos2q + cosq – 1 = 0,where 0 < q < 360° islehdj.k 6cos5q – 6cos4q – 5cos3q + 5cos2q + cosq – 1 = 0, tgk¡ 0 < q < 360° gS] ds gyksa dh la[;k gS

3. In a triangle ABC , if (a + b + c)(a + b – c) = lab, then number of integral values of l isf=Hkqt ABC es] ;fn (a + b + c)(a + b – c) = lab gS, rks l ds iw.kk±d ekuksa dh la[;k gksxh

0999DJA110319005


LTS-40/42

ALLEN


4. Suppose for any integer n ; (n 1); if n is evenƒ(n)

2n; if n is odd

-ì= í

î. If k Î N & ƒ (ƒ (ƒ (k))) = 21; then the

value of k5 is

ekuk fdlh iw.kk±d n ds fy, (n 1); n

ƒ(n)2n; n

ì -ï= íïî

;fn le gS

;fn fo"ke gS gSA ;fn k Î N rFkk ƒ (ƒ (ƒ (k))) = 21 gS; rks

k5 dk

eku gksxk5. If A = sin4a + cos4a and B = sin6b + cos6b for a, b Î R, then the value of + + -max min(A 2B) (2A B) is

;fn A = sin4a + cos4a rFkk B = sin6b + cos6b, tc a, b Î R gks] rks + + -max min(A 2B) (2A B) dk eku gksxk

6. Let ƒ (x) = max. {tanx, cotx} then number of roots of the equation ƒ (x) = 1

3 in (0, 2p) is -

ekuk ƒ (x) = vf/kdre {tanx, cotx} gS] rks vUrjky (0, 2p) esa lehdj.k ƒ (x) = 1

3 ds ewyksa dh la[;k gksxh -


LTS-41/420999DJA110319005

ALLEN

Corporate Office : ALLEN CAREER INSTITUTE, “SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan) INDIA 324005

+91-744-2757575 [email protected] www.dlp.allen.ac.in, dsat.allen.ac.in

Your Target is to secure Good Rank in JEE 2020 0999DJA110319005LTS-42/42


I have read all the instructionsand shall abide by them.

eSaus lHkh funs Z'kks a dks i<+ fy;k gS vkSj eS mudkvo'; ikyu d:¡xk@d:¡xhA

____________________________Signature of the Candidate / ijh{kkFkhZ ds gLrk{kj

I have verified the identity, name and Formnumber of the candidate, and that questionpaper and ORS codes are the same.eSaus ijh{kkFkhZ dk ifjp;] uke vkSj QkWeZ uEcj dks iwjh rjgtk¡p fy;k gS ,oa iz'u i= vkSj vks- vkj- ,l- dksM nksuks a leku gSaA

____________________________Signature of the Invigilator / fujh{kd ds gLr k{kj

NAME OF THE CANDIDATE / ijh{kkFkhZ dk uke .............................................................................FORM NO. / QkWeZ uEcj .............................................

ALLEN Que. No. Category-wise Marks for Each Question / oxkZuqlkj izR;sd iz'u ds vad MaximumSection Type of Full Marks Partial Marks Zero Marks Negative Marks of the

Que. iw.kZ vad vkaf'kd vad 'kwU; vad Marks section[k.M iz'u dk iz'uksa ½.k vad [k.M esa

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+4 +1 0 –1One or more If only the bubble(s) For darkening a bubble If none In all

correct corresponding corresponding to each of the otheroption(s) to all the correct correct option, provided bubbles is cases

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(Single corresponding to of the othercorrect option) the correct option bubbles is cases

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+3 0Numerical If only the bubble In allValue Type corresponding other

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(n'keyo ds nks dkyk fd;k gSLFkku rd)

Dear Student,

We request you to provide feedback for the test series till you have appeared. Kindly answer the questionsprovided on the reverse of paper with honesty and sincerely.

Although our test series questions are extremely well designed and are able to improve speed, accuracy &developing examination temperament, yet we are always open to improvements.

If you have not prepared well for today's test and if you are not feeling good today, then do not blame testseries for it.

We strive to prepare you for all kinds of situations and facing variations in paper, as this can also happen inMain exam. It is important for you to concentrate on your rank.

Go through the feedback form thoroughly and answer with complete loyalty. Darken your response (2, 1, 0) inOMR sheet corresponding to :

Distance Learning Programmes(Session-2019-20)

ALL INDIA TEST SERIES

ABOUT FEEDBACK SYSTEM

Questions

1. Any problem in subscription of test series:

[2] Not at all [1] Some time [0] Problem faced

2. Test paper start on time:

[2] As per schedule [1] Some time deviate from schedule [0] Always delay

3. Test paper timing :

[2] Comfortable [1] Average [0] Need to be change

4. Location of test center:

[2] Good and approachable [1] Average in terms of approach [0] difficult to reach

5. Are you satisfy with result analysis :

[2] Outstanding [1] Average [0] Below average

6. The level of test paper [meet all the requirement of competitive examination]

[2] Outstanding [1] Average [0] Below average

7. Number of mistake in test papers

[2] Negligible [1] Are very less [0] Maximum

8. Do you think our test series is able to improve speed, accuracy & developing examination temperament?

[2] Yes [1] Partly [0] Not at all

9. Response from ALLEN on email / telephonically

[2] Always good and prompt [1] Some time delay [0] Not satisfactory

10. Response on test center

[2] Satisfactory [1] Partly Satisfactory [0] Not good

Documents

(0999DJA110319005) )) Test Pattern DISTANCE LEARNING … · vks- vkj- ,l- esa gsj&Qsj@foÏfr u djsaA vks-vkj-,l- dk dPps dke ds fy , iz;ksx u djsaA 9. Wit yo nam, fo numbe sig it