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Lecture 25: DNA mutation, proofreading, and repair
Figure 16.7a, c (c) Space-filling model
C
T
A
A
T
CG
GC
A
C G
AT
AT
A T
TA
C
TA0.34 nm
3.4 nm
G
1 nm
G
T
2
Lecture Outline 11/2/05
• Review DNA replication machine
• Fidelity of replication and proofreading
• Replicating the ends of chromosomes
• Mutation– Types of mutations– Repair mechanisms
3
Figure 16.13
New strand Template strand5 end 3 end
Sugar A TBase
C
G
G
C
A
C
T
PP
P
OH
P P
5 end
Pyrophosphate
Phosphate
DNA synthesis goes 5’ to 3’
• DNA polymerases, add nucleotides to the 3 OH at the end of a growing strand
Nucleosidetriphosphate
OH
P
4Peter J. Russell, iGenetics: Copyright © Pearson Education, Inc., publishing as Benjamin Cummings.
Model for the “replication machine,” or replisome
5
Replication overview• Look at animations on your textbook CD
• Look again at the animation from DNAi– http://www.dnai.org– (go to the section on copying the code)
6Figs. from http://www.mun.ca/biochem/courses/3107
DNA Polymerase III• A complex enzyme with many subunits• one part adds the nucleotides• another helps it slide along the template• another checks for mis-pairing
7
Proofreading
• Even though bases preferentially pair G-C and A-T, the initial error rate is about 1 in 10,000.
• Many polymerases have “proofreading” ability. They can excise an mis-paired base and try again.
• This reduces the error rate to about 1 in a million.
One polymerase subunit adds nucleotides
Another “edits” out incorrect bases
8
Fidelity of replication
Replication step error rate
5′→3′ polymerization 1 × 105
3′→5′ proofreading 1 × 102
Strand-directed mismatch repair 1 × 102
Total error rate 1 × 109
9
What happens to the lagging strand at the very end of the chromosome?
3’
5’
Leaves a gap when the RNA primer is removed
5’
3’
3’
5’
10Figure 16.18
End of parentalDNA strands
Leading strandLagging strand
Last fragment Previous fragment
RNA primer
Lagging strand
Removal of primers andreplacement with DNAwhere a 3 end is available
Second roundof replication
New leading strand
New lagging strand 5
Further roundsof replication
Shorter and shorterdaughter molecules
5
3
5
3
5
3
5
3
3
Primer removed butcannot be replacedwith DNA becauseno 3 end available
for DNA polymerase
The ends of eukaryotic chromosomal DNA get shorter with each round of replication
If they get short enough, essential genes will eventually be deleted
11
Telomerase
Carries its own RNA template
Extends the old (template) strand
Normal synthesis of new DNA
12
What happens to the lagging strand that the end of the chromosome?
• Telomeres contain hundreds of simple tandem repeats. • In humans, the repeat sequence is TTAGGG
TTAGGG TTAGGG TTAGGG TTAGGG TTAGGG . . . . . . .
Lots of junk, so if the ends get slightly shorter, no essential genes are lost
• Cell lines with active telomerase live longer than those without telomerase. – That may be important in allowing cancer cells to continue to divide.
13
Mutations and repair
14
Various kinds of mutations:Purine -> Purine or Pymimidine -> Pyrimidine: common
Purine -> Pymimidine: rare
Some mutations change the code to a new amino acid
15
Types of base pair substitutions and mutations.
Additions and deletions
Others are silent
16
Mutations can be caused by:
• Chemical mutagens
• Ionizing radiation
• Slippage during DNA replication
• Spontaneous errors
17
--C-----G---
--U-----A---
--U-----G--- --G---
--C---
--T-----A---
Deamination changes C to U
After replication, new strand has an A
Chemical changes in one of the nucleotide bases
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UV damage (e.g. pyrimidine dimers)
UV radiation can cause thymine dimers
19
20Figure 16.17
Nuclease
DNApolymerase
DNAligase
A thymine dimerdistorts the DNA molecule.1
A nuclease enzyme cutsthe damaged DNA strandat two points and thedamaged section isremoved.
2
Repair synthesis bya DNA polymerasefills in the missingnucleotides.
3
DNA ligase seals theFree end of the new DNATo the old DNA, making thestrand complete.
4
• In nucleotide excision repair– Enzymes cut out and replace damaged
stretches of DNA
21
Certain bacterial mutations cause increased mutation rates
Defect in: Rifr mutants per 108 cells
Wild-type (mut+ ) 5-10
Pol III proofreading
(mutD)
4000-5000
Mis-match repair
(mutS)
760
Base excision repair
(mutY mutM)
8200
22
Mismatch repairHere is a mis-paired base that must be
repaired:
GT
How does the mismatch repair system know which strand is the new one and which strand is the old one?
How is the mistake recognized?
23
GT
MutS/L/H
GT GATC
CTAG
CH3
MutS/L/H
The old (template) DNA has methyl groups in certain places
Certain enzymes detect the deformed helix that results from the incorrect pairing
Cut the newly synthesized strand here
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GGATC G
CH3
CH3
GC
GATCCTAG
DNA pol I/IIIDNA Ligase
Re-synthesize DNA from the template using the normal DNA polymerases
Corrected base pair
25
• Various similar mechanisms for other types of mutations