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1 §2.4 Optimization. The student will learn how to optimization of a function.

1 §2.4 Optimization. The student will learn how to optimization of a function

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Page 1: 1 §2.4 Optimization. The student will learn how to optimization of a function

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§2.4 Optimization.

The student will learn how to optimization of a function.

Page 2: 1 §2.4 Optimization. The student will learn how to optimization of a function

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Review of Business Functions Total Cost Function C (x) = a + b x

(Where a is the fixed cost and b x is the variable cost.)

Price Function p (x)

(Which gives the price p at which consumers will buy exactly x units of the product.)

Revenue Function R = x p

(where p is the unit price and x is the quantity sold.)

Profit Function

P = R – C

Page 3: 1 §2.4 Optimization. The student will learn how to optimization of a function

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Review of Business Functions

Total Cost Function C (x) = a + b x

Average Cost FunctionC(x)

Cx

Marginal Cost Function C ' (x)

Marginal Average Cost Function C

The same is true for revenue, price and profit.

Consider going to my website and downloading the handout on

business functions.

Page 4: 1 §2.4 Optimization. The student will learn how to optimization of a function

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Review of Business Functions

We are going to see how to maximize or minimize these business functions. This is why you are in this course!

Page 5: 1 §2.4 Optimization. The student will learn how to optimization of a function

Explain!

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R (x)

A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are:

R (x) = xp =

C (x) = 60,000 + 60x and p = 200 – x/50 for 0 ≤ x ≤ 8,000

a. Find the maximum revenue. x

x(200 )50

R ‘ (x) = x

20025

or x = 5,000, and

R(5000) = $500,000

0 x 8,000 0 y 600,000.

Example 1

(5000, 500000) from calculator

Maximum at R ‘ (x) = 0

Explain!

2x200x

50

How do we maximize?

Page 6: 1 §2.4 Optimization. The student will learn how to optimization of a function

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P (x)

Example 1 continued

P (x) =

b. Find the maximum profit and the production level that will realize the maximum profit.

Solving P ‘ (x) = 0 gives a value at x =

2(200x x / 50) (60000 60x)

P (3500) =

P ‘ (x) = x140

25

3500.

$185,0000 x 8,000 0 y 600,000.

C (x) = 60,000 + 60x and R = 200x – x 2/50 for 0 ≤ x ≤ 8,000

(3500, 185000) From calculator.

Production level Maximum profit

WOW!2x

140x 60,00050

How do we maximize?

Page 7: 1 §2.4 Optimization. The student will learn how to optimization of a function

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R

C

P

Example 1 continued

P (x) =

c. Graph the cost and the revenue and the profit functions on the same graph.

Note the break even points (profit is 0).

2x140x 60,000

50

Max R at x = 5000.0 x 8,000 0 y 600,000.

C (x) = 60,000 + 60x and R = 200x – x 2/50 for 0 ≤ x ≤ 8,000

Note that max profit and max revenue do not occur at the same x value.

Max P at x = 3500.

Page 8: 1 §2.4 Optimization. The student will learn how to optimization of a function

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Example 1 continued

This brings us to a classic economic criteria for maximum profit

C ’ = R ’

C (x) = 60,000 + 60x and R = 200x – x 2/50 for 0 ≤ x ≤ 8,000

60 = 200 – x/25

x/25 = 140

x = 3500 as before.

R

C

P

Page 9: 1 §2.4 Optimization. The student will learn how to optimization of a function

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Example 1 concluded

Maximum revenue of $500,000 occurred at a sales level of 5,000.

R = 200x – x 2/50 and P(x) =

What price should you charge to maximize your profit?????

How many do you want to sell? x = 3500 as before.

C (x) = 60,000 + 60x and p = 200 – x/50 for 0 ≤ x ≤ 8,000 2x

140x 60,00050

Maximum profit of $185,000 occurred at a sales level of 3,500.

p (3500) = 200 – 3500/50 = 200 – 70 = $130

Now that is some mathematics!powerful

Page 10: 1 §2.4 Optimization. The student will learn how to optimization of a function

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Maximizing Tax Revenue If a tax on imports is too high, fewer will be sold and tax revenues will go down. To maximize revenue we need to find the tax rate that will produce the appropriate sales so that revenue is maximized.

Continued

What is the tax revenue?

What is the revenue?

$ 0

$ 0.11 million

Suppose that the relationship between the tax rate t on an item and its total sales S isS (t) = 4 – 6 3 t

At a tax rate of t = .08, sales will be S (0.08) = 4 – 6 Sales = 1.41 million dollars.

3 0.08

At a tax rate of t = 0, sales will be S (0) = 4 – 6 Sales = 4 million dollars.

3 0

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Tax Revenue ContinuedIf a tax on imports is too high, fewer will be sold and tax revenues will go down. To maximize revenue we need to find the tax rate that will produce the appropriate sales so that revenue is maximized.

The previous has shown the relationship between tax rate and sales. But we want the total revenue.R (t) = rate · sales =

S (t) = 4 – 6

Maximize R with your calculator!

t = 0.125 or 12.5% 0 ≤ x ≤ 0.2 0 ≤ y ≤ 0.15

R (t) = rate · sales = t · S (t) = t (4 – 6 ) = 4t – 6 t 4/33 t

3 t

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Optimization Although all of the optimizations we did today involved maximums it is also possible to optimize using minimums. For instance one might want to minimize the amount of materials or labor used in making a product. To do this follow the same methods we used today but when graphing use the minimum option under the appropriate menu on your calculator.

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Summary.

• We reviewed basic business functions.

• We learned how to optimization a tax revenue function.

• We learned how to optimize a function using our calculators and a derivative.

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ASSIGNMENT

§2.4 on my website.

1, 2, 3, 4, 5, 6, 7, 8, 9, 10.